How to join a line with a pattern with the next line with sed?












0















I can't find this case in the board, so I'm asking the question.



This is input file:



module  
x(a,b,c)
module
y(d,e,f,
g,h,i)
module
z(j,k,l)


And output file should be:



module x(a,b,c)  
module y(d,e,f,
g,h,i)
module z(j,k,l)









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  • If any of the answers solved your problem, please accept it by clicking the checkmark next to it. Thank you!

    – Jeff Schaller
    Jan 20 at 13:01
















0















I can't find this case in the board, so I'm asking the question.



This is input file:



module  
x(a,b,c)
module
y(d,e,f,
g,h,i)
module
z(j,k,l)


And output file should be:



module x(a,b,c)  
module y(d,e,f,
g,h,i)
module z(j,k,l)









share|improve this question

























  • If any of the answers solved your problem, please accept it by clicking the checkmark next to it. Thank you!

    – Jeff Schaller
    Jan 20 at 13:01














0












0








0


0






I can't find this case in the board, so I'm asking the question.



This is input file:



module  
x(a,b,c)
module
y(d,e,f,
g,h,i)
module
z(j,k,l)


And output file should be:



module x(a,b,c)  
module y(d,e,f,
g,h,i)
module z(j,k,l)









share|improve this question
















I can't find this case in the board, so I'm asking the question.



This is input file:



module  
x(a,b,c)
module
y(d,e,f,
g,h,i)
module
z(j,k,l)


And output file should be:



module x(a,b,c)  
module y(d,e,f,
g,h,i)
module z(j,k,l)






text-processing sed join






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share|improve this question













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share|improve this question








edited Dec 17 '18 at 6:34









αғsнιη

16.7k102865




16.7k102865










asked Dec 17 '18 at 6:24









funfunfunfun

112




112













  • If any of the answers solved your problem, please accept it by clicking the checkmark next to it. Thank you!

    – Jeff Schaller
    Jan 20 at 13:01



















  • If any of the answers solved your problem, please accept it by clicking the checkmark next to it. Thank you!

    – Jeff Schaller
    Jan 20 at 13:01

















If any of the answers solved your problem, please accept it by clicking the checkmark next to it. Thank you!

– Jeff Schaller
Jan 20 at 13:01





If any of the answers solved your problem, please accept it by clicking the checkmark next to it. Thank you!

– Jeff Schaller
Jan 20 at 13:01










3 Answers
3






active

oldest

votes


















2














What you want to do is to join the module lines with the next line.



Using sed:



$ sed '/^module/N;s/n//' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)


This is with your data copied and pasted as is, with spaces at the end of each line.



The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.



If your data has no spaces at the end of the lines, use



$ sed '/^module/N;s/n/ /' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)




Just in case you'd want this (assuming no spaces at end of input lines):



$ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd' 
-e ':pp' -e 'x;/^$/d;s/n/ /g' file
module x(a,b,c)
module y(d,e,f, g,h,i)
module z(j,k,l)


Annotated sed script:



/^module/ b print_previous; # print previous record
H; # append this line to hold space
$ b print_previous; # print previous (last) record
d; # end processing this line

:print_previous; # prints a record accumulated in the hold space
x; # swap in the hold space
/^$/ d; # if line is empty, delete it
s/n/ /g; # replace embedded newlines by spaces
# (implicit print)





share|improve this answer

































    1














    Using awk:



    ~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
    module x(a,b,c)
    module y(d,e,f,
    g,h,i)
    module z(j,k,l)


    For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.






    share|improve this answer































      0














      Another option: create an ed script!



      This starts by pre-counting the number of joins that are required; it then generates that number of ed search & join commands and pipes them, along with a save & quit at the end, into ed:



      #!/bin/bash
      n=$(grep -c '^module *$' input)
      {
      for((i=1; i <= n; i++))
      do
      printf '/^module *$/n.,+1jn'
      done
      echo w
      echo q
      } | ed -s input >/dev/null





      share|improve this answer























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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        What you want to do is to join the module lines with the next line.



