Python project not able to find file [closed]












0















I'm working with a python file that requires two pictures as an input and returns another picture which is the result of the first two. Using the terminal you are supposed to input the file path to these two pictures and the prefix for the results in this format:



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


When I enter:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


I get the error:



FileNotFoundError: [Errno 2] No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Notice that there's a space between the first quote and the first /. I am unsure why this is.



Also worth noting, entering locate Art.jpg and locate Cat.jpg returns /home/ryan/Desktop/Art.jpg and /home/ryan/Desktop/Cat.jpg, respectively.



The two jpg files are still on my desktop and don't have any additional whitespace in their names.










share|improve this question















closed as too broad by Rui F Ribeiro, Jeff Schaller, Mr Shunz, Archemar, Anthony Geoghegan Jan 21 at 14:49


Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • 2





    Is the leading space a symptom or a typo in the question?

    – Jeff Schaller
    Jan 20 at 20:35






  • 3





    The locate command doesn't mean that the data exists. It could have been deleted and the database hasn't been updated. Run updatedb and then see if locate returns it. Also, run ls -lQ on /home/ryan/Desktop which will list the data inside surrounded by quotation marks. It's possible that the filename has trailing whitespace.

    – Nasir Riley
    Jan 20 at 20:48













  • In your first example, the backslash () is used at the end of a line to let you span a command over multiple lines.  The backslash and the newline (which must follow it immediately) combine to form nothing.  But then you used a backslash in the middle of a line.  That’s your problem.  Even then, if you had said …Cat.jpg /home/ryan/Desktop/Art.jpg, you would have been OK.  But, by saying …Cat.jpg  /home/ryan/Desktop/Art.jpg, you had a backslash immediately followed by a space, and they combine to form a literal space — a space that is part of an argument, … (Cont’d)

    – G-Man
    Jan 22 at 6:31











  • (Cont’d) … rather than a separator between arguments.  So your Art.jpg argument becomes (space)/home/ryan/Desktop/Art.jpg (where the first character is a literal space).  This is a valid pathname, although obviously not what you wanted to say.  There’s no such file, so you got the error message that says that there’s no such file.

    – G-Man
    Jan 22 at 6:31
















0















I'm working with a python file that requires two pictures as an input and returns another picture which is the result of the first two. Using the terminal you are supposed to input the file path to these two pictures and the prefix for the results in this format:



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


When I enter:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


I get the error:



FileNotFoundError: [Errno 2] No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Notice that there's a space between the first quote and the first /. I am unsure why this is.



Also worth noting, entering locate Art.jpg and locate Cat.jpg returns /home/ryan/Desktop/Art.jpg and /home/ryan/Desktop/Cat.jpg, respectively.



The two jpg files are still on my desktop and don't have any additional whitespace in their names.










share|improve this question















closed as too broad by Rui F Ribeiro, Jeff Schaller, Mr Shunz, Archemar, Anthony Geoghegan Jan 21 at 14:49


Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • 2





    Is the leading space a symptom or a typo in the question?

    – Jeff Schaller
    Jan 20 at 20:35






  • 3





    The locate command doesn't mean that the data exists. It could have been deleted and the database hasn't been updated. Run updatedb and then see if locate returns it. Also, run ls -lQ on /home/ryan/Desktop which will list the data inside surrounded by quotation marks. It's possible that the filename has trailing whitespace.

    – Nasir Riley
    Jan 20 at 20:48













  • In your first example, the backslash () is used at the end of a line to let you span a command over multiple lines.  The backslash and the newline (which must follow it immediately) combine to form nothing.  But then you used a backslash in the middle of a line.  That’s your problem.  Even then, if you had said …Cat.jpg /home/ryan/Desktop/Art.jpg, you would have been OK.  But, by saying …Cat.jpg  /home/ryan/Desktop/Art.jpg, you had a backslash immediately followed by a space, and they combine to form a literal space — a space that is part of an argument, … (Cont’d)

    – G-Man
    Jan 22 at 6:31











  • (Cont’d) … rather than a separator between arguments.  So your Art.jpg argument becomes (space)/home/ryan/Desktop/Art.jpg (where the first character is a literal space).  This is a valid pathname, although obviously not what you wanted to say.  There’s no such file, so you got the error message that says that there’s no such file.

