Operator Search for Puzzle
$begingroup$
I was wondering if I could solve the problem here (mostly unrelated) using only simple binary operators since it is just mapping 100 different inputs to a boolean. For this I wrote this, but I have no real way to test, and I was also hoping it could be faster.
#include <iostream>
#define MIN(a,b) ((a) < (b) ? (a) : (b))
#define MAX_VAL 100
bool CODES = {1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1};
int op(int a, int b, int index) {
switch (index) {
case 0: return a + b; break;
case 1: return a - b; break;
case 2: return a * b; break;
case 3: return a / b; break;
case 4: return a & b; break;
case 5: return a | b; break;
case 6: return a ^ b; break;
case 7: return a % b; break;
}
}
int main(int argc, char const *argv) {
for (int A=1; A < 2; A++) {
std::cout << A << std::endl;
for (int B=1; B < 2; B++) {
std::cout << A << " " << B << std::endl;
for (int C=1; C < 2; C++) {
for (int D=1; D < MAX_VAL; D++) {
std::cout << A << " " << B << " " << C << " " << D << std::endl;
for (int E=1; E < MAX_VAL; E++) {
for (int opA = 0; opA < 8; opA++) {
for (int opB = 0; opB < 8; opB++) {
for (int opC = 0; opC < 8; opC++) {
for (int opD = 0; opD < 8; opD++) {
for (int opE = 0; opE < 8; opE++) {
bool good = true;
int index = 1;
for (bool item : CODES) {
int val = op(index, A, opA);
val = op(val, B, opB);
val = op(val, C, opC);
val = op(val, D, opD);
val = op(val, E, opE);
val &= 1;
if (val != item) {
good = false;
break;
}
index++;
}
if (good) {
std::cout<<"GOOD "<<A<<" "<<opA<<" "<<B<<" "<<opB<<" "<<C<<" "<<opC<<" "<<D<<" "<<opD<<" "<<E<<" "<<opE<<std::endl;
}
}
}
}
}
}
}
}
}
}
}
return 0;
}
I am specifically looking for help for optimization, but of course style, correctness, or anything else is much appreciated.
c++ performance
$endgroup$
add a comment |
$begingroup$
I was wondering if I could solve the problem here (mostly unrelated) using only simple binary operators since it is just mapping 100 different inputs to a boolean. For this I wrote this, but I have no real way to test, and I was also hoping it could be faster.
#include <iostream>
#define MIN(a,b) ((a) < (b) ? (a) : (b))
#define MAX_VAL 100
bool CODES = {1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1};
int op(int a, int b, int index) {
switch (index) {
case 0: return a + b; break;
case 1: return a - b; break;
case 2: return a * b; break;
case 3: return a / b; break;
case 4: return a & b; break;
case 5: return a | b; break;
case 6: return a ^ b; break;
case 7: return a % b; break;
}
}
int main(int argc, char const *argv) {
for (int A=1; A < 2; A++) {
std::cout << A << std::endl;
for (int B=1; B < 2; B++) {
std::cout << A << " " << B << std::endl;
for (int C=1; C < 2; C++) {
for (int D=1; D < MAX_VAL; D++) {
std::cout << A << " " << B << " " << C << " " << D << std::endl;
for (int E=1; E < MAX_VAL; E++) {
for (int opA = 0; opA < 8; opA++) {
for (int opB = 0; opB < 8; opB++) {
for (int opC = 0; opC < 8; opC++) {
for (int opD = 0; opD < 8; opD++) {
for (int opE = 0; opE < 8; opE++) {
bool good = true;
int index = 1;
for (bool item : CODES) {
int val = op(index, A, opA);
val = op(val, B, opB);
val = op(val, C, opC);
val = op(val, D, opD);
val = op(val, E, opE);
val &= 1;
if (val != item) {
good = false;
break;
}
index++;
}
if (good) {
std::cout<<"GOOD "<<A<<" "<<opA<<" "<<B<<" "<<opB<<" "<<C<<" "<<opC<<" "<<D<<" "<<opD<<" "<<E<<" "<<opE<<std::endl;
}
}
}
}
}
}
}
}
}
}
}
return 0;
}
I am specifically looking for help for optimization, but of course style, correctness, or anything else is much appreciated.
c++ performance
$endgroup$
add a comment |
$begingroup$
I was wondering if I could solve the problem here (mostly unrelated) using only simple binary operators since it is just mapping 100 different inputs to a boolean. For this I wrote this, but I have no real way to test, and I was also hoping it could be faster.
