Iteratively checking array of array of strings
$begingroup$
The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs
You are given 2 arguments:
possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]
personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]
Return an output (as an array of strings) that checks the arguments against each other in the
following format:
scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]
def scanner(possible_criminals , personal_information)
'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker
steps to solve the problem:
- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)
- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values
- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''
def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"
def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M
# driver program
final = init_output(possible_criminals , personal_information )
for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]
assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]
python formatting
$endgroup$
add a comment |
$begingroup$
The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs
You are given 2 arguments:
possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]
personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]
Return an output (as an array of strings) that checks the arguments against each other in the
following format:
scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]
def scanner(possible_criminals , personal_information)
'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker
steps to solve the problem:
- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)
- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values
- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''
def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"
def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M
# driver program
final = init_output(possible_criminals , personal_information )
for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]
assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]
python formatting
$endgroup$
add a comment |
$begingroup$
The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs
You are given 2 arguments:
possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]
personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]
Return an output (as an array of strings) that checks the arguments against each other in the
following format:
scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]
def scanner(possible_criminals , personal_information)
'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker
steps to solve the problem:
- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)
- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values
- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''
def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"
def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M
# driver program
final = init_output(possible_criminals , personal_information )
for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]
assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]
python formatting
$endgroup$
The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs
You are given 2 arguments:
possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]
personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]
Return an output (as an array of strings) that checks the arguments against each other in the
following format:
scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]
def scanner(possible_criminals , personal_information)
'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker
steps to solve the problem:
- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)
- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values
- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''
def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"
def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M
# driver program
final = init_output(possible_criminals , personal_information )
for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]
assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]
python formatting
python formatting
asked 33 mins ago
sgezasgeza
133
133
add a comment |
add a comment |
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