        Using sed:



        $ sed '/^module/N;s/n//' file
        module x(a,b,c)
        module y(d,e,f,
        g,h,i)
        module z(j,k,l)


        This is with your data copied and pasted as is, with spaces at the end of each line.



        The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.



        If your data has no spaces at the end of the lines, use



        $ sed '/^module/N;s/n/ /' file
        module x(a,b,c)
        module y(d,e,f,
        g,h,i)
        module z(j,k,l)




        Just in case you'd want this (assuming no spaces at end of input lines):



        $ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd' 
        -e ':pp' -e 'x;/^$/d;s/n/ /g' file
        module x(a,b,c)
        module y(d,e,f, g,h,i)
        module z(j,k,l)


        Annotated sed script:



        /^module/ b print_previous; # print previous record
        H; # append this line to hold space
        $ b print_previous; # print previous (last) record
        d; # end processing this line

        :print_previous; # prints a record accumulated in the hold space
        x; # swap in the hold space
        /^$/ d; # if line is empty, delete it
        s/n/ /g; # replace embedded newlines by spaces
        # (implicit print)





        share|improve this answer






























          2














          What you want to do is to join the module lines with the next line.



          Using sed:



          $ sed '/^module/N;s/n//' file
          module x(a,b,c)
          module y(d,e,f,
          g,h,i)
          module z(j,k,l)


          This is with your data copied and pasted as is, with spaces at the end of each line.



          The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.



          If your data has no spaces at the end of the lines, use



          $ sed '/^module/N;s/n/ /' file
          module x(a,b,c)
          module y(d,e,f,
          g,h,i)
          module z(j,k,l)




          Just in case you'd want this (assuming no spaces at end of input lines):



          $ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd' 
          -e ':pp' -e 'x;/^$/d;s/n/ /g' file
          module x(a,b,c)
          module y(d,e,f, g,h,i)
          module z(j,k,l)


          Annotated sed script:



          /^module/ b print_previous; # print previous record
          H; # append this line to hold space
          $ b print_previous; # print previous (last) record
          d; # end processing this line

          :print_previous; # prints a record accumulated in the hold space
          x; # swap in the hold space
          /^$/ d; # if line is empty, delete it
          s/n/ /g; # replace embedded newlines by spaces
          # (implicit print)





          share|improve this answer




























            2












            2








            2







            What you want to do is to join the module lines with the next line.



            Using sed:



            $ sed '/^module/N;s/n//' file
            module x(a,b,c)
            module y(d,e,f,
            g,h,i)
            module z(j,k,l)


            This is with your data copied and pasted as is, with spaces at the end of each line.



            The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.



            If your data has no spaces at the end of the lines, use



            $ sed '/^module/N;s/n/ /' file
            module x(a,b,c)
            module y(d,e,f,
            g,h,i)
            module z(j,k,l)




            Just in case you'd want this (assuming no spaces at end of input lines):



            $ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd' 
            -e ':pp' -e 'x;/^$/d;s/n/ /g' file
            module x(a,b,c)
            module y(d,e,f, g,h,i)
            module z(j,k,l)


            Annotated sed script:



            /^module/ b print_previous; # print previous record
            H; # append this line to hold space
            $ b print_previous; # print previous (last) record
            d; # end processing this line

            :print_previous; # prints a record accumulated in the hold space
            x; # swap in the hold space
            /^$/ d; # if line is empty, delete it
            s/n/ /g; # replace embedded newlines by spaces
            # (implicit print)





            share|improve this answer















            What you want to do is to join the module lines with the next line.



            Using sed:



            $ sed '/^module/N;s/n//' file
            module x(a,b,c)
            module y(d,e,f,
            g,h,i)
            module z(j,k,l)


            This is with your data copied and pasted as is, with spaces at the end of each line.



