Valid Badminton Score?












18












$begingroup$


Introduction:



I saw there was only one other badminton related challenge right now. Since I play badminton myself (for the past 13 years now), I figured I'd add some badminton-related challenges. Here the first one:



Challenge:



Input: Two integers
Output: One of three distinct and unique outputs of your own choice. One indicating that the input is a valid badminton score AND the set has ended with a winner; one indicating that the input is a valid badminton score AND the set is still in play; one indicating the input is not a valid badminton score.



With badminton, both (pairs of) players start with 0 points, and you stop when one of the two (pairs of) players has reached a score of 21, with at least 2 points difference, up to a maximum of 30-29.



So these are all possible input-pairs (in either order) indicating it's a valid badminton score AND the set has ended:



[[0,21],[1,21],[2,21],[3,21],[4,21],[5,21],[6,21],[7,21],[8,21],[9,21],[10,21],[11,21],[12,21],[13,21],[14,21],[15,21],[16,21],[17,21],[18,21],[19,21],[20,22],[21,23],[22,24],[23,25],[24,26],[25,27],[26,28],[27,29],[28,30],[29,30]]


And these are all possible input-pairs (in either order) indicating it's a valid badminton score BUT the set is still in play:



[[0,0],[0,1],[0,2],[0,3],[0,4],[0,5],[0,6],[0,7],[0,8],[0,9],[0,10],[0,11],[0,12],[0,13],[0,14],[0,15],[0,16],[0,17],[0,18],[0,19],[0,20],[1,1],[1,2],[1,3],[1,4],[1,5],[1,6],[1,7],[1,8],[1,9],[1,10],[1,11],[1,12],[1,13],[1,14],[1,15],[1,16],[1,17],[1,18],[1,19],[1,20],[2,2],[2,3],[2,4],[2,5],[2,6],[2,7],[2,8],[2,9],[2,10],[2,11],[2,12],[2,13],[2,14],[2,15],[2,16],[2,17],[2,18],[2,19],[2,20],[3,3],[3,4],[3,5],[3,6],[3,7],[3,8],[3,9],[3,10],[3,11],[3,12],[3,13],[3,14],[3,15],[3,16],[3,17],[3,18],[3,19],[3,20],[4,4],[4,5],[4,6],[4,7],[4,8],[4,9],[4,10],[4,11],[4,12],[4,13],[4,14],[4,15],[4,16],[4,17],[4,18],[4,19],[4,20],[5,5],[5,6],[5,7],[5,8],[5,9],[5,10],[5,11],[5,12],[5,13],[5,14],[5,15],[5,16],[5,17],[5,18],[5,19],[5,20],[6,6],[6,7],[6,8],[6,9],[6,10],[6,11],[6,12],[6,13],[6,14],[6,15],[6,16],[6,17],[6,18],[6,19],[6,20],[7,7],[7,8],[7,9],[7,10],[7,11],[7,12],[7,13],[7,14],[7,15],[7,16],[7,17],[7,18],[7,19],[7,20],[8,8],[8,9],[8,10],[8,11],[8,12],[8,13],[8,14],[8,15],[8,16],[8,17],[8,18],[8,19],[8,20],[9,9],[9,10],[9,11],[9,12],[9,13],[9,14],[9,15],[9,16],[9,17],[9,18],[9,19],[9,20],[10,10],[10,11],[10,12],[10,13],[10,14],[10,15],[10,16],[10,17],[10,18],[10,19],[10,20],[11,11],[11,12],[11,13],[11,14],[11,15],[11,16],[11,17],[11,18],[11,19],[11,20],[12,12],[12,13],[12,14],[12,15],[12,16],[12,17],[12,18],[12,19],[12,20],[13,13],[13,14],[13,15],[13,16],[13,17],[13,18],[13,19],[13,20],[14,14],[14,15],[14,16],[14,17],[14,18],[14,19],[14,20],[15,15],[15,16],[15,17],[15,18],[15,19],[15,20],[16,16],[16,17],[16,18],[16,19],[16,20],[17,17],[17,18],[17,19],[17,20],[18,18],[18,19],[18,20],[19,19],[19,20],[20,20],[20,21],[21,21],[21,22],[22,22],[22,23],[23,23],[23,24],[24,24],[24,25],[25,25],[25,26],[26,26],[26,27],[27,27],[27,28],[28,28],[28,29],[29,29]]


Any other pair of integer would be an invalid badminton score.



Challenge rules:




  • I/O is flexible, so:


    • You can take the input as a list of two numbers; two separated numbers through STDIN or function parameters; two strings; etc.

    • Output will be three distinct and unique values of your own choice. Can be integers (i.e. [0,1,2], [1,2,3], [-1,0,1], etc.); can be Booleans (i.e. [true,false,undefined/null/empty]); can be characters/strings (i.e. ["valid & ended","valid","invalid"]); etc.

    • Please specify the I/O you've used in your answer!



  • You are allowed to take the input-integers pre-ordered from lowest to highest or vice-versa.

  • The input integers can be negative, in which case they are of course invalid.


General rules:




  • This is code-golf, so shortest answer in bytes wins.

    Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.


  • Standard rules apply for your answer with default I/O rules, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.


  • Default Loopholes are forbidden.

  • If possible, please add a link with a test for your code (i.e. TIO).

  • Also, adding an explanation for your answer is highly recommended.


Test cases:



These test cases are valid, and the set has ended:



0 21
12 21
21 23
28 30
29 30


These test cases are valid, but the set is still in play:



0 0
0 20
12 12
21 21
21 22


These test cases are invalid:



-21 19
-19 21
-1 1
12 22
29 31
30 30
42 43
1021 1021









share|improve this question











$endgroup$

















    18












    $begingroup$


    Introduction:



    I saw there was only one other badminton related challenge right now. Since I play badminton myself (for the past 13 years now), I figured I'd add some badminton-related challenges. Here the first one:



    Challenge:



    Input: Two integers
    Output: One of three distinct and unique outputs of your own choice. One indicating that the input is a valid badminton score AND the set has ended with a winner; one indicating that the input is a valid badminton score AND the set is still in play; one indicating the input is not a valid badminton score.



    With badminton, both (pairs of) players start with 0 points, and you stop when one of the two (pairs of) players has reached a score of 21, with at least 2 points difference, up to a maximum of 30-29.



    So these are all possible input-pairs (in either order) indicating it's a valid badminton score AND the set has ended:



    [[0,21],[1,21],[2,21],[3,21],[4,21],[5,21],[6,21],[7,21],[8,21],[9,21],[10,21],[11,21],[12,21],[13,21],[14,21],[15,21],[16,21],[17,21],[18,21],[19,21],[20,22],[21,23],[22,24],[23,25],[24,26],[25,27],[26,28],[27,29],[28,30],[29,30]]


    And these are all possible input-pairs (in either order) indicating it's a valid badminton score BUT the set is still in play:



