how to pass echo statement output as argument to function?
I just want to pass the echo statement output as argument(${1}) to the logger function in the following example:
logfile=./testlog
`touch ${logfile}`
function logger(){
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
echo "started executing script" | logger
shell-script function
edited Jan 12 '17 at 23:43
рüффп
77831529
asked Oct 27 '16 at 5:44
user197279user197279
11
add a comment |
I just want to pass the echo statement output as argument(${1}) to the logger function in the following example:
logfile=./testlog
`touch ${logfile}`
function logger(){
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
echo "started executing script" | logger
shell-script function
edited Jan 12 '17 at 23:43
рüффп
77831529
asked Oct 27 '16 at 5:44
user197279user197279
11
logger "started executing script"
– Kamaraj
Oct 27 '16 at 5:50
Insider logger function replace $1 to $@
– Kamaraj
Oct 27 '16 at 5:52
my actual intention is to log the all echo statements output in a large shell script to logfile by calling this function. so in every call of this funciton can't write like (logger "started executing script")....
– user197279
Oct 27 '16 at 6:09
add a comment |
I just want to pass the echo statement output as argument(${1}) to the logger function in the following example:
logfile=./testlog
`touch ${logfile}`
function logger(){
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
echo "started executing script" | logger
shell-script function
edited Jan 12 '17 at 23:43
рüффп
77831529
asked Oct 27 '16 at 5:44
user197279user197279
11
I just want to pass the echo statement output as argument(${1}) to the logger function in the following example:
logfile=./testlog
`touch ${logfile}`
function logger(){
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
echo "started executing script" | logger
shell-script function
shell-script function
edited Jan 12 '17 at 23:43
рüффп
77831529
asked Oct 27 '16 at 5:44
user197279user197279
11
edited Jan 12 '17 at 23:43
рüффп
77831529
asked Oct 27 '16 at 5:44
user197279user197279
11
edited Jan 12 '17 at 23:43
рüффп
77831529
edited Jan 12 '17 at 23:43
рüффп
77831529
edited Jan 12 '17 at 23:43
рüффп
77831529
77831529
asked Oct 27 '16 at 5:44
user197279user197279
11
asked Oct 27 '16 at 5:44
user197279user197279
11
asked Oct 27 '16 at 5:44
user197279user197279
11
11
logger "started executing script"
– Kamaraj
Oct 27 '16 at 5:50
Insider logger function replace $1 to $@
– Kamaraj
Oct 27 '16 at 5:52
my actual intention is to log the all echo statements output in a large shell script to logfile by calling this function. so in every call of this funciton can't write like (logger "started executing script")....
– user197279
Oct 27 '16 at 6:09
add a comment |
logger "started executing script"
– Kamaraj
Oct 27 '16 at 5:50
Insider logger function replace $1 to $@
– Kamaraj
Oct 27 '16 at 5:52
my actual intention is to log the all echo statements output in a large shell script to logfile by calling this function. so in every call of this funciton can't write like (logger "started executing script")....
– user197279
Oct 27 '16 at 6:09
logger "started executing script"
– Kamaraj
Oct 27 '16 at 5:50
logger "started executing script"
– Kamaraj
Oct 27 '16 at 5:50
Insider logger function replace $1 to $@
– Kamaraj
Oct 27 '16 at 5:52
Insider logger function replace $1 to $@
– Kamaraj
Oct 27 '16 at 5:52
my actual intention is to log the all echo statements output in a large shell script to logfile by calling this function. so in every call of this funciton can't write like (logger "started executing script")....
– user197279
Oct 27 '16 at 6:09
my actual intention is to log the all echo statements output in a large shell script to logfile by calling this function. so in every call of this funciton can't write like (logger "started executing script")....
– user197279
Oct 27 '16 at 6:09
add a comment |
2 Answers
2
active
oldest
votes
Aside: logger is a standard Unix (POSIX) utility. You might choose a different name to avoid confusion.
For a program you could use | xargs -d 'n' logger. This would include the case where you rewrite your function as a script file, with 'shebang' line if necessary; however getting all the correct environment to that script could be difficult.
