javascript - consolidate multiple null/undefined checks
$begingroup$
My brain is fried from looking from looking at this for so long. Is there a more efficient way to do this code block. We have the ability to use es6 code too if that helps.
First it tries to set quantity to itemTemplateIDQty.value
if itemTemplateQty
is not valid and itemTemplateIDQty
is valid. Then it basically checks the opposite and sets quantity to itemTemplateQty.value
. I'm thinking since in that else block, I am simply checking the exact opposite, I shouldn't need to retype all that code again. Also I'm wondering if I can remove a lot of code by using something like quantity = itemTemplateIDQty.value || 1;
.
Update
I'll try to sum up the code more clearly. The default value for quantity
should be 1 if all the checks fail. First if there are no classes of itemTemplateQty
found and 1+ classes of 'itemTemplateQty' + itemId
found then set quantity to the value of the first class found of 'itemTemplateQty' + itemId
. If that check fails, then check if no classes of 'itemTemplateQty' + itemId
are found and 1+ classes of itemTemplateQty
are found, set quantity
to the value of the first class of itemTemplateQty
.
let itemId = 5;
let isDynamicRecommendation = false;
let itemTemplateQty =
document.getElementsByClassName('itemTemplateQty').length > 0 ? document.getElementsByClassName('itemTemplateQty') : null;
let itemTemplateIDQty =
document.getElementsByClassName('itemTemplateQty' + itemId).length > 0 ? document.getElementsByClassName('itemTemplateQty' + itemId) : null;
let quantity = 1;
if (!isDynamicRecommendation) {
if ((itemTemplateQty === null || itemTemplateQty.value == null || Number.parseInt(itemTemplateQty.value) <= 0) &&
(itemTemplateIDQty !== null && itemTemplateIDQty.value !== undefined && itemTemplateIDQty.value !== null && Number.parseInt(itemTemplateIDQty.value) > 0)) {
quantity = itemTemplateIDQty.value;
} else if ((itemTemplateIDQty === null || itemTemplateIDQty.value == null || Number.parseInt(itemTemplateIDQty.value) <= 0) &&
(itemTemplateQty !== null && itemTemplateQty.value !== undefined && itemTemplateQty.value !== null && Number.parseInt(itemTemplateQty.value) > 0)) {
quantity = itemTemplateQty.value;
}
}
console.log("quantity: ", quantity);
javascript
New contributor
$endgroup$
add a comment |
$begingroup$
My brain is fried from looking from looking at this for so long. Is there a more efficient way to do this code block. We have the ability to use es6 code too if that helps.
First it tries to set quantity to itemTemplateIDQty.value
if itemTemplateQty
is not valid and itemTemplateIDQty
is valid. Then it basically checks the opposite and sets quantity to itemTemplateQty.value
. I'm thinking since in that else block, I am simply checking the exact opposite, I shouldn't need to retype all that code again. Also I'm wondering if I can remove a lot of code by using something like quantity = itemTemplateIDQty.value || 1;
.
Update
I'll try to sum up the code more clearly. The default value for quantity
should be 1 if all the checks fail. First if there are no classes of itemTemplateQty
found and 1+ classes of 'itemTemplateQty' + itemId
found then set quantity to the value of the first class found of 'itemTemplateQty' + itemId
. If that check fails, then check if no classes of 'itemTemplateQty' + itemId
are found and 1+ classes of itemTemplateQty
are found, set quantity
to the value of the first class of itemTemplateQty
.
let itemId = 5;
let isDynamicRecommendation = false;
let itemTemplateQty =
document.getElementsByClassName('itemTemplateQty').length > 0 ? document.getElementsByClassName('itemTemplateQty') : null;
let itemTemplateIDQty =
document.getElementsByClassName('itemTemplateQty' + itemId).length > 0 ? document.getElementsByClassName('itemTemplateQty' + itemId) : null;
let quantity = 1;
if (!isDynamicRecommendation) {
if ((itemTemplateQty === null || itemTemplateQty.value == null || Number.parseInt(itemTemplateQty.value) <= 0) &&
(itemTemplateIDQty !== null && itemTemplateIDQty.value !== undefined && itemTemplateIDQty.value !== null && Number.parseInt(itemTemplateIDQty.value) > 0)) {
quantity = itemTemplateIDQty.value;
} else if ((itemTemplateIDQty === null || itemTemplateIDQty.value == null || Number.parseInt(itemTemplateIDQty.value) <= 0) &&
(itemTemplateQty !== null && itemTemplateQty.value !== undefined && itemTemplateQty.value !== null && Number.parseInt(itemTemplateQty.value) > 0)) {
quantity = itemTemplateQty.value;
}
}
console.log("quantity: ", quantity);
javascript
New contributor
$endgroup$
1
$begingroup$
Hey, welcome to Code Review! Please add some more information about what this code does and what the objects in it are (preferably with definitions). Don't forget to take the tour and have a look at our help center which contains a lot on what makes a good question here.
