square the elements of a sorted list and give the output in sorted order












0












$begingroup$



Given a sorted list of integers, square the elements and give the
output in sorted order.



For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].




My solution 1:



const square = el => el * el;

const sortAsc = (a, b) => a - b;

const sortSquare = list => list

  .map(square)

  .sort(sortAsc);



console.log(sortSquare([-9, -2, 0, 2, 3]));


My solution 2:



const sortSquare2 = list => {

  const result = ;

  list.sort((a, b) => Math.abs(a) - Math.abs(b));

  for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }

  return result;

};



console.log(sortSquare2([-9, -2, 0, 2, 3]));


Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.






javascript algorithm programming-challenge functional-programming ecmascript-6







share|improve this question









$endgroup$

















    0












    $begingroup$



    Given a sorted list of integers, square the elements and give the
    output in sorted order.



    For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].




    My solution 1:



    const square = el => el * el;
    
const sortAsc = (a, b) => a - b;
    
const sortSquare = list => list
    
  .map(square)
    
  .sort(sortAsc);
    

    
console.log(sortSquare([-9, -2, 0, 2, 3]));


    My solution 2:



    const sortSquare2 = list => {
    
  const result = ;
    
  list.sort((a, b) => Math.abs(a) - Math.abs(b));
    
  for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
    
  return result;
    
};
    

    
console.log(sortSquare2([-9, -2, 0, 2, 3]));


    Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.






    javascript algorithm programming-challenge functional-programming ecmascript-6







    share|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$



      Given a sorted list of integers, square the elements and give the
      output in sorted order.



      For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].




      My solution 1:



      const square = el => el * el;
      
const sortAsc = (a, b) => a - b;
      
const sortSquare = list => list
      
  .map(square)
      
  .sort(sortAsc);
      

      
console.log(sortSquare([-9, -2, 0, 2, 3]));


      My solution 2:



      const sortSquare2 = list => {
      
  const result = ;
      
  list.sort((a, b) => Math.abs(a) - Math.abs(b));
      
  for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
      
  return result;
      
};
      

      
console.log(sortSquare2([-9, -2, 0, 2, 3]));


      Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.






      javascript algorithm programming-challenge functional-programming ecmascript-6







      share|improve this question









      $endgroup$





      Given a sorted list of integers, square the elements and give the
      output in sorted order.



      For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].




      My solution 1:



      const square = el => el * el;
      
const sortAsc = (a, b) => a - b;
      
const sortSquare = list => list
      
  .map(square)
      
  .sort(sortAsc);
      

      
console.log(sortSquare([-9, -2, 0, 2, 3]));


      My solution 2:



      const sortSquare2 = list => {
      
  const result = ;
      
  list.sort((a, b) => Math.abs(a) - Math.abs(b));
      
  for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
      
  return result;
      
};
      

      
console.log(sortSquare2([-9, -2, 0, 2, 3]));


      Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.






      javascript algorithm programming-challenge functional-programming ecmascript-6




      javascript algorithm programming-challenge functional-programming ecmascript-6






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










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