What's the right way to sort a associated array in bash or zsh?
I'm wondering how should I sort the associated array in bash? I tried the manual, but seems nothing related to sort.
The current solution is echo everything out, and use external program i.e key value | sort -k2
That looks inefficient to me.
An example of array was:
A['192.168.2.2']=5
A['192.168.3.2']=1
A['192.168.1.1']=9
And I'll be looking for the top 2 used IP address, which is 192.168.1.1 and 192.168.2.2, that is, I need to sort this array by it's value.
bash zsh
|
show 3 more comments
I'm wondering how should I sort the associated array in bash? I tried the manual, but seems nothing related to sort.
The current solution is echo everything out, and use external program i.e key value | sort -k2
That looks inefficient to me.
An example of array was:
A['192.168.2.2']=5
A['192.168.3.2']=1
A['192.168.1.1']=9
And I'll be looking for the top 2 used IP address, which is 192.168.1.1 and 192.168.2.2, that is, I need to sort this array by it's value.
bash zsh
It sounds like what you are trying to accomplish is too complex forbash
to do easily. What are you trying to do?
– jw013
Oct 16 '12 at 15:10
And asking for the "right" way is just asking for trouble. ;)
– lynxlynxlynx
Oct 16 '12 at 17:09
mywiki.wooledge.org/BashWeaknesses
– jordanm
Oct 16 '12 at 20:04
Is switching to zsh an option? Otherwise, relying on external tools is common in shell programming.
– Gilles
Oct 16 '12 at 21:47
1
If you getting this data from parsing and have gawk available, I tend to just do it all in awk.
– jordanm
Oct 17 '12 at 2:40
|
show 3 more comments
I'm wondering how should I sort the associated array in bash? I tried the manual, but seems nothing related to sort.
The current solution is echo everything out, and use external program i.e key value | sort -k2
That looks inefficient to me.
An example of array was:
A['192.168.2.2']=5
A['192.168.3.2']=1
A['192.168.1.1']=9
And I'll be looking for the top 2 used IP address, which is 192.168.1.1 and 192.168.2.2, that is, I need to sort this array by it's value.
bash zsh
I'm wondering how should I sort the associated array in bash? I tried the manual, but seems nothing related to sort.
The current solution is echo everything out, and use external program i.e key value | sort -k2
That looks inefficient to me.
An example of array was:
A['192.168.2.2']=5
A['192.168.3.2']=1
A['192.168.1.1']=9
And I'll be looking for the top 2 used IP address, which is 192.168.1.1 and 192.168.2.2, that is, I need to sort this array by it's value.
bash zsh
bash zsh
edited Oct 17 '12 at 8:18
manatwork
21.9k38384
21.9k38384
asked Oct 16 '12 at 14:57
daisydaisy
28.8k49171302
28.8k49171302
It sounds like what you are trying to accomplish is too complex forbash
to do easily. What are you trying to do?
– jw013
Oct 16 '12 at 15:10
And asking for the "right" way is just asking for trouble. ;)
– lynxlynxlynx
Oct 16 '12 at 17:09
mywiki.wooledge.org/BashWeaknesses
– jordanm
Oct 16 '12 at 20:04
Is switching to zsh an option? Otherwise, relying on external tools is common in shell programming.
– Gilles
Oct 16 '12 at 21:47
1
If you getting this data from parsing and have gawk available, I tend to just do it all in awk.
– jordanm
Oct 17 '12 at 2:40
|
show 3 more comments
It sounds like what you are trying to accomplish is too complex forbash
to do easily. What are you trying to do?
– jw013
Oct 16 '12 at 15:10
And asking for the "right" way is just asking for trouble. ;)
– lynxlynxlynx
Oct 16 '12 at 17:09
mywiki.wooledge.org/BashWeaknesses
– jordanm
Oct 16 '12 at 20:04
Is switching to zsh an option? Otherwise, relying on external tools is common in shell programming.
– Gilles
Oct 16 '12 at 21:47
1
If you getting this data from parsing and have gawk available, I tend to just do it all in awk.
