need help in solving that numerical sequence












3












$begingroup$


Sequence: 2, 3, ?, 8, 6, 7, 6, 5, 9, 3, ?, 1



I've tried to figure out what number I should replace to the *?*I have initially thought that was a modified fibonacci sequence example: we start with 2+3=5 then 5+3=8 and that's the first group (2, 3, 5, 8, ), then we should do 8+5=13 and to reach 16 we need 3 so we should do 8+5+3=16 and we write only the six,then we proceed and do 6+8+3=17 and we should write only the 7 then we do 6+7=13+3=16 and at the moment we have done this part of the sequence:2, 3, 5, 8,6,7,6 the real problem comes out now because 6+7+x=5 but if we do 6+7+3 we get 16 and not 15 so I tought that I should have divided this sequence in different parts:



1st sequence composed of 4 numbers 2, 3, 5, 8 were we just do the sum of the number+previous number example 2+3=5 5+3=8 etc



2nd sequence composed of 3 numbers: 6, 7, 6 in this case you should do the basic fibonacci sequence and add 3 so 6+7+3=16 and we write only the six



3rd sequence composed of 2 numbers 5,9 and in this case we do 5+9+ 3*3=23 and we only write the number 3



4th sequence: 9, 3, 9+3 + 3*3*3=66 and we write numbers 6



5th sequence in this one we should do 6+3+ 3*3*3*3 but we get 90 and we should have gotten 91 please help me solve this problem



Author mislav predavec gave me his permission to repost










share|improve this question











$endgroup$

















    3












    $begingroup$


    Sequence: 2, 3, ?, 8, 6, 7, 6, 5, 9, 3, ?, 1



    I've tried to figure out what number I should replace to the *?*I have initially thought that was a modified fibonacci sequence example: we start with 2+3=5 then 5+3=8 and that's the first group (2, 3, 5, 8, ), then we should do 8+5=13 and to reach 16 we need 3 so we should do 8+5+3=16 and we write only the six,then we proceed and do 6+8+3=17 and we should write only the 7 then we do 6+7=13+3=16 and at the moment we have done this part of the sequence:2, 3, 5, 8,6,7,6 the real problem comes out now because 6+7+x=5 but if we do 6+7+3 we get 16 and not 15 so I tought that I should have divided this sequence in different parts:



    1st sequence composed of 4 numbers 2, 3, 5, 8 were we just do the sum of the number+previous number example 2+3=5 5+3=8 etc



    2nd sequence composed of 3 numbers: 6, 7, 6 in this case you should do the basic fibonacci sequence and add 3 so 6+7+3=16 and we write only the six



    3rd sequence composed of 2 numbers 5,9 and in this case we do 5+9+ 3*3=23 and we only write the number 3



    4th sequence: 9, 3, 9+3 + 3*3*3=66 and we write numbers 6



    5th sequence in this one we should do 6+3+ 3*3*3*3 but we get 90 and we should have gotten 91 please help me solve this problem



    Author mislav predavec gave me his permission to repost










    share|improve this question











    $endgroup$















      3












      3








      3





      $begingroup$


      Sequence: 2, 3, ?, 8, 6, 7, 6, 5, 9, 3, ?, 1



      I've tried to figure out what number I should replace to the *?*I have initially thought that was a modified fibonacci sequence example: we start with 2+3=5 then 5+3=8 and that's the first group (2, 3, 5, 8, ), then we should do 8+5=13 and to reach 16 we need 3 so we should do 8+5+3=16 and we write only the six,then we proceed and do 6+8+3=17 and we should write only the 7 then we do 6+7=13+3=16 and at the moment we have done this part of the sequence:2, 3, 5, 8,6,7,6 the real problem comes out now because 6+7+x=5 but if we do 6+7+3 we get 16 and not 15 so I tought that I should have divided this sequence in different parts:



      1st sequence composed of 4 numbers 2, 3, 5, 8 were we just do the sum of the number+previous number example 2+3=5 5+3=8 etc



      2nd sequence composed of 3 numbers: 6, 7, 6 in this case you should do the basic fibonacci sequence and add 3 so 6+7+3=16 and we write only the six



      3rd sequence composed of 2 numbers 5,9 and in this case we do 5+9+ 3*3=23 and we only write the number 3



