Summary statistics in shell script












0















I have multiple files (records) across multiple directories. Each record lies in its own path based on the date it was created.



Eg a record on 12 Nov 2016 is



~/records/2016/11/12/record.


In each record, there is a number in the final line and I am trying to calculate summary statistics for each year.



How do I write a script that takes two user inputs:




  • year

  • statistic


where statistic could be average, max, min or all (avg, max
and min)?










share|improve this question





























    0















    I have multiple files (records) across multiple directories. Each record lies in its own path based on the date it was created.



    Eg a record on 12 Nov 2016 is



    ~/records/2016/11/12/record.


    In each record, there is a number in the final line and I am trying to calculate summary statistics for each year.



    How do I write a script that takes two user inputs:




    • year

    • statistic


    where statistic could be average, max, min or all (avg, max
    and min)?










    share|improve this question



























      0












      0








      0








      I have multiple files (records) across multiple directories. Each record lies in its own path based on the date it was created.



      Eg a record on 12 Nov 2016 is



      ~/records/2016/11/12/record.


      In each record, there is a number in the final line and I am trying to calculate summary statistics for each year.



      How do I write a script that takes two user inputs:




      • year

      • statistic


      where statistic could be average, max, min or all (avg, max
      and min)?










      share|improve this question
















      I have multiple files (records) across multiple directories. Each record lies in its own path based on the date it was created.



      Eg a record on 12 Nov 2016 is



      ~/records/2016/11/12/record.


      In each record, there is a number in the final line and I am trying to calculate summary statistics for each year.



      How do I write a script that takes two user inputs:




      • year

      • statistic


      where statistic could be average, max, min or all (avg, max
      and min)?







      shell-script awk files statistics






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 29 at 13:04









      msp9011

      4,31844065




      4,31844065










      asked Jan 29 at 12:40









      marzomarzo

      132




      132






















          2 Answers
          2






          active

          oldest

          votes


















          1














          You can use the year input to define the root directory for a find command that searches all record files and calls tail -1 for every file.



          find ~/records/"$YEAR" -type f -name record -exec tail -1 {} ;


          This would be sufficient to print all values of the specified year.



          To calculate min/max/average pipe the output into awk for the calculation.



          awk -v stat="$STATISTICS" 'BEGIN { count=0; sum=0; }
          { if(!count) { min=$0; max=$0; }
          count++;
          sum += $0;
          if($0 > max) max = $0;
          if($0 < min) min = $0;
          }
          END {
          if(count) {
          # TODO: use variable "stat" to select only one result to print
          print min;
          print sum/count; # average
          print max;
          } else {
          print "no data";
          }
          }'


          You can combine and extend these snippets to get a complete script.






          share|improve this answer

































            0














            I have used below command to find the same and it worked fine



            echo "enter the year"
            read year

            find /records/$year/ -maxdepth 3 -type f -iname "filename" -exec sed -n '$p' {} ;| awk 'BEGIN{sum=0}{sum=sum+$1}END{print sum


            }'






            share|improve this answer























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              2 Answers
              2






              active

              oldest

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              2 Answers
              2






              active

              oldest

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              active

              oldest

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              active

              oldest

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              1














              You can use the year input to define the root directory for a find command that searches all record files and calls tail -1 for every file.



              find ~/records/"$YEAR" -type f -name record -exec tail -1 {} ;


              This would be sufficient to print all values of the specified year.



              To calculate min/max/average pipe the output into awk for the calculation.



              awk -v stat="$STATISTICS" 'BEGIN { count=0; sum=0; }
              { if(!count) { min=$0; max=$0; }
              count++;
              sum += $0;
              if($0 > max) max = $0;
              if($0 < min) min = $0;
              }
              END {
              if(count) {
              # TODO: use variable "stat" to select only one result to print
              print min;
              print sum/count; # average
              print max;
              } else {
              print "no data";
              }
              }'


              You can combine and extend these snippets to get a complete script.






              share|improve this answer






























                1














                You can use the year input to define the root directory for a find command that searches all record files and calls tail -1 for every file.



                find ~/records/"$YEAR" -type f -name record -exec tail -1 {} ;


                This would be sufficient to print all values of the specified year.