    [[0,0],[0,1],[0,2],[0,3],[0,4],[0,5],[0,6],[0,7],[0,8],[0,9],[0,10],[0,11],[0,12],[0,13],[0,14],[0,15],[0,16],[0,17],[0,18],[0,19],[0,20],[1,1],[1,2],[1,3],[1,4],[1,5],[1,6],[1,7],[1,8],[1,9],[1,10],[1,11],[1,12],[1,13],[1,14],[1,15],[1,16],[1,17],[1,18],[1,19],[1,20],[2,2],[2,3],[2,4],[2,5],[2,6],[2,7],[2,8],[2,9],[2,10],[2,11],[2,12],[2,13],[2,14],[2,15],[2,16],[2,17],[2,18],[2,19],[2,20],[3,3],[3,4],[3,5],[3,6],[3,7],[3,8],[3,9],[3,10],[3,11],[3,12],[3,13],[3,14],[3,15],[3,16],[3,17],[3,18],[3,19],[3,20],[4,4],[4,5],[4,6],[4,7],[4,8],[4,9],[4,10],[4,11],[4,12],[4,13],[4,14],[4,15],[4,16],[4,17],[4,18],[4,19],[4,20],[5,5],[5,6],[5,7],[5,8],[5,9],[5,10],[5,11],[5,12],[5,13],[5,14],[5,15],[5,16],[5,17],[5,18],[5,19],[5,20],[6,6],[6,7],[6,8],[6,9],[6,10],[6,11],[6,12],[6,13],[6,14],[6,15],[6,16],[6,17],[6,18],[6,19],[6,20],[7,7],[7,8],[7,9],[7,10],[7,11],[7,12],[7,13],[7,14],[7,15],[7,16],[7,17],[7,18],[7,19],[7,20],[8,8],[8,9],[8,10],[8,11],[8,12],[8,13],[8,14],[8,15],[8,16],[8,17],[8,18],[8,19],[8,20],[9,9],[9,10],[9,11],[9,12],[9,13],[9,14],[9,15],[9,16],[9,17],[9,18],[9,19],[9,20],[10,10],[10,11],[10,12],[10,13],[10,14],[10,15],[10,16],[10,17],[10,18],[10,19],[10,20],[11,11],[11,12],[11,13],[11,14],[11,15],[11,16],[11,17],[11,18],[11,19],[11,20],[12,12],[12,13],[12,14],[12,15],[12,16],[12,17],[12,18],[12,19],[12,20],[13,13],[13,14],[13,15],[13,16],[13,17],[13,18],[13,19],[13,20],[14,14],[14,15],[14,16],[14,17],[14,18],[14,19],[14,20],[15,15],[15,16],[15,17],[15,18],[15,19],[15,20],[16,16],[16,17],[16,18],[16,19],[16,20],[17,17],[17,18],[17,19],[17,20],[18,18],[18,19],[18,20],[19,19],[19,20],[20,20],[20,21],[21,21],[21,22],[22,22],[22,23],[23,23],[23,24],[24,24],[24,25],[25,25],[25,26],[26,26],[26,27],[27,27],[27,28],[28,28],[28,29],[29,29]]


    Any other pair of integer would be an invalid badminton score.



    Challenge rules:




    • I/O is flexible, so:


      • You can take the input as a list of two numbers; two separated numbers through STDIN or function parameters; two strings; etc.

      • Output will be three distinct and unique values of your own choice. Can be integers (i.e. [0,1,2], [1,2,3], [-1,0,1], etc.); can be Booleans (i.e. [true,false,undefined/null/empty]); can be characters/strings (i.e. ["valid & ended","valid","invalid"]); etc.

      • Please specify the I/O you've used in your answer!



    • You are allowed to take the input-integers pre-ordered from lowest to highest or vice-versa.

    • The input integers can be negative, in which case they are of course invalid.


    General rules:




    • This is code-golf, so shortest answer in bytes wins.

      Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.


    • Standard rules apply for your answer with default I/O rules, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.


    • Default Loopholes are forbidden.

    • If possible, please add a link with a test for your code (i.e. TIO).

    • Also, adding an explanation for your answer is highly recommended.


    Test cases:



    These test cases are valid, and the set has ended:



    0 21
    12 21
    21 23
    28 30
    29 30


    These test cases are valid, but the set is still in play:



    0 0
    0 20
    12 12
    21 21
    21 22


    These test cases are invalid:



    -21 19
    -19 21
    -1 1
    12 22
    29 31
    30 30
    42 43
    1021 1021









    share|improve this question











    $endgroup$















      18












      18








      18


      1



      $begingroup$


      Introduction:



      I saw there was only one other badminton related challenge right now. Since I play badminton myself (for the past 13 years now), I figured I'd add some badminton-related challenges. Here the first one:



      Challenge:



      Input: Two integers
      Output: One of three distinct and unique outputs of your own choice. One indicating that the input is a valid badminton score AND the set has ended with a winner; one indicating that the input is a valid badminton score AND the set is still in play; one indicating the input is not a valid badminton score.



      With badminton, both (pairs of) players start with 0 points, and you stop when one of the two (pairs of) players has reached a score of 21, with at least 2 points difference, up to a maximum of 30-29.



      So these are all possible input-pairs (in either order) indicating it's a valid badminton score AND the set has ended:



      [[0,21],[1,21],[2,21],[3,21],[4,21],[5,21],[6,21],[7,21],[8,21],[9,21],[10,21],[11,21],[12,21],[13,21],[14,21],[15,21],[16,21],[17,21],[18,21],[19,21],[20,22],[21,23],[22,24],[23,25],[24,26],[25,27],[26,28],[27,29],[28,30],[29,30]]


      And these are all possible input-pairs (in either order) indicating it's a valid badminton score BUT the set is still in play:



      [[0,0],[0,1],[0,2],[0,3],[0,4],[0,5],[0,6],[0,7],[0,8],[0,9],[0,10],[0,11],[0,12],[0,13],[0,14],[0,15],[0,16],[0,17],[0,18],[0,19],[0,20],[1,1],[1,2],[1,3],[1,4],[1,5],[1,6],[1,7],[1,8],[1,9],[1,10],[1,11],[1,12],[1,13],[1,14],[1,15],[1,16],[1,17],[1,18],[1,19],[1,20],[2,2],[2,3],[2,4],[2,5],[2,6],[2,7],[2,8],[2,9],[2,10],[2,11],[2,12],[2,13],[2,14],[2,15],[2,16],[2,17],[2,18],[2,19],[2,20],[3,3],[3,4],[3,5],[3,6],[3,7],[3,8],[3,9],[3,10],[3,11],[3,12],[3,13],[3,14],[3,15],[3,16],[3,17],[3,18],[3,19],[3,20],[4,4],[4,5],[4,6],[4,7],[4,8],[4,9],[4,10],[4,11],[4,12],[4,13],[4,14],[4,15],[4,16],[4,17],[4,18],[4,19],[4,20],[5,5],[5,6],[5,7],[5,8],[5,9],[5,10],[5,11],[5,12],[5,13],[5,14],[5,15],[5,16],[5,17],[5,18],[5,19],[5,20],[6,6],[6,7],[6,8],[6,9],[6,10],[6,11],[6,12],[6,13],[6,14],[6,15],[6,16],[6,17],[6,18],[6,19],[6,20],[7,7],[7,8],[7,9],[7,10],[7,11],[7,12],[7,13],[7,14],[7,15],[7,16],[7,17],[7,18],[7,19],[7,20],[8,8],[8,9],[8,10],[8,11],[8,12],[8,13],[8,14],[8,15],[8,16],[8,17],[8,18],[8,19],[8,20],[9,9],[9,10],[9,11],[9,12],[9,13],[9,14],[9,15],[9,16],[9,17],[9,18],[9,19],[9,20],[10,10],[10,11],[10,12],[10,13],[10,14],[10,15],[10,16],[10,17],[10,18],[10,19],[10,20],[11,11],[11,12],[11,13],[11,14],[11,15],[11,16],[11,17],[11,18],[11,19],[11,20],[12,12],[12,13],[12,14],[12,15],[12,16],[12,17],[12,18],[12,19],[12,20],[13,13],[13,14],[13,15],[13,16],[13,17],[13,18],[13,19],[13,20],[14,14],[14,15],[14,16],[14,17],[14,18],[14,19],[14,20],[15,15],[15,16],[15,17],[15,18],[15,19],[15,20],[16,16],[16,17],[16,18],[16,19],[16,20],[17,17],[17,18],[17,19],[17,20],[18,18],[18,19],[18,20],[19,19],[19,20],[20,20],[20,21],[21,21],[21,22],[22,22],[22,23],[23,23],[23,24],[24,24],[24,25],[25,25],[25,26],[26,26],[26,27],[27,27],[27,28],[28,28],[28,29],[29,29]]


      Any other pair of integer would be an invalid badminton score.



      Challenge rules:




      • I/O is flexible, so:


        • You can take the input as a list of two numbers; two separated numbers through STDIN or function parameters; two strings; etc.

        • Output will be three distinct and unique values of your own choice. Can be integers (i.e. [0,1,2], [1,2,3], [-1,0,1], etc.); can be Booleans (i.e. [true,false,undefined/null/empty]); can be characters/strings (i.e. ["valid & ended","valid","invalid"]); etc.

        • Please specify the I/O you've used in your answer!



      • You are allowed to take the input-integers pre-ordered from lowest to highest or vice-versa.

