How to extract elements of a list and append?
$begingroup$
A beginner's question:
Is there a way to extract elements of a list and append them into ONE number?
For example, if there is a list L={13,5,8,0}
, then I am looking for a way to append 13
, 5
, 8
and 0
to produce the result 13580
.
list-manipulation
New contributor
$endgroup$
add a comment |
$begingroup$
A beginner's question:
Is there a way to extract elements of a list and append them into ONE number?
For example, if there is a list L={13,5,8,0}
, then I am looking for a way to append 13
, 5
, 8
and 0
to produce the result 13580
.
list-manipulation
New contributor
$endgroup$
add a comment |
$begingroup$
A beginner's question:
Is there a way to extract elements of a list and append them into ONE number?
For example, if there is a list L={13,5,8,0}
, then I am looking for a way to append 13
, 5
, 8
and 0
to produce the result 13580
.
list-manipulation
New contributor
$endgroup$
A beginner's question:
Is there a way to extract elements of a list and append them into ONE number?
For example, if there is a list L={13,5,8,0}
, then I am looking for a way to append 13
, 5
, 8
and 0
to produce the result 13580
.
list-manipulation
list-manipulation
New contributor
New contributor
edited 45 mins ago
m0nhawk
2,57711531
2,57711531
New contributor
asked 46 mins ago
SreekzSreekz
112
112
New contributor
New contributor
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
You can convert the list numbers to strings, then join and finally convert back to number:
L = {13, 5, 8, 0};
ToExpression[StringJoin[ToString /@ L]]
(* 13580 *)
$endgroup$
add a comment |
$begingroup$
Or FromDigits:
FromDigits[{13, 5, 8, 0}]
13580
$endgroup$
1
$begingroup$
(+1) you will need something likeFromDigits[Flatten@IntegerDigits@L]
to cover cases likeL={1, 13, 5, 8, 0}
.
$endgroup$
– kglr
26 mins ago
$begingroup$
Thanks @kglr for showing a more general (robust) approach.
$endgroup$
– Rabbit
12 mins ago
add a comment |
$begingroup$
FromDigits @ StringJoin @ IntegerString @ L
13580
FromDigits @ StringJoin @ IntegerString @ {13, 5, 38, 13}
1353813
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can convert the list numbers to strings, then join and finally convert back to number:
L = {13, 5, 8, 0};
ToExpression[StringJoin[ToString /@ L]]
(* 13580 *)
$endgroup$
add a comment |
$begingroup$
You can convert the list numbers to strings, then join and finally convert back to number:
L = {13, 5, 8, 0};
ToExpression[StringJoin[ToString /@ L]]
(* 13580 *)
$endgroup$
add a comment |
$begingroup$
You can convert the list numbers to strings, then join and finally convert back to number:
L = {13, 5, 8, 0};
ToExpression[StringJoin[ToString /@ L]]
(* 13580 *)
$endgroup$
You can convert the list numbers to strings, then join and finally convert back to number:
L = {13, 5, 8, 0};
ToExpression[StringJoin[ToString /@ L]]
(* 13580 *)
answered 39 mins ago
m0nhawkm0nhawk
2,57711531
2,57711531
add a comment |
add a comment |
$begingroup$
Or FromDigits:
FromDigits[{13, 5, 8, 0}]
13580
$endgroup$
1
$begingroup$
(+1) you will need something likeFromDigits[Flatten@IntegerDigits@L]
to cover cases likeL={1, 13, 5, 8, 0}
.
$endgroup$
– kglr
26 mins ago
$begingroup$
Thanks @kglr for showing a more general (robust) approach.
$endgroup$
– Rabbit
12 mins ago
add a comment |
$begingroup$
Or FromDigits:
FromDigits[{13, 5, 8, 0}]
13580
$endgroup$
1
$begingroup$
(+1) you will need something likeFromDigits[Flatten@IntegerDigits@L]
to cover cases likeL={1, 13, 5, 8, 0}
.
$endgroup$
– kglr
26 mins ago
$begingroup$
Thanks @kglr for showing a more general (robust) approach.
$endgroup$
– Rabbit
12 mins ago
add a comment |
$begingroup$
Or FromDigits:
FromDigits[{13, 5, 8, 0}]
13580
$endgroup$
Or FromDigits:
FromDigits[{13, 5, 8, 0}]
13580
answered 31 mins ago
RabbitRabbit
327139
327139
1
$begingroup$
(+1) you will need something likeFromDigits[Flatten@IntegerDigits@L]
to cover cases likeL={1, 13, 5, 8, 0}
.
$endgroup$
– kglr
26 mins ago
$begingroup$
Thanks @kglr for showing a more general (robust) approach.
$endgroup$
– Rabbit
12 mins ago
add a comment |
1
$begingroup$
(+1) you will need something likeFromDigits[Flatten@IntegerDigits@L]
to cover cases likeL={1, 13, 5, 8, 0}
.
$endgroup$
– kglr
26 mins ago
$begingroup$
Thanks @kglr for showing a more general (robust) approach.
$endgroup$
– Rabbit
12 mins ago
1
1
$begingroup$
(+1) you will need something like
FromDigits[Flatten@IntegerDigits@L]
to cover cases like L={1, 13, 5, 8, 0}
.$endgroup$
– kglr
26 mins ago
$begingroup$
(+1) you will need something like
FromDigits[Flatten@IntegerDigits@L]
to cover cases like L={1, 13, 5, 8, 0}
.$endgroup$
– kglr
26 mins ago
$begingroup$
Thanks @kglr for showing a more general (robust) approach.
$endgroup$
– Rabbit
12 mins ago
$begingroup$
Thanks @kglr for showing a more general (robust) approach.
$endgroup$
– Rabbit
12 mins ago
add a comment |
$begingroup$
FromDigits @ StringJoin @ IntegerString @ L
13580
FromDigits @ StringJoin @ IntegerString @ {13, 5, 38, 13}
1353813
$endgroup$
add a comment |
$begingroup$
FromDigits @ StringJoin @ IntegerString @ L
13580
FromDigits @ StringJoin @ IntegerString @ {13, 5, 38, 13}
1353813
$endgroup$
add a comment |
$begingroup$
FromDigits @ StringJoin @ IntegerString @ L
13580
FromDigits @ StringJoin @ IntegerString @ {13, 5, 38, 13}
1353813
$endgroup$
FromDigits @ StringJoin @ IntegerString @ L
13580
FromDigits @ StringJoin @ IntegerString @ {13, 5, 38, 13}
1353813
answered 20 mins ago
kglrkglr
179k9199410
179k9199410
add a comment |
add a comment |
Sreekz is a new contributor. Be nice, and check out our Code of Conduct.
Sreekz is a new contributor. Be nice, and check out our Code of Conduct.
Sreekz is a new contributor. Be nice, and check out our Code of Conduct.
Sreekz is a new contributor. Be nice, and check out our Code of Conduct.
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