How can I search a specific list of files with ripgrep?












-1















I've got a list of files that I would like to search for a pattern with ripgrep.



How can this be done?










share|improve this question



























    -1















    I've got a list of files that I would like to search for a pattern with ripgrep.



    How can this be done?










    share|improve this question

























      -1












      -1








      -1








      I've got a list of files that I would like to search for a pattern with ripgrep.



      How can this be done?










      share|improve this question














      I've got a list of files that I would like to search for a pattern with ripgrep.



      How can this be done?







      ripgrep






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Jan 15 at 12:32









      Chris StryczynskiChris Stryczynski

      574419




      574419






















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          ripgrep accepts file paths as arguments. So just pass your files as arguments:



          rg pattern file1 file2 ...


          If your list is in a file, with one path per line, then use xargs:



          xargs -d 'n' -a list-file rg pattern


          Or if it's a list generated from find, then:



          find ./ ... -print0 | xargs -0 rg pattern





          share|improve this answer








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            1 Answer
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            active

            oldest

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            1














            ripgrep accepts file paths as arguments. So just pass your files as arguments:



            rg pattern file1 file2 ...


            If your list is in a file, with one path per line, then use xargs:



            xargs -d 'n' -a list-file rg pattern


            Or if it's a list generated from find, then:



            find ./ ... -print0 | xargs -0 rg pattern





            share|improve this answer








            New contributor




            BurntSushi5 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.

























              1














              ripgrep accepts file paths as arguments. So just pass your files as arguments:



              rg pattern file1 file2 ...


              If your list is in a file, with one path per line, then use xargs:



              xargs -d 'n' -a list-file rg pattern


              Or if it's a list generated from find, then:



              find ./ ... -print0 | xargs -0 rg pattern





              share|improve this answer








              New contributor




              BurntSushi5 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.























                1












                1








                1







                ripgrep accepts file paths as arguments. So just pass your files as arguments:



                rg pattern file1 file2 ...


                If your list is in a file, with one path per line, then use xargs:



                xargs -d 'n' -a list-file rg pattern


                Or if it's a list generated from find, then:



                find ./ ... -print0 | xargs -0 rg pattern





                share|improve this answer








                New contributor




                BurntSushi5 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.










                ripgrep accepts file paths as arguments. So just pass your files as arguments:



                rg pattern file1 file2 ...


                If your list is in a file, with one path per line, then use xargs:



                xargs -d 'n' -a list-file rg pattern


                Or if it's a list generated from find, then:



                find ./ ... -print0 | xargs -0 rg pattern






                share|improve this answer








                New contributor




                BurntSushi5 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                share|improve this answer



                share|improve this answer






                New contributor




                BurntSushi5 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                answered Jan 15 at 21:44









                BurntSushi5BurntSushi5

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                New contributor





                BurntSushi5 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                BurntSushi5 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






























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