      • The input integers can be negative, in which case they are of course invalid.


      General rules:




      • This is code-golf, so shortest answer in bytes wins.

        Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.


      • Standard rules apply for your answer with default I/O rules, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.


      • Default Loopholes are forbidden.

      • If possible, please add a link with a test for your code (i.e. TIO).

      • Also, adding an explanation for your answer is highly recommended.


      Test cases:



      These test cases are valid, and the set has ended:



      0 21
      12 21
      21 23
      28 30
      29 30


      These test cases are valid, but the set is still in play:



      0 0
      0 20
      12 12
      21 21
      21 22


      These test cases are invalid:



      -21 19
      -19 21
      -1 1
      12 22
      29 31
      30 30
      42 43
      1021 1021









      share|improve this question











      $endgroup$




      Introduction:



      I saw there was only one other badminton related challenge right now. Since I play badminton myself (for the past 13 years now), I figured I'd add some badminton-related challenges. Here the first one:



      Challenge:



      Input: Two integers
      Output: One of three distinct and unique outputs of your own choice. One indicating that the input is a valid badminton score AND the set has ended with a winner; one indicating that the input is a valid badminton score AND the set is still in play; one indicating the input is not a valid badminton score.



      With badminton, both (pairs of) players start with 0 points, and you stop when one of the two (pairs of) players has reached a score of 21, with at least 2 points difference, up to a maximum of 30-29.



      So these are all possible input-pairs (in either order) indicating it's a valid badminton score AND the set has ended:



      [[0,21],[1,21],[2,21],[3,21],[4,21],[5,21],[6,21],[7,21],[8,21],[9,21],[10,21],[11,21],[12,21],[13,21],[14,21],[15,21],[16,21],[17,21],[18,21],[19,21],[20,22],[21,23],[22,24],[23,25],[24,26],[25,27],[26,28],[27,29],[28,30],[29,30]]


      And these are all possible input-pairs (in either order) indicating it's a valid badminton score BUT the set is still in play:



      [[0,0],[0,1],[0,2],[0,3],[0,4],[0,5],[0,6],[0,7],[0,8],[0,9],[0,10],[0,11],[0,12],[0,13],[0,14],[0,15],[0,16],[0,17],[0,18],[0,19],[0,20],[1,1],[1,2],[1,3],[1,4],[1,5],[1,6],[1,7],[1,8],[1,9],[1,10],[1,11],[1,12],[1,13],[1,14],[1,15],[1,16],[1,17],[1,18],[1,19],[1,20],[2,2],[2,3],[2,4],[2,5],[2,6],[2,7],[2,8],[2,9],[2,10],[2,11],[2,12],[2,13],[2,14],[2,15],[2,16],[2,17],[2,18],[2,19],[2,20],[3,3],[3,4],[3,5],[3,6],[3,7],[3,8],[3,9],[3,10],[3,11],[3,12],[3,13],[3,14],[3,15],[3,16],[3,17],[3,18],[3,19],[3,20],[4,4],[4,5],[4,6],[4,7],[4,8],[4,9],[4,10],[4,11],[4,12],[4,13],[4,14],[4,15],[4,16],[4,17],[4,18],[4,19],[4,20],[5,5],[5,6],[5,7],[5,8],[5,9],[5,10],[5,11],[5,12],[5,13],[5,14],[5,15],[5,16],[5,17],[5,18],[5,19],[5,20],[6,6],[6,7],[6,8],[6,9],[6,10],[6,11],[6,12],[6,13],[6,14],[6,15],[6,16],[6,17],[6,18],[6,19],[6,20],[7,7],[7,8],[7,9],[7,10],[7,11],[7,12],[7,13],[7,14],[7,15],[7,16],[7,17],[7,18],[7,19],[7,20],[8,8],[8,9],[8,10],[8,11],[8,12],[8,13],[8,14],[8,15],[8,16],[8,17],[8,18],[8,19],[8,20],[9,9],[9,10],[9,11],[9,12],[9,13],[9,14],[9,15],[9,16],[9,17],[9,18],[9,19],[9,20],[10,10],[10,11],[10,12],[10,13],[10,14],[10,15],[10,16],[10,17],[10,18],[10,19],[10,20],[11,11],[11,12],[11,13],[11,14],[11,15],[11,16],[11,17],[11,18],[11,19],[11,20],[12,12],[12,13],[12,14],[12,15],[12,16],[12,17],[12,18],[12,19],[12,20],[13,13],[13,14],[13,15],[13,16],[13,17],[13,18],[13,19],[13,20],[14,14],[14,15],[14,16],[14,17],[14,18],[14,19],[14,20],[15,15],[15,16],[15,17],[15,18],[15,19],[15,20],[16,16],[16,17],[16,18],[16,19],[16,20],[17,17],[17,18],[17,19],[17,20],[18,18],[18,19],[18,20],[19,19],[19,20],[20,20],[20,21],[21,21],[21,22],[22,22],[22,23],[23,23],[23,24],[24,24],[24,25],[25,25],[25,26],[26,26],[26,27],[27,27],[27,28],[28,28],[28,29],[29,29]]


      Any other pair of integer would be an invalid badminton score.



      Challenge rules:




      • I/O is flexible, so:


        • You can take the input as a list of two numbers; two separated numbers through STDIN or function parameters; two strings; etc.

        • Output will be three distinct and unique values of your own choice. Can be integers (i.e. [0,1,2], [1,2,3], [-1,0,1], etc.); can be Booleans (i.e. [true,false,undefined/null/empty]); can be characters/strings (i.e. ["valid & ended","valid","invalid"]); etc.

        • Please specify the I/O you've used in your answer!



      • You are allowed to take the input-integers pre-ordered from lowest to highest or vice-versa.

      • The input integers can be negative, in which case they are of course invalid.


      General rules:




      • This is code-golf, so shortest answer in bytes wins.

        Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.


      • Standard rules apply for your answer with default I/O rules, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.


      • Default Loopholes are forbidden.

      • If possible, please add a link with a test for your code (i.e. TIO).

      • Also, adding an explanation for your answer is highly recommended.


      Test cases:



      These test cases are valid, and the set has ended:



      0 21
      12 21
      21 23
      28 30
      29 30


      These test cases are valid, but the set is still in play:



      0 0
      0 20
      12 12
      21 21
      21 22


      These test cases are invalid:



      -21 19
      -19 21
      -1 1
      12 22
      29 31
      30 30
      42 43
      1021 1021






      code-golf number integer






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 9 hours ago







      Kevin Cruijssen

















      asked 10 hours ago









      Kevin CruijssenKevin Cruijssen

      41.6k567215




      41.6k567215






















          8 Answers
          8






          active

          oldest

          votes


















          4












          $begingroup$


          Jelly, 25 bytes



          »19«28‘<‘×+2>ɗʋ⁹×,%Ƒ“œþ‘ɗ


          Try it online!



          Left argument: minimum. Right argument: maximum.

          Invalid: 0. Ongoing: 1. Ended: 2.






          share|improve this answer











          $endgroup$





















            4












            $begingroup$


            C# (Visual C# Interactive Compiler), 53 52 bytes





            a=>b=>b<0|a-b>2&a>21|b>29|a>30?3:a>20&a-b>1|a>29?1:2


            Called as f(max)(min). Returns 3 for invalid, 1 for finished, 2 for ongoing.



            Saved 1 byte thanks to Kevin Cruijjsen



            Try it online!






            share|improve this answer











            $endgroup$













            • $begingroup$
              a==30 can be a>29 to save a byte. And I forgot that C# can't return an int and bool in a single ternary.. Otherwise object or dynamic could have been used as return-type and the ?1:2 could have been omitted for 3,true,false as outputs.
              $endgroup$
              – Kevin Cruijssen
              7 hours ago



















            4












            $begingroup$


            Python 2, 97 95 75 72 71 70 bytes





            lambda a,b:(-1<a<=b<22or 0<a>=b-2<b<31>a+1)and(20<b-(b<30)>a)+(a<20<b)


            Try it online!



            Takes input as pre-ordered a,b.



            Returns 1, 0, False for ended, in play, invalid.



