A planet that cannot be orbited [duplicate]
$begingroup$
This question already has an answer here:
A moon that is hard to orbit
4 answers
I'm wondering if it is possible for a planet to be impossible to orbit stably over a significant length of time. The shorter the length of time the planet can be orbited for, the better. It should be possible to land on the planet, just not to maintain an orbit around it without the requirement for near-constant fuel expenditure for stationkeeping purposes.
What mechanism could cause the planet to be almost impossible to orbit for more than a few orbital periods?
reality-check spaceships hard-science orbital-mechanics
$endgroup$
marked as duplicate by Renan, Mołot, JBH, Community♦ 1 hour ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
$begingroup$
This question already has an answer here:
A moon that is hard to orbit
4 answers
I'm wondering if it is possible for a planet to be impossible to orbit stably over a significant length of time. The shorter the length of time the planet can be orbited for, the better. It should be possible to land on the planet, just not to maintain an orbit around it without the requirement for near-constant fuel expenditure for stationkeeping purposes.
What mechanism could cause the planet to be almost impossible to orbit for more than a few orbital periods?
reality-check spaceships hard-science orbital-mechanics
$endgroup$
marked as duplicate by Renan, Mołot, JBH, Community♦ 1 hour ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
$begingroup$
Orbit at any altitude?
$endgroup$
– Alexander
5 hours ago
$begingroup$
At any altitude or any inclination, ideally.
$endgroup$
– Gryphon
4 hours ago
$begingroup$
I would imagine a rogue planet that's spinning randomly without an axis could be a candidate for an "unorbitable" planet due to it's unstable/inconsistent gravity. Though since there's a hard-science tag, I don't really have the proof or numbers to prove this.
$endgroup$
– Basher
4 hours ago
add a comment |
$begingroup$
This question already has an answer here:
A moon that is hard to orbit
4 answers
I'm wondering if it is possible for a planet to be impossible to orbit stably over a significant length of time. The shorter the length of time the planet can be orbited for, the better. It should be possible to land on the planet, just not to maintain an orbit around it without the requirement for near-constant fuel expenditure for stationkeeping purposes.
What mechanism could cause the planet to be almost impossible to orbit for more than a few orbital periods?
reality-check spaceships hard-science orbital-mechanics
$endgroup$
This question already has an answer here:
A moon that is hard to orbit
4 answers
I'm wondering if it is possible for a planet to be impossible to orbit stably over a significant length of time. The shorter the length of time the planet can be orbited for, the better. It should be possible to land on the planet, just not to maintain an orbit around it without the requirement for near-constant fuel expenditure for stationkeeping purposes.
What mechanism could cause the planet to be almost impossible to orbit for more than a few orbital periods?
This question already has an answer here:
A moon that is hard to orbit
4 answers
reality-check spaceships hard-science orbital-mechanics
reality-check spaceships hard-science orbital-mechanics
asked 5 hours ago
GryphonGryphon
3,11222354
3,11222354
marked as duplicate by Renan, Mołot, JBH, Community♦ 1 hour ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Renan, Mołot, JBH, Community♦ 1 hour ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
$begingroup$
Orbit at any altitude?
$endgroup$
– Alexander
5 hours ago
$begingroup$
At any altitude or any inclination, ideally.
$endgroup$
– Gryphon
4 hours ago
$begingroup$
I would imagine a rogue planet that's spinning randomly without an axis could be a candidate for an "unorbitable" planet due to it's unstable/inconsistent gravity. Though since there's a hard-science tag, I don't really have the proof or numbers to prove this.
$endgroup$
– Basher
4 hours ago
add a comment |
$begingroup$
Orbit at any altitude?
$endgroup$
– Alexander
5 hours ago
$begingroup$
At any altitude or any inclination, ideally.
$endgroup$
– Gryphon
4 hours ago
$begingroup$
I would imagine a rogue planet that's spinning randomly without an axis could be a candidate for an "unorbitable" planet due to it's unstable/inconsistent gravity. Though since there's a hard-science tag, I don't really have the proof or numbers to prove this.
$endgroup$
– Basher
4 hours ago
$begingroup$
Orbit at any altitude?
