How do you interpret/draw out the simplified circuits in Sedra's Microelectronics?
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I legitimately do not understand how the simplified drawings in this book are meant to be interpreted. Coming from a basic circuit analysis class which had everything explicitly drawn, I'm having a lot of trouble even interpreting the simplest circuits in this book and can't even get started with solving them.
Where do the arrows go?
This notation is briefly addressed in chapter 1 where it says that the arrows are connected together, but that wouldn't make any sense, since I is given a different value in the problem.
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I legitimately do not understand how the simplified drawings in this book are meant to be interpreted. Coming from a basic circuit analysis class which had everything explicitly drawn, I'm having a lot of trouble even interpreting the simplest circuits in this book and can't even get started with solving them.
Where do the arrows go?
This notation is briefly addressed in chapter 1 where it says that the arrows are connected together, but that wouldn't make any sense, since I is given a different value in the problem.
basic
New contributor
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add a comment |
$begingroup$
I legitimately do not understand how the simplified drawings in this book are meant to be interpreted. Coming from a basic circuit analysis class which had everything explicitly drawn, I'm having a lot of trouble even interpreting the simplest circuits in this book and can't even get started with solving them.
Where do the arrows go?
This notation is briefly addressed in chapter 1 where it says that the arrows are connected together, but that wouldn't make any sense, since I is given a different value in the problem.
basic
New contributor
$endgroup$
I legitimately do not understand how the simplified drawings in this book are meant to be interpreted. Coming from a basic circuit analysis class which had everything explicitly drawn, I'm having a lot of trouble even interpreting the simplest circuits in this book and can't even get started with solving them.
Where do the arrows go?
This notation is briefly addressed in chapter 1 where it says that the arrows are connected together, but that wouldn't make any sense, since I is given a different value in the problem.
basic
basic
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asked 5 hours ago
mokanulmokanul
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It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
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i have seen where all the people are using the same strategy to follow ur strategy i hope this strategy are working good for them so check out here
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$begingroup$
It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
$endgroup$
add a comment |
$begingroup$
It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
$endgroup$
add a comment |
$begingroup$
It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
$endgroup$
It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
answered 5 hours ago
TransistorTransistor
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i have seen where all the people are using the same strategy to follow ur strategy i hope this strategy are working good for them so check out here
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i have seen where all the people are using the same strategy to follow ur strategy i hope this strategy are working good for them so check out here
New contributor
$endgroup$
add a comment |
$begingroup$
i have seen where all the people are using the same strategy to follow ur strategy i hope this strategy are working good for them so check out here
New contributor
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i have seen where all the people are using the same strategy to follow ur strategy i hope this strategy are working good for them so check out here
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answered 22 mins ago
Mohammed AsifMohammed Asif
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mokanul is a new contributor. Be nice, and check out our Code of Conduct.
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