            -1 byte, thanks to Kevin Cruijssen






            share|improve this answer











            $endgroup$













            • $begingroup$
              You can remove if a>b:a,b=b,a since I state in the rules: "You are allowed to take the input-integer pre-ordered from lowest to highest or vice-versa."
              $endgroup$
              – Kevin Cruijssen
              9 hours ago










            • $begingroup$
              and(20<b-(b<30)>a)+(a<20<b)+1 can be and(20<b-(b<30)>a)-~(a<20<b) for -1 byte if I'm not mistaken.
              $endgroup$
              – Kevin Cruijssen
              9 hours ago



















            3












            $begingroup$

            JavaScript (ES6),  55 53  48 bytes



            Thanks to @KevinCruijssen for noticing that I was not fully assuming $ale b$ (saving 5 bytes)



            Takes input as (a)(b) with $ale b$. Returns $0$ (valid), $1$ (ended) or $2$ (invalid).





            a=>b=>a<0|a>29|b>30|b>21&b-a>2?2:b>20&b-a>1|b>29


            Try it online!






            share|improve this answer











            $endgroup$













            • $begingroup$
              48 bytes?
              $endgroup$
              – Kevin Cruijssen
              8 hours ago








            • 1




              $begingroup$
              Hehe, based on all answers I've seen thus far of you, the word 'stupid' would be one of the last things I would think of. ;) But glad I could help.
              $endgroup$
              – Kevin Cruijssen
              8 hours ago



















            2












            $begingroup$


            VDM-SL, 80 bytes





            f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)} 


            This function takes the scores ordered in ascending order and returns the empty set if the score is invalid or the set containing whether the set is complete (so {true} if the set is complete and valid and {false} if the set is incomplete and valid)



            A full program to run might look like this:



            functions
            f:int*int+>set of bool
            f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)}


            Explanation:



            if(j-i>2 and j>21)             /*if scores are too far apart*/
            or(i<0 or i=30 or j>30) /*or scores not in a valid range*/
            then {} /*return the empty set*/
            else{ } /*else return the set containing...*/
            (j>20 and j-i>1 or j=30) /*if the set is complete*/





            share|improve this answer









            $endgroup$





















              1












              $begingroup$


              Retina 0.8.2, 92 bytes



              d+
              $*
              ^(1{0,19},1{21}|(1{20,28}),112|1{29},1{30})$|^(1*,1{0,20}|(1{0,28}),1?4)$|.+
              $#1$#3


              Try it online! Link includes test cases. Takes input in ascending order. Explanation: The first stage simply converts from decimal to unary so that the scores can be properly compared. The second stage contains six alternate patterns, grouped into three groups so that three distinct values can be output, which are 10 for win, 01 for ongoing and 00 for illegal. The patterns are:




              • Against 0-19, a score of 21 is a win

              • Against 20-28, a score of +2 is a win

              • Against 29, a score of 30 is a win

              • Against any (lower) score, a score of 0-20 is ongoing

              • Against a score of up to 28, a score of +1 is ongoing

              • Anything else (including negative scores) is illegal






              share|improve this answer









              $endgroup$





















                1












                $begingroup$


                Java (JDK), 59 48 bytes





                a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2


                Try it online!



                Returns an Object, which is the Integer 0 for invalid games and the Booleans true and false for valid ongoing games and for valid finished games respectively. Takes the score ordered (and curried), with the higher score first.



                -2 bytes by inverting the end-of-match check.
                -11 bytes by currying, using bitwise operators, and some return type autoboxing trickery - thanks to @KevinCruijssen



                Ungolfed



                a->                      // Curried: Target type IntFunction<IntFunction<Object>>
                b-> // Target type IntFunction<Object>
                // Invalid if:
                b<0 // Any score is negative
                | b > 29 // Both scores above 29
                | a > b + 2 // Lead too big
                & a > 21 // and leader has at least 21 points
                | a > 30 // Anyone has 31 points
                ? 0 // If invalid, return 0 (autoboxed to Integer)
                // If valid, return whether the game is ongoing (autoboxed to Boolean)
                // Ongoing if:
                : a < 21 // Nobody has 21 points
                | a < 30 // Leader has fewer than 30 points
                & a < b + 2 // and lead is small





                share|improve this answer











                $endgroup$









                • 1




                  $begingroup$
                  -11 bytes by using: a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2 :) All the || and && are now | and &. The (a,b)-> is a->b->. And the ?1:2 is removed, so you return 0 for invalid; true for valid ongoing; false for valid finished (of type Object).
                  $endgroup$
                  – Kevin Cruijssen
                  4 hours ago



















                0












                $begingroup$


                Python 2, 47 bytes





                lambda a,b:[61>60-a>b<3+max(19,a)for b in-~b,b]


                Try it online!



                Outputs a list of two Booleans. Thanks to TFeld for writing a test suite in their answer that made it easy to check my solution.



                ended: [False, True]
                going: [True, True]
                invalid: [False, False]


                The key insight is that a valid score ends the game exactly if increasing the higher value b makes the score invalid. So, we just code up the validity condition, and check it for (a,b+1) in addition to (a,b) to see if the game has ended.



                Validity is checked via three conditions that are chained together:





                • b<3+max(19,a): Checks that the higher score b isn't past winning, with either b<=21 or b<=a+2 (win by two)


                • 60-a>b: Equivalent to a+b<=59, ensuring the score isn't above (29,30)


                • 61>60-a: Equivalent to a>=0, ensures the lower score is non-negative





                Python 2, 44 bytes





                lambda a,b:0!=a/30or cmp(b,2+max(19,a)-a/29)


                Try it online!



                Outputs:



                ended: 0
                going: -1
                invalid: 1 (including True)





                share|improve this answer











                $endgroup$













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                  8 Answers
                  8






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                  8 Answers
                  8






                  active

                  oldest

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                  active

                  oldest

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                  active

                  oldest

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                  4












                  $begingroup$


                  Jelly, 25 bytes



                  »19«28‘<‘×+2>ɗʋ⁹×,%Ƒ“œþ‘ɗ


                  Try it online!



                  Left argument: minimum. Right argument: maximum.

                  Invalid: 0. Ongoing: 1. Ended: 2.






                  share|improve this answer











                  $endgroup$


















                    4












                    $begingroup$


                    Jelly, 25 bytes



                    »19«28‘<‘×+2>ɗʋ⁹×,%Ƒ“œþ‘ɗ


                    Try it online!



                    Left argument: minimum. Right argument: maximum.

                    Invalid: 0. Ongoing: 1. Ended: 2.






                    share|improve this answer











                    $endgroup$
















                      4












                      4








                      4





                      $begingroup$


                      Jelly, 25 bytes



                      »19«28‘<‘×+2>ɗʋ⁹×,%Ƒ“œþ‘ɗ


                      Try it online!



                      Left argument: minimum. Right argument: maximum.

                      Invalid: 0. Ongoing: 1. Ended: 2.






                      share|improve this answer











                      $endgroup$




                      Jelly, 25 bytes



                      »19«28‘<‘×+2>ɗʋ⁹×,%Ƒ“œþ‘ɗ


                      Try it online!



                      Left argument: minimum. Right argument: maximum.

                      Invalid: 0. Ongoing: 1. Ended: 2.







                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited 7 hours ago

























                      answered 8 hours ago









                      Erik the OutgolferErik the Outgolfer

                      32.8k429105




                      32.8k429105























                          4












                          $begingroup$


                          C# (Visual C# Interactive Compiler), 53 52 bytes





                          a=>b=>b<0|a-b>2&a>21|b>29|a>30?3:a>20&a-b>1|a>29?1:2


                          Called as f(max)(min). Returns 3 for invalid, 1 for finished, 2 for ongoing.



                          Saved 1 byte thanks to Kevin Cruijjsen



                          Try it online!






                          share|improve this answer











                          $endgroup$













                          • $begingroup$
                            a==30 can be a>29 to save a byte. And I forgot that C# can't return an int and bool in a single ternary.. Otherwise object or dynamic could have been used as return-type and the ?1:2 could have been omitted for 3,true,false as outputs.
                            $endgroup$
                            – Kevin Cruijssen
                            7 hours ago
















                          4












                          $begingroup$


                          C# (Visual C# Interactive Compiler), 53 52 bytes





                          a=>b=>b<0|a-b>2&a>21|b>29|a>30?3:a>20&a-b>1|a>29?1:2


                          Called as f(max)(min). Returns 3 for invalid, 1 for finished, 2 for ongoing.



