Iteratively checking array of array of strings












0












$begingroup$


The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs




You are given 2 arguments:



possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]



personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]



Return an output (as an array of strings) that checks the arguments against each other in the
following format:



scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]




def scanner(possible_criminals , personal_information)

'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker

steps to solve the problem:

- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)

- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values

- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''


def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"

def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M

# driver program
final = init_output(possible_criminals , personal_information )

for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]

assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]









share|improve this question









$endgroup$

















    0












    $begingroup$


    The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs




    You are given 2 arguments:



    possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
    '134.0', 'USD', 'M53'],
    ['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]



    personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
    'USD','M53', '37'],
    ['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]



    Return an output (as an array of strings) that checks the arguments against each other in the
    following format:



    scanner(possible_criminals, personal_information) =
    [['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
    'criminal']]




    def scanner(possible_criminals , personal_information)

    '''
    this problem can be simplified by understanding that the output
    contains an array of 3 values
    1) index[0] from argument 1
    2) index[0] from argument 2
    3) a value calculated by our function db_checker

    steps to solve the problem:

    - creating value 1) and 2) in output by extracting index 0 from given
    arguments(possible_criminals , personal_information)

    - "prepare" the arguments(possible_criminals , personal_information) for comparison
    by sanitizing them:
    - run "".lower() to account for case-insensitive matches
    - pop unnecessary values

    - calculating whether the arguments match by using a function
    that compares possible_criminals with their personal_information
    - function checks how many matches are there
    '''


    def db_checker(A, B):
    counter = 0
    for x in A:
    if B.count(x) == 0:
    counter += 1
    if counter == 0:
    return "criminal"
    elif counter == 1:
    return "possible"
    elif counter == 2:
    return "unlikely"
    else:
    return "none"

    def init_output(N, M):
    outputs =
    for i in range(len(N)):
    output =
    output += [N[i].pop(0)] + [M[i].pop(0)]
    outputs.append(output)
    N[i].pop(2) # remove undesired values
    M[i].pop(-1)
    N[i] = [y.lower() for y in N[i]]
    M[i] = [k.lower() for k in M[i]]
    return outputs, N, M

    # driver program
    final = init_output(possible_criminals , personal_information )

    for i in range(len(final[1])):
    final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
    return final[0]

    assert scanner(possible_criminals , personal_information) ==
    [['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]









    share|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs




      You are given 2 arguments:



      possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
      '134.0', 'USD', 'M53'],
      ['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]



      personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
      'USD','M53', '37'],
      ['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]



      Return an output (as an array of strings) that checks the arguments against each other in the
      following format:



      scanner(possible_criminals, personal_information) =
      [['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
      'criminal']]




      def scanner(possible_criminals , personal_information)

      '''
      this problem can be simplified by understanding that the output
      contains an array of 3 values
      1) index[0] from argument 1
      2) index[0] from argument 2
      3) a value calculated by our function db_checker

      steps to solve the problem:

      - creating value 1) and 2) in output by extracting index 0 from given
      arguments(possible_criminals , personal_information)

      - "prepare" the arguments(possible_criminals , personal_information) for comparison
      by sanitizing them:
      - run "".lower() to account for case-insensitive matches
      - pop unnecessary values

      - calculating whether the arguments match by using a function
      that compares possible_criminals with their personal_information
      - function checks how many matches are there
      '''


      def db_checker(A, B):
      counter = 0
      for x in A:
      if B.count(x) == 0:
      counter += 1
      if counter == 0:
      return "criminal"
      elif counter == 1:
      return "possible"
      elif counter == 2:
      return "unlikely"
      else:
      return "none"

      def init_output(N, M):
      outputs =
      for i in range(len(N)):
      output =
      output += [N[i].pop(0)] + [M[i].pop(0)]
      outputs.append(output)
      N[i].pop(2) # remove undesired values
      M[i].pop(-1)
      N[i] = [y.lower() for y in N[i]]
      M[i] = [k.lower() for k in M[i]]
      return outputs, N, M

      # driver program
      final = init_output(possible_criminals , personal_information )

      for i in range(len(final[1])):
      final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
      return final[0]

      assert scanner(possible_criminals , personal_information) ==
      [['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]









      share|improve this question









      $endgroup$




      The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs




      You are given 2 arguments:



      possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
      '134.0', 'USD', 'M53'],
      ['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]



      personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
      'USD','M53', '37'],
      ['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]



      Return an output (as an array of strings) that checks the arguments against each other in the
      following format:



      scanner(possible_criminals, personal_information) =
      [['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
      'criminal']]




      def scanner(possible_criminals , personal_information)

      '''
      this problem can be simplified by understanding that the output
      contains an array of 3 values
      1) index[0] from argument 1
      2) index[0] from argument 2
      3) a value calculated by our function db_checker

      steps to solve the problem:

      - creating value 1) and 2) in output by extracting index 0 from given
      arguments(possible_criminals , personal_information)

      - "prepare" the arguments(possible_criminals , personal_information) for comparison
      by sanitizing them:
      - run "".lower() to account for case-insensitive matches
      - pop unnecessary values

      - calculating whether the arguments match by using a function
      that compares possible_criminals with their personal_information
      - function checks how many matches are there
      '''


      def db_checker(A, B):
      counter = 0
      for x in A:
      if B.count(x) == 0:
      counter += 1
      if counter == 0:
      return "criminal"
      elif counter == 1:
      return "possible"
      elif counter == 2:
      return "unlikely"
      else:
      return "none"

      def init_output(N, M):
      outputs =
      for i in range(len(N)):
      output =
      output += [N[i].pop(0)] + [M[i].pop(0)]
      outputs.append(output)
      N[i].pop(2) # remove undesired values
      M[i].pop(-1)
      N[i] = [y.lower() for y in N[i]]
      M[i] = [k.lower() for k in M[i]]
      return outputs, N, M

      # driver program
      final = init_output(possible_criminals , personal_information )

      for i in range(len(final[1])):
      final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
      return final[0]

      assert scanner(possible_criminals , personal_information) ==
      [['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]






      python formatting






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      share|improve this question










      asked 33 mins ago









      sgezasgeza

      133




      133






















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