Number of occurences of letters in a word?












0















I would like to find out the number of occurrences of each of the alphabets in a word. Eg



input

aabbbddd 


output

a@2 b@3 c@0 d@3


How can I perform this using shell script?










share|improve this question




















  • 1





    Is your input sorted by default?

    – cuonglm
    Nov 17 '14 at 6:28











  • Please clarify your question. Do you need c@0, since that is not a letter within the word?

    – slm
    Nov 17 '14 at 6:35
















0















I would like to find out the number of occurrences of each of the alphabets in a word. Eg



input

aabbbddd 


output

a@2 b@3 c@0 d@3


How can I perform this using shell script?










share|improve this question




















  • 1





    Is your input sorted by default?

    – cuonglm
    Nov 17 '14 at 6:28











  • Please clarify your question. Do you need c@0, since that is not a letter within the word?

    – slm
    Nov 17 '14 at 6:35














0












0








0








I would like to find out the number of occurrences of each of the alphabets in a word. Eg



input

aabbbddd 


output

a@2 b@3 c@0 d@3


How can I perform this using shell script?










share|improve this question
















I would like to find out the number of occurrences of each of the alphabets in a word. Eg



input

aabbbddd 


output

a@2 b@3 c@0 d@3


How can I perform this using shell script?







bash shell shell-script






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 17 '14 at 6:34









slm

250k66527684




250k66527684










asked Nov 17 '14 at 6:14









Rakesh R NairRakesh R Nair

901511




901511








  • 1





    Is your input sorted by default?

    – cuonglm
    Nov 17 '14 at 6:28











  • Please clarify your question. Do you need c@0, since that is not a letter within the word?

    – slm
    Nov 17 '14 at 6:35














  • 1





    Is your input sorted by default?

    – cuonglm
    Nov 17 '14 at 6:28











  • Please clarify your question. Do you need c@0, since that is not a letter within the word?

    – slm
    Nov 17 '14 at 6:35








1




1





Is your input sorted by default?

– cuonglm
Nov 17 '14 at 6:28





Is your input sorted by default?

– cuonglm
Nov 17 '14 at 6:28













Please clarify your question. Do you need c@0, since that is not a letter within the word?

– slm
Nov 17 '14 at 6:35





Please clarify your question. Do you need c@0, since that is not a letter within the word?

– slm
Nov 17 '14 at 6:35










3 Answers
3






active

oldest

votes


















2














These solutions are case-insensitive:



start cmd:> echo aabbbddd | 
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {for (key in a) print key ": " a[key];}'
a: 2
b: 3
d: 3


Or for the complete alphabet:



start cmd:> echo Aabbbddd | 
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {chars="abcdefghijklmnopqrstuvwxyz";
for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
a: 2
b: 3
c:
d: 3
e:
f:
g:
h:
i:
j:
k:
l:
m:
n:
o:
p:
q:
r:
s:
t:
u:
v:
w:
x:
y:
z:





share|improve this answer





















  • 1





    The output is missing c as OP's desired output.

    – cuonglm
    Nov 17 '14 at 6:31



















4














You could use sed, uniq, and sort:



$ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
2 a
3 b
3 d


The above uses sed to take each character and replace it with itself + a newline (n). Now with each character on a newline (and sorted) you can use uniq -c to count the characters.



NOTE: This method will not show any of the characters in between that have zero occurrences.



Alternatively showing each letter's count



$ s="aabbbddd"; for i in {a..z}; do
v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
a : 2
b : 3
c : 0
d : 3
e : 0
f : 0
g : 0
h : 0
i : 0
j : 0
k : 0
l : 0
m : 0
n : 0
o : 0
p : 0
q : 0
r : 0
s : 0
t : 0
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0


This works by looping through all the letters of the alphabet:



 for i in {a..z}; do .... ; done


Each iteration of the loop we grep through the string looking for a specific character, and use the -o option of grep to only return these matches. We then use wc -l to count how many occurrences of each letter we found, and store it in variable $v. We then display each iteration:



 echo "$i : $v"


NOTE: This approach can handle the strings being out of order.






share|improve this answer

































    0














    Using only the shell (faster for short strings):



