need help in solving that numerical sequence
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Sequence: 2, 3, ?, 8, 6, 7, 6, 5, 9, 3, ?, 1
I've tried to figure out what number I should replace to the *?*I have initially thought that was a modified fibonacci sequence example: we start with 2+3=5 then 5+3=8 and that's the first group (2, 3, 5, 8, ), then we should do 8+5=13 and to reach 16 we need 3 so we should do 8+5+3=16 and we write only the six,then we proceed and do 6+8+3=17 and we should write only the 7 then we do 6+7=13+3=16 and at the moment we have done this part of the sequence:2, 3, 5, 8,6,7,6 the real problem comes out now because 6+7+x=5 but if we do 6+7+3 we get 16 and not 15 so I tought that I should have divided this sequence in different parts:
1st sequence composed of 4 numbers 2, 3, 5, 8 were we just do the sum of the number+previous number example 2+3=5 5+3=8 etc
2nd sequence composed of 3 numbers: 6, 7, 6 in this case you should do the basic fibonacci sequence and add 3 so 6+7+3=16 and we write only the six
3rd sequence composed of 2 numbers 5,9 and in this case we do 5+9+ 3*3=23 and we only write the number 3
4th sequence: 9, 3, 9+3 + 3*3*3=66 and we write numbers 6
5th sequence in this one we should do 6+3+ 3*3*3*3 but we get 90 and we should have gotten 91 please help me solve this problem
Author mislav predavec gave me his permission to repost
mathematics logical-deduction pattern
$endgroup$
add a comment |
$begingroup$
Sequence: 2, 3, ?, 8, 6, 7, 6, 5, 9, 3, ?, 1
I've tried to figure out what number I should replace to the *?*I have initially thought that was a modified fibonacci sequence example: we start with 2+3=5 then 5+3=8 and that's the first group (2, 3, 5, 8, ), then we should do 8+5=13 and to reach 16 we need 3 so we should do 8+5+3=16 and we write only the six,then we proceed and do 6+8+3=17 and we should write only the 7 then we do 6+7=13+3=16 and at the moment we have done this part of the sequence:2, 3, 5, 8,6,7,6 the real problem comes out now because 6+7+x=5 but if we do 6+7+3 we get 16 and not 15 so I tought that I should have divided this sequence in different parts:
1st sequence composed of 4 numbers 2, 3, 5, 8 were we just do the sum of the number+previous number example 2+3=5 5+3=8 etc
2nd sequence composed of 3 numbers: 6, 7, 6 in this case you should do the basic fibonacci sequence and add 3 so 6+7+3=16 and we write only the six
3rd sequence composed of 2 numbers 5,9 and in this case we do 5+9+ 3*3=23 and we only write the number 3
4th sequence: 9, 3, 9+3 + 3*3*3=66 and we write numbers 6
5th sequence in this one we should do 6+3+ 3*3*3*3 but we get 90 and we should have gotten 91 please help me solve this problem
Author mislav predavec gave me his permission to repost
mathematics logical-deduction pattern
$endgroup$
add a comment |
$begingroup$
Sequence: 2, 3, ?, 8, 6, 7, 6, 5, 9, 3, ?, 1
I've tried to figure out what number I should replace to the *?*I have initially thought that was a modified fibonacci sequence example: we start with 2+3=5 then 5+3=8 and that's the first group (2, 3, 5, 8, ), then we should do 8+5=13 and to reach 16 we need 3 so we should do 8+5+3=16 and we write only the six,then we proceed and do 6+8+3=17 and we should write only the 7 then we do 6+7=13+3=16 and at the moment we have done this part of the sequence:2, 3, 5, 8,6,7,6 the real problem comes out now because 6+7+x=5 but if we do 6+7+3 we get 16 and not 15 so I tought that I should have divided this sequence in different parts:
1st sequence composed of 4 numbers 2, 3, 5, 8 were we just do the sum of the number+previous number example 2+3=5 5+3=8 etc