      4th sequence: 9, 3, 9+3 + 3*3*3=66 and we write numbers 6



      5th sequence in this one we should do 6+3+ 3*3*3*3 but we get 90 and we should have gotten 91 please help me solve this problem



      Author mislav predavec gave me his permission to repost










      share|improve this question











      $endgroup$




      Sequence: 2, 3, ?, 8, 6, 7, 6, 5, 9, 3, ?, 1



      I've tried to figure out what number I should replace to the *?*I have initially thought that was a modified fibonacci sequence example: we start with 2+3=5 then 5+3=8 and that's the first group (2, 3, 5, 8, ), then we should do 8+5=13 and to reach 16 we need 3 so we should do 8+5+3=16 and we write only the six,then we proceed and do 6+8+3=17 and we should write only the 7 then we do 6+7=13+3=16 and at the moment we have done this part of the sequence:2, 3, 5, 8,6,7,6 the real problem comes out now because 6+7+x=5 but if we do 6+7+3 we get 16 and not 15 so I tought that I should have divided this sequence in different parts:



      1st sequence composed of 4 numbers 2, 3, 5, 8 were we just do the sum of the number+previous number example 2+3=5 5+3=8 etc



      2nd sequence composed of 3 numbers: 6, 7, 6 in this case you should do the basic fibonacci sequence and add 3 so 6+7+3=16 and we write only the six



      3rd sequence composed of 2 numbers 5,9 and in this case we do 5+9+ 3*3=23 and we only write the number 3



      4th sequence: 9, 3, 9+3 + 3*3*3=66 and we write numbers 6



      5th sequence in this one we should do 6+3+ 3*3*3*3 but we get 90 and we should have gotten 91 please help me solve this problem



      Author mislav predavec gave me his permission to repost







      mathematics logical-deduction pattern






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 20 at 14:34







      alnesi

















      asked Jan 20 at 14:17









      alnesialnesi

      888




      888






















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          How about:




          Splitting the sequence in half and looking at the reflective differences


           2,  3,  ?,  8,  6,  7  <-- first half
          1, ?, 3, 9, 5, 6 <-- second half backwards
          1, ?, ?, -1, 1, 1 <-- subtract

          One way could be that the differences are
           1,  1, -1, -1,  1,  1

          Giving
           2,  3,  2,  8,  6,  7,  6,  5,  9,  3,  2,  1

          ...and making both $?=2$





          share|improve this answer









          $endgroup$













          • $begingroup$
            i think that could be correct,waiting for others to answer
            $endgroup$
            – alnesi
            Jan 20 at 16:10










          • $begingroup$
            Seems overly complicated to me
            $endgroup$
            – Jonathan Allan
            Jan 20 at 16:48










          • $begingroup$
            I think that too,there could be a simple answer that we fail to see
            $endgroup$
            – alnesi
            Jan 20 at 16:54










          • $begingroup$
            what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
            $endgroup$
            – alnesi
            Jan 20 at 17:11











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "559"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f78633%2fneed-help-in-solving-that-numerical-sequence%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2












          $begingroup$

          How about:




          Splitting the sequence in half and looking at the reflective differences


           2,  3,  ?,  8,  6,  7  <-- first half
          1, ?, 3, 9, 5, 6 <-- second half backwards
          1, ?, ?, -1, 1, 1 <-- subtract

          One way could be that the differences are
           1,  1, -1, -1,  1,  1

          Giving
           2,  3,  2,  8,  6,  7,  6,  5,  9,  3,  2,  1

          ...and making both $?=2$





          share|improve this answer









          $endgroup$













          • $begingroup$
            i think that could be correct,waiting for others to answer
            $endgroup$
            – alnesi
            Jan 20 at 16:10










          • $begingroup$
            Seems overly complicated to me
            $endgroup$
            – Jonathan Allan
            Jan 20 at 16:48










          • $begingroup$
            I think that too,there could be a simple answer that we fail to see
            $endgroup$
            – alnesi
            Jan 20 at 16:54










          • $begingroup$
            what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
            $endgroup$
            – alnesi
            Jan 20 at 17:11
















          2












          $begingroup$

          How about:




          Splitting the sequence in half and looking at the reflective differences


           2,  3,  ?,  8,  6,  7  <-- first half
          1, ?, 3, 9, 5, 6 <-- second half backwards
          1, ?, ?, -1, 1, 1 <-- subtract