                          Saved 1 byte thanks to Kevin Cruijjsen



                          Try it online!






                          share|improve this answer











                          $endgroup$













                          • $begingroup$
                            a==30 can be a>29 to save a byte. And I forgot that C# can't return an int and bool in a single ternary.. Otherwise object or dynamic could have been used as return-type and the ?1:2 could have been omitted for 3,true,false as outputs.
                            $endgroup$
                            – Kevin Cruijssen
                            7 hours ago














                          4












                          4








                          4





                          $begingroup$


                          C# (Visual C# Interactive Compiler), 53 52 bytes





                          a=>b=>b<0|a-b>2&a>21|b>29|a>30?3:a>20&a-b>1|a>29?1:2


                          Called as f(max)(min). Returns 3 for invalid, 1 for finished, 2 for ongoing.



                          Saved 1 byte thanks to Kevin Cruijjsen



                          Try it online!






                          share|improve this answer











                          $endgroup$




                          C# (Visual C# Interactive Compiler), 53 52 bytes





                          a=>b=>b<0|a-b>2&a>21|b>29|a>30?3:a>20&a-b>1|a>29?1:2


                          Called as f(max)(min). Returns 3 for invalid, 1 for finished, 2 for ongoing.



                          Saved 1 byte thanks to Kevin Cruijjsen



                          Try it online!







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 7 hours ago

























                          answered 7 hours ago









                          Embodiment of IgnoranceEmbodiment of Ignorance

                          2,208125




                          2,208125












                          • $begingroup$
                            a==30 can be a>29 to save a byte. And I forgot that C# can't return an int and bool in a single ternary.. Otherwise object or dynamic could have been used as return-type and the ?1:2 could have been omitted for 3,true,false as outputs.
                            $endgroup$
                            – Kevin Cruijssen
                            7 hours ago


















                          • $begingroup$
                            a==30 can be a>29 to save a byte. And I forgot that C# can't return an int and bool in a single ternary.. Otherwise object or dynamic could have been used as return-type and the ?1:2 could have been omitted for 3,true,false as outputs.
                            $endgroup$
                            – Kevin Cruijssen
                            7 hours ago
















                          $begingroup$
                          a==30 can be a>29 to save a byte. And I forgot that C# can't return an int and bool in a single ternary.. Otherwise object or dynamic could have been used as return-type and the ?1:2 could have been omitted for 3,true,false as outputs.
                          $endgroup$
                          – Kevin Cruijssen
                          7 hours ago




                          $begingroup$
                          a==30 can be a>29 to save a byte. And I forgot that C# can't return an int and bool in a single ternary.. Otherwise object or dynamic could have been used as return-type and the ?1:2 could have been omitted for 3,true,false as outputs.
                          $endgroup$
                          – Kevin Cruijssen
                          7 hours ago











                          4












                          $begingroup$


                          Python 2, 97 95 75 72 71 70 bytes





                          lambda a,b:(-1<a<=b<22or 0<a>=b-2<b<31>a+1)and(20<b-(b<30)>a)+(a<20<b)


                          Try it online!



                          Takes input as pre-ordered a,b.



                          Returns 1, 0, False for ended, in play, invalid.



                          -1 byte, thanks to Kevin Cruijssen






                          share|improve this answer











                          $endgroup$













                          • $begingroup$
                            You can remove if a>b:a,b=b,a since I state in the rules: "You are allowed to take the input-integer pre-ordered from lowest to highest or vice-versa."
                            $endgroup$
                            – Kevin Cruijssen
                            9 hours ago










                          • $begingroup$
                            and(20<b-(b<30)>a)+(a<20<b)+1 can be and(20<b-(b<30)>a)-~(a<20<b) for -1 byte if I'm not mistaken.
                            $endgroup$
                            – Kevin Cruijssen
                            9 hours ago
















                          4












                          $begingroup$


                          Python 2, 97 95 75 72 71 70 bytes





                          lambda a,b:(-1<a<=b<22or 0<a>=b-2<b<31>a+1)and(20<b-(b<30)>a)+(a<20<b)


                          Try it online!



                          Takes input as pre-ordered a,b.



                          Returns 1, 0, False for ended, in play, invalid.



                          -1 byte, thanks to Kevin Cruijssen






                          share|improve this answer











                          $endgroup$













                          • $begingroup$
                            You can remove if a>b:a,b=b,a since I state in the rules: "You are allowed to take the input-integer pre-ordered from lowest to highest or vice-versa."
                            $endgroup$
                            – Kevin Cruijssen
                            9 hours ago










                          • $begingroup$
                            and(20<b-(b<30)>a)+(a<20<b)+1 can be and(20<b-(b<30)>a)-~(a<20<b) for -1 byte if I'm not mistaken.
                            $endgroup$
                            – Kevin Cruijssen
                            9 hours ago














                          4












                          4








                          4





                          $begingroup$


                          Python 2, 97 95 75 72 71 70 bytes





                          lambda a,b:(-1<a<=b<22or 0<a>=b-2<b<31>a+1)and(20<b-(b<30)>a)+(a<20<b)


                          Try it online!



                          Takes input as pre-ordered a,b.



                          Returns 1, 0, False for ended, in play, invalid.



                          -1 byte, thanks to Kevin Cruijssen






                          share|improve this answer











                          $endgroup$




                          Python 2, 97 95 75 72 71 70 bytes





                          lambda a,b:(-1<a<=b<22or 0<a>=b-2<b<31>a+1)and(20<b-(b<30)>a)+(a<20<b)


                          Try it online!



                          Takes input as pre-ordered a,b.



                          Returns 1, 0, False for ended, in play, invalid.



                          -1 byte, thanks to Kevin Cruijssen







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 6 hours ago

























                          answered 9 hours ago









                          TFeldTFeld

                          16.1k21449




                          16.1k21449












                          • $begingroup$
                            You can remove if a>b:a,b=b,a since I state in the rules: "You are allowed to take the input-integer pre-ordered from lowest to highest or vice-versa."
                            $endgroup$
                            – Kevin Cruijssen
                            9 hours ago










                          • $begingroup$
                            and(20<b-(b<30)>a)+(a<20<b)+1 can be and(20<b-(b<30)>a)-~(a<20<b) for -1 byte if I'm not mistaken.
                            $endgroup$
                            – Kevin Cruijssen
                            9 hours ago


















                          • $begingroup$
                            You can remove if a>b:a,b=b,a since I state in the rules: "You are allowed to take the input-integer pre-ordered from lowest to highest or vice-versa."
                            $endgroup$
                            – Kevin Cruijssen
                            9 hours ago










                          • $begingroup$
                            and(20<b-(b<30)>a)+(a<20<b)+1 can be and(20<b-(b<30)>a)-~(a<20<b) for -1 byte if I'm not mistaken.
                            $endgroup$
                            – Kevin Cruijssen
                            9 hours ago
















                          $begingroup$
                          You can remove if a>b:a,b=b,a since I state in the rules: "You are allowed to take the input-integer pre-ordered from lowest to highest or vice-versa."
                          $endgroup$
                          – Kevin Cruijssen
                          9 hours ago




                          $begingroup$
                          You can remove if a>b:a,b=b,a since I state in the rules: "You are allowed to take the input-integer pre-ordered from lowest to highest or vice-versa."
                          $endgroup$
                          – Kevin Cruijssen
                          9 hours ago












                          $begingroup$
                          and(20<b-(b<30)>a)+(a<20<b)+1 can be and(20<b-(b<30)>a)-~(a<20<b) for -1 byte if I'm not mistaken.
                          $endgroup$
                          – Kevin Cruijssen
                          9 hours ago




                          $begingroup$
                          and(20<b-(b<30)>a)+(a<20<b)+1 can be and(20<b-(b<30)>a)-~(a<20<b) for -1 byte if I'm not mistaken.
                          $endgroup$
                          – Kevin Cruijssen
                          9 hours ago











                          3












                          $begingroup$

                          JavaScript (ES6),  55 53  48 bytes



                          Thanks to @KevinCruijssen for noticing that I was not fully assuming $ale b$ (saving 5 bytes)



                          Takes input as (a)(b) with $ale b$. Returns $0$ (valid), $1$ (ended) or $2$ (invalid).