$endgroup$
– Alexander
5 hours ago
$begingroup$
Orbit at any altitude?
$endgroup$
– Alexander
5 hours ago
$begingroup$
At any altitude or any inclination, ideally.
$endgroup$
– Gryphon
4 hours ago
$begingroup$
At any altitude or any inclination, ideally.
$endgroup$
– Gryphon
4 hours ago
$begingroup$
I would imagine a rogue planet that's spinning randomly without an axis could be a candidate for an "unorbitable" planet due to it's unstable/inconsistent gravity. Though since there's a hard-science tag, I don't really have the proof or numbers to prove this.
$endgroup$
– Basher
4 hours ago
$begingroup$
I would imagine a rogue planet that's spinning randomly without an axis could be a candidate for an "unorbitable" planet due to it's unstable/inconsistent gravity. Though since there's a hard-science tag, I don't really have the proof or numbers to prove this.
$endgroup$
– Basher
4 hours ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
The simplest answer that comes to my mind is that the planet is surrounded by a cloud of debris (micrometeorites).
These are usually quite small, so can be detected only some minutes before the impact and follow very different orbits, with different inclinations compared to one anothe. So a ship in orbit should continuously maneuver to keep itself safe from impacts, while a landing ship could easily find a free window to cross safely the cloud and land.
The cloud of debris should be recent: in the long run, such a cloud would probably gradually fall onto the surface of the planet because of kinetic energy loss for high atmosphere friction or impacts among the micrometeorites.
Consider also that it is not necessary to have the orbits of the planet "covered" by these micrometeorites: I think that just some tens of thousands of these object, with enough random trajectories, could make orbiting around the planet a risky choice.
Of course the danger would be high only near the planet: probably it would be still possible to orbit it, even from very far.
EDIT
As Fay pointed, a similar scenario is called Kessler syndrome. In such case, the lower orbits would be safer for a ship to orbit (but it would still need to periodically burn its engines in order to correct its orbit because of air drag)
$endgroup$
$begingroup$
Psst, since you've started down this particular line: en.wikipedia.org/wiki/Kessler_syndrome You know you can edit your answer to improve it if you want right?
$endgroup$
– Fay Suggers
4 hours ago
$begingroup$
I think this idea has two problems, one, as Fay said, if only stops you from some orbits and second, it would prevent you from landing on the planet.
$endgroup$
– Etaila
4 hours ago
$begingroup$
@Fay Suggers: Thank you for the suggestion, I've updated the answer
$endgroup$
– McTroopers
4 hours ago
$begingroup$
@Etaila: I think that a landing ship could cross the cloud fast enough to minimize the chances of a collision (the debris would be in any case sparse enough that crossing it would present a far lower danger than staying in orbit for an undefined period of time)
$endgroup$
– McTroopers
4 hours ago
2
$begingroup$
Better than Kessler syndrome, I think, would be a moon that had ventured within its Roche limit and was being torn apart. More debris, in a wider variety of locations, and the moon itself will perturb other bodies' orbits as it passes by making the whole system more chaotic.
$endgroup$
– Cadence
4 hours ago
add a comment |
$begingroup$
Have it orbit very close to a massive body
What you want is a very small Hill sphere, which is the region of space where a particular body's gravitational influence dominates. On the other hand, the celestial body probably will have to become a moon.
If the mass of the smaller body (e.g. Earth) is ${displaystyle}$ m, and it orbits a heavier body (e.g. Sun) of mass ${displaystyle M}$ with a semi-major axis ${displaystyle a}$ and an eccentricity of ${displaystyle e}$, then the radius ${displaystyle r_{mathrm {H} }} $ of the Hill sphere of the smaller body (e.g. Earth) calculated at pericenter is, approximately
${displaystyle r_{mathrm {H} }approx a(1-e){sqrt[{3}]{frac {m}{3M}}}.} $
The above equation means if a satellite orbits a more massive body, it will have a smaller Hill sphere even if the satellite orbit stays the same. There is a limit on how close bodies can orbit each other however. Its called the Roche limit, and objects closer than this limit gets ripped apart by tidal forces.
The Roche limit for a rigid spherical satellite is the distance, ${displaystyle d}$, from the primary at which the gravitational force on a test mass at the surface of the object is exactly equal to the tidal force pulling the mass away from the object:
...
