Mac terminal : Sed regex, extracting part of a string












0















I have a string , exactly a file path



/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt,



I need to extract the path of its folder ,



to get /Users/dengjiangzhou/Documents/源码/198/ .



Here is what I tried.



echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@p' 



/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt


I use regex capture group , try to capture group one /李宏毅-机器学习2017秋季.txt, and replace it with ,



Seems like that regex capture group have the effect of matching from the end to beginning.



then I will get 



/Users/dengjiangzhou/Documents/源码/198


I have read Sed regex, extracting part of a string in Mac terminal again and again.



Hope get helped, amigo



Really want to get /Users/dengjiangzhou/Documents/源码/198/,



/Users/dengjiangzhou/Documents/源码/198 is not good.



any good idea?






mac terminal regex sed







share|improve this question



























    0















    I have a string , exactly a file path



    /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt,



    I need to extract the path of its folder ,



    to get /Users/dengjiangzhou/Documents/源码/198/ .



    Here is what I tried.



    echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@p' 
    

    
/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt


    I use regex capture group , try to capture group one /李宏毅-机器学习2017秋季.txt, and replace it with ,



    Seems like that regex capture group have the effect of matching from the end to beginning.



    then I will get 



    /Users/dengjiangzhou/Documents/源码/198


    I have read Sed regex, extracting part of a string in Mac terminal again and again.



    Hope get helped, amigo



    Really want to get /Users/dengjiangzhou/Documents/源码/198/,



    /Users/dengjiangzhou/Documents/源码/198 is not good.



    any good idea?






    mac terminal regex sed







    share|improve this question

























      0












      0








      0








      I have a string , exactly a file path



      /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt,



      I need to extract the path of its folder ,



      to get /Users/dengjiangzhou/Documents/源码/198/ .



      Here is what I tried.



      echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@p' 
      

      
/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt


      I use regex capture group , try to capture group one /李宏毅-机器学习2017秋季.txt, and replace it with ,



      Seems like that regex capture group have the effect of matching from the end to beginning.



      then I will get 



      /Users/dengjiangzhou/Documents/源码/198


      I have read Sed regex, extracting part of a string in Mac terminal again and again.



      Hope get helped, amigo



      Really want to get /Users/dengjiangzhou/Documents/源码/198/,



      /Users/dengjiangzhou/Documents/源码/198 is not good.



      any good idea?






      mac terminal regex sed







      share|improve this question














      I have a string , exactly a file path



      /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt,



      I need to extract the path of its folder ,



      to get /Users/dengjiangzhou/Documents/源码/198/ .



      Here is what I tried.



      echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@p' 
      

      
/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt


      I use regex capture group , try to capture group one /李宏毅-机器学习2017秋季.txt, and replace it with ,



      Seems like that regex capture group have the effect of matching from the end to beginning.



      then I will get 



      /Users/dengjiangzhou/Documents/源码/198


      I have read Sed regex, extracting part of a string in Mac terminal again and again.



      Hope get helped, amigo



      Really want to get /Users/dengjiangzhou/Documents/源码/198/,



      /Users/dengjiangzhou/Documents/源码/198 is not good.



      any good idea?






      mac terminal regex sed




      mac terminal regex sed






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Jan 11 at 2:10









      black_pearlblack_pearl

      1086




      1086






















          1 Answer
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          1














          The first try doesn't work because the escape for + is missing



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@' 
          
/李宏毅-机器学习2017秋季.txt


          (escapes for metacharacters can be avoided with -r or -E option, for Extended RE).



          What you want is the dirname part, then just group the first part of the ER.