                          a=>b=>a<0|a>29|b>30|b>21&b-a>2?2:b>20&b-a>1|b>29


                          Try it online!






                          share|improve this answer











                          $endgroup$













                          • $begingroup$
                            48 bytes?
                            $endgroup$
                            – Kevin Cruijssen
                            8 hours ago








                          • 1




                            $begingroup$
                            Hehe, based on all answers I've seen thus far of you, the word 'stupid' would be one of the last things I would think of. ;) But glad I could help.
                            $endgroup$
                            – Kevin Cruijssen
                            8 hours ago
















                          3












                          $begingroup$

                          JavaScript (ES6),  55 53  48 bytes



                          Thanks to @KevinCruijssen for noticing that I was not fully assuming $ale b$ (saving 5 bytes)



                          Takes input as (a)(b) with $ale b$. Returns $0$ (valid), $1$ (ended) or $2$ (invalid).





                          a=>b=>a<0|a>29|b>30|b>21&b-a>2?2:b>20&b-a>1|b>29


                          Try it online!






                          share|improve this answer











                          $endgroup$













                          • $begingroup$
                            48 bytes?
                            $endgroup$
                            – Kevin Cruijssen
                            8 hours ago








                          • 1




                            $begingroup$
                            Hehe, based on all answers I've seen thus far of you, the word 'stupid' would be one of the last things I would think of. ;) But glad I could help.
                            $endgroup$
                            – Kevin Cruijssen
                            8 hours ago














                          3












                          3








                          3





                          $begingroup$

                          JavaScript (ES6),  55 53  48 bytes



                          Thanks to @KevinCruijssen for noticing that I was not fully assuming $ale b$ (saving 5 bytes)



                          Takes input as (a)(b) with $ale b$. Returns $0$ (valid), $1$ (ended) or $2$ (invalid).





                          a=>b=>a<0|a>29|b>30|b>21&b-a>2?2:b>20&b-a>1|b>29


                          Try it online!






                          share|improve this answer











                          $endgroup$



                          JavaScript (ES6),  55 53  48 bytes



                          Thanks to @KevinCruijssen for noticing that I was not fully assuming $ale b$ (saving 5 bytes)



                          Takes input as (a)(b) with $ale b$. Returns $0$ (valid), $1$ (ended) or $2$ (invalid).





                          a=>b=>a<0|a>29|b>30|b>21&b-a>2?2:b>20&b-a>1|b>29


                          Try it online!







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 8 hours ago

























                          answered 9 hours ago









                          ArnauldArnauld

                          79.8k797330




                          79.8k797330












                          • $begingroup$
                            48 bytes?
                            $endgroup$
                            – Kevin Cruijssen
                            8 hours ago








                          • 1




                            $begingroup$
                            Hehe, based on all answers I've seen thus far of you, the word 'stupid' would be one of the last things I would think of. ;) But glad I could help.
                            $endgroup$
                            – Kevin Cruijssen
                            8 hours ago


















                          • $begingroup$
                            48 bytes?
                            $endgroup$
                            – Kevin Cruijssen
                            8 hours ago








                          • 1




                            $begingroup$
                            Hehe, based on all answers I've seen thus far of you, the word 'stupid' would be one of the last things I would think of. ;) But glad I could help.
                            $endgroup$
                            – Kevin Cruijssen
                            8 hours ago
















                          $begingroup$
                          48 bytes?
                          $endgroup$
                          – Kevin Cruijssen
                          8 hours ago






                          $begingroup$
                          48 bytes?
                          $endgroup$
                          – Kevin Cruijssen
                          8 hours ago






                          1




                          1




                          $begingroup$
                          Hehe, based on all answers I've seen thus far of you, the word 'stupid' would be one of the last things I would think of. ;) But glad I could help.
                          $endgroup$
                          – Kevin Cruijssen
                          8 hours ago




                          $begingroup$
                          Hehe, based on all answers I've seen thus far of you, the word 'stupid' would be one of the last things I would think of. ;) But glad I could help.
                          $endgroup$
                          – Kevin Cruijssen
                          8 hours ago











                          2












                          $begingroup$


                          VDM-SL, 80 bytes





                          f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)} 


                          This function takes the scores ordered in ascending order and returns the empty set if the score is invalid or the set containing whether the set is complete (so {true} if the set is complete and valid and {false} if the set is incomplete and valid)



                          A full program to run might look like this:



                          functions
                          f:int*int+>set of bool
                          f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)}


                          Explanation:



                          if(j-i>2 and j>21)             /*if scores are too far apart*/
                          or(i<0 or i=30 or j>30) /*or scores not in a valid range*/
                          then {} /*return the empty set*/
                          else{ } /*else return the set containing...*/
                          (j>20 and j-i>1 or j=30) /*if the set is complete*/





                          share|improve this answer









                          $endgroup$


















                            2












                            $begingroup$


                            VDM-SL, 80 bytes





                            f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)} 


                            This function takes the scores ordered in ascending order and returns the empty set if the score is invalid or the set containing whether the set is complete (so {true} if the set is complete and valid and {false} if the set is incomplete and valid)



                            A full program to run might look like this:



                            functions
                            f:int*int+>set of bool
                            f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)}


                            Explanation:



                            if(j-i>2 and j>21)             /*if scores are too far apart*/
                            or(i<0 or i=30 or j>30) /*or scores not in a valid range*/
                            then {} /*return the empty set*/
                            else{ } /*else return the set containing...*/
                            (j>20 and j-i>1 or j=30) /*if the set is complete*/





                            share|improve this answer









                            $endgroup$
















                              2












                              2








                              2





                              $begingroup$


                              VDM-SL, 80 bytes





                              f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)} 


                              This function takes the scores ordered in ascending order and returns the empty set if the score is invalid or the set containing whether the set is complete (so {true} if the set is complete and valid and {false} if the set is incomplete and valid)



                              A full program to run might look like this:



                              functions
                              f:int*int+>set of bool
                              f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)}


                              Explanation:



                              if(j-i>2 and j>21)             /*if scores are too far apart*/
                              or(i<0 or i=30 or j>30) /*or scores not in a valid range*/
                              then {} /*return the empty set*/
                              else{ } /*else return the set containing...*/
                              (j>20 and j-i>1 or j=30) /*if the set is complete*/





                              share|improve this answer









                              $endgroup$




                              VDM-SL, 80 bytes





                              f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)} 


                              This function takes the scores ordered in ascending order and returns the empty set if the score is invalid or the set containing whether the set is complete (so {true} if the set is complete and valid and {false} if the set is incomplete and valid)



                              A full program to run might look like this:



                              functions
                              f:int*int+>set of bool
                              f(i,j)==if(j-i>2and j>21)or(i<0or i=30or j>30)then{}else{(j>20and j-i>1or j=30)}


                              Explanation:



                              if(j-i>2 and j>21)             /*if scores are too far apart*/
                              or(i<0 or i=30 or j>30) /*or scores not in a valid range*/
                              then {} /*return the empty set*/
                              else{ } /*else return the set containing...*/
                              (j>20 and j-i>1 or j=30) /*if the set is complete*/






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered 7 hours ago









                              Expired DataExpired Data

                              3186




                              3186























                                  1












                                  $begingroup$


                                  Retina 0.8.2, 92 bytes



                                  d+
                                  $*
                                  ^(1{0,19},1{21}|(1{20,28}),112|1{29},1{30})$|^(1*,1{0,20}|(1{0,28}),1?4)$|.+
                                  $#1$#3


                                  Try it online! Link includes test cases. Takes input in ascending order. Explanation: The first stage simply converts from decimal to unary so that the scores can be properly compared. The second stage contains six alternate patterns, grouped into three groups so that three distinct values can be output, which are 10 for win, 01 for ongoing and 00 for illegal. The patterns are:




