Does `resize2fs` by default do nothing?
For resize2fs,
If ``size parameter is not specified, it will default to the
size of the partition
The size of a filesystem is by default the size of its underlying partition.
So by default, resize2fs doesn't change the size of a filesystem. Does it do nothing?
Thanks.
filesystems resize2fs
asked Feb 21 at 17:29
TimTim
27.6k78264480
add a comment |
For resize2fs,
If ``size parameter is not specified, it will default to the
size of the partition
The size of a filesystem is by default the size of its underlying partition.
So by default, resize2fs doesn't change the size of a filesystem. Does it do nothing?
Thanks.
filesystems resize2fs
asked Feb 21 at 17:29
TimTim
27.6k78264480
add a comment |
For resize2fs,
If ``size parameter is not specified, it will default to the
size of the partition
The size of a filesystem is by default the size of its underlying partition.
So by default, resize2fs doesn't change the size of a filesystem. Does it do nothing?
Thanks.
filesystems resize2fs
asked Feb 21 at 17:29
TimTim
27.6k78264480
For resize2fs,
If ``size parameter is not specified, it will default to the
size of the partition
The size of a filesystem is by default the size of its underlying partition.
So by default, resize2fs doesn't change the size of a filesystem. Does it do nothing?
Thanks.
filesystems resize2fs
filesystems resize2fs
asked Feb 21 at 17:29
TimTim
27.6k78264480
asked Feb 21 at 17:29
TimTim
27.6k78264480
asked Feb 21 at 17:29
TimTim
27.6k78264480
asked Feb 21 at 17:29
TimTim
27.6k78264480
asked Feb 21 at 17:29
TimTim
27.6k78264480
27.6k78264480
add a comment |
add a comment |
3 Answers
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If the underlying partition is larger than the filesystem within it, resize2fs will, by default, attempt to expand the filesystem to fill the partition.
For example, if /dev/sdd3 is a 1TB partition, and we were to run:
# mke2fs /dev/sdd3 500G
We will have a 500GB partition within a 1TB partition. If we then resize2fs /dev/sdd3, it will be expanded to the full 1TB.
answered Feb 21 at 17:41
DopeGhotiDopeGhoti
46.1k56089
add a comment |
The size of a filesystem is by default the size of its underlying partition.
Usually, yes. There's little point in creating a filesystem smaller than the available space on the partition.
But if you're trying to enlarge the filesystem, you'll first have to enlarge the device it's on. For the usual fixed partitions, that's not often possible (you'd need to have available space after the partition itself), but with something like LVM it's trivial, since you can just resize the logical volume at will.
After resizing the partition/volume, the filesystem only makes use of the originally available space, and at that point resize2fs is necessary. Again, you'll usually want to resize the partition to the fill all the now available space, so the default action is what you want.
answered Feb 21 at 18:07
ilkkachuilkkachu
60.9k1098174
add a comment |
I also often (ab)use resize2fs in some smallish/skeletal VMs for not to have to setup LVM.
For extending a drive/partition, I can provisioning/extend a virtual physical hard disk, and then delete and create a new bigger partition. Once I do that, I can extend the partition to the new "physical" space. (for instance, in vmware, I just edit an existing virtual disk, and edit it to be 10GB instead of 5GB...)
Or even in a physical disk, you can delete a second partition, delete the 1st one and recreate it using the former space of the two partitions, and then use resizefs for having a single partition where once you had two partitions.
So, resize2fs does something even without using LVM.
answered Feb 21 at 19:58
Rui F RibeiroRui F Ribeiro
41.4k1481140
add a comment |
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3 Answers
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active
oldest
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3 Answers
3
active
oldest
votes
active
oldest
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oldest
votes
If the underlying partition is larger than the filesystem within it, resize2fs will, by default, attempt to expand the filesystem to fill the partition.