#include <iostream>
#define MIN(a,b) ((a) < (b) ? (a) : (b))
#define MAX_VAL 100
bool CODES = {1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1};
int op(int a, int b, int index) {
switch (index) {
case 0: return a + b; break;
case 1: return a - b; break;
case 2: return a * b; break;
case 3: return a / b; break;
case 4: return a & b; break;
case 5: return a | b; break;
case 6: return a ^ b; break;
case 7: return a % b; break;
}
}
int main(int argc, char const *argv) {
for (int A=1; A < 2; A++) {
std::cout << A << std::endl;
for (int B=1; B < 2; B++) {
std::cout << A << " " << B << std::endl;
for (int C=1; C < 2; C++) {
for (int D=1; D < MAX_VAL; D++) {
std::cout << A << " " << B << " " << C << " " << D << std::endl;
for (int E=1; E < MAX_VAL; E++) {
for (int opA = 0; opA < 8; opA++) {
for (int opB = 0; opB < 8; opB++) {
for (int opC = 0; opC < 8; opC++) {
for (int opD = 0; opD < 8; opD++) {
for (int opE = 0; opE < 8; opE++) {
bool good = true;
int index = 1;
for (bool item : CODES) {
int val = op(index, A, opA);
val = op(val, B, opB);
val = op(val, C, opC);
val = op(val, D, opD);
val = op(val, E, opE);
val &= 1;
if (val != item) {
good = false;
break;
}
index++;
}
if (good) {
std::cout<<"GOOD "<<A<<" "<<opA<<" "<<B<<" "<<opB<<" "<<C<<" "<<opC<<" "<<D<<" "<<opD<<" "<<E<<" "<<opE<<std::endl;
}
}
}
}
}
}
}
}
}
}
}
return 0;
}
I am specifically looking for help for optimization, but of course style, correctness, or anything else is much appreciated.
c++ performance
$endgroup$
I was wondering if I could solve the problem here (mostly unrelated) using only simple binary operators since it is just mapping 100 different inputs to a boolean. For this I wrote this, but I have no real way to test, and I was also hoping it could be faster.
#include <iostream>
#define MIN(a,b) ((a) < (b) ? (a) : (b))
#define MAX_VAL 100
bool CODES = {1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1};
int op(int a, int b, int index) {
switch (index) {
case 0: return a + b; break;
case 1: return a - b; break;
case 2: return a * b; break;
case 3: return a / b; break;
case 4: return a & b; break;
case 5: return a | b; break;
case 6: return a ^ b; break;
case 7: return a % b; break;
}
}
int main(int argc, char const *argv) {
for (int A=1; A < 2; A++) {
std::cout << A << std::endl;
for (int B=1; B < 2; B++) {
std::cout << A << " " << B << std::endl;
for (int C=1; C < 2; C++) {
for (int D=1; D < MAX_VAL; D++) {
std::cout << A << " " << B << " " << C << " " << D << std::endl;
for (int E=1; E < MAX_VAL; E++) {
for (int opA = 0; opA < 8; opA++) {
for (int opB = 0; opB < 8; opB++) {
for (int opC = 0; opC < 8; opC++) {
for (int opD = 0; opD < 8; opD++) {
for (int opE = 0; opE < 8; opE++) {
bool good = true;
int index = 1;
for (bool item : CODES) {
int val = op(index, A, opA);
val = op(val, B, opB);
val = op(val, C, opC);
val = op(val, D, opD);
val = op(val, E, opE);
val &= 1;
if (val != item) {
good = false;
break;
}
index++;
}
if (good) {
std::cout<<"GOOD "<<A<<" "<<opA<<" "<<B<<" "<<opB<<" "<<C<<" "<<opC<<" "<<D<<" "<<opD<<" "<<E<<" "<<opE<<std::endl;
}
}
}
}
}
}
}
}
}
}
}
return 0;
}
I am specifically looking for help for optimization, but of course style, correctness, or anything else is much appreciated.
c++ performance
c++ performance
asked 3 hours ago
nedla2004nedla2004
1244
1244
add a comment |
add a comment |
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