$endgroup$
– Graipher
6 hours ago
$begingroup$
I added more details to the question. Let me know if anything else is needed.
$endgroup$
– dmikester1
5 hours ago
1
$begingroup$
As Graipher said, you should provide more context for this code — ideally a live demo including the HTML form (press Ctrl-M in the question editor to make one). How many elements of classitemTemplateQty
anditemTemplateQty123
should there be? What is the expected behavior if there are none, or if there are more than one?
$endgroup$
– 200_success
5 hours ago
1
$begingroup$
Instead of reiterating what the code does, try telling us what goal of the code is, as if talking to a non-technical person.
$endgroup$
– 200_success
5 hours ago
add a comment |
$begingroup$
My brain is fried from looking from looking at this for so long. Is there a more efficient way to do this code block. We have the ability to use es6 code too if that helps.
First it tries to set quantity to itemTemplateIDQty.value
if itemTemplateQty
is not valid and itemTemplateIDQty
is valid. Then it basically checks the opposite and sets quantity to itemTemplateQty.value
. I'm thinking since in that else block, I am simply checking the exact opposite, I shouldn't need to retype all that code again. Also I'm wondering if I can remove a lot of code by using something like quantity = itemTemplateIDQty.value || 1;
.
Update
I'll try to sum up the code more clearly. The default value for quantity
should be 1 if all the checks fail. First if there are no classes of itemTemplateQty
found and 1+ classes of 'itemTemplateQty' + itemId
found then set quantity to the value of the first class found of 'itemTemplateQty' + itemId
. If that check fails, then check if no classes of 'itemTemplateQty' + itemId
are found and 1+ classes of itemTemplateQty
are found, set quantity
to the value of the first class of itemTemplateQty
.
let itemId = 5;
let isDynamicRecommendation = false;
let itemTemplateQty =
document.getElementsByClassName('itemTemplateQty').length > 0 ? document.getElementsByClassName('itemTemplateQty') : null;
let itemTemplateIDQty =
document.getElementsByClassName('itemTemplateQty' + itemId).length > 0 ? document.getElementsByClassName('itemTemplateQty' + itemId) : null;
let quantity = 1;
if (!isDynamicRecommendation) {
if ((itemTemplateQty === null || itemTemplateQty.value == null || Number.parseInt(itemTemplateQty.value) <= 0) &&
(itemTemplateIDQty !== null && itemTemplateIDQty.value !== undefined && itemTemplateIDQty.value !== null && Number.parseInt(itemTemplateIDQty.value) > 0)) {
quantity = itemTemplateIDQty.value;
} else if ((itemTemplateIDQty === null || itemTemplateIDQty.value == null || Number.parseInt(itemTemplateIDQty.value) <= 0) &&
(itemTemplateQty !== null && itemTemplateQty.value !== undefined && itemTemplateQty.value !== null && Number.parseInt(itemTemplateQty.value) > 0)) {
quantity = itemTemplateQty.value;
}
}
console.log("quantity: ", quantity);
javascript
New contributor
$endgroup$
My brain is fried from looking from looking at this for so long. Is there a more efficient way to do this code block. We have the ability to use es6 code too if that helps.
First it tries to set quantity to itemTemplateIDQty.value
if itemTemplateQty
is not valid and itemTemplateIDQty
is valid. Then it basically checks the opposite and sets quantity to itemTemplateQty.value
. I'm thinking since in that else block, I am simply checking the exact opposite, I shouldn't need to retype all that code again. Also I'm wondering if I can remove a lot of code by using something like quantity = itemTemplateIDQty.value || 1;
.
Update
I'll try to sum up the code more clearly. The default value for quantity
should be 1 if all the checks fail. First if there are no classes of itemTemplateQty
found and 1+ classes of 'itemTemplateQty' + itemId
found then set quantity to the value of the first class found of 'itemTemplateQty' + itemId
. If that check fails, then check if no classes of 'itemTemplateQty' + itemId
are found and 1+ classes of itemTemplateQty
are found, set quantity
to the value of the first class of itemTemplateQty
.