                                  • Against 0-19, a score of 21 is a win

                                  • Against 20-28, a score of +2 is a win

                                  • Against 29, a score of 30 is a win

                                  • Against any (lower) score, a score of 0-20 is ongoing

                                  • Against a score of up to 28, a score of +1 is ongoing

                                  • Anything else (including negative scores) is illegal






                                  share|improve this answer









                                  $endgroup$


















                                    1












                                    $begingroup$


                                    Retina 0.8.2, 92 bytes



                                    d+
                                    $*
                                    ^(1{0,19},1{21}|(1{20,28}),112|1{29},1{30})$|^(1*,1{0,20}|(1{0,28}),1?4)$|.+
                                    $#1$#3


                                    Try it online! Link includes test cases. Takes input in ascending order. Explanation: The first stage simply converts from decimal to unary so that the scores can be properly compared. The second stage contains six alternate patterns, grouped into three groups so that three distinct values can be output, which are 10 for win, 01 for ongoing and 00 for illegal. The patterns are:




                                    • Against 0-19, a score of 21 is a win

                                    • Against 20-28, a score of +2 is a win

                                    • Against 29, a score of 30 is a win

                                    • Against any (lower) score, a score of 0-20 is ongoing

                                    • Against a score of up to 28, a score of +1 is ongoing

                                    • Anything else (including negative scores) is illegal






                                    share|improve this answer









                                    $endgroup$
















                                      1












                                      1








                                      1





                                      $begingroup$


                                      Retina 0.8.2, 92 bytes



                                      d+
                                      $*
                                      ^(1{0,19},1{21}|(1{20,28}),112|1{29},1{30})$|^(1*,1{0,20}|(1{0,28}),1?4)$|.+
                                      $#1$#3


                                      Try it online! Link includes test cases. Takes input in ascending order. Explanation: The first stage simply converts from decimal to unary so that the scores can be properly compared. The second stage contains six alternate patterns, grouped into three groups so that three distinct values can be output, which are 10 for win, 01 for ongoing and 00 for illegal. The patterns are:




                                      • Against 0-19, a score of 21 is a win

                                      • Against 20-28, a score of +2 is a win

                                      • Against 29, a score of 30 is a win

                                      • Against any (lower) score, a score of 0-20 is ongoing

                                      • Against a score of up to 28, a score of +1 is ongoing

                                      • Anything else (including negative scores) is illegal






                                      share|improve this answer









                                      $endgroup$




                                      Retina 0.8.2, 92 bytes



                                      d+
                                      $*
                                      ^(1{0,19},1{21}|(1{20,28}),112|1{29},1{30})$|^(1*,1{0,20}|(1{0,28}),1?4)$|.+
                                      $#1$#3


                                      Try it online! Link includes test cases. Takes input in ascending order. Explanation: The first stage simply converts from decimal to unary so that the scores can be properly compared. The second stage contains six alternate patterns, grouped into three groups so that three distinct values can be output, which are 10 for win, 01 for ongoing and 00 for illegal. The patterns are:




                                      • Against 0-19, a score of 21 is a win

                                      • Against 20-28, a score of +2 is a win

                                      • Against 29, a score of 30 is a win

                                      • Against any (lower) score, a score of 0-20 is ongoing

                                      • Against a score of up to 28, a score of +1 is ongoing

                                      • Anything else (including negative scores) is illegal







                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered 5 hours ago









                                      NeilNeil

                                      82.1k745178




                                      82.1k745178























                                          1












                                          $begingroup$


                                          Java (JDK), 59 48 bytes





                                          a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2


                                          Try it online!



                                          Returns an Object, which is the Integer 0 for invalid games and the Booleans true and false for valid ongoing games and for valid finished games respectively. Takes the score ordered (and curried), with the higher score first.



                                          -2 bytes by inverting the end-of-match check.
                                          -11 bytes by currying, using bitwise operators, and some return type autoboxing trickery - thanks to @KevinCruijssen



                                          Ungolfed



                                          a->                      // Curried: Target type IntFunction<IntFunction<Object>>
                                          b-> // Target type IntFunction<Object>
                                          // Invalid if:
                                          b<0 // Any score is negative
                                          | b > 29 // Both scores above 29
                                          | a > b + 2 // Lead too big
                                          & a > 21 // and leader has at least 21 points
                                          | a > 30 // Anyone has 31 points
                                          ? 0 // If invalid, return 0 (autoboxed to Integer)
                                          // If valid, return whether the game is ongoing (autoboxed to Boolean)
                                          // Ongoing if:
                                          : a < 21 // Nobody has 21 points
                                          | a < 30 // Leader has fewer than 30 points
                                          & a < b + 2 // and lead is small





                                          share|improve this answer











                                          $endgroup$









                                          • 1




                                            $begingroup$
                                            -11 bytes by using: a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2 :) All the || and && are now | and &. The (a,b)-> is a->b->. And the ?1:2 is removed, so you return 0 for invalid; true for valid ongoing; false for valid finished (of type Object).
                                            $endgroup$
                                            – Kevin Cruijssen
                                            4 hours ago
















                                          1












                                          $begingroup$


                                          Java (JDK), 59 48 bytes





                                          a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2


                                          Try it online!



                                          Returns an Object, which is the Integer 0 for invalid games and the Booleans true and false for valid ongoing games and for valid finished games respectively. Takes the score ordered (and curried), with the higher score first.



                                          -2 bytes by inverting the end-of-match check.
                                          -11 bytes by currying, using bitwise operators, and some return type autoboxing trickery - thanks to @KevinCruijssen



                                          Ungolfed



                                          a->                      // Curried: Target type IntFunction<IntFunction<Object>>
                                          b-> // Target type IntFunction<Object>
                                          // Invalid if:
                                          b<0 // Any score is negative
                                          | b > 29 // Both scores above 29
                                          | a > b + 2 // Lead too big
                                          & a > 21 // and leader has at least 21 points
                                          | a > 30 // Anyone has 31 points
                                          ? 0 // If invalid, return 0 (autoboxed to Integer)
                                          // If valid, return whether the game is ongoing (autoboxed to Boolean)
                                          // Ongoing if:
                                          : a < 21 // Nobody has 21 points
                                          | a < 30 // Leader has fewer than 30 points
                                          & a < b + 2 // and lead is small





                                          share|improve this answer











                                          $endgroup$









                                          • 1




                                            $begingroup$
                                            -11 bytes by using: a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2 :) All the || and && are now | and &. The (a,b)-> is a->b->. And the ?1:2 is removed, so you return 0 for invalid; true for valid ongoing; false for valid finished (of type Object).
                                            $endgroup$
                                            – Kevin Cruijssen
                                            4 hours ago














                                          1












                                          1








                                          1





                                          $begingroup$


                                          Java (JDK), 59 48 bytes





                                          a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2


                                          Try it online!



                                          Returns an Object, which is the Integer 0 for invalid games and the Booleans true and false for valid ongoing games and for valid finished games respectively. Takes the score ordered (and curried), with the higher score first.



                                          -2 bytes by inverting the end-of-match check.
                                          -11 bytes by currying, using bitwise operators, and some return type autoboxing trickery - thanks to @KevinCruijssen



                                          Ungolfed



                                          a->                      // Curried: Target type IntFunction<IntFunction<Object>>
                                          b-> // Target type IntFunction<Object>
                                          // Invalid if:
                                          b<0 // Any score is negative
                                          | b > 29 // Both scores above 29
                                          | a > b + 2 // Lead too big
                                          & a > 21 // and leader has at least 21 points
                                          | a > 30 // Anyone has 31 points
                                          ? 0 // If invalid, return 0 (autoboxed to Integer)
                                          // If valid, return whether the game is ongoing (autoboxed to Boolean)
                                          // Ongoing if:
                                          : a < 21 // Nobody has 21 points
                                          | a < 30 // Leader has fewer than 30 points
                                          & a < b + 2 // and lead is small





                                          share|improve this answer











                                          $endgroup$




                                          Java (JDK), 59 48 bytes





                                          a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2


                                          Try it online!



                                          Returns an Object, which is the Integer 0 for invalid games and the Booleans true and false for valid ongoing games and for valid finished games respectively. Takes the score ordered (and curried), with the higher score first.