                To calculate min/max/average pipe the output into awk for the calculation.



                awk -v stat="$STATISTICS" 'BEGIN { count=0; sum=0; }
                { if(!count) { min=$0; max=$0; }
                count++;
                sum += $0;
                if($0 > max) max = $0;
                if($0 < min) min = $0;
                }
                END {
                if(count) {
                # TODO: use variable "stat" to select only one result to print
                print min;
                print sum/count; # average
                print max;
                } else {
                print "no data";
                }
                }'


                You can combine and extend these snippets to get a complete script.






                share|improve this answer




























                  1












                  1








                  1







                  You can use the year input to define the root directory for a find command that searches all record files and calls tail -1 for every file.



                  find ~/records/"$YEAR" -type f -name record -exec tail -1 {} ;


                  This would be sufficient to print all values of the specified year.



                  To calculate min/max/average pipe the output into awk for the calculation.



                  awk -v stat="$STATISTICS" 'BEGIN { count=0; sum=0; }
                  { if(!count) { min=$0; max=$0; }
                  count++;
                  sum += $0;
                  if($0 > max) max = $0;
                  if($0 < min) min = $0;
                  }
                  END {
                  if(count) {
                  # TODO: use variable "stat" to select only one result to print
                  print min;
                  print sum/count; # average
                  print max;
                  } else {
                  print "no data";
                  }
                  }'


                  You can combine and extend these snippets to get a complete script.






                  share|improve this answer















                  You can use the year input to define the root directory for a find command that searches all record files and calls tail -1 for every file.



                  find ~/records/"$YEAR" -type f -name record -exec tail -1 {} ;


                  This would be sufficient to print all values of the specified year.



                  To calculate min/max/average pipe the output into awk for the calculation.



                  awk -v stat="$STATISTICS" 'BEGIN { count=0; sum=0; }
                  { if(!count) { min=$0; max=$0; }
                  count++;
                  sum += $0;
                  if($0 > max) max = $0;
                  if($0 < min) min = $0;
                  }
                  END {
                  if(count) {
                  # TODO: use variable "stat" to select only one result to print
                  print min;
                  print sum/count; # average
                  print max;
                  } else {
                  print "no data";
                  }
                  }'


                  You can combine and extend these snippets to get a complete script.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Jan 31 at 16:14

























                  answered Jan 29 at 13:10









                  BodoBodo

                  84818




                  84818

























                      0














                      I have used below command to find the same and it worked fine



                      echo "enter the year"
                      read year

                      find /records/$year/ -maxdepth 3 -type f -iname "filename" -exec sed -n '$p' {} ;| awk 'BEGIN{sum=0}{sum=sum+$1}END{print sum


                      }'






                      share|improve this answer




























                        0














                        I have used below command to find the same and it worked fine



                        echo "enter the year"
                        read year

                        find /records/$year/ -maxdepth 3 -type f -iname "filename" -exec sed -n '$p' {} ;| awk 'BEGIN{sum=0}{sum=sum+$1}END{print sum


                        }'






                        share|improve this answer


























                          0












                          0








                          0







                          I have used below command to find the same and it worked fine



                          echo "enter the year"
                          read year

                          find /records/$year/ -maxdepth 3 -type f -iname "filename" -exec sed -n '$p' {} ;| awk 'BEGIN{sum=0}{sum=sum+$1}END{print sum


                          }'






                          share|improve this answer













                          I have used below command to find the same and it worked fine



                          echo "enter the year"
                          read year

                          find /records/$year/ -maxdepth 3 -type f -iname "filename" -exec sed -n '$p' {} ;| awk 'BEGIN{sum=0}{sum=sum+$1}END{print sum


                          }'







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Jan 29 at 17:00









                          Praveen Kumar BSPraveen Kumar BS

                          1,464138




                          1,464138






























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