${displaystyle d=R_{m}left(2{frac {M}{m}}right)^{frac {1}{3}}}$
where ${displaystyle R_{m}}$ is the radius of the secondary, ${displaystyle M}$ is the mass of the primary, and ${displaystyle m}$ is the mass of the secondary.
(edited for formatting clarity)
So put your planet-like moon close to the parent body and make the parent body big. That might cause a host of other problems though depending on your story such as massive amounts of radiation, high delta-v cost to get to and from the planet, etc, depending on the details.
$endgroup$
add a comment |
$begingroup$
To orbit a planet the main factor for orbiting a Planet is Mass (gravity of an object) and Speed. The best way would be a multi planet solar system, where the planets orbits are getting close enough to interfere with each others gravity, so orbiting would only be possible for a short time.
However I don't know how the planets themselves could stay in their orbits and not change orbits themselves.
$endgroup$
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The simplest answer that comes to my mind is that the planet is surrounded by a cloud of debris (micrometeorites).
These are usually quite small, so can be detected only some minutes before the impact and follow very different orbits, with different inclinations compared to one anothe. So a ship in orbit should continuously maneuver to keep itself safe from impacts, while a landing ship could easily find a free window to cross safely the cloud and land.
The cloud of debris should be recent: in the long run, such a cloud would probably gradually fall onto the surface of the planet because of kinetic energy loss for high atmosphere friction or impacts among the micrometeorites.
Consider also that it is not necessary to have the orbits of the planet "covered" by these micrometeorites: I think that just some tens of thousands of these object, with enough random trajectories, could make orbiting around the planet a risky choice.
Of course the danger would be high only near the planet: probably it would be still possible to orbit it, even from very far.
EDIT
As Fay pointed, a similar scenario is called Kessler syndrome. In such case, the lower orbits would be safer for a ship to orbit (but it would still need to periodically burn its engines in order to correct its orbit because of air drag)
$endgroup$
$begingroup$
Psst, since you've started down this particular line: en.wikipedia.org/wiki/Kessler_syndrome You know you can edit your answer to improve it if you want right?
$endgroup$
– Fay Suggers
4 hours ago
$begingroup$
I think this idea has two problems, one, as Fay said, if only stops you from some orbits and second, it would prevent you from landing on the planet.
$endgroup$
– Etaila
4 hours ago
$begingroup$
@Fay Suggers: Thank you for the suggestion, I've updated the answer
$endgroup$
– McTroopers
4 hours ago
$begingroup$
@Etaila: I think that a landing ship could cross the cloud fast enough to minimize the chances of a collision (the debris would be in any case sparse enough that crossing it would present a far lower danger than staying in orbit for an undefined period of time)
$endgroup$
– McTroopers
4 hours ago
2
$begingroup$
Better than Kessler syndrome, I think, would be a moon that had ventured within its Roche limit and was being torn apart. More debris, in a wider variety of locations, and the moon itself will perturb other bodies' orbits as it passes by making the whole system more chaotic.
$endgroup$
– Cadence
4 hours ago
add a comment |
$begingroup$
The simplest answer that comes to my mind is that the planet is surrounded by a cloud of debris (micrometeorites).
These are usually quite small, so can be detected only some minutes before the impact and follow very different orbits, with different inclinations compared to one anothe. So a ship in orbit should continuously maneuver to keep itself safe from impacts, while a landing ship could easily find a free window to cross safely the cloud and land.
The cloud of debris should be recent: in the long run, such a cloud would probably gradually fall onto the surface of the planet because of kinetic energy loss for high atmosphere friction or impacts among the micrometeorites.
Consider also that it is not necessary to have the orbits of the planet "covered" by these micrometeorites: I think that just some tens of thousands of these object, with enough random trajectories, could make orbiting around the planet a risky choice.
Of course the danger would be high only near the planet: probably it would be still possible to orbit it, even from very far.
EDIT
As Fay pointed, a similar scenario is called Kessler syndrome. In such case, the lower orbits would be safer for a ship to orbit (but it would still need to periodically burn its engines in order to correct its orbit because of air drag)
$endgroup$
$begingroup$
Psst, since you've started down this particular line: en.wikipedia.org/wiki/Kessler_syndrome You know you can edit your answer to improve it if you want right?