2nd sequence composed of 3 numbers: 6, 7, 6 in this case you should do the basic fibonacci sequence and add 3 so 6+7+3=16 and we write only the six
3rd sequence composed of 2 numbers 5,9 and in this case we do 5+9+ 3*3=23 and we only write the number 3
4th sequence: 9, 3, 9+3 + 3*3*3=66 and we write numbers 6
5th sequence in this one we should do 6+3+ 3*3*3*3 but we get 90 and we should have gotten 91 please help me solve this problem
Author mislav predavec gave me his permission to repost
mathematics logical-deduction pattern
$endgroup$
Sequence: 2, 3, ?, 8, 6, 7, 6, 5, 9, 3, ?, 1
I've tried to figure out what number I should replace to the *?*I have initially thought that was a modified fibonacci sequence example: we start with 2+3=5 then 5+3=8 and that's the first group (2, 3, 5, 8, ), then we should do 8+5=13 and to reach 16 we need 3 so we should do 8+5+3=16 and we write only the six,then we proceed and do 6+8+3=17 and we should write only the 7 then we do 6+7=13+3=16 and at the moment we have done this part of the sequence:2, 3, 5, 8,6,7,6 the real problem comes out now because 6+7+x=5 but if we do 6+7+3 we get 16 and not 15 so I tought that I should have divided this sequence in different parts:
1st sequence composed of 4 numbers 2, 3, 5, 8 were we just do the sum of the number+previous number example 2+3=5 5+3=8 etc
2nd sequence composed of 3 numbers: 6, 7, 6 in this case you should do the basic fibonacci sequence and add 3 so 6+7+3=16 and we write only the six
3rd sequence composed of 2 numbers 5,9 and in this case we do 5+9+ 3*3=23 and we only write the number 3
4th sequence: 9, 3, 9+3 + 3*3*3=66 and we write numbers 6
5th sequence in this one we should do 6+3+ 3*3*3*3 but we get 90 and we should have gotten 91 please help me solve this problem
Author mislav predavec gave me his permission to repost
mathematics logical-deduction pattern
mathematics logical-deduction pattern
edited Jan 20 at 14:34
alnesi
asked Jan 20 at 14:17
alnesialnesi
888
888
add a comment |
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1 Answer
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$begingroup$
How about:
Splitting the sequence in half and looking at the reflective differences
2, 3, ?, 8, 6, 7 <-- first half
1, ?, 3, 9, 5, 6 <-- second half backwards
1, ?, ?, -1, 1, 1 <-- subtract
One way could be that the differences are
1, 1, -1, -1, 1, 1
Giving
2, 3, 2, 8, 6, 7, 6, 5, 9, 3, 2, 1
...and making both $?=2$
$endgroup$
$begingroup$
i think that could be correct,waiting for others to answer
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– alnesi
Jan 20 at 16:10
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Seems overly complicated to me
$endgroup$
– Jonathan Allan
Jan 20 at 16:48
$begingroup$
I think that too,there could be a simple answer that we fail to see
$endgroup$
– alnesi
Jan 20 at 16:54
$begingroup$
what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
$endgroup$
– alnesi
Jan 20 at 17:11
add a comment |
Your Answer
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1 Answer
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1 Answer
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$begingroup$
How about:
Splitting the sequence in half and looking at the reflective differences
2, 3, ?, 8, 6, 7 <-- first half
1, ?, 3, 9, 5, 6 <-- second half backwards
1, ?, ?, -1, 1, 1 <-- subtract
One way could be that the differences are
1, 1, -1, -1, 1, 1
Giving
2, 3, 2, 8, 6, 7, 6, 5, 9, 3, 2, 1
...and making both $?=2$
$endgroup$
$begingroup$
i think that could be correct,waiting for others to answer
$endgroup$
– alnesi
Jan 20 at 16:10
