Run a function in a Shell Script as a different user [duplicate]
This question already has an answer here:
Executing a Bash Script Function with Sudo
5 answers
Forward function and variables into sudo su - <user> <<EOF
3 answers
“command not found” when sudo'ing function from ~/.zshrc
3 answers
I have a .sh script which contains a set of functions. I have made the script executable (chmod 777).
If I want to run a function as my current user I simply do:
. /path/to/script/functions.sh && fc_number1 "${item1}" "${item2}" &
This works fine. However I have another function, that needs to be run by a different user with different privileges.
I have tried:
sudo -unewuser . /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}"
sudo -unewuser -c "bash -c fc_number2 ${item1} ${item2} ${item3}"
Neither of which works. I simply get sudo: .: command not found or bash: export: fc_number2: not a function, or some other error.
Is there something else I need to do to make this work. Everything I read basically comes back to one of the two options I have tried above.
bash function
asked Feb 18 at 13:35
IGGtIGGt
68541527
marked as duplicate by Kusalananda bash
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Feb 18 at 13:36
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Executing a Bash Script Function with Sudo
5 answers
Forward function and variables into sudo su - <user> <<EOF
3 answers
“command not found” when sudo'ing function from ~/.zshrc
3 answers
I have a .sh script which contains a set of functions. I have made the script executable (chmod 777).
If I want to run a function as my current user I simply do:
. /path/to/script/functions.sh && fc_number1 "${item1}" "${item2}" &
This works fine. However I have another function, that needs to be run by a different user with different privileges.
I have tried:
sudo -unewuser . /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}"
sudo -unewuser -c "bash -c fc_number2 ${item1} ${item2} ${item3}"
Neither of which works. I simply get sudo: .: command not found or bash: export: fc_number2: not a function, or some other error.
Is there something else I need to do to make this work. Everything I read basically comes back to one of the two options I have tried above.
bash function
asked Feb 18 at 13:35
IGGtIGGt
68541527
marked as duplicate by Kusalananda bash
Users with the bash badge can single-handedly close bash questions as duplicates and reopen them as needed.
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Feb 18 at 13:36
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
You could use a wrapper script that contains. /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}"and run it assudo -unewuser wrapper_script.sh. If necessary you could also create a wrapper script that takes command line arguments and passes them to the function call.
– Bodo
Feb 18 at 13:41
It is better to not give scripts a.shending. And if you give a mode of777then you give everyone on the system, permission to write/change the script.
– ctrl-alt-delor
Feb 18 at 13:53
the 777 was purely to try and get it working on my test environment. It just means there is one less thing that may be preventing it working. Once I have it working it would then refine it back down to the bare minimum privileges needed to make it work.
– IGGt
Feb 18 at 13:58
add a comment |
This question already has an answer here:
Executing a Bash Script Function with Sudo
5 answers
Forward function and variables into sudo su - <user> <<EOF
3 answers
“command not found” when sudo'ing function from ~/.zshrc
3 answers
I have a .sh script which contains a set of functions. I have made the script executable (chmod 777).
If I want to run a function as my current user I simply do:
. /path/to/script/functions.sh && fc_number1 "${item1}" "${item2}" &
This works fine. However I have another function, that needs to be run by a different user with different privileges.
I have tried:
sudo -unewuser . /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}"
sudo -unewuser -c "bash -c fc_number2 ${item1} ${item2} ${item3}"
Neither of which works. I simply get sudo: .: command not found or bash: export: fc_number2: not a function, or some other error.
Is there something else I need to do to make this work. Everything I read basically comes back to one of the two options I have tried above.
bash function
asked Feb 18 at 13:35
IGGtIGGt
68541527
This question already has an answer here:
Executing a Bash Script Function with Sudo
5 answers
Forward function and variables into sudo su - <user> <<EOF
3 answers
“command not found” when sudo'ing function from ~/.zshrc
3 answers
I have a .sh script which contains a set of functions. I have made the script executable (chmod 777).
If I want to run a function as my current user I simply do:
. /path/to/script/functions.sh && fc_number1 "${item1}" "${item2}" &
This works fine. However I have another function, that needs to be run by a different user with different privileges.
I have tried:
sudo -unewuser . /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}"
sudo -unewuser -c "bash -c fc_number2 ${item1} ${item2} ${item3}"
Neither of which works. I simply get sudo: .: command not found or bash: export: fc_number2: not a function, or some other error.
Is there something else I need to do to make this work. Everything I read basically comes back to one of the two options I have tried above.
This question already has an answer here:
Executing a Bash Script Function with Sudo
5 answers
Forward function and variables into sudo su - <user> <<EOF
3 answers
“command not found” when sudo'ing function from ~/.zshrc
3 answers
bash function
bash function
asked Feb 18 at 13:35
IGGtIGGt
68541527
asked Feb 18 at 13:35
IGGtIGGt
68541527
asked Feb 18 at 13:35
IGGtIGGt
68541527
asked Feb 18 at 13:35
IGGtIGGt
68541527
asked Feb 18 at 13:35
IGGtIGGt
68541527
68541527
marked as duplicate by Kusalananda bash
Users with the bash badge can single-handedly close bash questions as duplicates and reopen them as needed.
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Feb 18 at 13:36
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Kusalananda bash
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Feb 18 at 13:36
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
You could use a wrapper script that contains. /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}"and run it assudo -unewuser wrapper_script.sh. If necessary you could also create a wrapper script that takes command line arguments and passes them to the function call.
– Bodo
Feb 18 at 13:41
It is better to not give scripts a.shending. And if you give a mode of777then you give everyone on the system, permission to write/change the script.
– ctrl-alt-delor
Feb 18 at 13:53
the 777 was purely to try and get it working on my test environment. It just means there is one less thing that may be preventing it working. Once I have it working it would then refine it back down to the bare minimum privileges needed to make it work.
– IGGt
Feb 18 at 13:58
add a comment |
You could use a wrapper script that contains. /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}"and run it assudo -unewuser wrapper_script.sh. If necessary you could also create a wrapper script that takes command line arguments and passes them to the function call.
– Bodo
Feb 18 at 13:41
It is better to not give scripts a.shending. And if you give a mode of777then you give everyone on the system, permission to write/change the script.
– ctrl-alt-delor
Feb 18 at 13:53
the 777 was purely to try and get it working on my test environment. It just means there is one less thing that may be preventing it working. Once I have it working it would then refine it back down to the bare minimum privileges needed to make it work.
– IGGt
Feb 18 at 13:58
You could use a wrapper script that contains
. /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}" and run it as sudo -unewuser wrapper_script.sh. If necessary you could also create a wrapper script that takes command line arguments and passes them to the function call.– Bodo
Feb 18 at 13:41
You could use a wrapper script that contains
. /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}" and run it as sudo -unewuser wrapper_script.sh. If necessary you could also create a wrapper script that takes command line arguments and passes them to the function call.– Bodo
Feb 18 at 13:41
It is better to not give scripts a
.sh ending. And if you give a mode of 777 then you give everyone on the system, permission to write/change the script.– ctrl-alt-delor
Feb 18 at 13:53
It is better to not give scripts a
.sh ending. And if you give a mode of 777 then you give everyone on the system, permission to write/change the script.– ctrl-alt-delor
Feb 18 at 13:53
the 777 was purely to try and get it working on my test environment. It just means there is one less thing that may be preventing it working. Once I have it working it would then refine it back down to the bare minimum privileges needed to make it work.
– IGGt
Feb 18 at 13:58
the 777 was purely to try and get it working on my test environment. It just means there is one less thing that may be preventing it working. Once I have it working it would then refine it back down to the bare minimum privileges needed to make it work.
– IGGt
Feb 18 at 13:58
add a comment |
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You could use a wrapper script that contains
. /path/to/script/functions.sh && fc_number2 "${item1}" "${item2}" "${item3}"and run it assudo -unewuser wrapper_script.sh. If necessary you could also create a wrapper script that takes command line arguments and passes them to the function call.– Bodo
Feb 18 at 13:41
It is better to not give scripts a
.shending. And if you give a mode of777then you give everyone on the system, permission to write/change the script.– ctrl-alt-delor
Feb 18 at 13:53
the 777 was purely to try and get it working on my test environment. It just means there is one less thing that may be preventing it working. Once I have it working it would then refine it back down to the bare minimum privileges needed to make it work.
– IGGt
Feb 18 at 13:58