$endgroup$
– Fay Suggers
4 hours ago
$begingroup$
I think this idea has two problems, one, as Fay said, if only stops you from some orbits and second, it would prevent you from landing on the planet.
$endgroup$
– Etaila
4 hours ago
$begingroup$
@Fay Suggers: Thank you for the suggestion, I've updated the answer
$endgroup$
– McTroopers
4 hours ago
$begingroup$
@Etaila: I think that a landing ship could cross the cloud fast enough to minimize the chances of a collision (the debris would be in any case sparse enough that crossing it would present a far lower danger than staying in orbit for an undefined period of time)
$endgroup$
– McTroopers
4 hours ago
2
$begingroup$
Better than Kessler syndrome, I think, would be a moon that had ventured within its Roche limit and was being torn apart. More debris, in a wider variety of locations, and the moon itself will perturb other bodies' orbits as it passes by making the whole system more chaotic.
$endgroup$
– Cadence
4 hours ago
add a comment |
$begingroup$
The simplest answer that comes to my mind is that the planet is surrounded by a cloud of debris (micrometeorites).
These are usually quite small, so can be detected only some minutes before the impact and follow very different orbits, with different inclinations compared to one anothe. So a ship in orbit should continuously maneuver to keep itself safe from impacts, while a landing ship could easily find a free window to cross safely the cloud and land.
The cloud of debris should be recent: in the long run, such a cloud would probably gradually fall onto the surface of the planet because of kinetic energy loss for high atmosphere friction or impacts among the micrometeorites.
Consider also that it is not necessary to have the orbits of the planet "covered" by these micrometeorites: I think that just some tens of thousands of these object, with enough random trajectories, could make orbiting around the planet a risky choice.
Of course the danger would be high only near the planet: probably it would be still possible to orbit it, even from very far.
EDIT
As Fay pointed, a similar scenario is called Kessler syndrome. In such case, the lower orbits would be safer for a ship to orbit (but it would still need to periodically burn its engines in order to correct its orbit because of air drag)
$endgroup$
The simplest answer that comes to my mind is that the planet is surrounded by a cloud of debris (micrometeorites).
These are usually quite small, so can be detected only some minutes before the impact and follow very different orbits, with different inclinations compared to one anothe. So a ship in orbit should continuously maneuver to keep itself safe from impacts, while a landing ship could easily find a free window to cross safely the cloud and land.
The cloud of debris should be recent: in the long run, such a cloud would probably gradually fall onto the surface of the planet because of kinetic energy loss for high atmosphere friction or impacts among the micrometeorites.
Consider also that it is not necessary to have the orbits of the planet "covered" by these micrometeorites: I think that just some tens of thousands of these object, with enough random trajectories, could make orbiting around the planet a risky choice.
Of course the danger would be high only near the planet: probably it would be still possible to orbit it, even from very far.
EDIT
As Fay pointed, a similar scenario is called Kessler syndrome. In such case, the lower orbits would be safer for a ship to orbit (but it would still need to periodically burn its engines in order to correct its orbit because of air drag)
edited 4 hours ago
answered 4 hours ago
McTroopersMcTroopers
2113
2113
$begingroup$
Psst, since you've started down this particular line: en.wikipedia.org/wiki/Kessler_syndrome You know you can edit your answer to improve it if you want right?
$endgroup$
– Fay Suggers
4 hours ago
$begingroup$
I think this idea has two problems, one, as Fay said, if only stops you from some orbits and second, it would prevent you from landing on the planet.
$endgroup$
– Etaila
4 hours ago
$begingroup$
@Fay Suggers: Thank you for the suggestion, I've updated the answer
$endgroup$
– McTroopers
4 hours ago
$begingroup$
@Etaila: I think that a landing ship could cross the cloud fast enough to minimize the chances of a collision (the debris would be in any case sparse enough that crossing it would present a far lower danger than staying in orbit for an undefined period of time)
$endgroup$
– McTroopers
4 hours ago
2
$begingroup$
Better than Kessler syndrome, I think, would be a moon that had ventured within its Roche limit and was being torn apart. More debris, in a wider variety of locations, and the moon itself will perturb other bodies' orbits as it passes by making the whole system more chaotic.