    #! /bin/bash -
    input=${*:-'aabbbddd'}

    tmp=$input
    arr=()
    maxlen=0
    maxchar=''
    while ((${#tmp})); do
    firstchar=${tmp:0:1}
    next=${tmp//"$firstchar"}
    len=$((${#tmp}-${#next}))
    arr+=("$firstchar: $len")
    if ((maxlen<len)); then
    maxlen=$len
    maxchar=$firstchar
    fi
    tmp=$next
    done

    printf '%sn' "${arr[@]}"
    echo "The char "$maxchar" appear $maxlen times in "$input""


    Called as:



    $ ./script
    a@2 b@3 d@3
    The char "b" appear 3 times in "aabbbddd"





    share|improve this answer























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      These solutions are case-insensitive:



      start cmd:> echo aabbbddd | 
      awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
      END {for (key in a) print key ": " a[key];}'
      a: 2
      b: 3
      d: 3


      Or for the complete alphabet:



      start cmd:> echo Aabbbddd | 
      awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
      END {chars="abcdefghijklmnopqrstuvwxyz";
      for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
      a: 2
      b: 3
      c:
      d: 3
      e:
      f:
      g:
      h:
      i:
      j:
      k:
      l:
      m:
      n:
      o:
      p:
      q:
      r:
      s:
      t:
      u:
      v:
      w:
      x:
      y:
      z:





      share|improve this answer





















      • 1





        The output is missing c as OP's desired output.

        – cuonglm
        Nov 17 '14 at 6:31
















      2














      These solutions are case-insensitive:



      start cmd:> echo aabbbddd | 
      awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
      END {for (key in a) print key ": " a[key];}'
      a: 2
      b: 3
      d: 3


      Or for the complete alphabet:



      start cmd:> echo Aabbbddd | 
      awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
      END {chars="abcdefghijklmnopqrstuvwxyz";
      for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
      a: 2
      b: 3
      c:
      d: 3
      e:
      f:
      g:
      h:
      i:
      j:
      k:
      l:
      m:
      n:
      o:
      p:
      q:
      r:
      s:
      t:
      u:
      v:
      w:
      x:
      y:
      z:





      share|improve this answer





















      • 1





        The output is missing c as OP's desired output.

        – cuonglm
        Nov 17 '14 at 6:31














      2












      2








      2







      These solutions are case-insensitive:



      start cmd:> echo aabbbddd | 
      awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
      END {for (key in a) print key ": " a[key];}'
      a: 2
      b: 3
      d: 3


      Or for the complete alphabet:



      start cmd:> echo Aabbbddd | 
      awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
      END {chars="abcdefghijklmnopqrstuvwxyz";
      for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
      a: 2
      b: 3
      c:
      d: 3
      e:
      f:
      g:
      h:
      i:
      j:
      k:
      l:
      m:
      n:
      o:
      p:
      q:
      r:
      s:
      t:
      u:
      v:
      w:
      x:
      y:
      z:





      share|improve this answer















      These solutions are case-insensitive:



      start cmd:> echo aabbbddd | 
      awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
      END {for (key in a) print key ": " a[key];}'
      a: 2
      b: 3
      d: 3


      Or for the complete alphabet:



      start cmd:> echo Aabbbddd | 
      awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
      END {chars="abcdefghijklmnopqrstuvwxyz";
      for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
      a: 2
      b: 3
      c:
      d: 3
      e:
      f:
      g:
      h:
      i:
      j:
      k:
      l:
      m:
      n:
      o:
      p:
      q:
      r:
      s:
      t:
      u:
      v:
      w:
      x:
      y:
      z:






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 17 '14 at 15:42

























      answered Nov 17 '14 at 6:27









      Hauke LagingHauke Laging

      56.5k1285135




      56.5k1285135








      • 1





        The output is missing c as OP's desired output.

        – cuonglm
        Nov 17 '14 at 6:31














      • 1





        The output is missing c as OP's desired output.

        – cuonglm
        Nov 17 '14 at 6:31








      1




      1





      The output is missing c as OP's desired output.

      – cuonglm
      Nov 17 '14 at 6:31





      The output is missing c as OP's desired output.