    – G-Man
    Jan 22 at 6:31














0












0








0








I'm working with a python file that requires two pictures as an input and returns another picture which is the result of the first two. Using the terminal you are supposed to input the file path to these two pictures and the prefix for the results in this format:



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


When I enter:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


I get the error:



FileNotFoundError: [Errno 2] No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Notice that there's a space between the first quote and the first /. I am unsure why this is.



Also worth noting, entering locate Art.jpg and locate Cat.jpg returns /home/ryan/Desktop/Art.jpg and /home/ryan/Desktop/Cat.jpg, respectively.



The two jpg files are still on my desktop and don't have any additional whitespace in their names.










share|improve this question
















I'm working with a python file that requires two pictures as an input and returns another picture which is the result of the first two. Using the terminal you are supposed to input the file path to these two pictures and the prefix for the results in this format:



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


When I enter:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


I get the error:



FileNotFoundError: [Errno 2] No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Notice that there's a space between the first quote and the first /. I am unsure why this is.



Also worth noting, entering locate Art.jpg and locate Cat.jpg returns /home/ryan/Desktop/Art.jpg and /home/ryan/Desktop/Cat.jpg, respectively.



The two jpg files are still on my desktop and don't have any additional whitespace in their names.







ubuntu python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 22 at 4:21







Ryan Marr

















asked Jan 20 at 20:01









Ryan MarrRyan Marr

184




184




closed as too broad by Rui F Ribeiro, Jeff Schaller, Mr Shunz, Archemar, Anthony Geoghegan Jan 21 at 14:49


Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.









closed as too broad by Rui F Ribeiro, Jeff Schaller, Mr Shunz, Archemar, Anthony Geoghegan Jan 21 at 14:49


Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.










  • 2





    Is the leading space a symptom or a typo in the question?

    – Jeff Schaller
    Jan 20 at 20:35






  • 3





    The locate command doesn't mean that the data exists. It could have been deleted and the database hasn't been updated. Run updatedb and then see if locate returns it. Also, run ls -lQ on /home/ryan/Desktop which will list the data inside surrounded by quotation marks. It's possible that the filename has trailing whitespace.

    – Nasir Riley
    Jan 20 at 20:48













  • In your first example, the backslash () is used at the end of a line to let you span a command over multiple lines.  The backslash and the newline (which must follow it immediately) combine to form nothing.  But then you used a backslash in the middle of a line.  That’s your problem.  Even then, if you had said …Cat.jpg /home/ryan/Desktop/Art.jpg, you would have been OK.  But, by saying …Cat.jpg  /home/ryan/Desktop/Art.jpg, you had a backslash immediately followed by a space, and they combine to form a literal space — a space that is part of an argument, … (Cont’d)

    – G-Man
    Jan 22 at 6:31











  • (Cont’d) … rather than a separator between arguments.  So your Art.jpg argument becomes (space)/home/ryan/Desktop/Art.jpg (where the first character is a literal space).  This is a valid pathname, although obviously not what you wanted to say.  There’s no such file, so you got the error message that says that there’s no such file.

    – G-Man
    Jan 22 at 6:31














  • 2





    Is the leading space a symptom or a typo in the question?

    – Jeff Schaller
    Jan 20 at 20:35






  • 3





    The locate command doesn't mean that the data exists. It could have been deleted and the database hasn't been updated. Run updatedb and then see if locate returns it. Also, run ls -lQ on /home/ryan/Desktop which will list the data inside surrounded by quotation marks. It's possible that the filename has trailing whitespace.