For a function, the only way to pass an argument is to pass an argument. You could write a second function that wraps your first function, which I'll rename logger1:
logger1(){ echo "... $1" >>$file; }
logger2(){ read -r x; logger1 "$x"; }
echo this is some log info | logger2
or you could just have your function read its input in the first place. You could even code a loop and have it handle multiple lines if provided, like the real logging facilities in most systems do.
answered Oct 27 '16 at 13:32
dave_thompson_085dave_thompson_085
2,09211111
add a comment |
put the echo statement inside the function.
logfile=./testlog
`touch ${logfile}`
function logger()
{
echo "$@"
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
logger "started executing scirpt"
answered Oct 27 '16 at 6:13
KamarajKamaraj
2,9641513
thanks,its working fine... But is there anyway to automatically redirect the output of echo statement as argument of this function like i have given using "|" ? please suggest..
– user197279
Oct 27 '16 at 7:21
Trylogger <(echo "started executing script)
– Valentin B.
Oct 27 '16 at 8:27
it's not working....
– user197279
Oct 27 '16 at 10:00
its is working loggerecho "started executing script"
– user197279
Oct 27 '16 at 10:24
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Aside: logger is a standard Unix (POSIX) utility. You might choose a different name to avoid confusion.
For a program you could use | xargs -d 'n' logger. This would include the case where you rewrite your function as a script file, with 'shebang' line if necessary; however getting all the correct environment to that script could be difficult.
For a function, the only way to pass an argument is to pass an argument. You could write a second function that wraps your first function, which I'll rename logger1:
logger1(){ echo "... $1" >>$file; }
logger2(){ read -r x; logger1 "$x"; }
echo this is some log info | logger2
or you could just have your function read its input in the first place. You could even code a loop and have it handle multiple lines if provided, like the real logging facilities in most systems do.
answered Oct 27 '16 at 13:32
dave_thompson_085dave_thompson_085
2,09211111
add a comment |
Aside: logger is a standard Unix (POSIX) utility. You might choose a different name to avoid confusion.
For a program you could use | xargs -d 'n' logger. This would include the case where you rewrite your function as a script file, with 'shebang' line if necessary; however getting all the correct environment to that script could be difficult.
For a function, the only way to pass an argument is to pass an argument. You could write a second function that wraps your first function, which I'll rename logger1:
logger1(){ echo "... $1" >>$file; }
logger2(){ read -r x; logger1 "$x"; }
echo this is some log info | logger2
or you could just have your function read its input in the first place. You could even code a loop and have it handle multiple lines if provided, like the real logging facilities in most systems do.
answered Oct 27 '16 at 13:32
dave_thompson_085dave_thompson_085
2,09211111
add a comment |
Aside: logger is a standard Unix (POSIX) utility. You might choose a different name to avoid confusion.
For a program you could use | xargs -d 'n' logger. This would include the case where you rewrite your function as a script file, with 'shebang' line if necessary; however getting all the correct environment to that script could be difficult.
For a function, the only way to pass an argument is to pass an argument. You could write a second function that wraps your first function, which I'll rename logger1:
logger1(){ echo "... $1" >>$file; }
logger2(){ read -r x; logger1 "$x"; }
echo this is some log info | logger2
or you could just have your function read its input in the first place. You could even code a loop and have it handle multiple lines if provided, like the real logging facilities in most systems do.
answered Oct 27 '16 at 13:32
dave_thompson_085dave_thompson_085
2,09211111
Aside: logger is a standard Unix (POSIX) utility. You might choose a different name to avoid confusion.
For a program you could use | xargs -d 'n' logger. This would include the case where you rewrite your function as a script file, with 'shebang' line if necessary; however getting all the correct environment to that script could be difficult.
For a function, the only way to pass an argument is to pass an argument. You could write a second function that wraps your first function, which I'll rename logger1:
logger1(){ echo "... $1" >>$file; }
logger2(){ read -r x; logger1 "$x"; }
echo this is some log info | logger2
or you could just have your function read its input in the first place. You could even code a loop and have it handle multiple lines if provided, like the real logging facilities in most systems do.
answered Oct 27 '16 at 13:32
dave_thompson_085dave_thompson_085
2,09211111
answered Oct 27 '16 at 13:32
dave_thompson_085dave_thompson_085
2,09211111
answered Oct 27 '16 at 13:32
dave_thompson_085dave_thompson_085
2,09211111
answered Oct 27 '16 at 13:32
dave_thompson_085dave_thompson_085
2,09211111
2,09211111
add a comment |
add a comment |
put the echo statement inside the function.
logfile=./testlog
`touch ${logfile}`
function logger()
{
echo "$@"
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
logger "started executing scirpt"
answered Oct 27 '16 at 6:13
KamarajKamaraj
2,9641513
thanks,its working fine... But is there anyway to automatically redirect the output of echo statement as argument of this function like i have given using "|" ? please suggest..