let itemId = 5;
let isDynamicRecommendation = false;
let itemTemplateQty =
document.getElementsByClassName('itemTemplateQty').length > 0 ? document.getElementsByClassName('itemTemplateQty') : null;
let itemTemplateIDQty =
document.getElementsByClassName('itemTemplateQty' + itemId).length > 0 ? document.getElementsByClassName('itemTemplateQty' + itemId) : null;
let quantity = 1;
if (!isDynamicRecommendation) {
if ((itemTemplateQty === null || itemTemplateQty.value == null || Number.parseInt(itemTemplateQty.value) <= 0) &&
(itemTemplateIDQty !== null && itemTemplateIDQty.value !== undefined && itemTemplateIDQty.value !== null && Number.parseInt(itemTemplateIDQty.value) > 0)) {
quantity = itemTemplateIDQty.value;
} else if ((itemTemplateIDQty === null || itemTemplateIDQty.value == null || Number.parseInt(itemTemplateIDQty.value) <= 0) &&
(itemTemplateQty !== null && itemTemplateQty.value !== undefined && itemTemplateQty.value !== null && Number.parseInt(itemTemplateQty.value) > 0)) {
quantity = itemTemplateQty.value;
}
}
console.log("quantity: ", quantity);
let itemId = 5;
let isDynamicRecommendation = false;
let itemTemplateQty =
document.getElementsByClassName('itemTemplateQty').length > 0 ? document.getElementsByClassName('itemTemplateQty') : null;
let itemTemplateIDQty =
document.getElementsByClassName('itemTemplateQty' + itemId).length > 0 ? document.getElementsByClassName('itemTemplateQty' + itemId) : null;
let quantity = 1;
if (!isDynamicRecommendation) {
if ((itemTemplateQty === null || itemTemplateQty.value == null || Number.parseInt(itemTemplateQty.value) <= 0) &&
(itemTemplateIDQty !== null && itemTemplateIDQty.value !== undefined && itemTemplateIDQty.value !== null && Number.parseInt(itemTemplateIDQty.value) > 0)) {
quantity = itemTemplateIDQty.value;
} else if ((itemTemplateIDQty === null || itemTemplateIDQty.value == null || Number.parseInt(itemTemplateIDQty.value) <= 0) &&
(itemTemplateQty !== null && itemTemplateQty.value !== undefined && itemTemplateQty.value !== null && Number.parseInt(itemTemplateQty.value) > 0)) {
quantity = itemTemplateQty.value;
}
}
console.log("quantity: ", quantity);
let itemId = 5;
let isDynamicRecommendation = false;
let itemTemplateQty =
document.getElementsByClassName('itemTemplateQty').length > 0 ? document.getElementsByClassName('itemTemplateQty') : null;
let itemTemplateIDQty =
document.getElementsByClassName('itemTemplateQty' + itemId).length > 0 ? document.getElementsByClassName('itemTemplateQty' + itemId) : null;
let quantity = 1;
if (!isDynamicRecommendation) {
if ((itemTemplateQty === null || itemTemplateQty.value == null || Number.parseInt(itemTemplateQty.value) <= 0) &&
(itemTemplateIDQty !== null && itemTemplateIDQty.value !== undefined && itemTemplateIDQty.value !== null && Number.parseInt(itemTemplateIDQty.value) > 0)) {
quantity = itemTemplateIDQty.value;
} else if ((itemTemplateIDQty === null || itemTemplateIDQty.value == null || Number.parseInt(itemTemplateIDQty.value) <= 0) &&
(itemTemplateQty !== null && itemTemplateQty.value !== undefined && itemTemplateQty.value !== null && Number.parseInt(itemTemplateQty.value) > 0)) {
quantity = itemTemplateQty.value;
}
}
console.log("quantity: ", quantity);
javascript
javascript
New contributor
New contributor
edited 5 hours ago
dmikester1
New contributor
asked 6 hours ago
dmikester1dmikester1
1115
1115
New contributor
New contributor
1
$begingroup$
Hey, welcome to Code Review! Please add some more information about what this code does and what the objects in it are (preferably with definitions). Don't forget to take the tour and have a look at our help center which contains a lot on what makes a good question here.
$endgroup$
– Graipher
6 hours ago
$begingroup$
I added more details to the question. Let me know if anything else is needed.
$endgroup$
– dmikester1
5 hours ago
1
$begingroup$
As Graipher said, you should provide more context for this code — ideally a live demo including the HTML form (press Ctrl-M in the question editor to make one). How many elements of classitemTemplateQty
anditemTemplateQty123
should there be? What is the expected behavior if there are none, or if there are more than one?
$endgroup$
– 200_success
5 hours ago
1
$begingroup$
Instead of reiterating what the code does, try telling us what goal of the code is, as if talking to a non-technical person.
$endgroup$
– 200_success
5 hours ago
add a comment |
1
$begingroup$
Hey, welcome to Code Review! Please add some more information about what this code does and what the objects in it are (preferably with definitions). Don't forget to take the tour and have a look at our help center which contains a lot on what makes a good question here.
$endgroup$
– Graipher
6 hours ago
$begingroup$
I added more details to the question. Let me know if anything else is needed.
$endgroup$
– dmikester1
5 hours ago
1
$begingroup$
As Graipher said, you should provide more context for this code — ideally a live demo including the HTML form (press Ctrl-M in the question editor to make one). How many elements of classitemTemplateQty
anditemTemplateQty123
should there be? What is the expected behavior if there are none, or if there are more than one?
$endgroup$
– 200_success
5 hours ago
1
$begingroup$
Instead of reiterating what the code does, try telling us what goal of the code is, as if talking to a non-technical person.