$begingroup$
Seems overly complicated to me
$endgroup$
– Jonathan Allan
Jan 20 at 16:48
$begingroup$
I think that too,there could be a simple answer that we fail to see
$endgroup$
– alnesi
Jan 20 at 16:54
$begingroup$
what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
$endgroup$
– alnesi
Jan 20 at 17:11
add a comment |
$begingroup$
How about:
Splitting the sequence in half and looking at the reflective differences
2, 3, ?, 8, 6, 7 <-- first half
1, ?, 3, 9, 5, 6 <-- second half backwards
1, ?, ?, -1, 1, 1 <-- subtract
One way could be that the differences are
1, 1, -1, -1, 1, 1
Giving
2, 3, 2, 8, 6, 7, 6, 5, 9, 3, 2, 1
...and making both $?=2$
$endgroup$
$begingroup$
i think that could be correct,waiting for others to answer
$endgroup$
– alnesi
Jan 20 at 16:10
$begingroup$
Seems overly complicated to me
$endgroup$
– Jonathan Allan
Jan 20 at 16:48
$begingroup$
I think that too,there could be a simple answer that we fail to see
$endgroup$
– alnesi
Jan 20 at 16:54
$begingroup$
what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
$endgroup$
– alnesi
Jan 20 at 17:11
add a comment |
$begingroup$
How about:
Splitting the sequence in half and looking at the reflective differences
2, 3, ?, 8, 6, 7 <-- first half
1, ?, 3, 9, 5, 6 <-- second half backwards
1, ?, ?, -1, 1, 1 <-- subtract
One way could be that the differences are
1, 1, -1, -1, 1, 1
Giving
2, 3, 2, 8, 6, 7, 6, 5, 9, 3, 2, 1
...and making both $?=2$
$endgroup$
How about:
Splitting the sequence in half and looking at the reflective differences
2, 3, ?, 8, 6, 7 <-- first half
1, ?, 3, 9, 5, 6 <-- second half backwards
1, ?, ?, -1, 1, 1 <-- subtract
One way could be that the differences are
1, 1, -1, -1, 1, 1
Giving
2, 3, 2, 8, 6, 7, 6, 5, 9, 3, 2, 1
...and making both $?=2$
answered Jan 20 at 15:15
Jonathan AllanJonathan Allan
17.7k14697
17.7k14697
$begingroup$
i think that could be correct,waiting for others to answer
$endgroup$
– alnesi
Jan 20 at 16:10
$begingroup$
Seems overly complicated to me
$endgroup$
– Jonathan Allan
Jan 20 at 16:48
$begingroup$
I think that too,there could be a simple answer that we fail to see
$endgroup$
– alnesi
Jan 20 at 16:54
$begingroup$
what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
$endgroup$
– alnesi
Jan 20 at 17:11
add a comment |
$begingroup$
i think that could be correct,waiting for others to answer
$endgroup$
– alnesi
Jan 20 at 16:10
$begingroup$
Seems overly complicated to me
$endgroup$
– Jonathan Allan
Jan 20 at 16:48
$begingroup$
I think that too,there could be a simple answer that we fail to see
$endgroup$
– alnesi
Jan 20 at 16:54
$begingroup$
what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
$endgroup$
– alnesi
Jan 20 at 17:11
$begingroup$
i think that could be correct,waiting for others to answer
$endgroup$
– alnesi
Jan 20 at 16:10
$begingroup$
i think that could be correct,waiting for others to answer
$endgroup$
– alnesi
Jan 20 at 16:10
$begingroup$
Seems overly complicated to me
$endgroup$
– Jonathan Allan
Jan 20 at 16:48
$begingroup$
Seems overly complicated to me
$endgroup$
– Jonathan Allan
Jan 20 at 16:48
$begingroup$
I think that too,there could be a simple answer that we fail to see
$endgroup$
– alnesi
Jan 20 at 16:54
$begingroup$
I think that too,there could be a simple answer that we fail to see
$endgroup$
– alnesi
Jan 20 at 16:54
$begingroup$
what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
$endgroup$
– alnesi
Jan 20 at 17:11
$begingroup$
what if it's something like that @jonathan allan :puzzling.stackexchange.com/questions/64791/…
$endgroup$
– alnesi
Jan 20 at 17:11
add a comment |
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