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@(.*)/.*@1@' 
          
/Users/dengjiangzhou/Documents/源码/198


          The quantifiers in sed are greedy, it means that when you ask to match a regex like .*/.*, the first .* will match all line until the end, because you asked to match anything. in any number*, and a / is anything in any number.



          edit- If you want to read about regular expressions and sed, take a look
          https://www.regular-expressions.info/tutorial.html
          http://www.grymoire.com/Unix/Sed.html#uh-0






          share|improve this answer


























          • The second regex is intuitive and nice. could you tell me why I try the first regex in my terminal echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' result is /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt. not you showed above

            – black_pearl
            Jan 11 at 3:27








          • 1





            @black_pearl This command line echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' you posted in the comment works, the output is /李宏毅-机器学习2017秋季.txt. Are you running this at MacOS (by the post title)? If yes, we are running different versions of sed, I'm on GNU/Linux. I don't know if all those unicode characters could affect the output. Could you try only with ASCII to see if it works echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' results in expected /file2017.txt

            – Paulo
            Jan 11 at 12:01











          • I run in a MacBook. No , still that. echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' , result is /Users/dengjiangzhou/Documents/198/file2017.txt. I should read your links, and try

            – black_pearl
            Jan 11 at 15:19








          • 1





            This does work? echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed -E 's@.*(/.+)@1@'. Try that with the unicode string too please, it should work. I ran in a FreeBSD VirtualBox vm and it worked, but it's language isn't properly configured.

            – Paulo
            Jan 11 at 17:58






          • 1





            It seems that backreference in MacOS belongs to ERE, it needs -E option.

            – Paulo
            Jan 12 at 13:25











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          active

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          1














          The first try doesn't work because the escape for + is missing



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@' 
          
/李宏毅-机器学习2017秋季.txt


          (escapes for metacharacters can be avoided with -r or -E option, for Extended RE).



          What you want is the dirname part, then just group the first part of the ER.



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@(.*)/.*@1@' 
          
/Users/dengjiangzhou/Documents/源码/198


          The quantifiers in sed are greedy, it means that when you ask to match a regex like .*/.*, the first .* will match all line until the end, because you asked to match anything. in any number*, and a / is anything in any number.



          edit- If you want to read about regular expressions and sed, take a look
          https://www.regular-expressions.info/tutorial.html
          http://www.grymoire.com/Unix/Sed.html#uh-0






          share|improve this answer


























          • The second regex is intuitive and nice. could you tell me why I try the first regex in my terminal echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' result is /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt. not you showed above

            – black_pearl
            Jan 11 at 3:27








          • 1





            @black_pearl This command line echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' you posted in the comment works, the output is /李宏毅-机器学习2017秋季.txt. Are you running this at MacOS (by the post title)? If yes, we are running different versions of sed, I'm on GNU/Linux. I don't know if all those unicode characters could affect the output. Could you try only with ASCII to see if it works echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' results in expected /file2017.txt

            – Paulo
            Jan 11 at 12:01











          • I run in a MacBook. No , still that. echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' , result is /Users/dengjiangzhou/Documents/198/file2017.txt. I should read your links, and try

            – black_pearl
            Jan 11 at 15:19








          • 1





            This does work? echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed -E 's@.*(/.+)@1@'. Try that with the unicode string too please, it should work. I ran in a FreeBSD VirtualBox vm and it worked, but it's language isn't properly configured.

            – Paulo
            Jan 11 at 17:58






          • 1





            It seems that backreference in MacOS belongs to ERE, it needs -E option.

            – Paulo
            Jan 12 at 13:25
















          1














          The first try doesn't work because the escape for + is missing



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@' 
          
/李宏毅-机器学习2017秋季.txt


          (escapes for metacharacters can be avoided with -r or -E option, for Extended RE).



          What you want is the dirname part, then just group the first part of the ER.