– user197279
Oct 27 '16 at 7:21
Trylogger <(echo "started executing script)
– Valentin B.
Oct 27 '16 at 8:27
it's not working....
– user197279
Oct 27 '16 at 10:00
its is working loggerecho "started executing script"
– user197279
Oct 27 '16 at 10:24
add a comment |
put the echo statement inside the function.
logfile=./testlog
`touch ${logfile}`
function logger()
{
echo "$@"
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
logger "started executing scirpt"
answered Oct 27 '16 at 6:13
KamarajKamaraj
2,9641513
thanks,its working fine... But is there anyway to automatically redirect the output of echo statement as argument of this function like i have given using "|" ? please suggest..
– user197279
Oct 27 '16 at 7:21
Trylogger <(echo "started executing script)
– Valentin B.
Oct 27 '16 at 8:27
it's not working....
– user197279
Oct 27 '16 at 10:00
its is working loggerecho "started executing script"
– user197279
Oct 27 '16 at 10:24
add a comment |
put the echo statement inside the function.
logfile=./testlog
`touch ${logfile}`
function logger()
{
echo "$@"
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
logger "started executing scirpt"
answered Oct 27 '16 at 6:13
KamarajKamaraj
2,9641513
put the echo statement inside the function.
logfile=./testlog
`touch ${logfile}`
function logger()
{
echo "$@"
echo "[${USER}] [$nowTimestamp] [INFO] ${1}" >> ${logfile}
}
logger "started executing scirpt"
answered Oct 27 '16 at 6:13
KamarajKamaraj
2,9641513
answered Oct 27 '16 at 6:13
KamarajKamaraj
2,9641513
answered Oct 27 '16 at 6:13
KamarajKamaraj
2,9641513
answered Oct 27 '16 at 6:13
KamarajKamaraj
2,9641513
2,9641513
thanks,its working fine... But is there anyway to automatically redirect the output of echo statement as argument of this function like i have given using "|" ? please suggest..
– user197279
Oct 27 '16 at 7:21
Trylogger <(echo "started executing script)
– Valentin B.
Oct 27 '16 at 8:27
it's not working....
– user197279
Oct 27 '16 at 10:00
its is working loggerecho "started executing script"
– user197279
Oct 27 '16 at 10:24
add a comment |
thanks,its working fine... But is there anyway to automatically redirect the output of echo statement as argument of this function like i have given using "|" ? please suggest..
– user197279
Oct 27 '16 at 7:21
Trylogger <(echo "started executing script)
– Valentin B.
Oct 27 '16 at 8:27
it's not working....
– user197279
Oct 27 '16 at 10:00
its is working loggerecho "started executing script"
– user197279
Oct 27 '16 at 10:24
thanks,its working fine... But is there anyway to automatically redirect the output of echo statement as argument of this function like i have given using "|" ? please suggest..
– user197279
Oct 27 '16 at 7:21
thanks,its working fine... But is there anyway to automatically redirect the output of echo statement as argument of this function like i have given using "|" ? please suggest..
– user197279
Oct 27 '16 at 7:21
Try
logger <(echo "started executing script)– Valentin B.
Oct 27 '16 at 8:27
Try
logger <(echo "started executing script)– Valentin B.
Oct 27 '16 at 8:27
it's not working....
– user197279
Oct 27 '16 at 10:00
it's not working....
– user197279
Oct 27 '16 at 10:00
its is working logger
echo "started executing script"– user197279
Oct 27 '16 at 10:24
its is working logger
echo "started executing script"– user197279
Oct 27 '16 at 10:24
add a comment |
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logger "started executing script"
– Kamaraj
Oct 27 '16 at 5:50
Insider logger function replace $1 to $@
– Kamaraj
Oct 27 '16 at 5:52
my actual intention is to log the all echo statements output in a large shell script to logfile by calling this function. so in every call of this funciton can't write like (logger "started executing script")....
– user197279
Oct 27 '16 at 6:09