          One way could be that the differences are
           1,  1, -1, -1,  1,  1

          Giving
           2,  3,  2,  8,  6,  7,  6,  5,  9,  3,  2,  1

          ...and making both $?=2$





          share|improve this answer









          $endgroup$













          • $begingroup$
            i think that could be correct,waiting for others to answer
            $endgroup$
            – alnesi
            Jan 20 at 16:10










          • $begingroup$
            Seems overly complicated to me
            $endgroup$
            – Jonathan Allan
            Jan 20 at 16:48










          • $begingroup$
            I think that too,there could be a simple answer that we fail to see
            $endgroup$
            – alnesi
            Jan 20 at 16:54










          • $begingroup$
            what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
            $endgroup$
            – alnesi
            Jan 20 at 17:11














          2












          2








          2





          $begingroup$

          How about:




          Splitting the sequence in half and looking at the reflective differences


           2,  3,  ?,  8,  6,  7  <-- first half
          1, ?, 3, 9, 5, 6 <-- second half backwards
          1, ?, ?, -1, 1, 1 <-- subtract

          One way could be that the differences are
           1,  1, -1, -1,  1,  1

          Giving
           2,  3,  2,  8,  6,  7,  6,  5,  9,  3,  2,  1

          ...and making both $?=2$





          share|improve this answer









          $endgroup$



          How about:




          Splitting the sequence in half and looking at the reflective differences


           2,  3,  ?,  8,  6,  7  <-- first half
          1, ?, 3, 9, 5, 6 <-- second half backwards
          1, ?, ?, -1, 1, 1 <-- subtract

          One way could be that the differences are
           1,  1, -1, -1,  1,  1

          Giving
           2,  3,  2,  8,  6,  7,  6,  5,  9,  3,  2,  1

          ...and making both $?=2$






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jan 20 at 15:15









          Jonathan AllanJonathan Allan

          17.7k14697




          17.7k14697












          • $begingroup$
            i think that could be correct,waiting for others to answer
            $endgroup$
            – alnesi
            Jan 20 at 16:10










          • $begingroup$
            Seems overly complicated to me
            $endgroup$
            – Jonathan Allan
            Jan 20 at 16:48










          • $begingroup$
            I think that too,there could be a simple answer that we fail to see
            $endgroup$
            – alnesi
            Jan 20 at 16:54










          • $begingroup$
            what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
            $endgroup$
            – alnesi
            Jan 20 at 17:11


















          • $begingroup$
            i think that could be correct,waiting for others to answer
            $endgroup$
            – alnesi
            Jan 20 at 16:10










          • $begingroup$
            Seems overly complicated to me
            $endgroup$
            – Jonathan Allan
            Jan 20 at 16:48










          • $begingroup$
            I think that too,there could be a simple answer that we fail to see
            $endgroup$
            – alnesi
            Jan 20 at 16:54










          • $begingroup$
            what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
            $endgroup$
            – alnesi
            Jan 20 at 17:11
















          $begingroup$
          i think that could be correct,waiting for others to answer
          $endgroup$
          – alnesi
          Jan 20 at 16:10




          $begingroup$
          i think that could be correct,waiting for others to answer
          $endgroup$
          – alnesi
          Jan 20 at 16:10












          $begingroup$
          Seems overly complicated to me
          $endgroup$
          – Jonathan Allan
          Jan 20 at 16:48




          $begingroup$
          Seems overly complicated to me
          $endgroup$
          – Jonathan Allan
          Jan 20 at 16:48












          $begingroup$
          I think that too,there could be a simple answer that we fail to see
          $endgroup$
          – alnesi
          Jan 20 at 16:54




          $begingroup$
          I think that too,there could be a simple answer that we fail to see
          $endgroup$
          – alnesi
          Jan 20 at 16:54












          $begingroup$
          what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
          $endgroup$
          – alnesi
          Jan 20 at 17:11




          $begingroup$
          what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
          $endgroup$
          – alnesi
          Jan 20 at 17:11


















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Puzzling Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f78633%2fneed-help-in-solving-that-numerical-sequence%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          How to make a Squid Proxy server?

          Is this a new Fibonacci Identity?

          19世紀