source and destination path for the copy command in single file then how to copy?












0















I have a single file which contains source file paths and destination file paths.



example



$ cat test.txt
/home/data/source.txt /home/code/destination.txt
/home/abc/def.txt /home/mnp/xyz.txt


Here i want to copy /home/data/source.txt to /home/code/destination.txt (cp /home/data/source.txt /home/code/destination.txt)



I have so many source path and Destination path in a single file



So I want a command by which I can copy file from source path to destination path.



Thanks.










share|improve this question





























    0















    I have a single file which contains source file paths and destination file paths.



    example



    $ cat test.txt
    /home/data/source.txt /home/code/destination.txt
    /home/abc/def.txt /home/mnp/xyz.txt


    Here i want to copy /home/data/source.txt to /home/code/destination.txt (cp /home/data/source.txt /home/code/destination.txt)



    I have so many source path and Destination path in a single file



    So I want a command by which I can copy file from source path to destination path.



    Thanks.










    share|improve this question



























      0












      0








      0








      I have a single file which contains source file paths and destination file paths.



      example



      $ cat test.txt
      /home/data/source.txt /home/code/destination.txt
      /home/abc/def.txt /home/mnp/xyz.txt


      Here i want to copy /home/data/source.txt to /home/code/destination.txt (cp /home/data/source.txt /home/code/destination.txt)



      I have so many source path and Destination path in a single file



      So I want a command by which I can copy file from source path to destination path.



      Thanks.










      share|improve this question
















      I have a single file which contains source file paths and destination file paths.



      example



      $ cat test.txt
      /home/data/source.txt /home/code/destination.txt
      /home/abc/def.txt /home/mnp/xyz.txt


      Here i want to copy /home/data/source.txt to /home/code/destination.txt (cp /home/data/source.txt /home/code/destination.txt)



      I have so many source path and Destination path in a single file



      So I want a command by which I can copy file from source path to destination path.



      Thanks.







      linux cp xargs






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 13 '17 at 14:50









      stderr

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      905412










      asked Mar 13 '17 at 14:23









      VishalVishal

      162




      162






















          2 Answers
          2






          active

          oldest

          votes


















          1














          Here's an idea:




          • make a copy of your file: cp test.txt test.sh

          • put cp at the beginning of each line: sed -i 's/^/cp / test.sh

          • make the file executable: chmod +x test.sh

          • execute the file: ./test.sh






          share|improve this answer































            1














            cat test.txt | xargs -L 1 cp -v


            where:





            • test.txt is your input file


            • xargs -L 1 will list lines one by one and run


            • cp is the copy command


            • -v is there to have visibility and for check






            share|improve this answer























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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              1














              Here's an idea:




              • make a copy of your file: cp test.txt test.sh

              • put cp at the beginning of each line: sed -i 's/^/cp / test.sh

              • make the file executable: chmod +x test.sh

              • execute the file: ./test.sh






              share|improve this answer




























                1














                Here's an idea:




                • make a copy of your file: cp test.txt test.sh

                • put cp at the beginning of each line: sed -i 's/^/cp / test.sh

                • make the file executable: chmod +x test.sh

                • execute the file: ./test.sh






                share|improve this answer


























                  1












                  1








                  1







                  Here's an idea:




                  • make a copy of your file: cp test.txt test.sh

                  • put cp at the beginning of each line: sed -i 's/^/cp / test.sh

                  • make the file executable: chmod +x test.sh

                  • execute the file: ./test.sh






                  share|improve this answer













                  Here's an idea:




                  • make a copy of your file: cp test.txt test.sh

                  • put cp at the beginning of each line: sed -i 's/^/cp / test.sh

                  • make the file executable: chmod +x test.sh

                  • execute the file: ./test.sh







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 13 '17 at 14:29









                  David DaiDavid Dai

                  1,66221326




                  1,66221326

























                      1














                      cat test.txt | xargs -L 1 cp -v


                      where:





                      • test.txt is your input file


                      • xargs -L 1 will list lines one by one and run


                      • cp is the copy command


                      • -v is there to have visibility and for check






                      share|improve this answer




























                        1














                        cat test.txt | xargs -L 1 cp -v


                        where:





                        • test.txt is your input file


                        • xargs -L 1 will list lines one by one and run


                        • cp is the copy command


                        • -v is there to have visibility and for check






                        share|improve this answer


























                          1












                          1








                          1







                          cat test.txt | xargs -L 1 cp -v


                          where:





                          • test.txt is your input file


                          • xargs -L 1 will list lines one by one and run


                          • cp is the copy command


                          • -v is there to have visibility and for check






                          share|improve this answer













                          cat test.txt | xargs -L 1 cp -v


                          where:





                          • test.txt is your input file


                          • xargs -L 1 will list lines one by one and run


                          • cp is the copy command


                          • -v is there to have visibility and for check







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Mar 13 '17 at 14:33









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                          905412




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