See if a specific resource exists in a kubernetes namespace












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So I want to have a function that checks to see if a certain resource (deployment, job, cronjob etc) exist in a namespace. Using the kubernetes python client, I can create a boolean function (using deployments as a concrete example).



from kubernetes import client, config



config.load_kube_config()

client = client.AppsV1Api()

try:

    client.read_namespaced_deployment("deployment_name", "default")

    return True

except ApiException as e:

    if e.status == 404:

        return False


Is there a way to achieve the same without relying on the ApiException explicitly?






python exception






share









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    0












    $begingroup$


    So I want to have a function that checks to see if a certain resource (deployment, job, cronjob etc) exist in a namespace. Using the kubernetes python client, I can create a boolean function (using deployments as a concrete example).



    from kubernetes import client, config
    

    
config.load_kube_config()
    
client = client.AppsV1Api()
    
try:
    
    client.read_namespaced_deployment("deployment_name", "default")
    
    return True
    
except ApiException as e:
    
    if e.status == 404:
    
        return False


    Is there a way to achieve the same without relying on the ApiException explicitly?






    python exception






    share









    $endgroup$















      0












      0








      0





      $begingroup$


      So I want to have a function that checks to see if a certain resource (deployment, job, cronjob etc) exist in a namespace. Using the kubernetes python client, I can create a boolean function (using deployments as a concrete example).



      from kubernetes import client, config
      

      
config.load_kube_config()
      
client = client.AppsV1Api()
      
try:
      
    client.read_namespaced_deployment("deployment_name", "default")
      
    return True
      
except ApiException as e:
      
    if e.status == 404:
      
        return False


      Is there a way to achieve the same without relying on the ApiException explicitly?






      python exception






      share









      $endgroup$




      So I want to have a function that checks to see if a certain resource (deployment, job, cronjob etc) exist in a namespace. Using the kubernetes python client, I can create a boolean function (using deployments as a concrete example).



      from kubernetes import client, config
      

      
config.load_kube_config()
      
client = client.AppsV1Api()
      
try:
      
    client.read_namespaced_deployment("deployment_name", "default")
      
    return True
      
except ApiException as e:
      
    if e.status == 404:
      
        return False


      Is there a way to achieve the same without relying on the ApiException explicitly?






      python exception




      python exception





      share












      share










      share



      share










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      user3079474user3079474

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