$endgroup$
– 200_success
5 hours ago
1
1
$begingroup$
Hey, welcome to Code Review! Please add some more information about what this code does and what the objects in it are (preferably with definitions). Don't forget to take the tour and have a look at our help center which contains a lot on what makes a good question here.
$endgroup$
– Graipher
6 hours ago
$begingroup$
Hey, welcome to Code Review! Please add some more information about what this code does and what the objects in it are (preferably with definitions). Don't forget to take the tour and have a look at our help center which contains a lot on what makes a good question here.
$endgroup$
– Graipher
6 hours ago
$begingroup$
I added more details to the question. Let me know if anything else is needed.
$endgroup$
– dmikester1
5 hours ago
$begingroup$
I added more details to the question. Let me know if anything else is needed.
$endgroup$
– dmikester1
5 hours ago
1
1
$begingroup$
As Graipher said, you should provide more context for this code — ideally a live demo including the HTML form (press Ctrl-M in the question editor to make one). How many elements of class
itemTemplateQty
and itemTemplateQty123
should there be? What is the expected behavior if there are none, or if there are more than one?$endgroup$
– 200_success
5 hours ago
$begingroup$
As Graipher said, you should provide more context for this code — ideally a live demo including the HTML form (press Ctrl-M in the question editor to make one). How many elements of class
itemTemplateQty
and itemTemplateQty123
should there be? What is the expected behavior if there are none, or if there are more than one?$endgroup$
– 200_success
5 hours ago
1
1
$begingroup$
Instead of reiterating what the code does, try telling us what goal of the code is, as if talking to a non-technical person.
$endgroup$
– 200_success
5 hours ago
$begingroup$
Instead of reiterating what the code does, try telling us what goal of the code is, as if talking to a non-technical person.
$endgroup$
– 200_success
5 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
.getElementsByClassName()
returns an HTMLCollection
, not a single element. You can use bracket notation [n]
to get an element at index n
of the collection returned.
One if
statement can be used to evalaute !itemData.isDynamicRecommendation
. One if..else..if
can be used to evaluate itemTemplateQty[0] && itemTemplateQty[0].value <= 0
or itemTemplateIDQty[0] && itemTemplateIDQty[0].value <= 0
.
To convert the string .value
to an integer you can use +
operator preceding +itemTemplateQty[0].value.value
or alternatively use .valueAsNumber
.
let itemData = 5;
let isDynamicRecommendation = false;
let itemTemplateQty = document.getElementsByClassName('itemTemplateQty')[0];
let itemTemplateIDQty = document.getElementsByClassName('itemTemplateQty' + itemData)[0];
let quantity = 1;
if (!isDynamicRecommendation) {
if (itemTemplateQty && itemTemplateQty.value <= 0) {
quantity = +itemTemplateQty.value;
} else if (itemTemplateIDQty && itemTemplateIDQty.value <= 0) {
quantity = +itemTemplateIDQty.value;
}
}
console.log({quantity});
$endgroup$
$begingroup$
Wouldn't you want this and the next one to be||
not&&
?if (itemTemplateQty && itemTemplateQty[0].value <= 0) {
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1 Not sure what you mean?
$endgroup$
– guest271314
5 hours ago
$begingroup$
the if and else if should have or's not and's I think
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1if..else
could essentially be considered an OR gate. The code could be re-written many different ways. For example, conditional operator could be substituted forif
andif..else
. One issue with the code at the question was not using bracket notation to get a specific element in the returned collection, resulting in false positive results. Isquantity
expected to be an integer or a string?
$endgroup$
– guest271314
5 hours ago
$begingroup$
quantity
should be an integer
$endgroup$
– dmikester1
5 hours ago
|
show 5 more comments
$begingroup$
Without the HTML it is hard to workout what is wanted.
General point
- Use
const
for variables that do not change. - Use functions to do common tasks, they simplify the code by reducing its size.
- Don't test more that you need to. If a is true then you know its not false, you don't then test if its not false.
- The statement
if (!isDynamicRecommendation) {
is always true and not needed. (A reminder that at codeReview code must not be example code, we assume this is production code) - Use
querySelector
if you are after just the first instance of an element. It returnsnull
if nothing is found. - The code given should be as a function.
Names ar poor and too verbose. We read words by their shape especially when they are more than half a dozen characters long. Long names means it's hard to spot errors. This is especially bad in JS as it does not care if you use an undefined variable names.
itemTemplateQty
anditemTemplateIDQty
if you have a single line with these variables repeated 7 times. Can you spot the error in the following?itemTemplateQty, itemTemplateQty, itemTemplateQty, itemTemplateIDQty, itemTemplateIDQty, itemTemplate1DQty, itemTemplateIDQty
You know its an
item
. thetemplate
part is irrelevant, the only important part is to differentiate the ID (BTWId
should have a lowercased
),qty
andqtyId
would be better.
Now spot the same error
qty, qty, qty, qtyId, qtyId, qty1d, qtyId
itemId
??? Have no idea what this actually is?