    – Nasir Riley
    Jan 20 at 20:48













  • In your first example, the backslash () is used at the end of a line to let you span a command over multiple lines.  The backslash and the newline (which must follow it immediately) combine to form nothing.  But then you used a backslash in the middle of a line.  That’s your problem.  Even then, if you had said …Cat.jpg /home/ryan/Desktop/Art.jpg, you would have been OK.  But, by saying …Cat.jpg  /home/ryan/Desktop/Art.jpg, you had a backslash immediately followed by a space, and they combine to form a literal space — a space that is part of an argument, … (Cont’d)

    – G-Man
    Jan 22 at 6:31











  • (Cont’d) … rather than a separator between arguments.  So your Art.jpg argument becomes (space)/home/ryan/Desktop/Art.jpg (where the first character is a literal space).  This is a valid pathname, although obviously not what you wanted to say.  There’s no such file, so you got the error message that says that there’s no such file.

    – G-Man
    Jan 22 at 6:31








2




2





Is the leading space a symptom or a typo in the question?

– Jeff Schaller
Jan 20 at 20:35





Is the leading space a symptom or a typo in the question?

– Jeff Schaller
Jan 20 at 20:35




3




3





The locate command doesn't mean that the data exists. It could have been deleted and the database hasn't been updated. Run updatedb and then see if locate returns it. Also, run ls -lQ on /home/ryan/Desktop which will list the data inside surrounded by quotation marks. It's possible that the filename has trailing whitespace.

– Nasir Riley
Jan 20 at 20:48







The locate command doesn't mean that the data exists. It could have been deleted and the database hasn't been updated. Run updatedb and then see if locate returns it. Also, run ls -lQ on /home/ryan/Desktop which will list the data inside surrounded by quotation marks. It's possible that the filename has trailing whitespace.

– Nasir Riley
Jan 20 at 20:48















In your first example, the backslash () is used at the end of a line to let you span a command over multiple lines.  The backslash and the newline (which must follow it immediately) combine to form nothing.  But then you used a backslash in the middle of a line.  That’s your problem.  Even then, if you had said …Cat.jpg /home/ryan/Desktop/Art.jpg, you would have been OK.  But, by saying …Cat.jpg  /home/ryan/Desktop/Art.jpg, you had a backslash immediately followed by a space, and they combine to form a literal space — a space that is part of an argument, … (Cont’d)

– G-Man
Jan 22 at 6:31





In your first example, the backslash () is used at the end of a line to let you span a command over multiple lines.  The backslash and the newline (which must follow it immediately) combine to form nothing.  But then you used a backslash in the middle of a line.  That’s your problem.  Even then, if you had said …Cat.jpg /home/ryan/Desktop/Art.jpg, you would have been OK.  But, by saying …Cat.jpg  /home/ryan/Desktop/Art.jpg, you had a backslash immediately followed by a space, and they combine to form a literal space — a space that is part of an argument, … (Cont’d)

– G-Man
Jan 22 at 6:31













(Cont’d) … rather than a separator between arguments.  So your Art.jpg argument becomes (space)/home/ryan/Desktop/Art.jpg (where the first character is a literal space).  This is a valid pathname, although obviously not what you wanted to say.  There’s no such file, so you got the error message that says that there’s no such file.

– G-Man
Jan 22 at 6:31





(Cont’d) … rather than a separator between arguments.  So your Art.jpg argument becomes (space)/home/ryan/Desktop/Art.jpg (where the first character is a literal space).  This is a valid pathname, although obviously not what you wanted to say.  There’s no such file, so you got the error message that says that there’s no such file.

– G-Man
Jan 22 at 6:31










1 Answer
1






active

oldest

votes


















4














No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Note the leading whitespace in the quoted pathname in the error message. If that's actually included in the variable that contains the pathname, and not just an extra space in the python command that outputs the error message, the error happens because the pathname the program is looking for is actually not:



/home/ryan/Desktop/Art.jpg


but



./ /home/ryan/Desktop/Art.jpg


relative to whatever is the current working directory of the Python program.



