Red implementation of Rock, Scissors, Paper












0












$begingroup$


I have implemented the Rosetta Code Rock Paper Scissors game in Red, but I'm sure that there are better ways to do every thing that I did. I would appreciate any feedback on this code, which does work according to spec:




Implement the classic children's game Rock-Paper-Scissors, as well as
a simple predictive AI (artificial intelligence) player.



Rock Paper Scissors is a two player game.



Each player chooses one of rock, paper or scissors, without knowing
the other player's choice.



The winner is decided by a set of rules:




  • Rock beats scissors

  • Scissors beat paper

  • Paper beats rock


If both players choose the same thing, there is no winner for that
round.



For this task, the computer will be one of the players.



The operator will select Rock, Paper or Scissors and the computer will
keep a record of the choice frequency, and use that information to
make a weighted random choice in an attempt to defeat its opponent.




Red [
Problem: %http://www.rosettacode.org/wiki/Rock-paper-scissors
Code: %https://github.com/metaperl/red-rosetta/blob/master/rock-paper-scissors.red
]

help1: %https://stackoverflow.com/questions/54272942/how-to-find-the-first-element-of-a-block-of-strings-whose-first-character-matche
help2: %https://stackoverflow.com/questions/54272956/how-to-increment-element-of-block-after-found-element
help3: %https://stackoverflow.com/questions/54273057/two-dimensional-dispatch-table-with-templated-response
help4: %https://stackoverflow.com/questions/54273161/in-red-how-do-i-search-through-a-block-for-a-string-matching-a-pattern/54275072#54275072

games-played: 0

weapons: ["rock" "scissors" "paper"]
matching-weapon: func [abbrev][
foreach weapon weapons [
if (first weapon) = first abbrev [
return weapon
]
]
]
player-choices: ["rock" 0 "scissors" 0 "paper" 0 ]
player-choice-tally: func [choice][player-choices/(choice): player-choices/(choice) + 1]

player-choice: "x"
valid-choice: func [c][find "rpsq" c]

player-wins: [
["rock" "scissors"] "breaks"
["paper" "rock"] "covers"
["scissors" "paper"] "cut"
]

player-wins?: function [player1 player2] [
game: reduce [player1 player2]
winning: player-wins/(game)
]

report-win: func [player1 player2][rejoin [player1 " " (player-wins? player1 player2) " " player2]]


draw: func [player computer][player = computer]

update-stats: func [player-choice][
player-choice-tally player-choice
games-played: games-played + 1
]

make-computer-choice: func [
either games-played >= 3 [
tmp: random games-played
tally: select "rock" player-choices
either tmp <= tally [return "rock"][
tally: tally + select "scissors" player-choices
either tmp <= tally [return "scissors"][
return "paper"
]
]
][random/only weapons]
]

while [not player-choice = "q"][
player-choice: ask "(r)ock, (s)cissors, (p)aper or (q)uit? "
either (player-choice = "q") [
if (valid-choice player-choice) [
computer-choice: random/only weapons
player-choice: matching-weapon player-choice
update-stats player-choice
print rejoin ["Player choice: " player-choice "tally" player-choices "Computer choice:" computer-choice]
either draw player-choice computer-choice [print "Draw"][
tmp: player-wins? player-choice computer-choice
print either tmp [rejoin ["Player wins: " report-win player-choice computer-choice]]
[rejoin ["Computer wins: " report-win computer-choice player-choice]]
]
]
]

]









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    $begingroup$


    I have implemented the Rosetta Code Rock Paper Scissors game in Red, but I'm sure that there are better ways to do every thing that I did. I would appreciate any feedback on this code, which does work according to spec:




    Implement the classic children's game Rock-Paper-Scissors, as well as
    a simple predictive AI (artificial intelligence) player.



    Rock Paper Scissors is a two player game.



    Each player chooses one of rock, paper or scissors, without knowing
    the other player's choice.



    The winner is decided by a set of rules:




    • Rock beats scissors

    • Scissors beat paper

    • Paper beats rock


    If both players choose the same thing, there is no winner for that
    round.



    For this task, the computer will be one of the players.



    The operator will select Rock, Paper or Scissors and the computer will
    keep a record of the choice frequency, and use that information to
    make a weighted random choice in an attempt to defeat its opponent.