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@(.*)/.*@1@' 
          
/Users/dengjiangzhou/Documents/源码/198


          The quantifiers in sed are greedy, it means that when you ask to match a regex like .*/.*, the first .* will match all line until the end, because you asked to match anything. in any number*, and a / is anything in any number.



          edit- If you want to read about regular expressions and sed, take a look
          https://www.regular-expressions.info/tutorial.html
          http://www.grymoire.com/Unix/Sed.html#uh-0






          share|improve this answer


























          • The second regex is intuitive and nice. could you tell me why I try the first regex in my terminal echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' result is /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt. not you showed above

            – black_pearl
            Jan 11 at 3:27








          • 1





            @black_pearl This command line echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' you posted in the comment works, the output is /李宏毅-机器学习2017秋季.txt. Are you running this at MacOS (by the post title)? If yes, we are running different versions of sed, I'm on GNU/Linux. I don't know if all those unicode characters could affect the output. Could you try only with ASCII to see if it works echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' results in expected /file2017.txt

            – Paulo
            Jan 11 at 12:01











          • I run in a MacBook. No , still that. echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' , result is /Users/dengjiangzhou/Documents/198/file2017.txt. I should read your links, and try

            – black_pearl
            Jan 11 at 15:19








          • 1





            This does work? echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed -E 's@.*(/.+)@1@'. Try that with the unicode string too please, it should work. I ran in a FreeBSD VirtualBox vm and it worked, but it's language isn't properly configured.

            – Paulo
            Jan 11 at 17:58






          • 1





            It seems that backreference in MacOS belongs to ERE, it needs -E option.

            – Paulo
            Jan 12 at 13:25














          1












          1








          1







          The first try doesn't work because the escape for + is missing



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@' 
          
/李宏毅-机器学习2017秋季.txt


          (escapes for metacharacters can be avoided with -r or -E option, for Extended RE).



          What you want is the dirname part, then just group the first part of the ER.



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@(.*)/.*@1@' 
          
/Users/dengjiangzhou/Documents/源码/198


          The quantifiers in sed are greedy, it means that when you ask to match a regex like .*/.*, the first .* will match all line until the end, because you asked to match anything. in any number*, and a / is anything in any number.



          edit- If you want to read about regular expressions and sed, take a look
          https://www.regular-expressions.info/tutorial.html
          http://www.grymoire.com/Unix/Sed.html#uh-0






          share|improve this answer















          The first try doesn't work because the escape for + is missing



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@.*(/.+)@1@' 
          
/李宏毅-机器学习2017秋季.txt


          (escapes for metacharacters can be avoided with -r or -E option, for Extended RE).



          What you want is the dirname part, then just group the first part of the ER.



          echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt " | sed  's@(.*)/.*@1@' 
          
/Users/dengjiangzhou/Documents/源码/198


          The quantifiers in sed are greedy, it means that when you ask to match a regex like .*/.*, the first .* will match all line until the end, because you asked to match anything. in any number*, and a / is anything in any number.



          edit- If you want to read about regular expressions and sed, take a look
          https://www.regular-expressions.info/tutorial.html
          http://www.grymoire.com/Unix/Sed.html#uh-0







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 11 at 3:08

























          answered Jan 11 at 3:03









          PauloPaulo

          57628




          57628













          • The second regex is intuitive and nice. could you tell me why I try the first regex in my terminal echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' result is /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt. not you showed above

            – black_pearl
            Jan 11 at 3:27








          • 1





            @black_pearl This command line echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' you posted in the comment works, the output is /李宏毅-机器学习2017秋季.txt. Are you running this at MacOS (by the post title)? If yes, we are running different versions of sed, I'm on GNU/Linux. I don't know if all those unicode characters could affect the output. Could you try only with ASCII to see if it works echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' results in expected /file2017.txt

            – Paulo
            Jan 11 at 12:01











          • I run in a MacBook. No , still that. echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' , result is /Users/dengjiangzhou/Documents/198/file2017.txt. I should read your links, and try

            – black_pearl
            Jan 11 at 15:19








          • 1





            This does work? echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed -E 's@.*(/.+)@1@'. Try that with the unicode string too please, it should work. I ran in a FreeBSD VirtualBox vm and it worked, but it's language isn't properly configured.