When you type in a multi-line command line like



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


as a single line, you should delete the backslash too:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


If you leave the backslash in and place a space (instead of a line-feed character) after it, it's the same as typing:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  ' /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which, in turn, is the same as:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg './ /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which is obviously not what you intended, but that's how your Python program understood it.






share|improve this answer


























  • If I do this for all path names python neural_style_transfer.py ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg I get neural_style_transfer.py: error: unrecognized arguments: /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg.

    – Ryan Marr
    Jan 22 at 4:25













  • You’re not supposed to add ./ in front of every path, telcoM is using that to explain what is happening. Forget ./ , forget backslashes, enter the file names as they are without adding anything to them.

    – Stephen Kitt
    Jan 22 at 8:12











  • Edited to clarify based on the information added to the question. Does this make it any clearer?

    – telcoM
    Jan 22 at 9:22











  • Thank you very much for explaining it clearly.

    – Ryan Marr
    Jan 23 at 2:50


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Note the leading whitespace in the quoted pathname in the error message. If that's actually included in the variable that contains the pathname, and not just an extra space in the python command that outputs the error message, the error happens because the pathname the program is looking for is actually not:



/home/ryan/Desktop/Art.jpg


but



./ /home/ryan/Desktop/Art.jpg


relative to whatever is the current working directory of the Python program.



When you type in a multi-line command line like



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


as a single line, you should delete the backslash too:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


If you leave the backslash in and place a space (instead of a line-feed character) after it, it's the same as typing:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  ' /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which, in turn, is the same as:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg './ /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which is obviously not what you intended, but that's how your Python program understood it.






share|improve this answer


























  • If I do this for all path names python neural_style_transfer.py ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg I get neural_style_transfer.py: error: unrecognized arguments: /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg.

    – Ryan Marr
    Jan 22 at 4:25













  • You’re not supposed to add ./ in front of every path, telcoM is using that to explain what is happening. Forget ./ , forget backslashes, enter the file names as they are without adding anything to them.

    – Stephen Kitt
    Jan 22 at 8:12











  • Edited to clarify based on the information added to the question. Does this make it any clearer?

    – telcoM
    Jan 22 at 9:22











  • Thank you very much for explaining it clearly.

    – Ryan Marr
    Jan 23 at 2:50
















4














No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Note the leading whitespace in the quoted pathname in the error message. If that's actually included in the variable that contains the pathname, and not just an extra space in the python command that outputs the error message, the error happens because the pathname the program is looking for is actually not:



/home/ryan/Desktop/Art.jpg


but



./ /home/ryan/Desktop/Art.jpg


relative to whatever is the current working directory of the Python program.



When you type in a multi-line command line like



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


as a single line, you should delete the backslash too:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


If you leave the backslash in and place a space (instead of a line-feed character) after it, it's the same as typing:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  ' /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which, in turn, is the same as:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg './ /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which is obviously not what you intended, but that's how your Python program understood it.






share|improve this answer


























  • If I do this for all path names python neural_style_transfer.py ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg I get neural_style_transfer.py: error: unrecognized arguments: /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg.

    – Ryan Marr
    Jan 22 at 4:25













  • You’re not supposed to add ./ in front of every path, telcoM is using that to explain what is happening. Forget ./ , forget backslashes, enter the file names as they are without adding anything to them.

    – Stephen Kitt
    Jan 22 at 8:12











  • Edited to clarify based on the information added to the question. Does this make it any clearer?

    – telcoM
    Jan 22 at 9:22











  • Thank you very much for explaining it clearly.

    – Ryan Marr
    Jan 23 at 2:50














4












4








4







No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Note the leading whitespace in the quoted pathname in the error message. If that's actually included in the variable that contains the pathname, and not just an extra space in the python command that outputs the error message, the error happens because the pathname the program is looking for is actually not:



/home/ryan/Desktop/Art.jpg


but



./ /home/ryan/Desktop/Art.jpg


relative to whatever is the current working directory of the Python program.