– jordanm
Oct 17 '12 at 2:40
It sounds like what you are trying to accomplish is too complex for
bash
to do easily. What are you trying to do?– jw013
Oct 16 '12 at 15:10
It sounds like what you are trying to accomplish is too complex for
bash
to do easily. What are you trying to do?– jw013
Oct 16 '12 at 15:10
And asking for the "right" way is just asking for trouble. ;)
– lynxlynxlynx
Oct 16 '12 at 17:09
And asking for the "right" way is just asking for trouble. ;)
– lynxlynxlynx
Oct 16 '12 at 17:09
mywiki.wooledge.org/BashWeaknesses
– jordanm
Oct 16 '12 at 20:04
mywiki.wooledge.org/BashWeaknesses
– jordanm
Oct 16 '12 at 20:04
Is switching to zsh an option? Otherwise, relying on external tools is common in shell programming.
– Gilles
Oct 16 '12 at 21:47
Is switching to zsh an option? Otherwise, relying on external tools is common in shell programming.
– Gilles
Oct 16 '12 at 21:47
1
1
If you getting this data from parsing and have gawk available, I tend to just do it all in awk.
– jordanm
Oct 17 '12 at 2:40
If you getting this data from parsing and have gawk available, I tend to just do it all in awk.
– jordanm
Oct 17 '12 at 2:40
|
show 3 more comments
4 Answers
4
active
oldest
votes
Zsh has a built-in way to sort lists. However, I don't think there's a way to sort the values while keeping the correlation with the keys using parameter expansion flags and subscript flags, which means that an explicit loop is necessary. Assuming that your values don't contain a null character, you can build an array containing the values and keys concatenated with a null character in between, and sort that.
keys=("${(@k)A}")
values=("${(@v)A}")
combined=()
for ((i=1; i <= $#values; i++)) { combined[i]=($values[i]$''$keys[i]); }
keys_sorted_by_decreasing_value=("${${(@On)combined}#*$''}")
keys_of_the_top_two_values=("${(@)keys_sorted_by_decreasing_value[1,2]}")
EDIT by @sch: the first 4 lines can be simplified to
combined=()
for k v ("${(@kv)A}") combined+=($k$''$v)
The variables keys
and values
contain the keys and values of A
in an arbitrary but consistent order. You can write keys=(${(k)A})
if there are no empty keys, and similarly for values. keys_sorted_by_decreasing_value
sorts keys lexicographically, add the n
flag to sort numerically (9
before 10
) and remove O
if you want to sort in increasing order (in which case the top two values can be obtained with the subscript [-2,-1]
).
Ksh93 has a way to sort the positional parameters only, with set -s
; this also exists in zsh but not in bash 4.2. Assuming your values don't contain newlines or control characters that sort before newlines:
keys=("${!A[@]}")
combined=()
for ((i=0; i <= ${#keys}; i++)); do combined[i]=(${A[${keys[$i]}]}$'n'${keys[$i]}); done
set -A sorted -s "${combined[@]}"
top_combined=${sorted[${#sorted[@]}-1]} # -2 for the next-to-largest, etc.
top_key=${top_combined#*$'n'}
This is all pretty complex, so you might as well go for the external sort, which is a lot easier to write. Assuming that neither keys nor values contain control characters, in ksh or bash:
IFS=$'n'; set -f
keys_sorted_by_decreasing_value=($(
for k in "${!A[@]}"; do printf '%st%sn' "${A[$k]}" "$k"; done |
sort | sed $'s/t.*//'
))
add a comment |
A shell is before all a tool to run other tools. It sounds to me you're after a programming language like perl, ruby, python...
Having said that, here is some possible solution for zsh.
In zsh, you can get a sorted list of the keys of an associated array (${(kOn)A}
) or of the values (${(On)A}
) but not directly a list of keys from the sorted list of values (AFAIK), but you could do things like:
typeset -A A B
A=(
192.168.2.2 5
192.168.3.2 1
192.168.1.1 9
192.168.8.1 9
)
for v ("${(@nO)A}") B+=("${(@kv)A[(eR)$v]}")
That is, order (O
) the list of values ($A
) numerically (n
) and for
each v
alue, add the k
ey/v
alue pairs matching the value $v
(e
for exact match, R
to get the reverse list based on value, not key) and add that to the B
associative array.
