Python checking end of file before last iteration [on hold]

i have this loop processing a csv i get to the last line and i get an error because it tries to read empty line and kills program how would i check here for that ?

while True:

     if  in_file.closed: break

     lines = line.strip()

     if len(lines) > 0:

         print (line ,"line1")

         src_ip, src_port, dst_ip, dst_port, msg = lines.split(',')

         src = '{}:{}'.format(src_ip, src_port)

         dst = '{}:{}'.format(dst_ip, dst_port)

     if  in_file is None: 

        break



     else:

         line2 =next(in_file)

         print(line2)

         lines2 = line2.strip()

the point where it stops is on the line2 =next(in_file)
i get this error from my run ------
Traceback (most recent call last):
File "C:Usersmattseclipse-workspacemy_projectsrcpostprocesspost_process.py", line 74, in
line2 =next(in_file)
StopIteration

new to python so any help appreciated Thanks

asked 2 hours ago

mKalita

New contributor

put on hold as off-topic by l0b0, Austin Hastings, Vogel612♦ 1 hour ago

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – l0b0, Austin Hastings, Vogel612

If this question can be reworded to fit the rules in the help center, please edit the question.

$begingroup$
Welcome to Code Review! I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
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– Vogel612♦
1 hour ago

add a comment |

i have this loop processing a csv i get to the last line and i get an error because it tries to read empty line and kills program how would i check here for that ?

while True:

     if  in_file.closed: break

     lines = line.strip()

     if len(lines) > 0:

         print (line ,"line1")

         src_ip, src_port, dst_ip, dst_port, msg = lines.split(',')

         src = '{}:{}'.format(src_ip, src_port)

         dst = '{}:{}'.format(dst_ip, dst_port)

     if  in_file is None: 

        break



     else:

         line2 =next(in_file)

         print(line2)

         lines2 = line2.strip()

new to python so any help appreciated Thanks

asked 2 hours ago

mKalita

New contributor

put on hold as off-topic by l0b0, Austin Hastings, Vogel612♦ 1 hour ago

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – l0b0, Austin Hastings, Vogel612

If this question can be reworded to fit the rules in the help center, please edit the question.

$begingroup$
Welcome to Code Review! I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
$endgroup$
– Vogel612♦
1 hour ago

add a comment |

i have this loop processing a csv i get to the last line and i get an error because it tries to read empty line and kills program how would i check here for that ?

while True:

     if  in_file.closed: break

     lines = line.strip()

     if len(lines) > 0:

         print (line ,"line1")

         src_ip, src_port, dst_ip, dst_port, msg = lines.split(',')

         src = '{}:{}'.format(src_ip, src_port)

         dst = '{}:{}'.format(dst_ip, dst_port)

     if  in_file is None: 

        break



     else:

         line2 =next(in_file)

         print(line2)

         lines2 = line2.strip()

new to python so any help appreciated Thanks

asked 2 hours ago

mKalita

New contributor

i have this loop processing a csv i get to the last line and i get an error because it tries to read empty line and kills program how would i check here for that ?

while True:

     if  in_file.closed: break

     lines = line.strip()

     if len(lines) > 0:

         print (line ,"line1")

         src_ip, src_port, dst_ip, dst_port, msg = lines.split(',')

         src = '{}:{}'.format(src_ip, src_port)

         dst = '{}:{}'.format(dst_ip, dst_port)

     if  in_file is None: 

        break



     else:

         line2 =next(in_file)

         print(line2)

         lines2 = line2.strip()

new to python so any help appreciated Thanks

python

asked 2 hours ago

mKalita

New contributor

asked 2 hours ago

mKalita

New contributor

asked 2 hours ago

mKalita

New contributor

asked 2 hours ago

mKalita

asked 2 hours ago

mKalita

New contributor

mKalita is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

put on hold as off-topic by l0b0, Austin Hastings, Vogel612♦ 1 hour ago

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – l0b0, Austin Hastings, Vogel612

If this question can be reworded to fit the rules in the help center, please edit the question.

put on hold as off-topic by l0b0, Austin Hastings, Vogel612♦ 1 hour ago

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – l0b0, Austin Hastings, Vogel612

If this question can be reworded to fit the rules in the help center, please edit the question.

$begingroup$
Welcome to Code Review! I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
$endgroup$
– Vogel612♦
1 hour ago

add a comment |

$begingroup$
Welcome to Code Review! I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
$endgroup$
– Vogel612♦
1 hour ago

Welcome to Code Review! I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.

– Vogel612♦
1 hour ago

add a comment |

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