            – Paulo
            Jan 11 at 17:58






          • 1





            It seems that backreference in MacOS belongs to ERE, it needs -E option.

            – Paulo
            Jan 12 at 13:25



















          • The second regex is intuitive and nice. could you tell me why I try the first regex in my terminal echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' result is /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt. not you showed above

            – black_pearl
            Jan 11 at 3:27








          • 1





            @black_pearl This command line echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' you posted in the comment works, the output is /李宏毅-机器学习2017秋季.txt. Are you running this at MacOS (by the post title)? If yes, we are running different versions of sed, I'm on GNU/Linux. I don't know if all those unicode characters could affect the output. Could you try only with ASCII to see if it works echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' results in expected /file2017.txt

            – Paulo
            Jan 11 at 12:01











          • I run in a MacBook. No , still that. echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' , result is /Users/dengjiangzhou/Documents/198/file2017.txt. I should read your links, and try

            – black_pearl
            Jan 11 at 15:19








          • 1





            This does work? echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed -E 's@.*(/.+)@1@'. Try that with the unicode string too please, it should work. I ran in a FreeBSD VirtualBox vm and it worked, but it's language isn't properly configured.

            – Paulo
            Jan 11 at 17:58






          • 1





            It seems that backreference in MacOS belongs to ERE, it needs -E option.

            – Paulo
            Jan 12 at 13:25

















          The second regex is intuitive and nice. could you tell me why I try the first regex in my terminal echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' result is /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt. not you showed above

          – black_pearl
          Jan 11 at 3:27







          The second regex is intuitive and nice. could you tell me why I try the first regex in my terminal echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' result is /Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt. not you showed above

          – black_pearl
          Jan 11 at 3:27






          1




          1





          @black_pearl This command line echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' you posted in the comment works, the output is /李宏毅-机器学习2017秋季.txt. Are you running this at MacOS (by the post title)? If yes, we are running different versions of sed, I'm on GNU/Linux. I don't know if all those unicode characters could affect the output. Could you try only with ASCII to see if it works echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' results in expected /file2017.txt

          – Paulo
          Jan 11 at 12:01





          @black_pearl This command line echo "/Users/dengjiangzhou/Documents/源码/198/李宏毅-机器学习2017秋季.txt" | sed 's@.*(/.+)@1@' you posted in the comment works, the output is /李宏毅-机器学习2017秋季.txt. Are you running this at MacOS (by the post title)? If yes, we are running different versions of sed, I'm on GNU/Linux. I don't know if all those unicode characters could affect the output. Could you try only with ASCII to see if it works echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' results in expected /file2017.txt

          – Paulo
          Jan 11 at 12:01













          I run in a MacBook. No , still that. echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' , result is /Users/dengjiangzhou/Documents/198/file2017.txt. I should read your links, and try

          – black_pearl
          Jan 11 at 15:19







          I run in a MacBook. No , still that. echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed 's@.*(/.+)@1@' , result is /Users/dengjiangzhou/Documents/198/file2017.txt. I should read your links, and try

          – black_pearl
          Jan 11 at 15:19






          1




          1





          This does work? echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed -E 's@.*(/.+)@1@'. Try that with the unicode string too please, it should work. I ran in a FreeBSD VirtualBox vm and it worked, but it's language isn't properly configured.

          – Paulo
          Jan 11 at 17:58





          This does work? echo "/Users/dengjiangzhou/Documents/198/file2017.txt" | sed -E 's@.*(/.+)@1@'. Try that with the unicode string too please, it should work. I ran in a FreeBSD VirtualBox vm and it worked, but it's language isn't properly configured.

          – Paulo
          Jan 11 at 17:58




          1




          1





          It seems that backreference in MacOS belongs to ERE, it needs -E option.

          – Paulo
          Jan 12 at 13:25





          It seems that backreference in MacOS belongs to ERE, it needs -E option.

          – Paulo
          Jan 12 at 13:25


















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