Then, you'd get the sorted list in B
:
$ printf '%s => %sn' "${(@kv)B}"
192.168.8.1 => 9
192.168.1.1 => 9
192.168.2.2 => 5
192.168.3.2 => 1
And you can select the first 2 keys with
$ print -rl -- ${${(k)B}[1,2]}
192.168.8.1
192.168.1.1
add a comment |
"Associative Array" often means that the data in array have real-world meaning, which is your case. External unix sort is ideal for this task, and few C programmer can out-perform unix sort. Especially for big data you can tailor, slice, fork, bring full power of unix and shell. This is why so many shell and awk platform there don't bother with a sort.
add a comment |
The best way to sort a bash associative array by KEY is to NOT sort it.
Instead, get the list of KEYS, sort that list as a variable, and iterate through the list. Example: Suppose you have an array of IP addresses (keys) and host names (values):
Alternative:
Create new list from KEYs, convert to lines, sort it, convert back to list, and use it to iterate through the array.
declare -A ADDR
ADDR[192.168.1.1]="host1"
ADDR[192.168.1.2]="host2"
etc...
KEYS=`echo ${!ADDR[@]} | tr ' ' '12' | sort | tr '12' ' '`
for KEY in $KEYS; do
VAL=${ADDR[$KEY]}
echo "KEY=[$KEY] VAL=[$VAL]"
done
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "106"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f51998%2fwhats-the-right-way-to-sort-a-associated-array-in-bash-or-zsh%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Zsh has a built-in way to sort lists. However, I don't think there's a way to sort the values while keeping the correlation with the keys using parameter expansion flags and subscript flags, which means that an explicit loop is necessary. Assuming that your values don't contain a null character, you can build an array containing the values and keys concatenated with a null character in between, and sort that.
keys=("${(@k)A}")
values=("${(@v)A}")
combined=()
for ((i=1; i <= $#values; i++)) { combined[i]=($values[i]$''$keys[i]); }
keys_sorted_by_decreasing_value=("${${(@On)combined}#*$''}")
keys_of_the_top_two_values=("${(@)keys_sorted_by_decreasing_value[1,2]}")
EDIT by @sch: the first 4 lines can be simplified to
combined=()
for k v ("${(@kv)A}") combined+=($k$''$v)
The variables keys
and values
contain the keys and values of A
in an arbitrary but consistent order. You can write keys=(${(k)A})
if there are no empty keys, and similarly for values. keys_sorted_by_decreasing_value
sorts keys lexicographically, add the n
flag to sort numerically (9
before 10
) and remove O
if you want to sort in increasing order (in which case the top two values can be obtained with the subscript [-2,-1]
).
Ksh93 has a way to sort the positional parameters only, with set -s
; this also exists in zsh but not in bash 4.2. Assuming your values don't contain newlines or control characters that sort before newlines:
keys=("${!A[@]}")
combined=()
for ((i=0; i <= ${#keys}; i++)); do combined[i]=(${A[${keys[$i]}]}$'n'${keys[$i]}); done
set -A sorted -s "${combined[@]}"
top_combined=${sorted[${#sorted[@]}-1]} # -2 for the next-to-largest, etc.
top_key=${top_combined#*$'n'}
This is all pretty complex, so you might as well go for the external sort, which is a lot easier to write. Assuming that neither keys nor values contain control characters, in ksh or bash:
IFS=$'n'; set -f
keys_sorted_by_decreasing_value=($(
for k in "${!A[@]}"; do printf '%st%sn' "${A[$k]}" "$k"; done |
sort | sed $'s/t.*//'
))
add a comment |
Zsh has a built-in way to sort lists. However, I don't think there's a way to sort the values while keeping the correlation with the keys using parameter expansion flags and subscript flags, which means that an explicit loop is necessary. Assuming that your values don't contain a null character, you can build an array containing the values and keys concatenated with a null character in between, and sort that.