For example, if /dev/sdd3 is a 1TB partition, and we were to run:
# mke2fs /dev/sdd3 500G
We will have a 500GB partition within a 1TB partition. If we then resize2fs /dev/sdd3, it will be expanded to the full 1TB.
answered Feb 21 at 17:41
DopeGhotiDopeGhoti
46.1k56089
add a comment |
If the underlying partition is larger than the filesystem within it, resize2fs will, by default, attempt to expand the filesystem to fill the partition.
For example, if /dev/sdd3 is a 1TB partition, and we were to run:
# mke2fs /dev/sdd3 500G
We will have a 500GB partition within a 1TB partition. If we then resize2fs /dev/sdd3, it will be expanded to the full 1TB.
answered Feb 21 at 17:41
DopeGhotiDopeGhoti
46.1k56089
add a comment |
If the underlying partition is larger than the filesystem within it, resize2fs will, by default, attempt to expand the filesystem to fill the partition.
For example, if /dev/sdd3 is a 1TB partition, and we were to run:
# mke2fs /dev/sdd3 500G
We will have a 500GB partition within a 1TB partition. If we then resize2fs /dev/sdd3, it will be expanded to the full 1TB.
answered Feb 21 at 17:41
DopeGhotiDopeGhoti
46.1k56089
If the underlying partition is larger than the filesystem within it, resize2fs will, by default, attempt to expand the filesystem to fill the partition.
For example, if /dev/sdd3 is a 1TB partition, and we were to run:
# mke2fs /dev/sdd3 500G
We will have a 500GB partition within a 1TB partition. If we then resize2fs /dev/sdd3, it will be expanded to the full 1TB.
answered Feb 21 at 17:41
DopeGhotiDopeGhoti
46.1k56089
answered Feb 21 at 17:41
DopeGhotiDopeGhoti
46.1k56089
answered Feb 21 at 17:41
DopeGhotiDopeGhoti
46.1k56089
answered Feb 21 at 17:41
DopeGhotiDopeGhoti
46.1k56089
46.1k56089
add a comment |
add a comment |
The size of a filesystem is by default the size of its underlying partition.
Usually, yes. There's little point in creating a filesystem smaller than the available space on the partition.
But if you're trying to enlarge the filesystem, you'll first have to enlarge the device it's on. For the usual fixed partitions, that's not often possible (you'd need to have available space after the partition itself), but with something like LVM it's trivial, since you can just resize the logical volume at will.
After resizing the partition/volume, the filesystem only makes use of the originally available space, and at that point resize2fs is necessary. Again, you'll usually want to resize the partition to the fill all the now available space, so the default action is what you want.
answered Feb 21 at 18:07
ilkkachuilkkachu
60.9k1098174
add a comment |
The size of a filesystem is by default the size of its underlying partition.
Usually, yes. There's little point in creating a filesystem smaller than the available space on the partition.
But if you're trying to enlarge the filesystem, you'll first have to enlarge the device it's on. For the usual fixed partitions, that's not often possible (you'd need to have available space after the partition itself), but with something like LVM it's trivial, since you can just resize the logical volume at will.
After resizing the partition/volume, the filesystem only makes use of the originally available space, and at that point resize2fs is necessary. Again, you'll usually want to resize the partition to the fill all the now available space, so the default action is what you want.
answered Feb 21 at 18:07
ilkkachuilkkachu
60.9k1098174
add a comment |
The size of a filesystem is by default the size of its underlying partition.
Usually, yes. There's little point in creating a filesystem smaller than the available space on the partition.
But if you're trying to enlarge the filesystem, you'll first have to enlarge the device it's on. For the usual fixed partitions, that's not often possible (you'd need to have available space after the partition itself), but with something like LVM it's trivial, since you can just resize the logical volume at will.
After resizing the partition/volume, the filesystem only makes use of the originally available space, and at that point resize2fs is necessary. Again, you'll usually want to resize the partition to the fill all the now available space, so the default action is what you want.
answered Feb 21 at 18:07
ilkkachuilkkachu
60.9k1098174
The size of a filesystem is by default the size of its underlying partition.
Usually, yes. There's little point in creating a filesystem smaller than the available space on the partition.