Example
By using two functions we can greatly reduce the complexity of the code. Removing the overly verbose names also make things easier on the eyes, and helps prevent brain fry.
function getQuantity() {
const query = id => document.querySelector(".itemTemplateQty" + id);
const valid = item => item && !isNaN(item.value) && Number(item.value) > 0.5;
const qty = query(""), qtyId = query("5");
return Math.round(valid(qty) ?
(!valid(qtyId) ? qty.value : 1) :
( valid(qtyId) ? qtyId.value : 1));
}
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
.getElementsByClassName()
returns an HTMLCollection
, not a single element. You can use bracket notation [n]
to get an element at index n
of the collection returned.
One if
statement can be used to evalaute !itemData.isDynamicRecommendation
. One if..else..if
can be used to evaluate itemTemplateQty[0] && itemTemplateQty[0].value <= 0
or itemTemplateIDQty[0] && itemTemplateIDQty[0].value <= 0
.
To convert the string .value
to an integer you can use +
operator preceding +itemTemplateQty[0].value.value
or alternatively use .valueAsNumber
.
let itemData = 5;
let isDynamicRecommendation = false;
let itemTemplateQty = document.getElementsByClassName('itemTemplateQty')[0];
let itemTemplateIDQty = document.getElementsByClassName('itemTemplateQty' + itemData)[0];
let quantity = 1;
if (!isDynamicRecommendation) {
if (itemTemplateQty && itemTemplateQty.value <= 0) {
quantity = +itemTemplateQty.value;
} else if (itemTemplateIDQty && itemTemplateIDQty.value <= 0) {
quantity = +itemTemplateIDQty.value;
}
}
console.log({quantity});
$endgroup$
$begingroup$
Wouldn't you want this and the next one to be||
not&&
?if (itemTemplateQty && itemTemplateQty[0].value <= 0) {
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1 Not sure what you mean?
$endgroup$
– guest271314
5 hours ago
$begingroup$
the if and else if should have or's not and's I think
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1if..else
could essentially be considered an OR gate. The code could be re-written many different ways. For example, conditional operator could be substituted forif
andif..else
. One issue with the code at the question was not using bracket notation to get a specific element in the returned collection, resulting in false positive results. Isquantity
expected to be an integer or a string?
$endgroup$
– guest271314
5 hours ago
$begingroup$
quantity
should be an integer
$endgroup$
– dmikester1
5 hours ago
|
show 5 more comments
$begingroup$
.getElementsByClassName()
returns an HTMLCollection
, not a single element. You can use bracket notation [n]
to get an element at index n
of the collection returned.
One if
statement can be used to evalaute !itemData.isDynamicRecommendation
. One if..else..if
can be used to evaluate itemTemplateQty[0] && itemTemplateQty[0].value <= 0
or itemTemplateIDQty[0] && itemTemplateIDQty[0].value <= 0
.
To convert the string .value
to an integer you can use +
operator preceding +itemTemplateQty[0].value.value
or alternatively use .valueAsNumber
.
let itemData = 5;
let isDynamicRecommendation = false;
let itemTemplateQty = document.getElementsByClassName('itemTemplateQty')[0];
let itemTemplateIDQty = document.getElementsByClassName('itemTemplateQty' + itemData)[0];
let quantity = 1;
if (!isDynamicRecommendation) {
if (itemTemplateQty && itemTemplateQty.value <= 0) {
quantity = +itemTemplateQty.value;
} else if (itemTemplateIDQty && itemTemplateIDQty.value <= 0) {
quantity = +itemTemplateIDQty.value;
}
}
console.log({quantity});
$endgroup$
$begingroup$
Wouldn't you want this and the next one to be||
not&&
?if (itemTemplateQty && itemTemplateQty[0].value <= 0) {
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1 Not sure what you mean?
$endgroup$
– guest271314
5 hours ago
$begingroup$
the if and else if should have or's not and's I think
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1if..else
could essentially be considered an OR gate. The code could be re-written many different ways. For example, conditional operator could be substituted forif
andif..else
. One issue with the code at the question was not using bracket notation to get a specific element in the returned collection, resulting in false positive results. Isquantity
expected to be an integer or a string?
$endgroup$
– guest271314
5 hours ago
$begingroup$
quantity
should be an integer
$endgroup$
– dmikester1
5 hours ago
|
show 5 more comments
$begingroup$
.getElementsByClassName()
returns an HTMLCollection
, not a single element. You can use bracket notation [n]
to get an element at index n
of the collection returned.
One if
statement can be used to evalaute !itemData.isDynamicRecommendation
. One if..else..if
can be used to evaluate itemTemplateQty[0] && itemTemplateQty[0].value <= 0
or itemTemplateIDQty[0] && itemTemplateIDQty[0].value <= 0
.