keys=("${(@k)A}")
values=("${(@v)A}")
combined=()
for ((i=1; i <= $#values; i++)) { combined[i]=($values[i]$''$keys[i]); }
keys_sorted_by_decreasing_value=("${${(@On)combined}#*$''}")
keys_of_the_top_two_values=("${(@)keys_sorted_by_decreasing_value[1,2]}")
EDIT by @sch: the first 4 lines can be simplified to
combined=()
for k v ("${(@kv)A}") combined+=($k$''$v)
The variables keys
and values
contain the keys and values of A
in an arbitrary but consistent order. You can write keys=(${(k)A})
if there are no empty keys, and similarly for values. keys_sorted_by_decreasing_value
sorts keys lexicographically, add the n
flag to sort numerically (9
before 10
) and remove O
if you want to sort in increasing order (in which case the top two values can be obtained with the subscript [-2,-1]
).
Ksh93 has a way to sort the positional parameters only, with set -s
; this also exists in zsh but not in bash 4.2. Assuming your values don't contain newlines or control characters that sort before newlines:
keys=("${!A[@]}")
combined=()
for ((i=0; i <= ${#keys}; i++)); do combined[i]=(${A[${keys[$i]}]}$'n'${keys[$i]}); done
set -A sorted -s "${combined[@]}"
top_combined=${sorted[${#sorted[@]}-1]} # -2 for the next-to-largest, etc.
top_key=${top_combined#*$'n'}
This is all pretty complex, so you might as well go for the external sort, which is a lot easier to write. Assuming that neither keys nor values contain control characters, in ksh or bash:
IFS=$'n'; set -f
keys_sorted_by_decreasing_value=($(
for k in "${!A[@]}"; do printf '%st%sn' "${A[$k]}" "$k"; done |
sort | sed $'s/t.*//'
))
add a comment |
Zsh has a built-in way to sort lists. However, I don't think there's a way to sort the values while keeping the correlation with the keys using parameter expansion flags and subscript flags, which means that an explicit loop is necessary. Assuming that your values don't contain a null character, you can build an array containing the values and keys concatenated with a null character in between, and sort that.
keys=("${(@k)A}")
values=("${(@v)A}")
combined=()
for ((i=1; i <= $#values; i++)) { combined[i]=($values[i]$''$keys[i]); }
keys_sorted_by_decreasing_value=("${${(@On)combined}#*$''}")
keys_of_the_top_two_values=("${(@)keys_sorted_by_decreasing_value[1,2]}")
EDIT by @sch: the first 4 lines can be simplified to
combined=()
for k v ("${(@kv)A}") combined+=($k$''$v)
The variables keys
and values
contain the keys and values of A
in an arbitrary but consistent order. You can write keys=(${(k)A})
if there are no empty keys, and similarly for values. keys_sorted_by_decreasing_value
sorts keys lexicographically, add the n
flag to sort numerically (9
before 10
) and remove O
if you want to sort in increasing order (in which case the top two values can be obtained with the subscript [-2,-1]
).
Ksh93 has a way to sort the positional parameters only, with set -s
; this also exists in zsh but not in bash 4.2. Assuming your values don't contain newlines or control characters that sort before newlines:
keys=("${!A[@]}")
combined=()
for ((i=0; i <= ${#keys}; i++)); do combined[i]=(${A[${keys[$i]}]}$'n'${keys[$i]}); done
set -A sorted -s "${combined[@]}"
top_combined=${sorted[${#sorted[@]}-1]} # -2 for the next-to-largest, etc.
top_key=${top_combined#*$'n'}
This is all pretty complex, so you might as well go for the external sort, which is a lot easier to write. Assuming that neither keys nor values contain control characters, in ksh or bash:
IFS=$'n'; set -f
keys_sorted_by_decreasing_value=($(
for k in "${!A[@]}"; do printf '%st%sn' "${A[$k]}" "$k"; done |
sort | sed $'s/t.*//'
))
Zsh has a built-in way to sort lists. However, I don't think there's a way to sort the values while keeping the correlation with the keys using parameter expansion flags and subscript flags, which means that an explicit loop is necessary. Assuming that your values don't contain a null character, you can build an array containing the values and keys concatenated with a null character in between, and sort that.