But if you're trying to enlarge the filesystem, you'll first have to enlarge the device it's on. For the usual fixed partitions, that's not often possible (you'd need to have available space after the partition itself), but with something like LVM it's trivial, since you can just resize the logical volume at will.
After resizing the partition/volume, the filesystem only makes use of the originally available space, and at that point resize2fs is necessary. Again, you'll usually want to resize the partition to the fill all the now available space, so the default action is what you want.
answered Feb 21 at 18:07
ilkkachuilkkachu
60.9k1098174
answered Feb 21 at 18:07
ilkkachuilkkachu
60.9k1098174
answered Feb 21 at 18:07
ilkkachuilkkachu
60.9k1098174
answered Feb 21 at 18:07
ilkkachuilkkachu
60.9k1098174
60.9k1098174
add a comment |
add a comment |
I also often (ab)use resize2fs in some smallish/skeletal VMs for not to have to setup LVM.
For extending a drive/partition, I can provisioning/extend a virtual physical hard disk, and then delete and create a new bigger partition. Once I do that, I can extend the partition to the new "physical" space. (for instance, in vmware, I just edit an existing virtual disk, and edit it to be 10GB instead of 5GB...)
Or even in a physical disk, you can delete a second partition, delete the 1st one and recreate it using the former space of the two partitions, and then use resizefs for having a single partition where once you had two partitions.
So, resize2fs does something even without using LVM.
answered Feb 21 at 19:58
Rui F RibeiroRui F Ribeiro
41.4k1481140
add a comment |
I also often (ab)use resize2fs in some smallish/skeletal VMs for not to have to setup LVM.
For extending a drive/partition, I can provisioning/extend a virtual physical hard disk, and then delete and create a new bigger partition. Once I do that, I can extend the partition to the new "physical" space. (for instance, in vmware, I just edit an existing virtual disk, and edit it to be 10GB instead of 5GB...)
Or even in a physical disk, you can delete a second partition, delete the 1st one and recreate it using the former space of the two partitions, and then use resizefs for having a single partition where once you had two partitions.
So, resize2fs does something even without using LVM.
answered Feb 21 at 19:58
Rui F RibeiroRui F Ribeiro
41.4k1481140
add a comment |
I also often (ab)use resize2fs in some smallish/skeletal VMs for not to have to setup LVM.
For extending a drive/partition, I can provisioning/extend a virtual physical hard disk, and then delete and create a new bigger partition. Once I do that, I can extend the partition to the new "physical" space. (for instance, in vmware, I just edit an existing virtual disk, and edit it to be 10GB instead of 5GB...)
Or even in a physical disk, you can delete a second partition, delete the 1st one and recreate it using the former space of the two partitions, and then use resizefs for having a single partition where once you had two partitions.
So, resize2fs does something even without using LVM.
answered Feb 21 at 19:58
Rui F RibeiroRui F Ribeiro
41.4k1481140
I also often (ab)use resize2fs in some smallish/skeletal VMs for not to have to setup LVM.
For extending a drive/partition, I can provisioning/extend a virtual physical hard disk, and then delete and create a new bigger partition. Once I do that, I can extend the partition to the new "physical" space. (for instance, in vmware, I just edit an existing virtual disk, and edit it to be 10GB instead of 5GB...)
Or even in a physical disk, you can delete a second partition, delete the 1st one and recreate it using the former space of the two partitions, and then use resizefs for having a single partition where once you had two partitions.
So, resize2fs does something even without using LVM.
answered Feb 21 at 19:58
Rui F RibeiroRui F Ribeiro
41.4k1481140
edited Feb 21 at 20:38
answered Feb 21 at 19:58
Rui F RibeiroRui F Ribeiro
41.4k1481140
answered Feb 21 at 19:58
Rui F RibeiroRui F Ribeiro
41.4k1481140
answered Feb 21 at 19:58
Rui F RibeiroRui F Ribeiro
41.4k1481140
41.4k1481140
add a comment |
add a comment |
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