To convert the string .value
to an integer you can use +
operator preceding +itemTemplateQty[0].value.value
or alternatively use .valueAsNumber
.
let itemData = 5;
let isDynamicRecommendation = false;
let itemTemplateQty = document.getElementsByClassName('itemTemplateQty')[0];
let itemTemplateIDQty = document.getElementsByClassName('itemTemplateQty' + itemData)[0];
let quantity = 1;
if (!isDynamicRecommendation) {
if (itemTemplateQty && itemTemplateQty.value <= 0) {
quantity = +itemTemplateQty.value;
} else if (itemTemplateIDQty && itemTemplateIDQty.value <= 0) {
quantity = +itemTemplateIDQty.value;
}
}
console.log({quantity});
$endgroup$
.getElementsByClassName()
returns an HTMLCollection
, not a single element. You can use bracket notation [n]
to get an element at index n
of the collection returned.
One if
statement can be used to evalaute !itemData.isDynamicRecommendation
. One if..else..if
can be used to evaluate itemTemplateQty[0] && itemTemplateQty[0].value <= 0
or itemTemplateIDQty[0] && itemTemplateIDQty[0].value <= 0
.
To convert the string .value
to an integer you can use +
operator preceding +itemTemplateQty[0].value.value
or alternatively use .valueAsNumber
.
let itemData = 5;
let isDynamicRecommendation = false;
let itemTemplateQty = document.getElementsByClassName('itemTemplateQty')[0];
let itemTemplateIDQty = document.getElementsByClassName('itemTemplateQty' + itemData)[0];
let quantity = 1;
if (!isDynamicRecommendation) {
if (itemTemplateQty && itemTemplateQty.value <= 0) {
quantity = +itemTemplateQty.value;
} else if (itemTemplateIDQty && itemTemplateIDQty.value <= 0) {
quantity = +itemTemplateIDQty.value;
}
}
console.log({quantity});
let itemData = 5;
let isDynamicRecommendation = false;
let itemTemplateQty = document.getElementsByClassName('itemTemplateQty')[0];
let itemTemplateIDQty = document.getElementsByClassName('itemTemplateQty' + itemData)[0];
let quantity = 1;
if (!isDynamicRecommendation) {
if (itemTemplateQty && itemTemplateQty.value <= 0) {
quantity = +itemTemplateQty.value;
} else if (itemTemplateIDQty && itemTemplateIDQty.value <= 0) {
quantity = +itemTemplateIDQty.value;
}
}
console.log({quantity});
let itemData = 5;
let isDynamicRecommendation = false;
let itemTemplateQty = document.getElementsByClassName('itemTemplateQty')[0];
let itemTemplateIDQty = document.getElementsByClassName('itemTemplateQty' + itemData)[0];
let quantity = 1;
if (!isDynamicRecommendation) {
if (itemTemplateQty && itemTemplateQty.value <= 0) {
quantity = +itemTemplateQty.value;
} else if (itemTemplateIDQty && itemTemplateIDQty.value <= 0) {
quantity = +itemTemplateIDQty.value;
}
}
console.log({quantity});
edited 5 hours ago
answered 5 hours ago
guest271314guest271314
38018
38018
$begingroup$
Wouldn't you want this and the next one to be||
not&&
?if (itemTemplateQty && itemTemplateQty[0].value <= 0) {
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1 Not sure what you mean?
$endgroup$
– guest271314
5 hours ago
$begingroup$
the if and else if should have or's not and's I think
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1if..else
could essentially be considered an OR gate. The code could be re-written many different ways. For example, conditional operator could be substituted forif
andif..else
. One issue with the code at the question was not using bracket notation to get a specific element in the returned collection, resulting in false positive results. Isquantity
expected to be an integer or a string?
$endgroup$
– guest271314
5 hours ago
$begingroup$
quantity
should be an integer
$endgroup$
– dmikester1
5 hours ago
|
show 5 more comments
$begingroup$
Wouldn't you want this and the next one to be||
not&&
?if (itemTemplateQty && itemTemplateQty[0].value <= 0) {
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1 Not sure what you mean?
$endgroup$
– guest271314
5 hours ago
$begingroup$
the if and else if should have or's not and's I think
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1if..else
could essentially be considered an OR gate. The code could be re-written many different ways. For example, conditional operator could be substituted forif
andif..else
. One issue with the code at the question was not using bracket notation to get a specific element in the returned collection, resulting in false positive results. Isquantity
expected to be an integer or a string?
$endgroup$
– guest271314
5 hours ago
$begingroup$
quantity
should be an integer
$endgroup$
– dmikester1
5 hours ago
$begingroup$
Wouldn't you want this and the next one to be
||
not &&
? if (itemTemplateQty && itemTemplateQty[0].value <= 0) {
$endgroup$
– dmikester1
5 hours ago
$begingroup$
Wouldn't you want this and the next one to be
||
not &&
? if (itemTemplateQty && itemTemplateQty[0].value <= 0) {
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1 Not sure what you mean?