keys=("${(@k)A}")
values=("${(@v)A}")
combined=()
for ((i=1; i <= $#values; i++)) { combined[i]=($values[i]$''$keys[i]); }
keys_sorted_by_decreasing_value=("${${(@On)combined}#*$''}")
keys_of_the_top_two_values=("${(@)keys_sorted_by_decreasing_value[1,2]}")
EDIT by @sch: the first 4 lines can be simplified to
combined=()
for k v ("${(@kv)A}") combined+=($k$''$v)
The variables keys
and values
contain the keys and values of A
in an arbitrary but consistent order. You can write keys=(${(k)A})
if there are no empty keys, and similarly for values. keys_sorted_by_decreasing_value
sorts keys lexicographically, add the n
flag to sort numerically (9
before 10
) and remove O
if you want to sort in increasing order (in which case the top two values can be obtained with the subscript [-2,-1]
).
Ksh93 has a way to sort the positional parameters only, with set -s
; this also exists in zsh but not in bash 4.2. Assuming your values don't contain newlines or control characters that sort before newlines:
keys=("${!A[@]}")
combined=()
for ((i=0; i <= ${#keys}; i++)); do combined[i]=(${A[${keys[$i]}]}$'n'${keys[$i]}); done
set -A sorted -s "${combined[@]}"
top_combined=${sorted[${#sorted[@]}-1]} # -2 for the next-to-largest, etc.
top_key=${top_combined#*$'n'}
This is all pretty complex, so you might as well go for the external sort, which is a lot easier to write. Assuming that neither keys nor values contain control characters, in ksh or bash:
IFS=$'n'; set -f
keys_sorted_by_decreasing_value=($(
for k in "${!A[@]}"; do printf '%st%sn' "${A[$k]}" "$k"; done |
sort | sed $'s/t.*//'
))
edited Oct 17 '12 at 13:46
Stéphane Chazelas
306k57577931
306k57577931
answered Oct 17 '12 at 12:56
GillesGilles
538k12810881605
538k12810881605
add a comment |
add a comment |
A shell is before all a tool to run other tools. It sounds to me you're after a programming language like perl, ruby, python...
Having said that, here is some possible solution for zsh.
In zsh, you can get a sorted list of the keys of an associated array (${(kOn)A}
) or of the values (${(On)A}
) but not directly a list of keys from the sorted list of values (AFAIK), but you could do things like:
typeset -A A B
A=(
192.168.2.2 5
192.168.3.2 1
192.168.1.1 9
192.168.8.1 9
)
for v ("${(@nO)A}") B+=("${(@kv)A[(eR)$v]}")
That is, order (O
) the list of values ($A
) numerically (n
) and for
each v
alue, add the k
ey/v
alue pairs matching the value $v
(e
for exact match, R
to get the reverse list based on value, not key) and add that to the B
associative array.
Then, you'd get the sorted list in B
:
$ printf '%s => %sn' "${(@kv)B}"
192.168.8.1 => 9
192.168.1.1 => 9
192.168.2.2 => 5
192.168.3.2 => 1
And you can select the first 2 keys with
$ print -rl -- ${${(k)B}[1,2]}
192.168.8.1
192.168.1.1
add a comment |
A shell is before all a tool to run other tools. It sounds to me you're after a programming language like perl, ruby, python...
Having said that, here is some possible solution for zsh.
In zsh, you can get a sorted list of the keys of an associated array (${(kOn)A}
) or of the values (${(On)A}
) but not directly a list of keys from the sorted list of values (AFAIK), but you could do things like:
typeset -A A B
A=(
192.168.2.2 5
192.168.3.2 1
192.168.1.1 9
192.168.8.1 9
)
for v ("${(@nO)A}") B+=("${(@kv)A[(eR)$v]}")
That is, order (O
) the list of values ($A
) numerically (n
) and for
each v
alue, add the k
ey/v
alue pairs matching the value $v
(e
for exact match, R
to get the reverse list based on value, not key) and add that to the B
associative array.
