Definition of Statistic
$begingroup$
I keep seeing conflicting definitions of a statistic. Is a statistic a random variable such that it is a function of the random variables of a random sample? Or is it the value of the function of the random sample, after each random variable of the random sample has taken on a specific value?
$$(1) S=f(X_1,X_2...X_n)$$
$$(2) s=f(x_1,x_2...x_n)$$
I haven't been able to get any clarification for this and I've seen the term statistic describe both situations
estimation sampling inference random-variable interpretation
asked 8 hours ago
Colin HicksColin Hicks
1183
New contributor
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I keep seeing conflicting definitions of a statistic. Is a statistic a random variable such that it is a function of the random variables of a random sample? Or is it the value of the function of the random sample, after each random variable of the random sample has taken on a specific value?
$$(1) S=f(X_1,X_2...X_n)$$
$$(2) s=f(x_1,x_2...x_n)$$
I haven't been able to get any clarification for this and I've seen the term statistic describe both situations
estimation sampling inference random-variable interpretation
asked 8 hours ago
Colin HicksColin Hicks
1183
New contributor
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
It seems that there are also plenty of conflicting views on estimator and estimate which go hand in hand with this. As an estimator is supposed to be a kind of statistic, whether an estimator is a random variable or not would also clarify some things. There seems to be a lot of conflicting definitions on this site though.
$endgroup$
– Colin Hicks
7 hours ago
add a comment |
$begingroup$
I keep seeing conflicting definitions of a statistic. Is a statistic a random variable such that it is a function of the random variables of a random sample? Or is it the value of the function of the random sample, after each random variable of the random sample has taken on a specific value?
$$(1) S=f(X_1,X_2...X_n)$$
$$(2) s=f(x_1,x_2...x_n)$$
I haven't been able to get any clarification for this and I've seen the term statistic describe both situations
estimation sampling inference random-variable interpretation
asked 8 hours ago
Colin HicksColin Hicks
1183
New contributor
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I keep seeing conflicting definitions of a statistic. Is a statistic a random variable such that it is a function of the random variables of a random sample? Or is it the value of the function of the random sample, after each random variable of the random sample has taken on a specific value?
$$(1) S=f(X_1,X_2...X_n)$$
$$(2) s=f(x_1,x_2...x_n)$$
I haven't been able to get any clarification for this and I've seen the term statistic describe both situations
estimation sampling inference random-variable interpretation
estimation sampling inference random-variable interpretation
asked 8 hours ago
Colin HicksColin Hicks
1183
New contributor
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
Colin HicksColin Hicks
1183
New contributor
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
Colin HicksColin Hicks
1183
New contributor
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
Colin HicksColin Hicks
1183
asked 8 hours ago
Colin HicksColin Hicks
1183
1183
New contributor
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Colin Hicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
It seems that there are also plenty of conflicting views on estimator and estimate which go hand in hand with this. As an estimator is supposed to be a kind of statistic, whether an estimator is a random variable or not would also clarify some things. There seems to be a lot of conflicting definitions on this site though.
$endgroup$
– Colin Hicks
7 hours ago
add a comment |
$begingroup$
It seems that there are also plenty of conflicting views on estimator and estimate which go hand in hand with this. As an estimator is supposed to be a kind of statistic, whether an estimator is a random variable or not would also clarify some things. There seems to be a lot of conflicting definitions on this site though.
$endgroup$
– Colin Hicks
7 hours ago
$begingroup$
It seems that there are also plenty of conflicting views on estimator and estimate which go hand in hand with this. As an estimator is supposed to be a kind of statistic, whether an estimator is a random variable or not would also clarify some things. There seems to be a lot of conflicting definitions on this site though.
$endgroup$
– Colin Hicks
7 hours ago
$begingroup$
It seems that there are also plenty of conflicting views on estimator and estimate which go hand in hand with this. As an estimator is supposed to be a kind of statistic, whether an estimator is a random variable or not would also clarify some things. There seems to be a lot of conflicting definitions on this site though.
$endgroup$
– Colin Hicks
7 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
A statistic is a function that maps from the set of outcomes of the observable values to a real number. Thus, with $n$ data points, a statistic will be a function $s: mathbb{R}^nrightarrow mathbb{R}$ as in your second form. However, it is also possible to view the statistic in its random sense by taking the appropriate composition of function with the original random variables. (Remember that each random variable $X_i: Omega rightarrow mathbb{R}$ is a measurable function that maps from the sample space to the real numbers.) That is, you can form the random variable $S: Omega rightarrow mathbb{R}$ as:
$$S(omega) = s(X_1(omega), ..., X_n(omega)).$$
The random variable $S$ is the random version of the statistic $s$. Both are often referred to as "statistics", but it is important to bear in mind that $S$ is a composition with the functions for the observable random variables.
answered 7 hours ago
BenBen
26.5k229124
$endgroup$
$begingroup$
that was very helpful. A lot of this notation is really confusing and seems at time almost conflicting as in this case where the term can be used in both contexts.