      – cuonglm
      Nov 17 '14 at 6:31













      4














      You could use sed, uniq, and sort:



      $ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
      2 a
      3 b
      3 d


      The above uses sed to take each character and replace it with itself + a newline (n). Now with each character on a newline (and sorted) you can use uniq -c to count the characters.



      NOTE: This method will not show any of the characters in between that have zero occurrences.



      Alternatively showing each letter's count



      $ s="aabbbddd"; for i in {a..z}; do
      v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
      a : 2
      b : 3
      c : 0
      d : 3
      e : 0
      f : 0
      g : 0
      h : 0
      i : 0
      j : 0
      k : 0
      l : 0
      m : 0
      n : 0
      o : 0
      p : 0
      q : 0
      r : 0
      s : 0
      t : 0
      u : 0
      v : 0
      w : 0
      x : 0
      y : 0
      z : 0


      This works by looping through all the letters of the alphabet:



       for i in {a..z}; do .... ; done


      Each iteration of the loop we grep through the string looking for a specific character, and use the -o option of grep to only return these matches. We then use wc -l to count how many occurrences of each letter we found, and store it in variable $v. We then display each iteration:



       echo "$i : $v"


      NOTE: This approach can handle the strings being out of order.






      share|improve this answer






























        4














        You could use sed, uniq, and sort:



        $ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
        2 a
        3 b
        3 d


        The above uses sed to take each character and replace it with itself + a newline (n). Now with each character on a newline (and sorted) you can use uniq -c to count the characters.



        NOTE: This method will not show any of the characters in between that have zero occurrences.



        Alternatively showing each letter's count



        $ s="aabbbddd"; for i in {a..z}; do
        v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
        a : 2
        b : 3
        c : 0
        d : 3
        e : 0
        f : 0
        g : 0
        h : 0
        i : 0
        j : 0
        k : 0
        l : 0
        m : 0
        n : 0
        o : 0
        p : 0
        q : 0
        r : 0
        s : 0
        t : 0
        u : 0
        v : 0
        w : 0
        x : 0
        y : 0
        z : 0


        This works by looping through all the letters of the alphabet:



         for i in {a..z}; do .... ; done


        Each iteration of the loop we grep through the string looking for a specific character, and use the -o option of grep to only return these matches. We then use wc -l to count how many occurrences of each letter we found, and store it in variable $v. We then display each iteration:



         echo "$i : $v"


        NOTE: This approach can handle the strings being out of order.






        share|improve this answer




























          4












          4








          4







          You could use sed, uniq, and sort:



          $ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
          2 a
          3 b
          3 d


          The above uses sed to take each character and replace it with itself + a newline (n). Now with each character on a newline (and sorted) you can use uniq -c to count the characters.



          NOTE: This method will not show any of the characters in between that have zero occurrences.



          Alternatively showing each letter's count



          $ s="aabbbddd"; for i in {a..z}; do
          v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
          a : 2
          b : 3
          c : 0
          d : 3
          e : 0
          f : 0
          g : 0
          h : 0
          i : 0
          j : 0
          k : 0
          l : 0
          m : 0
          n : 0
          o : 0
          p : 0
          q : 0
          r : 0
          s : 0
          t : 0
          u : 0
          v : 0
          w : 0
          x : 0
          y : 0
          z : 0


          This works by looping through all the letters of the alphabet:



           for i in {a..z}; do .... ; done


          Each iteration of the loop we grep through the string looking for a specific character, and use the -o option of grep to only return these matches. We then use wc -l to count how many occurrences of each letter we found, and store it in variable $v. We then display each iteration:



           echo "$i : $v"


          NOTE: This approach can handle the strings being out of order.






          share|improve this answer















          You could use sed, uniq, and sort:



          $ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
          2 a
          3 b
          3 d


          The above uses sed to take each character and replace it with itself + a newline (n). Now with each character on a newline (and sorted) you can use uniq -c to count the characters.



          NOTE: This method will not show any of the characters in between that have zero occurrences.