Then, you'd get the sorted list in B
:
$ printf '%s => %sn' "${(@kv)B}"
192.168.8.1 => 9
192.168.1.1 => 9
192.168.2.2 => 5
192.168.3.2 => 1
And you can select the first 2 keys with
$ print -rl -- ${${(k)B}[1,2]}
192.168.8.1
192.168.1.1
add a comment |
A shell is before all a tool to run other tools. It sounds to me you're after a programming language like perl, ruby, python...
Having said that, here is some possible solution for zsh.
In zsh, you can get a sorted list of the keys of an associated array (${(kOn)A}
) or of the values (${(On)A}
) but not directly a list of keys from the sorted list of values (AFAIK), but you could do things like:
typeset -A A B
A=(
192.168.2.2 5
192.168.3.2 1
192.168.1.1 9
192.168.8.1 9
)
for v ("${(@nO)A}") B+=("${(@kv)A[(eR)$v]}")
That is, order (O
) the list of values ($A
) numerically (n
) and for
each v
alue, add the k
ey/v
alue pairs matching the value $v
(e
for exact match, R
to get the reverse list based on value, not key) and add that to the B
associative array.
Then, you'd get the sorted list in B
:
$ printf '%s => %sn' "${(@kv)B}"
192.168.8.1 => 9
192.168.1.1 => 9
192.168.2.2 => 5
192.168.3.2 => 1
And you can select the first 2 keys with
$ print -rl -- ${${(k)B}[1,2]}
192.168.8.1
192.168.1.1
A shell is before all a tool to run other tools. It sounds to me you're after a programming language like perl, ruby, python...
Having said that, here is some possible solution for zsh.
In zsh, you can get a sorted list of the keys of an associated array (${(kOn)A}
) or of the values (${(On)A}
) but not directly a list of keys from the sorted list of values (AFAIK), but you could do things like:
typeset -A A B
A=(
192.168.2.2 5
192.168.3.2 1
192.168.1.1 9
192.168.8.1 9
)
for v ("${(@nO)A}") B+=("${(@kv)A[(eR)$v]}")
That is, order (O
) the list of values ($A
) numerically (n
) and for
each v
alue, add the k
ey/v
alue pairs matching the value $v
(e
for exact match, R
to get the reverse list based on value, not key) and add that to the B
associative array.
Then, you'd get the sorted list in B
:
$ printf '%s => %sn' "${(@kv)B}"
192.168.8.1 => 9
192.168.1.1 => 9
192.168.2.2 => 5
192.168.3.2 => 1
And you can select the first 2 keys with
$ print -rl -- ${${(k)B}[1,2]}
192.168.8.1
192.168.1.1
edited Oct 19 '12 at 6:13
answered Oct 17 '12 at 10:06
Stéphane ChazelasStéphane Chazelas
306k57577931
306k57577931
add a comment |
add a comment |
"Associative Array" often means that the data in array have real-world meaning, which is your case. External unix sort is ideal for this task, and few C programmer can out-perform unix sort. Especially for big data you can tailor, slice, fork, bring full power of unix and shell. This is why so many shell and awk platform there don't bother with a sort.
add a comment |
"Associative Array" often means that the data in array have real-world meaning, which is your case. External unix sort is ideal for this task, and few C programmer can out-perform unix sort. Especially for big data you can tailor, slice, fork, bring full power of unix and shell. This is why so many shell and awk platform there don't bother with a sort.
add a comment |
"Associative Array" often means that the data in array have real-world meaning, which is your case. External unix sort is ideal for this task, and few C programmer can out-perform unix sort. Especially for big data you can tailor, slice, fork, bring full power of unix and shell. This is why so many shell and awk platform there don't bother with a sort.