$endgroup$
– guest271314
5 hours ago
$begingroup$
@dmikester1 Not sure what you mean?
$endgroup$
– guest271314
5 hours ago
$begingroup$
the if and else if should have or's not and's I think
$endgroup$
– dmikester1
5 hours ago
$begingroup$
the if and else if should have or's not and's I think
$endgroup$
– dmikester1
5 hours ago
$begingroup$
@dmikester1
if..else
could essentially be considered an OR gate. The code could be re-written many different ways. For example, conditional operator could be substituted for if
and if..else
. One issue with the code at the question was not using bracket notation to get a specific element in the returned collection, resulting in false positive results. Is quantity
expected to be an integer or a string?$endgroup$
– guest271314
5 hours ago
$begingroup$
@dmikester1
if..else
could essentially be considered an OR gate. The code could be re-written many different ways. For example, conditional operator could be substituted for if
and if..else
. One issue with the code at the question was not using bracket notation to get a specific element in the returned collection, resulting in false positive results. Is quantity
expected to be an integer or a string?$endgroup$
– guest271314
5 hours ago
$begingroup$
quantity
should be an integer$endgroup$
– dmikester1
5 hours ago
$begingroup$
quantity
should be an integer$endgroup$
– dmikester1
5 hours ago
|
show 5 more comments
$begingroup$
Without the HTML it is hard to workout what is wanted.
General point
- Use
const
for variables that do not change. - Use functions to do common tasks, they simplify the code by reducing its size.
- Don't test more that you need to. If a is true then you know its not false, you don't then test if its not false.
- The statement
if (!isDynamicRecommendation) {
is always true and not needed. (A reminder that at codeReview code must not be example code, we assume this is production code) - Use
querySelector
if you are after just the first instance of an element. It returnsnull
if nothing is found. - The code given should be as a function.
Names ar poor and too verbose. We read words by their shape especially when they are more than half a dozen characters long. Long names means it's hard to spot errors. This is especially bad in JS as it does not care if you use an undefined variable names.
itemTemplateQty
anditemTemplateIDQty
if you have a single line with these variables repeated 7 times. Can you spot the error in the following?itemTemplateQty, itemTemplateQty, itemTemplateQty, itemTemplateIDQty, itemTemplateIDQty, itemTemplate1DQty, itemTemplateIDQty
You know its an
item
. thetemplate
part is irrelevant, the only important part is to differentiate the ID (BTWId
should have a lowercased
),qty
andqtyId
would be better.
Now spot the same error
qty, qty, qty, qtyId, qtyId, qty1d, qtyId
itemId
??? Have no idea what this actually is?
Example
By using two functions we can greatly reduce the complexity of the code. Removing the overly verbose names also make things easier on the eyes, and helps prevent brain fry.
function getQuantity() {
const query = id => document.querySelector(".itemTemplateQty" + id);
const valid = item => item && !isNaN(item.value) && Number(item.value) > 0.5;
const qty = query(""), qtyId = query("5");
return Math.round(valid(qty) ?
(!valid(qtyId) ? qty.value : 1) :
( valid(qtyId) ? qtyId.value : 1));
}
$endgroup$
add a comment |
$begingroup$
Without the HTML it is hard to workout what is wanted.
General point
- Use
const
for variables that do not change. - Use functions to do common tasks, they simplify the code by reducing its size.
- Don't test more that you need to. If a is true then you know its not false, you don't then test if its not false.
- The statement
if (!isDynamicRecommendation) {
is always true and not needed. (A reminder that at codeReview code must not be example code, we assume this is production code) - Use
querySelector
if you are after just the first instance of an element. It returnsnull
if nothing is found. - The code given should be as a function.
Names ar poor and too verbose. We read words by their shape especially when they are more than half a dozen characters long. Long names means it's hard to spot errors. This is especially bad in JS as it does not care if you use an undefined variable names.
itemTemplateQty
anditemTemplateIDQty
if you have a single line with these variables repeated 7 times. Can you spot the error in the following?itemTemplateQty, itemTemplateQty, itemTemplateQty, itemTemplateIDQty, itemTemplateIDQty, itemTemplate1DQty, itemTemplateIDQty
You know its an
item
. thetemplate
part is irrelevant, the only important part is to differentiate the ID (BTWId
should have a lowercased
),qty
andqtyId
would be better.
Now spot the same error
qty, qty, qty, qtyId, qtyId, qty1d, qtyId
itemId
??? Have no idea what this actually is?
Example
By using two functions we can greatly reduce the complexity of the code. Removing the overly verbose names also make things easier on the eyes, and helps prevent brain fry.
function getQuantity() {
const query = id => document.querySelector(".itemTemplateQty" + id);
const valid = item => item && !isNaN(item.value) && Number(item.value) > 0.5;
const qty = query(""), qtyId = query("5");
return Math.round(valid(qty) ?
