Counts “islands” of 1s in sea of 0s (2d array matrix)
$begingroup$
This solution surpassed 100% of submissions for efficiency! My method was to recursively check surrounding values and change any contiguous "land" to "water". Is there a better way to write what I wrote?
Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.
class Solution {
public int numIslands(char grid) {
int islands = 0;
for (int i = 0; i < grid.length; i++) {
for (int j = 0; j < grid[i].length; j++) {
if (grid[i][j] == '1') {
islands++;
destroyIsland(grid, i, j);
}
}
}
return islands;
}
public void destroyIsland(char grid, int i, int j) {
grid[i][j] = '0';
if (i < grid.length - 1 && grid[i+1][j] == '1') {
destroyIsland(grid, i+1, j);
}
if (i > 0 && grid[i-1][j] == '1') {
destroyIsland(grid, i-1, j);
}
if (j < grid[i].length - 1 && grid[i][j+1] == '1') {
destroyIsland(grid, i, j+1);
}
if (j > 0 && grid[i][j-1] == '1') {
destroyIsland(grid, i, j-1);
}
}
}
java algorithm
New contributor
$endgroup$
add a comment |
$begingroup$
This solution surpassed 100% of submissions for efficiency! My method was to recursively check surrounding values and change any contiguous "land" to "water". Is there a better way to write what I wrote?
Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.
class Solution {
public int numIslands(char grid) {
int islands = 0;
for (int i = 0; i < grid.length; i++) {
for (int j = 0; j < grid[i].length; j++) {
if (grid[i][j] == '1') {
islands++;
destroyIsland(grid, i, j);
}
}
}
return islands;
}
public void destroyIsland(char grid, int i, int j) {
grid[i][j] = '0';
if (i < grid.length - 1 && grid[i+1][j] == '1') {
destroyIsland(grid, i+1, j);
}
if (i > 0 && grid[i-1][j] == '1') {
destroyIsland(grid, i-1, j);
}
if (j < grid[i].length - 1 && grid[i][j+1] == '1') {
destroyIsland(grid, i, j+1);
}
if (j > 0 && grid[i][j-1] == '1') {
destroyIsland(grid, i, j-1);
}
}
}
java algorithm
New contributor
$endgroup$
add a comment |
$begingroup$
This solution surpassed 100% of submissions for efficiency! My method was to recursively check surrounding values and change any contiguous "land" to "water". Is there a better way to write what I wrote?
Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.
class Solution {
public int numIslands(char grid) {
int islands = 0;
for (int i = 0; i < grid.length; i++) {
for (int j = 0; j < grid[i].length; j++) {
if (grid[i][j] == '1') {
islands++;
destroyIsland(grid, i, j);
}
}
}
return islands;
}
public void destroyIsland(char grid, int i, int j) {
grid[i][j] = '0';
if (i < grid.length - 1 && grid[i+1][j] == '1') {
destroyIsland(grid, i+1, j);
}
if (i > 0 && grid[i-1][j] == '1') {
destroyIsland(grid, i-1, j);
}
if (j < grid[i].length - 1 && grid[i][j+1] == '1') {
destroyIsland(grid, i, j+1);
}
if (j > 0 && grid[i][j-1] == '1') {
destroyIsland(grid, i, j-1);
}
}
}
java algorithm
New contributor
$endgroup$
This solution surpassed 100% of submissions for efficiency! My method was to recursively check surrounding values and change any contiguous "land" to "water". Is there a better way to write what I wrote?
Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.
class Solution {
public int numIslands(char grid) {
int islands = 0;
for (int i = 0; i < grid.length; i++) {
for (int j = 0; j < grid[i].length; j++) {
if (grid[i][j] == '1') {
islands++;
destroyIsland(grid, i, j);
}
}
}
return islands;
}
public void destroyIsland(char grid, int i, int j) {
grid[i][j] = '0';
if (i < grid.length - 1 && grid[i+1][j] == '1') {
destroyIsland(grid, i+1, j);
}
if (i > 0 && grid[i-1][j] == '1') {
destroyIsland(grid, i-1, j);
}
if (j < grid[i].length - 1 && grid[i][j+1] == '1') {
destroyIsland(grid, i, j+1);
}
if (j > 0 && grid[i][j-1] == '1') {
destroyIsland(grid, i, j-1);
}
}
}
java algorithm
java algorithm
New contributor
New contributor
edited 1 hour ago
200_success
129k15152415
129k15152415
New contributor
asked 8 hours ago
Ned RedmondNed Redmond
111
111
New contributor
New contributor
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
The code seems correct. The only missing part is
You may assume all four edges of the grid are all surrounded by water.
which means that numIslands
may iterate
for (int i = 1; i < grid.length - 1; i++) {
for (int j = 1; j < grid[i].length - 1; j++) {
and do not bother destroyIsland
with validating the surroundings.
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "196"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Ned Redmond is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f211954%2fcounts-islands-of-1s-in-sea-of-0s-2d-array-matrix%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The code seems correct. The only missing part is
You may assume all four edges of the grid are all surrounded by water.
which means that numIslands
may iterate
for (int i = 1; i < grid.length - 1; i++) {
for (int j = 1; j < grid[i].length - 1; j++) {
and do not bother destroyIsland
with validating the surroundings.
$endgroup$
add a comment |
$begingroup$
The code seems correct. The only missing part is
You may assume all four edges of the grid are all surrounded by water.
which means that numIslands
may iterate
for (int i = 1; i < grid.length - 1; i++) {
for (int j = 1; j < grid[i].length - 1; j++) {
and do not bother destroyIsland
with validating the surroundings.
$endgroup$
add a comment |
$begingroup$
The code seems correct. The only missing part is
You may assume all four edges of the grid are all surrounded by water.
which means that numIslands
may iterate
for (int i = 1; i < grid.length - 1; i++) {
for (int j = 1; j < grid[i].length - 1; j++) {
and do not bother destroyIsland
with validating the surroundings.
$endgroup$
The code seems correct. The only missing part is
You may assume all four edges of the grid are all surrounded by water.
which means that numIslands
may iterate
for (int i = 1; i < grid.length - 1; i++) {
for (int j = 1; j < grid[i].length - 1; j++) {
and do not bother destroyIsland
with validating the surroundings.
answered 5 hours ago
vnpvnp
39k13098
39k13098
add a comment |
add a comment |
Ned Redmond is a new contributor. Be nice, and check out our Code of Conduct.
Ned Redmond is a new contributor. Be nice, and check out our Code of Conduct.
Ned Redmond is a new contributor. Be nice, and check out our Code of Conduct.
Ned Redmond is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f211954%2fcounts-islands-of-1s-in-sea-of-0s-2d-array-matrix%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown