How much time does it take for a broken magnet to recover its poles?
$begingroup$
I understand that when you cut a magnet you end up with 2 magnets but I wonder how much time does it take to the magnetic domains to rearange and form the new pole. I know the answer may vary depending on the size of the magnet, the material, and some other variable so I'm searching for an answer as general as possible and how the variables may affect the answer.
electromagnetism
asked 4 hours ago
Diego Rodríguez CidDiego Rodríguez Cid
214
$endgroup$
add a comment |
$begingroup$
I understand that when you cut a magnet you end up with 2 magnets but I wonder how much time does it take to the magnetic domains to rearange and form the new pole. I know the answer may vary depending on the size of the magnet, the material, and some other variable so I'm searching for an answer as general as possible and how the variables may affect the answer.
electromagnetism
asked 4 hours ago
Diego Rodríguez CidDiego Rodríguez Cid
214
$endgroup$
add a comment |
$begingroup$
I understand that when you cut a magnet you end up with 2 magnets but I wonder how much time does it take to the magnetic domains to rearange and form the new pole. I know the answer may vary depending on the size of the magnet, the material, and some other variable so I'm searching for an answer as general as possible and how the variables may affect the answer.
electromagnetism
asked 4 hours ago
Diego Rodríguez CidDiego Rodríguez Cid
214
$endgroup$
I understand that when you cut a magnet you end up with 2 magnets but I wonder how much time does it take to the magnetic domains to rearange and form the new pole. I know the answer may vary depending on the size of the magnet, the material, and some other variable so I'm searching for an answer as general as possible and how the variables may affect the answer.
electromagnetism
electromagnetism
asked 4 hours ago
Diego Rodríguez CidDiego Rodríguez Cid
214
asked 4 hours ago
Diego Rodríguez CidDiego Rodríguez Cid
214
asked 4 hours ago
Diego Rodríguez CidDiego Rodríguez Cid
214
asked 4 hours ago
Diego Rodríguez CidDiego Rodríguez Cid
214
asked 4 hours ago
Diego Rodríguez CidDiego Rodríguez Cid
214
214
add a comment |
add a comment |
2 Answers
2
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$begingroup$
It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.
The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,
$$nablacdotmathbf{B}=0.$$
The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.
answered 4 hours ago
G. SmithG. Smith
8,59111426
$endgroup$
$begingroup$
Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
$endgroup$
– dmckee♦
3 hours ago
add a comment |
$begingroup$
I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.
answered 3 hours ago
TechDroidTechDroid
1317
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add a comment |
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2 Answers
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2 Answers
2
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.
The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,
$$nablacdotmathbf{B}=0.$$
The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.
answered 4 hours ago
G. SmithG. Smith
8,59111426
$endgroup$
$begingroup$
Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
$endgroup$
– dmckee♦
3 hours ago
add a comment |
$begingroup$
It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.
The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,
$$nablacdotmathbf{B}=0.$$
The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.
answered 4 hours ago
G. SmithG. Smith
8,59111426
$endgroup$
$begingroup$
Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
$endgroup$
– dmckee♦
3 hours ago
add a comment |
$begingroup$
It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.
The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,
$$nablacdotmathbf{B}=0.$$
The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.
answered 4 hours ago
G. SmithG. Smith
8,59111426
$endgroup$
It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.
The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,
$$nablacdotmathbf{B}=0.$$
The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.
answered 4 hours ago
G. SmithG. Smith
8,59111426
edited 3 hours ago
answered 4 hours ago
G. SmithG. Smith
8,59111426
answered 4 hours ago
G. SmithG. Smith
8,59111426
answered 4 hours ago
G. SmithG. Smith
8,59111426
8,59111426
$begingroup$
Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
$endgroup$
– dmckee♦
3 hours ago
add a comment |
$begingroup$
Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
$endgroup$
– dmckee♦
3 hours ago
$begingroup$
Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
$endgroup$
– dmckee♦
3 hours ago
$begingroup$
Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
$endgroup$
– dmckee♦
3 hours ago
add a comment |
$begingroup$
I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.
answered 3 hours ago
TechDroidTechDroid
1317
$endgroup$
add a comment |
$begingroup$
I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.
answered 3 hours ago
TechDroidTechDroid
1317
$endgroup$
add a comment |
$begingroup$
I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.
answered 3 hours ago
TechDroidTechDroid
1317
$endgroup$
I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.
answered 3 hours ago
TechDroidTechDroid
1317
answered 3 hours ago
TechDroidTechDroid
1317
answered 3 hours ago
TechDroidTechDroid
1317
answered 3 hours ago
TechDroidTechDroid
1317
1317
add a comment |
add a comment |
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