Shuffling a deck of cards












0












$begingroup$


I've written a function to sort an array that'd simulate shuffling a deck of cards in the way of if you had [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].



The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.






let cards = [1,2,3,4,5,6,7,8,9,0];



const shuffle = cards => {

  const shuffled = ;

  const l = cards.slice(0, cards.length / 2);

  const r = cards.slice(cards.length / 2, cards.length);

  if (l.length === r.length) {

    for (let i = 0; i < l.length; i++) {

      shuffled.push(l[i], r[i]);

    }

  }

  return shuffled;

}



shuffle(a);








javascript shuffle







share|improve this question











$endgroup$

















    0












    $begingroup$


    I've written a function to sort an array that'd simulate shuffling a deck of cards in the way of if you had [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].



    The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.






    let cards = [1,2,3,4,5,6,7,8,9,0];
    

    
const shuffle = cards => {
    
  const shuffled = ;
    
  const l = cards.slice(0, cards.length / 2);
    
  const r = cards.slice(cards.length / 2, cards.length);
    
  if (l.length === r.length) {
    
    for (let i = 0; i < l.length; i++) {
    
      shuffled.push(l[i], r[i]);
    
    }
    
  }
    
  return shuffled;
    
}
    

    
shuffle(a);








    javascript shuffle







    share|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      I've written a function to sort an array that'd simulate shuffling a deck of cards in the way of if you had [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].



      The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.






      let cards = [1,2,3,4,5,6,7,8,9,0];
      

      
const shuffle = cards => {
      
  const shuffled = ;
      
  const l = cards.slice(0, cards.length / 2);
      
  const r = cards.slice(cards.length / 2, cards.length);
      
  if (l.length === r.length) {
      
    for (let i = 0; i < l.length; i++) {
      
      shuffled.push(l[i], r[i]);
      
    }
      
  }
      
  return shuffled;
      
}
      

      
shuffle(a);








      javascript shuffle







      share|improve this question











      $endgroup$




      I've written a function to sort an array that'd simulate shuffling a deck of cards in the way of if you had [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].



      The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.






      let cards = [1,2,3,4,5,6,7,8,9,0];
      

      
const shuffle = cards => {
      
  const shuffled = ;
      
  const l = cards.slice(0, cards.length / 2);
      
  const r = cards.slice(cards.length / 2, cards.length);
      
  if (l.length === r.length) {
      
    for (let i = 0; i < l.length; i++) {
      
      shuffled.push(l[i], r[i]);
      
    }
      
  }
      
  return shuffled;
      
}
      

      
shuffle(a);








      let cards = [1,2,3,4,5,6,7,8,9,0];
      

      
const shuffle = cards => {
      
  const shuffled = ;
      
  const l = cards.slice(0, cards.length / 2);
      
  const r = cards.slice(cards.length / 2, cards.length);
      
  if (l.length === r.length) {
      
    for (let i = 0; i < l.length; i++) {
      
      shuffled.push(l[i], r[i]);
      
    }
      
  }
      
  return shuffled;
      
}
      

      
shuffle(a);





      let cards = [1,2,3,4,5,6,7,8,9,0];
      

      
const shuffle = cards => {
      
  const shuffled = ;
      
  const l = cards.slice(0, cards.length / 2);
      
  const r = cards.slice(cards.length / 2, cards.length);
      
  if (l.length === r.length) {
      
    for (let i = 0; i < l.length; i++) {
      
      shuffled.push(l[i], r[i]);
      
    }
      
  }
      
  return shuffled;
      
}
      

      
shuffle(a);





      javascript shuffle




      javascript shuffle






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 20 mins ago









      Jamal♦

      30.3k11117227




      30.3k11117227










      asked 51 mins ago









      totalnoobtotalnoob

      1435




      1435






















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