digits in string












0















I am validating string with some standards. It should start wih R- and proj_nm as a variable and project_cd as numbers and any desc
i.e, R-${PROJ_NM}-[Numbers]-anything



if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]]"-"* ]] ; then echo "Naming convention is in correct format" else echo "Not in correct format" exit 1 fi


I am getting output as not in correct format.






bash shell-script







share|improve this question




















  • 4





    Please edit your question and show us a few examples of input, what you want to get from that input and what you actually get from that input.

    – terdon♦
    Feb 8 at 12:02
















0















I am validating string with some standards. It should start wih R- and proj_nm as a variable and project_cd as numbers and any desc
i.e, R-${PROJ_NM}-[Numbers]-anything



if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]]"-"* ]] ; then echo "Naming convention is in correct format" else echo "Not in correct format" exit 1 fi


I am getting output as not in correct format.






bash shell-script







share|improve this question




















  • 4





    Please edit your question and show us a few examples of input, what you want to get from that input and what you actually get from that input.

    – terdon♦
    Feb 8 at 12:02














0












0








0








I am validating string with some standards. It should start wih R- and proj_nm as a variable and project_cd as numbers and any desc
i.e, R-${PROJ_NM}-[Numbers]-anything



if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]]"-"* ]] ; then echo "Naming convention is in correct format" else echo "Not in correct format" exit 1 fi


I am getting output as not in correct format.






bash shell-script







share|improve this question
















I am validating string with some standards. It should start wih R- and proj_nm as a variable and project_cd as numbers and any desc
i.e, R-${PROJ_NM}-[Numbers]-anything



if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]]"-"* ]] ; then echo "Naming convention is in correct format" else echo "Not in correct format" exit 1 fi


I am getting output as not in correct format.






bash shell-script




bash shell-script






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Feb 8 at 13:21









Rui F Ribeiro

40.4k1479137




40.4k1479137










asked Feb 8 at 11:54









user_297020user_297020

197




197








  • 4





    Please edit your question and show us a few examples of input, what you want to get from that input and what you actually get from that input.

    – terdon♦
    Feb 8 at 12:02














  • 4





    Please edit your question and show us a few examples of input, what you want to get from that input and what you actually get from that input.

    – terdon♦
    Feb 8 at 12:02








4




4





Please edit your question and show us a few examples of input, what you want to get from that input and what you actually get from that input.

– terdon♦
Feb 8 at 12:02





Please edit your question and show us a few examples of input, what you want to get from that input and what you actually get from that input.

– terdon♦
Feb 8 at 12:02










1 Answer
1






active

oldest

votes


















4














If you need to have one or more numbers (you said numbers), then you need [[:digit:]][[:digit:]] for two, [[:digit:]][[:digit:]][[:digit:]] for three etc.



if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]][[:digit:]]"-"* ]] ; then 

    echo "Naming convention is in correct format"

else 

    echo "Not in correct format" 

fi


But you can simplify your quotes a little:



if [[ $var == "R-${PROJ_NM}-"[[:digit:]][[:digit:]]"-"* ]] ; then 

    echo "Naming convention is in correct format"

else 

    echo "Not in correct format" 

fi


Alternatively, with newer bash versions, you can use regular expressions:



if [[ $var =~ ^R-${PROJ_NM}-[0-9]+- ]] ; then 

    echo "Naming convention is in correct format"

else 

    echo "Not in correct format" 

fi





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    1 Answer
    1






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    active

    oldest

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    4














    If you need to have one or more numbers (you said numbers), then you need [[:digit:]][[:digit:]] for two, [[:digit:]][[:digit:]][[:digit:]] for three etc.



    if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]][[:digit:]]"-"* ]] ; then 
    
    echo "Naming convention is in correct format"
    
else 
    
    echo "Not in correct format" 
    
fi


    But you can simplify your quotes a little:



    if [[ $var == "R-${PROJ_NM}-"[[:digit:]][[:digit:]]"-"* ]] ; then 
    
    echo "Naming convention is in correct format"
    
else 
    
    echo "Not in correct format" 
    
fi


    Alternatively, with newer bash versions, you can use regular expressions:



    if [[ $var =~ ^R-${PROJ_NM}-[0-9]+- ]] ; then 
    
    echo "Naming convention is in correct format"
    
else 
    
    echo "Not in correct format" 
    
fi





    share|improve this answer






























      4














      If you need to have one or more numbers (you said numbers), then you need [[:digit:]][[:digit:]] for two, [[:digit:]][[:digit:]][[:digit:]] for three etc.



      if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]][[:digit:]]"-"* ]] ; then 
      
    echo "Naming convention is in correct format"
      
else 
      
    echo "Not in correct format" 
      
fi


      But you can simplify your quotes a little:



      if [[ $var == "R-${PROJ_NM}-"[[:digit:]][[:digit:]]"-"* ]] ; then 
      
    echo "Naming convention is in correct format"
      
else 
      
    echo "Not in correct format" 
      
fi


      Alternatively, with newer bash versions, you can use regular expressions:



      if [[ $var =~ ^R-${PROJ_NM}-[0-9]+- ]] ; then 
      
    echo "Naming convention is in correct format"
      
else 
      
    echo "Not in correct format" 
      
fi





      share|improve this answer




























        4












        4








        4







        If you need to have one or more numbers (you said numbers), then you need [[:digit:]][[:digit:]] for two, [[:digit:]][[:digit:]][[:digit:]] for three etc.



        if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]][[:digit:]]"-"* ]] ; then 
        
    echo "Naming convention is in correct format"
        
else 
        
    echo "Not in correct format" 
        
fi


        But you can simplify your quotes a little:



        if [[ $var == "R-${PROJ_NM}-"[[:digit:]][[:digit:]]"-"* ]] ; then 
        
    echo "Naming convention is in correct format"
        
else 
        
    echo "Not in correct format" 
        
fi


        Alternatively, with newer bash versions, you can use regular expressions:



        if [[ $var =~ ^R-${PROJ_NM}-[0-9]+- ]] ; then 
        
    echo "Naming convention is in correct format"
        
else 
        
    echo "Not in correct format" 
        
fi





        share|improve this answer















        If you need to have one or more numbers (you said numbers), then you need [[:digit:]][[:digit:]] for two, [[:digit:]][[:digit:]][[:digit:]] for three etc.



        if [[ $var == "R-"${PROJ_NM}"-"[[:digit:]][[:digit:]]"-"* ]] ; then 
        
    echo "Naming convention is in correct format"
        
else 
        
    echo "Not in correct format" 
        
fi


        But you can simplify your quotes a little:



        if [[ $var == "R-${PROJ_NM}-"[[:digit:]][[:digit:]]"-"* ]] ; then 
        
    echo "Naming convention is in correct format"
        
else 
        
    echo "Not in correct format" 
        
fi


        Alternatively, with newer bash versions, you can use regular expressions:



        if [[ $var =~ ^R-${PROJ_NM}-[0-9]+- ]] ; then 
        
    echo "Naming convention is in correct format"
        
else 
        
    echo "Not in correct format" 
        
fi






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Feb 8 at 12:32

























        answered Feb 8 at 12:12









        terdon♦terdon

        131k32257436




        131k32257436






























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