    Red [
    Problem: %http://www.rosettacode.org/wiki/Rock-paper-scissors
    Code: %https://github.com/metaperl/red-rosetta/blob/master/rock-paper-scissors.red
    ]

    help1: %https://stackoverflow.com/questions/54272942/how-to-find-the-first-element-of-a-block-of-strings-whose-first-character-matche
    help2: %https://stackoverflow.com/questions/54272956/how-to-increment-element-of-block-after-found-element
    help3: %https://stackoverflow.com/questions/54273057/two-dimensional-dispatch-table-with-templated-response
    help4: %https://stackoverflow.com/questions/54273161/in-red-how-do-i-search-through-a-block-for-a-string-matching-a-pattern/54275072#54275072

    games-played: 0

    weapons: ["rock" "scissors" "paper"]
    matching-weapon: func [abbrev][
    foreach weapon weapons [
    if (first weapon) = first abbrev [
    return weapon
    ]
    ]
    ]
    player-choices: ["rock" 0 "scissors" 0 "paper" 0 ]
    player-choice-tally: func [choice][player-choices/(choice): player-choices/(choice) + 1]

    player-choice: "x"
    valid-choice: func [c][find "rpsq" c]

    player-wins: [
    ["rock" "scissors"] "breaks"
    ["paper" "rock"] "covers"
    ["scissors" "paper"] "cut"
    ]

    player-wins?: function [player1 player2] [
    game: reduce [player1 player2]
    winning: player-wins/(game)
    ]

    report-win: func [player1 player2][rejoin [player1 " " (player-wins? player1 player2) " " player2]]


    draw: func [player computer][player = computer]

    update-stats: func [player-choice][
    player-choice-tally player-choice
    games-played: games-played + 1
    ]

    make-computer-choice: func [
    either games-played >= 3 [
    tmp: random games-played
    tally: select "rock" player-choices
    either tmp <= tally [return "rock"][
    tally: tally + select "scissors" player-choices
    either tmp <= tally [return "scissors"][
    return "paper"
    ]
    ]
    ][random/only weapons]
    ]

    while [not player-choice = "q"][
    player-choice: ask "(r)ock, (s)cissors, (p)aper or (q)uit? "
    either (player-choice = "q") [
    if (valid-choice player-choice) [
    computer-choice: random/only weapons
    player-choice: matching-weapon player-choice
    update-stats player-choice
    print rejoin ["Player choice: " player-choice "tally" player-choices "Computer choice:" computer-choice]
    either draw player-choice computer-choice [print "Draw"][
    tmp: player-wins? player-choice computer-choice
    print either tmp [rejoin ["Player wins: " report-win player-choice computer-choice]]
    [rejoin ["Computer wins: " report-win computer-choice player-choice]]
    ]
    ]
    ]

    ]









    share|improve this question









    New contributor




    Terrence Brannon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      0












      0








      0





      $begingroup$


      I have implemented the Rosetta Code Rock Paper Scissors game in Red, but I'm sure that there are better ways to do every thing that I did. I would appreciate any feedback on this code, which does work according to spec:




      Implement the classic children's game Rock-Paper-Scissors, as well as
      a simple predictive AI (artificial intelligence) player.



      Rock Paper Scissors is a two player game.



      Each player chooses one of rock, paper or scissors, without knowing
      the other player's choice.



      The winner is decided by a set of rules:




      • Rock beats scissors

      • Scissors beat paper

      • Paper beats rock


      If both players choose the same thing, there is no winner for that
      round.



      For this task, the computer will be one of the players.



      The operator will select Rock, Paper or Scissors and the computer will
      keep a record of the choice frequency, and use that information to
      make a weighted random choice in an attempt to defeat its opponent.




      Red [
      Problem: %http://www.rosettacode.org/wiki/Rock-paper-scissors
      Code: %https://github.com/metaperl/red-rosetta/blob/master/rock-paper-scissors.red
      ]

      help1: %https://stackoverflow.com/questions/54272942/how-to-find-the-first-element-of-a-block-of-strings-whose-first-character-matche
      help2: %https://stackoverflow.com/questions/54272956/how-to-increment-element-of-block-after-found-element
      help3: %https://stackoverflow.com/questions/54273057/two-dimensional-dispatch-table-with-templated-response
      help4: %https://stackoverflow.com/questions/54273161/in-red-how-do-i-search-through-a-block-for-a-string-matching-a-pattern/54275072#54275072

      games-played: 0

      weapons: ["rock" "scissors" "paper"]
      matching-weapon: func [abbrev][
      foreach weapon weapons [
      if (first weapon) = first abbrev [
      return weapon
      ]
      ]
      ]
      player-choices: ["rock" 0 "scissors" 0 "paper" 0 ]
      player-choice-tally: func [choice][player-choices/(choice): player-choices/(choice) + 1]

      player-choice: "x"
      valid-choice: func [c][find "rpsq" c]

      player-wins: [
      ["rock" "scissors"] "breaks"
      ["paper" "rock"] "covers"
      ["scissors" "paper"] "cut"
      ]

      player-wins?: function [player1 player2] [
      game: reduce [player1 player2]
      winning: player-wins/(game)
      ]

      report-win: func [player1 player2][rejoin [player1 " " (player-wins? player1 player2) " " player2]]


      draw: func [player computer][player = computer]

      update-stats: func [player-choice][
      player-choice-tally player-choice
      games-played: games-played + 1
      ]