            The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.



            If your data has no spaces at the end of the lines, use



            $ sed '/^module/N;s/n/ /' file
            module x(a,b,c)
            module y(d,e,f,
            g,h,i)
            module z(j,k,l)




            Just in case you'd want this (assuming no spaces at end of input lines):



            $ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd' 
            -e ':pp' -e 'x;/^$/d;s/n/ /g' file
            module x(a,b,c)
            module y(d,e,f, g,h,i)
            module z(j,k,l)


            Annotated sed script:



            /^module/ b print_previous; # print previous record
            H; # append this line to hold space
            $ b print_previous; # print previous (last) record
            d; # end processing this line

            :print_previous; # prints a record accumulated in the hold space
            x; # swap in the hold space
            /^$/ d; # if line is empty, delete it
            s/n/ /g; # replace embedded newlines by spaces
            # (implicit print)






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Dec 17 '18 at 10:46

























            answered Dec 17 '18 at 6:52









            KusalanandaKusalananda

            126k16239393




            126k16239393

























                1














                Using awk:



                ~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
                module x(a,b,c)
                module y(d,e,f,
                g,h,i)
                module z(j,k,l)


                For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.






                share|improve this answer




























                  1














                  Using awk:



                  ~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
                  module x(a,b,c)
                  module y(d,e,f,
                  g,h,i)
                  module z(j,k,l)


                  For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.






                  share|improve this answer


























                    1












                    1








                    1







                    Using awk:



                    ~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
                    module x(a,b,c)
                    module y(d,e,f,
                    g,h,i)
                    module z(j,k,l)


                    For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.






                    share|improve this answer













                    Using awk:



                    ~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
                    module x(a,b,c)
                    module y(d,e,f,
                    g,h,i)
                    module z(j,k,l)


                    For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Dec 17 '18 at 6:52









                    murumuru

                    1




                    1























                        0














                        Another option: create an ed script!



                        This starts by pre-counting the number of joins that are required; it then generates that number of ed search & join commands and pipes them, along with a save & quit at the end, into ed:



                        #!/bin/bash
                        n=$(grep -c '^module *$' input)
                        {
                        for((i=1; i <= n; i++))
                        do
                        printf '/^module *$/n.,+1jn'
                        done
                        echo w
                        echo q
                        } | ed -s input >/dev/null





                        share|improve this answer




























                          0














                          Another option: create an ed script!



                          This starts by pre-counting the number of joins that are required; it then generates that number of ed search & join commands and pipes them, along with a save & quit at the end, into ed:



                          #!/bin/bash
                          n=$(grep -c '^module *$' input)
                          {
                          for((i=1; i <= n; i++))
                          do
                          printf '/^module *$/n.,+1jn'
                          done
                          echo w
                          echo q
                          } | ed -s input >/dev/null





                          share|improve this answer


























                            0












                            0








                            0







                            Another option: create an ed script!



                            This starts by pre-counting the number of joins that are required; it then generates that number of ed search & join commands and pipes them, along with a save & quit at the end, into ed:



                            #!/bin/bash
                            n=$(grep -c '^module *$' input)
                            {
                            for((i=1; i <= n; i++))
                            do
                            printf '/^module *$/n.,+1jn'
                            done
                            echo w
                            echo q
                            } | ed -s input >/dev/null





                            share|improve this answer













                            Another option: create an ed script!



                            This starts by pre-counting the number of joins that are required; it then generates that number of ed search & join commands and pipes them, along with a save & quit at the end, into ed:



                            #!/bin/bash
                            n=$(grep -c '^module *$' input)
                            {
                            for((i=1; i <= n; i++))
                            do
                            printf '/^module *$/n.,+1jn'
                            done
                            echo w
                            echo q
                            } | ed -s input >/dev/null






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Jan 19 at 2:37









                            Jeff SchallerJeff Schaller

                            40.1k1054126




                            40.1k1054126






























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