          Alternatively showing each letter's count



          $ s="aabbbddd"; for i in {a..z}; do
          v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
          a : 2
          b : 3
          c : 0
          d : 3
          e : 0
          f : 0
          g : 0
          h : 0
          i : 0
          j : 0
          k : 0
          l : 0
          m : 0
          n : 0
          o : 0
          p : 0
          q : 0
          r : 0
          s : 0
          t : 0
          u : 0
          v : 0
          w : 0
          x : 0
          y : 0
          z : 0


          This works by looping through all the letters of the alphabet:



           for i in {a..z}; do .... ; done


          Each iteration of the loop we grep through the string looking for a specific character, and use the -o option of grep to only return these matches. We then use wc -l to count how many occurrences of each letter we found, and store it in variable $v. We then display each iteration:



           echo "$i : $v"


          NOTE: This approach can handle the strings being out of order.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 17 '14 at 6:51

























          answered Nov 17 '14 at 6:32









          slmslm

          250k66527684




          250k66527684























              0














              Using only the shell (faster for short strings):



              #! /bin/bash -
              input=${*:-'aabbbddd'}

              tmp=$input
              arr=()
              maxlen=0
              maxchar=''
              while ((${#tmp})); do
              firstchar=${tmp:0:1}
              next=${tmp//"$firstchar"}
              len=$((${#tmp}-${#next}))
              arr+=("$firstchar: $len")
              if ((maxlen<len)); then
              maxlen=$len
              maxchar=$firstchar
              fi
              tmp=$next
              done

              printf '%sn' "${arr[@]}"
              echo "The char "$maxchar" appear $maxlen times in "$input""


              Called as:



              $ ./script
              a@2 b@3 d@3
              The char "b" appear 3 times in "aabbbddd"





              share|improve this answer




























                0














                Using only the shell (faster for short strings):



                #! /bin/bash -
                input=${*:-'aabbbddd'}

                tmp=$input
                arr=()
                maxlen=0
                maxchar=''
                while ((${#tmp})); do
                firstchar=${tmp:0:1}
                next=${tmp//"$firstchar"}
                len=$((${#tmp}-${#next}))
                arr+=("$firstchar: $len")
                if ((maxlen<len)); then
                maxlen=$len
                maxchar=$firstchar
                fi
                tmp=$next
                done

                printf '%sn' "${arr[@]}"
                echo "The char "$maxchar" appear $maxlen times in "$input""


                Called as:



                $ ./script
                a@2 b@3 d@3
                The char "b" appear 3 times in "aabbbddd"





                share|improve this answer


























                  0












                  0








                  0







                  Using only the shell (faster for short strings):



                  #! /bin/bash -
                  input=${*:-'aabbbddd'}

                  tmp=$input
                  arr=()
                  maxlen=0
                  maxchar=''
                  while ((${#tmp})); do
                  firstchar=${tmp:0:1}
                  next=${tmp//"$firstchar"}
                  len=$((${#tmp}-${#next}))
                  arr+=("$firstchar: $len")
                  if ((maxlen<len)); then
                  maxlen=$len
                  maxchar=$firstchar
                  fi
                  tmp=$next
                  done

                  printf '%sn' "${arr[@]}"
                  echo "The char "$maxchar" appear $maxlen times in "$input""


                  Called as:



                  $ ./script
                  a@2 b@3 d@3
                  The char "b" appear 3 times in "aabbbddd"





                  share|improve this answer













                  Using only the shell (faster for short strings):



                  #! /bin/bash -
                  input=${*:-'aabbbddd'}

                  tmp=$input
                  arr=()
                  maxlen=0
                  maxchar=''
                  while ((${#tmp})); do
                  firstchar=${tmp:0:1}
                  next=${tmp//"$firstchar"}
                  len=$((${#tmp}-${#next}))
                  arr+=("$firstchar: $len")
                  if ((maxlen<len)); then
                  maxlen=$len
                  maxchar=$firstchar
                  fi
                  tmp=$next
                  done

                  printf '%sn' "${arr[@]}"
                  echo "The char "$maxchar" appear $maxlen times in "$input""


                  Called as:



                  $ ./script
                  a@2 b@3 d@3
                  The char "b" appear 3 times in "aabbbddd"






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Jan 27 at 5:34









                  IsaacIsaac

                  11.8k11752




                  11.8k11752






























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