(!valid(qtyId) ? qty.value : 1) :
( valid(qtyId) ? qtyId.value : 1));
}
$endgroup$
add a comment |
$begingroup$
Without the HTML it is hard to workout what is wanted.
General point
- Use
const
for variables that do not change. - Use functions to do common tasks, they simplify the code by reducing its size.
- Don't test more that you need to. If a is true then you know its not false, you don't then test if its not false.
- The statement
if (!isDynamicRecommendation) {
is always true and not needed. (A reminder that at codeReview code must not be example code, we assume this is production code) - Use
querySelector
if you are after just the first instance of an element. It returnsnull
if nothing is found. - The code given should be as a function.
Names ar poor and too verbose. We read words by their shape especially when they are more than half a dozen characters long. Long names means it's hard to spot errors. This is especially bad in JS as it does not care if you use an undefined variable names.
itemTemplateQty
anditemTemplateIDQty
if you have a single line with these variables repeated 7 times. Can you spot the error in the following?itemTemplateQty, itemTemplateQty, itemTemplateQty, itemTemplateIDQty, itemTemplateIDQty, itemTemplate1DQty, itemTemplateIDQty
You know its an
item
. thetemplate
part is irrelevant, the only important part is to differentiate the ID (BTWId
should have a lowercased
),qty
andqtyId
would be better.
Now spot the same error
qty, qty, qty, qtyId, qtyId, qty1d, qtyId
itemId
??? Have no idea what this actually is?
Example
By using two functions we can greatly reduce the complexity of the code. Removing the overly verbose names also make things easier on the eyes, and helps prevent brain fry.
function getQuantity() {
const query = id => document.querySelector(".itemTemplateQty" + id);
const valid = item => item && !isNaN(item.value) && Number(item.value) > 0.5;
const qty = query(""), qtyId = query("5");
return Math.round(valid(qty) ?
(!valid(qtyId) ? qty.value : 1) :
( valid(qtyId) ? qtyId.value : 1));
}
$endgroup$
Without the HTML it is hard to workout what is wanted.
General point
- Use
const
for variables that do not change. - Use functions to do common tasks, they simplify the code by reducing its size.
- Don't test more that you need to. If a is true then you know its not false, you don't then test if its not false.
- The statement
if (!isDynamicRecommendation) {
is always true and not needed. (A reminder that at codeReview code must not be example code, we assume this is production code) - Use
querySelector
if you are after just the first instance of an element. It returnsnull
if nothing is found. - The code given should be as a function.
Names ar poor and too verbose. We read words by their shape especially when they are more than half a dozen characters long. Long names means it's hard to spot errors. This is especially bad in JS as it does not care if you use an undefined variable names.
itemTemplateQty
anditemTemplateIDQty
if you have a single line with these variables repeated 7 times. Can you spot the error in the following?itemTemplateQty, itemTemplateQty, itemTemplateQty, itemTemplateIDQty, itemTemplateIDQty, itemTemplate1DQty, itemTemplateIDQty
You know its an
item
. thetemplate
part is irrelevant, the only important part is to differentiate the ID (BTWId
should have a lowercased
),qty
andqtyId
would be better.
Now spot the same error
qty, qty, qty, qtyId, qtyId, qty1d, qtyId
itemId
??? Have no idea what this actually is?
Example
By using two functions we can greatly reduce the complexity of the code. Removing the overly verbose names also make things easier on the eyes, and helps prevent brain fry.
function getQuantity() {
const query = id => document.querySelector(".itemTemplateQty" + id);
const valid = item => item && !isNaN(item.value) && Number(item.value) > 0.5;
const qty = query(""), qtyId = query("5");
return Math.round(valid(qty) ?
(!valid(qtyId) ? qty.value : 1) :
( valid(qtyId) ? qtyId.value : 1));
}
answered 2 hours ago
Blindman67Blindman67
7,3811521
7,3811521
add a comment |
add a comment |
dmikester1 is a new contributor. Be nice, and check out our Code of Conduct.
dmikester1 is a new contributor. Be nice, and check out our Code of Conduct.
dmikester1 is a new contributor. Be nice, and check out our Code of Conduct.
dmikester1 is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
Hey, welcome to Code Review! Please add some more information about what this code does and what the objects in it are (preferably with definitions). Don't forget to take the tour and have a look at our help center which contains a lot on what makes a good question here.
$endgroup$
– Graipher
6 hours ago
$begingroup$
I added more details to the question. Let me know if anything else is needed.
$endgroup$
– dmikester1
5 hours ago
1
$begingroup$
As Graipher said, you should provide more context for this code — ideally a live demo including the HTML form (press Ctrl-M in the question editor to make one). How many elements of class
itemTemplateQty
anditemTemplateQty123
should there be? What is the expected behavior if there are none, or if there are more than one?$endgroup$
– 200_success
5 hours ago
1
$begingroup$
Instead of reiterating what the code does, try telling us what goal of the code is, as if talking to a non-technical person.
$endgroup$
– 200_success
5 hours ago