$endgroup$
– Colin Hicks
7 hours ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "65"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Colin Hicks is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstats.stackexchange.com%2fquestions%2f396944%2fdefinition-of-statistic%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
A statistic is a function that maps from the set of outcomes of the observable values to a real number. Thus, with $n$ data points, a statistic will be a function $s: mathbb{R}^nrightarrow mathbb{R}$ as in your second form. However, it is also possible to view the statistic in its random sense by taking the appropriate composition of function with the original random variables. (Remember that each random variable $X_i: Omega rightarrow mathbb{R}$ is a measurable function that maps from the sample space to the real numbers.) That is, you can form the random variable $S: Omega rightarrow mathbb{R}$ as:
$$S(omega) = s(X_1(omega), ..., X_n(omega)).$$
The random variable $S$ is the random version of the statistic $s$. Both are often referred to as "statistics", but it is important to bear in mind that $S$ is a composition with the functions for the observable random variables.
answered 7 hours ago
BenBen
26.5k229124
$endgroup$
$begingroup$
that was very helpful. A lot of this notation is really confusing and seems at time almost conflicting as in this case where the term can be used in both contexts.
$endgroup$
– Colin Hicks
7 hours ago
add a comment |
$begingroup$
A statistic is a function that maps from the set of outcomes of the observable values to a real number. Thus, with $n$ data points, a statistic will be a function $s: mathbb{R}^nrightarrow mathbb{R}$ as in your second form. However, it is also possible to view the statistic in its random sense by taking the appropriate composition of function with the original random variables. (Remember that each random variable $X_i: Omega rightarrow mathbb{R}$ is a measurable function that maps from the sample space to the real numbers.) That is, you can form the random variable $S: Omega rightarrow mathbb{R}$ as:
$$S(omega) = s(X_1(omega), ..., X_n(omega)).$$
The random variable $S$ is the random version of the statistic $s$. Both are often referred to as "statistics", but it is important to bear in mind that $S$ is a composition with the functions for the observable random variables.
answered 7 hours ago
BenBen
26.5k229124
$endgroup$
$begingroup$
that was very helpful. A lot of this notation is really confusing and seems at time almost conflicting as in this case where the term can be used in both contexts.
$endgroup$
– Colin Hicks
7 hours ago
add a comment |
$begingroup$
A statistic is a function that maps from the set of outcomes of the observable values to a real number. Thus, with $n$ data points, a statistic will be a function $s: mathbb{R}^nrightarrow mathbb{R}$ as in your second form. However, it is also possible to view the statistic in its random sense by taking the appropriate composition of function with the original random variables. (Remember that each random variable $X_i: Omega rightarrow mathbb{R}$ is a measurable function that maps from the sample space to the real numbers.) That is, you can form the random variable $S: Omega rightarrow mathbb{R}$ as:
$$S(omega) = s(X_1(omega), ..., X_n(omega)).$$
The random variable $S$ is the random version of the statistic $s$. Both are often referred to as "statistics", but it is important to bear in mind that $S$ is a composition with the functions for the observable random variables.
answered 7 hours ago
BenBen
26.5k229124
$endgroup$
A statistic is a function that maps from the set of outcomes of the observable values to a real number. Thus, with $n$ data points, a statistic will be a function $s: mathbb{R}^nrightarrow mathbb{R}$ as in your second form. However, it is also possible to view the statistic in its random sense by taking the appropriate composition of function with the original random variables. (Remember that each random variable $X_i: Omega rightarrow mathbb{R}$ is a measurable function that maps from the sample space to the real numbers.) That is, you can form the random variable $S: Omega rightarrow mathbb{R}$ as:
$$S(omega) = s(X_1(omega), ..., X_n(omega)).$$
The random variable $S$ is the random version of the statistic $s$. Both are often referred to as "statistics", but it is important to bear in mind that $S$ is a composition with the functions for the observable random variables.
answered 7 hours ago
BenBen
26.5k229124
answered 7 hours ago
BenBen
26.5k229124
answered 7 hours ago
BenBen
26.5k229124
answered 7 hours ago
BenBen
26.5k229124
26.5k229124
$begingroup$
that was very helpful. A lot of this notation is really confusing and seems at time almost conflicting as in this case where the term can be used in both contexts.
$endgroup$
– Colin Hicks
7 hours ago
add a comment |
$begingroup$
that was very helpful. A lot of this notation is really confusing and seems at time almost conflicting as in this case where the term can be used in both contexts.
$endgroup$
– Colin Hicks
7 hours ago
$begingroup$
that was very helpful. A lot of this notation is really confusing and seems at time almost conflicting as in this case where the term can be used in both contexts.
$endgroup$
– Colin Hicks
7 hours ago
$begingroup$
that was very helpful. A lot of this notation is really confusing and seems at time almost conflicting as in this case where the term can be used in both contexts.
$endgroup$
– Colin Hicks
7 hours ago
add a comment |
Colin Hicks is a new contributor. Be nice, and check out our Code of Conduct.
Colin Hicks is a new contributor. Be nice, and check out our Code of Conduct.
Colin Hicks is a new contributor. Be nice, and check out our Code of Conduct.
Colin Hicks is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Cross Validated!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstats.stackexchange.com%2fquestions%2f396944%2fdefinition-of-statistic%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
It seems that there are also plenty of conflicting views on estimator and estimate which go hand in hand with this. As an estimator is supposed to be a kind of statistic, whether an estimator is a random variable or not would also clarify some things. There seems to be a lot of conflicting definitions on this site though.
$endgroup$
– Colin Hicks
7 hours ago