                                          -2 bytes by inverting the end-of-match check.
                                          -11 bytes by currying, using bitwise operators, and some return type autoboxing trickery - thanks to @KevinCruijssen



                                          Ungolfed



                                          a->                      // Curried: Target type IntFunction<IntFunction<Object>>
                                          b-> // Target type IntFunction<Object>
                                          // Invalid if:
                                          b<0 // Any score is negative
                                          | b > 29 // Both scores above 29
                                          | a > b + 2 // Lead too big
                                          & a > 21 // and leader has at least 21 points
                                          | a > 30 // Anyone has 31 points
                                          ? 0 // If invalid, return 0 (autoboxed to Integer)
                                          // If valid, return whether the game is ongoing (autoboxed to Boolean)
                                          // Ongoing if:
                                          : a < 21 // Nobody has 21 points
                                          | a < 30 // Leader has fewer than 30 points
                                          & a < b + 2 // and lead is small






                                          share|improve this answer














                                          share|improve this answer



                                          share|improve this answer








                                          edited 3 hours ago

























                                          answered 5 hours ago









                                          Sara JSara J

                                          36519




                                          36519








                                          • 1




                                            $begingroup$
                                            -11 bytes by using: a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2 :) All the || and && are now | and &. The (a,b)-> is a->b->. And the ?1:2 is removed, so you return 0 for invalid; true for valid ongoing; false for valid finished (of type Object).
                                            $endgroup$
                                            – Kevin Cruijssen
                                            4 hours ago














                                          • 1




                                            $begingroup$
                                            -11 bytes by using: a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2 :) All the || and && are now | and &. The (a,b)-> is a->b->. And the ?1:2 is removed, so you return 0 for invalid; true for valid ongoing; false for valid finished (of type Object).
                                            $endgroup$
                                            – Kevin Cruijssen
                                            4 hours ago








                                          1




                                          1




                                          $begingroup$
                                          -11 bytes by using: a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2 :) All the || and && are now | and &. The (a,b)-> is a->b->. And the ?1:2 is removed, so you return 0 for invalid; true for valid ongoing; false for valid finished (of type Object).
                                          $endgroup$
                                          – Kevin Cruijssen
                                          4 hours ago




                                          $begingroup$
                                          -11 bytes by using: a->b->b<0|b>29|a>b+2&a>21|a>30?0:a<21|a<30&a<b+2 :) All the || and && are now | and &. The (a,b)-> is a->b->. And the ?1:2 is removed, so you return 0 for invalid; true for valid ongoing; false for valid finished (of type Object).
                                          $endgroup$
                                          – Kevin Cruijssen
                                          4 hours ago











                                          0












                                          $begingroup$


                                          Python 2, 47 bytes





                                          lambda a,b:[61>60-a>b<3+max(19,a)for b in-~b,b]


                                          Try it online!



                                          Outputs a list of two Booleans. Thanks to TFeld for writing a test suite in their answer that made it easy to check my solution.



                                          ended: [False, True]
                                          going: [True, True]
                                          invalid: [False, False]


                                          The key insight is that a valid score ends the game exactly if increasing the higher value b makes the score invalid. So, we just code up the validity condition, and check it for (a,b+1) in addition to (a,b) to see if the game has ended.



                                          Validity is checked via three conditions that are chained together:





                                          • b<3+max(19,a): Checks that the higher score b isn't past winning, with either b<=21 or b<=a+2 (win by two)


                                          • 60-a>b: Equivalent to a+b<=59, ensuring the score isn't above (29,30)


                                          • 61>60-a: Equivalent to a>=0, ensures the lower score is non-negative





                                          Python 2, 44 bytes





                                          lambda a,b:0!=a/30or cmp(b,2+max(19,a)-a/29)


                                          Try it online!



                                          Outputs:



                                          ended: 0
                                          going: -1
                                          invalid: 1 (including True)





                                          share|improve this answer











                                          $endgroup$


















                                            0












                                            $begingroup$


                                            Python 2, 47 bytes





                                            lambda a,b:[61>60-a>b<3+max(19,a)for b in-~b,b]


                                            Try it online!



                                            Outputs a list of two Booleans. Thanks to TFeld for writing a test suite in their answer that made it easy to check my solution.



                                            ended: [False, True]
                                            going: [True, True]
                                            invalid: [False, False]


                                            The key insight is that a valid score ends the game exactly if increasing the higher value b makes the score invalid. So, we just code up the validity condition, and check it for (a,b+1) in addition to (a,b) to see if the game has ended.



                                            Validity is checked via three conditions that are chained together:





                                            • b<3+max(19,a): Checks that the higher score b isn't past winning, with either b<=21 or b<=a+2 (win by two)


                                            • 60-a>b: Equivalent to a+b<=59, ensuring the score isn't above (29,30)


                                            • 61>60-a: Equivalent to a>=0, ensures the lower score is non-negative





                                            Python 2, 44 bytes





                                            lambda a,b:0!=a/30or cmp(b,2+max(19,a)-a/29)


                                            Try it online!



                                            Outputs:



                                            ended: 0
                                            going: -1
                                            invalid: 1 (including True)





                                            share|improve this answer











                                            $endgroup$
















                                              0












                                              0








                                              0





                                              $begingroup$


                                              Python 2, 47 bytes





                                              lambda a,b:[61>60-a>b<3+max(19,a)for b in-~b,b]


                                              Try it online!



                                              Outputs a list of two Booleans. Thanks to TFeld for writing a test suite in their answer that made it easy to check my solution.



                                              ended: [False, True]
                                              going: [True, True]
                                              invalid: [False, False]


                                              The key insight is that a valid score ends the game exactly if increasing the higher value b makes the score invalid. So, we just code up the validity condition, and check it for (a,b+1) in addition to (a,b) to see if the game has ended.



                                              Validity is checked via three conditions that are chained together:





                                              • b<3+max(19,a): Checks that the higher score b isn't past winning, with either b<=21 or b<=a+2 (win by two)


                                              • 60-a>b: Equivalent to a+b<=59, ensuring the score isn't above (29,30)


                                              • 61>60-a: Equivalent to a>=0, ensures the lower score is non-negative





                                              Python 2, 44 bytes





                                              lambda a,b:0!=a/30or cmp(b,2+max(19,a)-a/29)


                                              Try it online!



                                              Outputs:



                                              ended: 0
                                              going: -1
                                              invalid: 1 (including True)





                                              share|improve this answer











                                              $endgroup$




                                              Python 2, 47 bytes





                                              lambda a,b:[61>60-a>b<3+max(19,a)for b in-~b,b]


                                              Try it online!



                                              Outputs a list of two Booleans. Thanks to TFeld for writing a test suite in their answer that made it easy to check my solution.



                                              ended: [False, True]
                                              going: [True, True]
                                              invalid: [False, False]


                                              The key insight is that a valid score ends the game exactly if increasing the higher value b makes the score invalid. So, we just code up the validity condition, and check it for (a,b+1) in addition to (a,b) to see if the game has ended.



                                              Validity is checked via three conditions that are chained together:





                                              • b<3+max(19,a): Checks that the higher score b isn't past winning, with either b<=21 or b<=a+2 (win by two)


                                              • 60-a>b: Equivalent to a+b<=59, ensuring the score isn't above (29,30)


                                              • 61>60-a: Equivalent to a>=0, ensures the lower score is non-negative





                                              Python 2, 44 bytes





                                              lambda a,b:0!=a/30or cmp(b,2+max(19,a)-a/29)


                                              Try it online!



                                              Outputs:



                                              ended: 0
                                              going: -1
                                              invalid: 1 (including True)






                                              share|improve this answer














                                              share|improve this answer



                                              share|improve this answer








                                              edited 41 mins ago

























                                              answered 1 hour ago









                                              xnorxnor

                                              93k18190447




                                              93k18190447






























                                                  draft saved

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                                                  If this is an answer to a challenge…




                                                  • …Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.


                                                  • …Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
                                                    Explanations of your answer make it more interesting to read and are very much encouraged.


                                                  • …Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.



                                                  More generally…




                                                  • …Please make sure to answer the question and provide sufficient detail.


                                                  • …Avoid asking for help, clarification or responding to other answers (use comments instead).





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