$endgroup$
– Cadence
4 hours ago
add a comment |
$begingroup$
Psst, since you've started down this particular line: en.wikipedia.org/wiki/Kessler_syndrome You know you can edit your answer to improve it if you want right?
$endgroup$
– Fay Suggers
4 hours ago
$begingroup$
I think this idea has two problems, one, as Fay said, if only stops you from some orbits and second, it would prevent you from landing on the planet.
$endgroup$
– Etaila
4 hours ago
$begingroup$
@Fay Suggers: Thank you for the suggestion, I've updated the answer
$endgroup$
– McTroopers
4 hours ago
$begingroup$
@Etaila: I think that a landing ship could cross the cloud fast enough to minimize the chances of a collision (the debris would be in any case sparse enough that crossing it would present a far lower danger than staying in orbit for an undefined period of time)
$endgroup$
– McTroopers
4 hours ago
2
$begingroup$
Better than Kessler syndrome, I think, would be a moon that had ventured within its Roche limit and was being torn apart. More debris, in a wider variety of locations, and the moon itself will perturb other bodies' orbits as it passes by making the whole system more chaotic.
$endgroup$
– Cadence
4 hours ago
$begingroup$
Psst, since you've started down this particular line: en.wikipedia.org/wiki/Kessler_syndrome You know you can edit your answer to improve it if you want right?
$endgroup$
– Fay Suggers
4 hours ago
$begingroup$
Psst, since you've started down this particular line: en.wikipedia.org/wiki/Kessler_syndrome You know you can edit your answer to improve it if you want right?
$endgroup$
– Fay Suggers
4 hours ago
$begingroup$
I think this idea has two problems, one, as Fay said, if only stops you from some orbits and second, it would prevent you from landing on the planet.
$endgroup$
– Etaila
4 hours ago
$begingroup$
I think this idea has two problems, one, as Fay said, if only stops you from some orbits and second, it would prevent you from landing on the planet.
$endgroup$
– Etaila
4 hours ago
$begingroup$
@Fay Suggers: Thank you for the suggestion, I've updated the answer
$endgroup$
– McTroopers
4 hours ago
$begingroup$
@Fay Suggers: Thank you for the suggestion, I've updated the answer
$endgroup$
– McTroopers
4 hours ago
$begingroup$
@Etaila: I think that a landing ship could cross the cloud fast enough to minimize the chances of a collision (the debris would be in any case sparse enough that crossing it would present a far lower danger than staying in orbit for an undefined period of time)
$endgroup$
– McTroopers
4 hours ago
$begingroup$
@Etaila: I think that a landing ship could cross the cloud fast enough to minimize the chances of a collision (the debris would be in any case sparse enough that crossing it would present a far lower danger than staying in orbit for an undefined period of time)
$endgroup$
– McTroopers
4 hours ago
2
2
$begingroup$
Better than Kessler syndrome, I think, would be a moon that had ventured within its Roche limit and was being torn apart. More debris, in a wider variety of locations, and the moon itself will perturb other bodies' orbits as it passes by making the whole system more chaotic.
$endgroup$
– Cadence
4 hours ago
$begingroup$
Better than Kessler syndrome, I think, would be a moon that had ventured within its Roche limit and was being torn apart. More debris, in a wider variety of locations, and the moon itself will perturb other bodies' orbits as it passes by making the whole system more chaotic.
$endgroup$
– Cadence
4 hours ago
add a comment |
$begingroup$
Have it orbit very close to a massive body
What you want is a very small Hill sphere, which is the region of space where a particular body's gravitational influence dominates. On the other hand, the celestial body probably will have to become a moon.
