Let's create a RandomFunction using 0 and 1
$begingroup$
I asked you the last time, but I can not solve it.
I have a function that return 0 and 1 at random
const get_zero_or_one = () => {
return Math.floor(Math.random() * (2))
}
I want to make a random function using the above function. But without Math.random (except get_zero_or_one used above).
const RandomResult = (max_number) => {
let answer = 0;
for (let i = 0; i < max_number -1; i++) {
answer += get_zero_or_one()
}
return answer
}
This is the code I wrote. Can I change to better code?
The reason I do not use Random.math is the challenge I found in Korea.
What I think is the problem with my code is that I send a high factor value to my code RandomResult because the result is inaccurate.
Thanks.
javascript
asked 9 mins ago
MarcusMarcus
1
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$endgroup$
add a comment |
$begingroup$
I asked you the last time, but I can not solve it.
I have a function that return 0 and 1 at random
const get_zero_or_one = () => {
return Math.floor(Math.random() * (2))
}
I want to make a random function using the above function. But without Math.random (except get_zero_or_one used above).
const RandomResult = (max_number) => {
let answer = 0;
for (let i = 0; i < max_number -1; i++) {
answer += get_zero_or_one()
}
return answer
}
This is the code I wrote. Can I change to better code?
The reason I do not use Random.math is the challenge I found in Korea.
What I think is the problem with my code is that I send a high factor value to my code RandomResult because the result is inaccurate.
Thanks.
javascript
asked 9 mins ago
MarcusMarcus
1
New contributor
Marcus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I asked you the last time, but I can not solve it.
I have a function that return 0 and 1 at random
const get_zero_or_one = () => {
return Math.floor(Math.random() * (2))
}
I want to make a random function using the above function. But without Math.random (except get_zero_or_one used above).
const RandomResult = (max_number) => {
let answer = 0;
for (let i = 0; i < max_number -1; i++) {
answer += get_zero_or_one()
}
return answer
}
This is the code I wrote. Can I change to better code?
The reason I do not use Random.math is the challenge I found in Korea.
What I think is the problem with my code is that I send a high factor value to my code RandomResult because the result is inaccurate.
Thanks.
javascript
asked 9 mins ago
MarcusMarcus
1
New contributor
Marcus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I asked you the last time, but I can not solve it.
I have a function that return 0 and 1 at random
const get_zero_or_one = () => {
return Math.floor(Math.random() * (2))
}
I want to make a random function using the above function. But without Math.random (except get_zero_or_one used above).
const RandomResult = (max_number) => {
let answer = 0;
for (let i = 0; i < max_number -1; i++) {
answer += get_zero_or_one()
}
return answer
}
This is the code I wrote. Can I change to better code?
The reason I do not use Random.math is the challenge I found in Korea.
What I think is the problem with my code is that I send a high factor value to my code RandomResult because the result is inaccurate.
Thanks.
javascript
javascript
asked 9 mins ago
MarcusMarcus
1
New contributor
Marcus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
MarcusMarcus
1
New contributor
Marcus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
MarcusMarcus
1
New contributor
Marcus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
MarcusMarcus
1
asked 9 mins ago
MarcusMarcus
1
1
New contributor
Marcus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Marcus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Marcus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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