"Associative Array" often means that the data in array have real-world meaning, which is your case. External unix sort is ideal for this task, and few C programmer can out-perform unix sort. Especially for big data you can tailor, slice, fork, bring full power of unix and shell. This is why so many shell and awk platform there don't bother with a sort.
answered Oct 19 '12 at 6:48
MeaCulpaMeaCulpa
31614
31614
add a comment |
add a comment |
The best way to sort a bash associative array by KEY is to NOT sort it.
Instead, get the list of KEYS, sort that list as a variable, and iterate through the list. Example: Suppose you have an array of IP addresses (keys) and host names (values):
Alternative:
Create new list from KEYs, convert to lines, sort it, convert back to list, and use it to iterate through the array.
declare -A ADDR
ADDR[192.168.1.1]="host1"
ADDR[192.168.1.2]="host2"
etc...
KEYS=`echo ${!ADDR[@]} | tr ' ' '12' | sort | tr '12' ' '`
for KEY in $KEYS; do
VAL=${ADDR[$KEY]}
echo "KEY=[$KEY] VAL=[$VAL]"
done
add a comment |
The best way to sort a bash associative array by KEY is to NOT sort it.
Instead, get the list of KEYS, sort that list as a variable, and iterate through the list. Example: Suppose you have an array of IP addresses (keys) and host names (values):
Alternative:
Create new list from KEYs, convert to lines, sort it, convert back to list, and use it to iterate through the array.
declare -A ADDR
ADDR[192.168.1.1]="host1"
ADDR[192.168.1.2]="host2"
etc...
KEYS=`echo ${!ADDR[@]} | tr ' ' '12' | sort | tr '12' ' '`
for KEY in $KEYS; do
VAL=${ADDR[$KEY]}
echo "KEY=[$KEY] VAL=[$VAL]"
done
add a comment |
The best way to sort a bash associative array by KEY is to NOT sort it.
Instead, get the list of KEYS, sort that list as a variable, and iterate through the list. Example: Suppose you have an array of IP addresses (keys) and host names (values):
Alternative:
Create new list from KEYs, convert to lines, sort it, convert back to list, and use it to iterate through the array.
declare -A ADDR
ADDR[192.168.1.1]="host1"
ADDR[192.168.1.2]="host2"
etc...
KEYS=`echo ${!ADDR[@]} | tr ' ' '12' | sort | tr '12' ' '`
for KEY in $KEYS; do
VAL=${ADDR[$KEY]}
echo "KEY=[$KEY] VAL=[$VAL]"
done
The best way to sort a bash associative array by KEY is to NOT sort it.
Instead, get the list of KEYS, sort that list as a variable, and iterate through the list. Example: Suppose you have an array of IP addresses (keys) and host names (values):
Alternative:
Create new list from KEYs, convert to lines, sort it, convert back to list, and use it to iterate through the array.
declare -A ADDR
ADDR[192.168.1.1]="host1"
ADDR[192.168.1.2]="host2"
etc...
KEYS=`echo ${!ADDR[@]} | tr ' ' '12' | sort | tr '12' ' '`
for KEY in $KEYS; do
VAL=${ADDR[$KEY]}
echo "KEY=[$KEY] VAL=[$VAL]"
done
answered Feb 6 at 18:24
mz4wheelermz4wheeler
1
1
add a comment |
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f51998%2fwhats-the-right-way-to-sort-a-associated-array-in-bash-or-zsh%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
It sounds like what you are trying to accomplish is too complex for
bash
to do easily. What are you trying to do?– jw013
Oct 16 '12 at 15:10
And asking for the "right" way is just asking for trouble. ;)
– lynxlynxlynx
Oct 16 '12 at 17:09
mywiki.wooledge.org/BashWeaknesses
– jordanm
Oct 16 '12 at 20:04
Is switching to zsh an option? Otherwise, relying on external tools is common in shell programming.
– Gilles
Oct 16 '12 at 21:47
1
If you getting this data from parsing and have gawk available, I tend to just do it all in awk.
– jordanm
Oct 17 '12 at 2:40