If the mass of the smaller body (e.g. Earth) is ${displaystyle}$ m, and it orbits a heavier body (e.g. Sun) of mass ${displaystyle M}$ with a semi-major axis ${displaystyle a}$ and an eccentricity of ${displaystyle e}$, then the radius ${displaystyle r_{mathrm {H} }} $ of the Hill sphere of the smaller body (e.g. Earth) calculated at pericenter is, approximately
${displaystyle r_{mathrm {H} }approx a(1-e){sqrt[{3}]{frac {m}{3M}}}.} $
The above equation means if a satellite orbits a more massive body, it will have a smaller Hill sphere even if the satellite orbit stays the same. There is a limit on how close bodies can orbit each other however. Its called the Roche limit, and objects closer than this limit gets ripped apart by tidal forces.
The Roche limit for a rigid spherical satellite is the distance, ${displaystyle d}$, from the primary at which the gravitational force on a test mass at the surface of the object is exactly equal to the tidal force pulling the mass away from the object:
...
${displaystyle d=R_{m}left(2{frac {M}{m}}right)^{frac {1}{3}}}$
where ${displaystyle R_{m}}$ is the radius of the secondary, ${displaystyle M}$ is the mass of the primary, and ${displaystyle m}$ is the mass of the secondary.
(edited for formatting clarity)
So put your planet-like moon close to the parent body and make the parent body big. That might cause a host of other problems though depending on your story such as massive amounts of radiation, high delta-v cost to get to and from the planet, etc, depending on the details.
$endgroup$
add a comment |
$begingroup$
Have it orbit very close to a massive body
What you want is a very small Hill sphere, which is the region of space where a particular body's gravitational influence dominates. On the other hand, the celestial body probably will have to become a moon.
If the mass of the smaller body (e.g. Earth) is ${displaystyle}$ m, and it orbits a heavier body (e.g. Sun) of mass ${displaystyle M}$ with a semi-major axis ${displaystyle a}$ and an eccentricity of ${displaystyle e}$, then the radius ${displaystyle r_{mathrm {H} }} $ of the Hill sphere of the smaller body (e.g. Earth) calculated at pericenter is, approximately
${displaystyle r_{mathrm {H} }approx a(1-e){sqrt[{3}]{frac {m}{3M}}}.} $
The above equation means if a satellite orbits a more massive body, it will have a smaller Hill sphere even if the satellite orbit stays the same. There is a limit on how close bodies can orbit each other however. Its called the Roche limit, and objects closer than this limit gets ripped apart by tidal forces.
The Roche limit for a rigid spherical satellite is the distance, ${displaystyle d}$, from the primary at which the gravitational force on a test mass at the surface of the object is exactly equal to the tidal force pulling the mass away from the object:
...
${displaystyle d=R_{m}left(2{frac {M}{m}}right)^{frac {1}{3}}}$
where ${displaystyle R_{m}}$ is the radius of the secondary, ${displaystyle M}$ is the mass of the primary, and ${displaystyle m}$ is the mass of the secondary.
(edited for formatting clarity)
So put your planet-like moon close to the parent body and make the parent body big. That might cause a host of other problems though depending on your story such as massive amounts of radiation, high delta-v cost to get to and from the planet, etc, depending on the details.
$endgroup$
add a comment |
$begingroup$
Have it orbit very close to a massive body
What you want is a very small Hill sphere, which is the region of space where a particular body's gravitational influence dominates. On the other hand, the celestial body probably will have to become a moon.
If the mass of the smaller body (e.g. Earth) is ${displaystyle}$ m, and it orbits a heavier body (e.g. Sun) of mass ${displaystyle M}$ with a semi-major axis ${displaystyle a}$ and an eccentricity of ${displaystyle e}$, then the radius ${displaystyle r_{mathrm {H} }} $ of the Hill sphere of the smaller body (e.g. Earth) calculated at pericenter is, approximately
${displaystyle r_{mathrm {H} }approx a(1-e){sqrt[{3}]{frac {m}{3M}}}.} $
The above equation means if a satellite orbits a more massive body, it will have a smaller Hill sphere even if the satellite orbit stays the same. There is a limit on how close bodies can orbit each other however. Its called the Roche limit, and objects closer than this limit gets ripped apart by tidal forces.
The Roche limit for a rigid spherical satellite is the distance, ${displaystyle d}$, from the primary at which the gravitational force on a test mass at the surface of the object is exactly equal to the tidal force pulling the mass away from the object:
...