When you type in a multi-line command line like



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


as a single line, you should delete the backslash too:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


If you leave the backslash in and place a space (instead of a line-feed character) after it, it's the same as typing:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  ' /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which, in turn, is the same as:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg './ /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which is obviously not what you intended, but that's how your Python program understood it.






share|improve this answer















No such file or directory: ' /home/ryan/Desktop/Art.jpg'


Note the leading whitespace in the quoted pathname in the error message. If that's actually included in the variable that contains the pathname, and not just an extra space in the python command that outputs the error message, the error happens because the pathname the program is looking for is actually not:



/home/ryan/Desktop/Art.jpg


but



./ /home/ryan/Desktop/Art.jpg


relative to whatever is the current working directory of the Python program.



When you type in a multi-line command line like



python neural_style_transfer.py path_to_your_base_image.jpg 
path_to_your_reference.jpg prefix_for_results


as a single line, you should delete the backslash too:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg /home/ryan/Desktop/Art.jpg /home/ryan/Desktop


If you leave the backslash in and place a space (instead of a line-feed character) after it, it's the same as typing:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg  ' /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which, in turn, is the same as:



python neural_style_transfer.py /home/ryan/Desktop/Cat.jpg './ /home/ryan/Desktop/Art.jpg' /home/ryan/Desktop


Which is obviously not what you intended, but that's how your Python program understood it.







share|improve this answer














share|improve this answer



share|improve this answer








edited Jan 22 at 9:19

























answered Jan 21 at 9:33









telcoMtelcoM

16.5k12345




16.5k12345













  • If I do this for all path names python neural_style_transfer.py ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg I get neural_style_transfer.py: error: unrecognized arguments: /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg.

    – Ryan Marr
    Jan 22 at 4:25













  • You’re not supposed to add ./ in front of every path, telcoM is using that to explain what is happening. Forget ./ , forget backslashes, enter the file names as they are without adding anything to them.

    – Stephen Kitt
    Jan 22 at 8:12











  • Edited to clarify based on the information added to the question. Does this make it any clearer?

    – telcoM
    Jan 22 at 9:22











  • Thank you very much for explaining it clearly.

    – Ryan Marr
    Jan 23 at 2:50



















  • If I do this for all path names python neural_style_transfer.py ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg I get neural_style_transfer.py: error: unrecognized arguments: /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg.

    – Ryan Marr
    Jan 22 at 4:25













  • You’re not supposed to add ./ in front of every path, telcoM is using that to explain what is happening. Forget ./ , forget backslashes, enter the file names as they are without adding anything to them.

    – Stephen Kitt
    Jan 22 at 8:12











  • Edited to clarify based on the information added to the question. Does this make it any clearer?

    – telcoM
    Jan 22 at 9:22











  • Thank you very much for explaining it clearly.

    – Ryan Marr
    Jan 23 at 2:50

















If I do this for all path names python neural_style_transfer.py ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg I get neural_style_transfer.py: error: unrecognized arguments: /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg.

– Ryan Marr
Jan 22 at 4:25







If I do this for all path names python neural_style_transfer.py ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg I get neural_style_transfer.py: error: unrecognized arguments: /home/ryan/Desktop/Art.jpg ./ /home/ryan/Desktop/Art.jpg.

– Ryan Marr
Jan 22 at 4:25















You’re not supposed to add ./ in front of every path, telcoM is using that to explain what is happening. Forget ./ , forget backslashes, enter the file names as they are without adding anything to them.

– Stephen Kitt
Jan 22 at 8:12





You’re not supposed to add ./ in front of every path, telcoM is using that to explain what is happening. Forget ./ , forget backslashes, enter the file names as they are without adding anything to them.

– Stephen Kitt
Jan 22 at 8:12













Edited to clarify based on the information added to the question. Does this make it any clearer?

– telcoM
Jan 22 at 9:22





Edited to clarify based on the information added to the question. Does this make it any clearer?

– telcoM
Jan 22 at 9:22













Thank you very much for explaining it clearly.

– Ryan Marr
Jan 23 at 2:50





Thank you very much for explaining it clearly.

– Ryan Marr
Jan 23 at 2:50



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