      make-computer-choice: func [
      either games-played >= 3 [
      tmp: random games-played
      tally: select "rock" player-choices
      either tmp <= tally [return "rock"][
      tally: tally + select "scissors" player-choices
      either tmp <= tally [return "scissors"][
      return "paper"
      ]
      ]
      ][random/only weapons]
      ]

      while [not player-choice = "q"][
      player-choice: ask "(r)ock, (s)cissors, (p)aper or (q)uit? "
      either (player-choice = "q") [
      if (valid-choice player-choice) [
      computer-choice: random/only weapons
      player-choice: matching-weapon player-choice
      update-stats player-choice
      print rejoin ["Player choice: " player-choice "tally" player-choices "Computer choice:" computer-choice]
      either draw player-choice computer-choice [print "Draw"][
      tmp: player-wins? player-choice computer-choice
      print either tmp [rejoin ["Player wins: " report-win player-choice computer-choice]]
      [rejoin ["Computer wins: " report-win computer-choice player-choice]]
      ]
      ]
      ]

      ]









      share|improve this question









      New contributor




      Terrence Brannon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I have implemented the Rosetta Code Rock Paper Scissors game in Red, but I'm sure that there are better ways to do every thing that I did. I would appreciate any feedback on this code, which does work according to spec:




      Implement the classic children's game Rock-Paper-Scissors, as well as
      a simple predictive AI (artificial intelligence) player.



      Rock Paper Scissors is a two player game.



      Each player chooses one of rock, paper or scissors, without knowing
      the other player's choice.



      The winner is decided by a set of rules:




      • Rock beats scissors

      • Scissors beat paper

      • Paper beats rock


      If both players choose the same thing, there is no winner for that
      round.



      For this task, the computer will be one of the players.



      The operator will select Rock, Paper or Scissors and the computer will
      keep a record of the choice frequency, and use that information to
      make a weighted random choice in an attempt to defeat its opponent.




      Red [
      Problem: %http://www.rosettacode.org/wiki/Rock-paper-scissors
      Code: %https://github.com/metaperl/red-rosetta/blob/master/rock-paper-scissors.red
      ]

      help1: %https://stackoverflow.com/questions/54272942/how-to-find-the-first-element-of-a-block-of-strings-whose-first-character-matche
      help2: %https://stackoverflow.com/questions/54272956/how-to-increment-element-of-block-after-found-element
      help3: %https://stackoverflow.com/questions/54273057/two-dimensional-dispatch-table-with-templated-response
      help4: %https://stackoverflow.com/questions/54273161/in-red-how-do-i-search-through-a-block-for-a-string-matching-a-pattern/54275072#54275072

      games-played: 0

      weapons: ["rock" "scissors" "paper"]
      matching-weapon: func [abbrev][
      foreach weapon weapons [
      if (first weapon) = first abbrev [
      return weapon
      ]
      ]
      ]
      player-choices: ["rock" 0 "scissors" 0 "paper" 0 ]
      player-choice-tally: func [choice][player-choices/(choice): player-choices/(choice) + 1]

      player-choice: "x"
      valid-choice: func [c][find "rpsq" c]

      player-wins: [
      ["rock" "scissors"] "breaks"
      ["paper" "rock"] "covers"
      ["scissors" "paper"] "cut"
      ]

      player-wins?: function [player1 player2] [
      game: reduce [player1 player2]
      winning: player-wins/(game)
      ]

      report-win: func [player1 player2][rejoin [player1 " " (player-wins? player1 player2) " " player2]]


      draw: func [player computer][player = computer]

      update-stats: func [player-choice][
      player-choice-tally player-choice
      games-played: games-played + 1
      ]

      make-computer-choice: func [
      either games-played >= 3 [
      tmp: random games-played
      tally: select "rock" player-choices
      either tmp <= tally [return "rock"][
      tally: tally + select "scissors" player-choices
      either tmp <= tally [return "scissors"][
      return "paper"
      ]
      ]
      ][random/only weapons]
      ]

      while [not player-choice = "q"][
      player-choice: ask "(r)ock, (s)cissors, (p)aper or (q)uit? "
      either (player-choice = "q") [
      if (valid-choice player-choice) [
      computer-choice: random/only weapons
      player-choice: matching-weapon player-choice
      update-stats player-choice
      print rejoin ["Player choice: " player-choice "tally" player-choices "Computer choice:" computer-choice]
      either draw player-choice computer-choice [print "Draw"][
      tmp: player-wins? player-choice computer-choice
      print either tmp [rejoin ["Player wins: " report-win player-choice computer-choice]]
      [rejoin ["Computer wins: " report-win computer-choice player-choice]]
      ]
      ]
      ]

      ]






      rock-paper-scissors rebol2






      share|improve this question









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      Terrence Brannon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Terrence Brannon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 1 hour ago









      Jamal

      30.3k11116226




      30.3k11116226






      New contributor




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      asked 5 hours ago









      Terrence BrannonTerrence Brannon

      1011




      1011




      New contributor




      Terrence Brannon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      New contributor





      Terrence Brannon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Terrence Brannon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















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