${displaystyle d=R_{m}left(2{frac {M}{m}}right)^{frac {1}{3}}}$
where ${displaystyle R_{m}}$ is the radius of the secondary, ${displaystyle M}$ is the mass of the primary, and ${displaystyle m}$ is the mass of the secondary.
(edited for formatting clarity)
So put your planet-like moon close to the parent body and make the parent body big. That might cause a host of other problems though depending on your story such as massive amounts of radiation, high delta-v cost to get to and from the planet, etc, depending on the details.
$endgroup$
Have it orbit very close to a massive body
What you want is a very small Hill sphere, which is the region of space where a particular body's gravitational influence dominates. On the other hand, the celestial body probably will have to become a moon.
If the mass of the smaller body (e.g. Earth) is ${displaystyle}$ m, and it orbits a heavier body (e.g. Sun) of mass ${displaystyle M}$ with a semi-major axis ${displaystyle a}$ and an eccentricity of ${displaystyle e}$, then the radius ${displaystyle r_{mathrm {H} }} $ of the Hill sphere of the smaller body (e.g. Earth) calculated at pericenter is, approximately
${displaystyle r_{mathrm {H} }approx a(1-e){sqrt[{3}]{frac {m}{3M}}}.} $
The above equation means if a satellite orbits a more massive body, it will have a smaller Hill sphere even if the satellite orbit stays the same. There is a limit on how close bodies can orbit each other however. Its called the Roche limit, and objects closer than this limit gets ripped apart by tidal forces.
The Roche limit for a rigid spherical satellite is the distance, ${displaystyle d}$, from the primary at which the gravitational force on a test mass at the surface of the object is exactly equal to the tidal force pulling the mass away from the object:
...
${displaystyle d=R_{m}left(2{frac {M}{m}}right)^{frac {1}{3}}}$
where ${displaystyle R_{m}}$ is the radius of the secondary, ${displaystyle M}$ is the mass of the primary, and ${displaystyle m}$ is the mass of the secondary.
(edited for formatting clarity)
So put your planet-like moon close to the parent body and make the parent body big. That might cause a host of other problems though depending on your story such as massive amounts of radiation, high delta-v cost to get to and from the planet, etc, depending on the details.
answered 3 hours ago
0something00something0
77018
77018
add a comment |
add a comment |
$begingroup$
To orbit a planet the main factor for orbiting a Planet is Mass (gravity of an object) and Speed. The best way would be a multi planet solar system, where the planets orbits are getting close enough to interfere with each others gravity, so orbiting would only be possible for a short time.
However I don't know how the planets themselves could stay in their orbits and not change orbits themselves.
$endgroup$
add a comment |
$begingroup$
To orbit a planet the main factor for orbiting a Planet is Mass (gravity of an object) and Speed. The best way would be a multi planet solar system, where the planets orbits are getting close enough to interfere with each others gravity, so orbiting would only be possible for a short time.
However I don't know how the planets themselves could stay in their orbits and not change orbits themselves.
$endgroup$
add a comment |
$begingroup$
To orbit a planet the main factor for orbiting a Planet is Mass (gravity of an object) and Speed. The best way would be a multi planet solar system, where the planets orbits are getting close enough to interfere with each others gravity, so orbiting would only be possible for a short time.
However I don't know how the planets themselves could stay in their orbits and not change orbits themselves.
$endgroup$
To orbit a planet the main factor for orbiting a Planet is Mass (gravity of an object) and Speed. The best way would be a multi planet solar system, where the planets orbits are getting close enough to interfere with each others gravity, so orbiting would only be possible for a short time.
However I don't know how the planets themselves could stay in their orbits and not change orbits themselves.
answered 4 hours ago
EtailaEtaila
718312
718312
add a comment |
add a comment |
$begingroup$
Orbit at any altitude?
$endgroup$
– Alexander
5 hours ago
$begingroup$
At any altitude or any inclination, ideally.
$endgroup$
– Gryphon
4 hours ago
$begingroup$
I would imagine a rogue planet that's spinning randomly without an axis could be a candidate for an "unorbitable" planet due to it's unstable/inconsistent gravity. Though since there's a hard-science tag, I don't really have the proof or numbers to prove this.
$endgroup$
– Basher
4 hours ago