What is the correct way to format this grep?












0















I am having trouble figuring out where to place the in this command. 



grep "^D.*(A1|A2|A3)$" input.txt > output.txt


I'm searching for each line that starts with a D and ends with A1, A2, or A3, which is at the end of the line.






command-line grep regex







share|improve this question

























  • Try the -E option.

    – Gunnar Hjalmarsson
    Jan 25 at 23:23






  • 1





    For this particular case, you could use a simple character range ^D.*A[1-3]$

    – steeldriver
    Jan 26 at 2:09
















0















I am having trouble figuring out where to place the in this command. 



grep "^D.*(A1|A2|A3)$" input.txt > output.txt


I'm searching for each line that starts with a D and ends with A1, A2, or A3, which is at the end of the line.






command-line grep regex







share|improve this question

























  • Try the -E option.

    – Gunnar Hjalmarsson
    Jan 25 at 23:23






  • 1





    For this particular case, you could use a simple character range ^D.*A[1-3]$

    – steeldriver
    Jan 26 at 2:09














0












0








0








I am having trouble figuring out where to place the in this command. 



grep "^D.*(A1|A2|A3)$" input.txt > output.txt


I'm searching for each line that starts with a D and ends with A1, A2, or A3, which is at the end of the line.






command-line grep regex







share|improve this question
















I am having trouble figuring out where to place the in this command. 



grep "^D.*(A1|A2|A3)$" input.txt > output.txt


I'm searching for each line that starts with a D and ends with A1, A2, or A3, which is at the end of the line.






command-line grep regex




command-line grep regex






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 25 at 23:39









wjandrea

9,13942363




9,13942363










asked Jan 25 at 23:00









Sim GrocSim Groc

31




31













  • Try the -E option.

    – Gunnar Hjalmarsson
    Jan 25 at 23:23






  • 1





    For this particular case, you could use a simple character range ^D.*A[1-3]$

    – steeldriver
    Jan 26 at 2:09



















  • Try the -E option.

    – Gunnar Hjalmarsson
    Jan 25 at 23:23






  • 1





    For this particular case, you could use a simple character range ^D.*A[1-3]$

    – steeldriver
    Jan 26 at 2:09

















Try the -E option.

– Gunnar Hjalmarsson
Jan 25 at 23:23





Try the -E option.

– Gunnar Hjalmarsson
Jan 25 at 23:23




1




1





For this particular case, you could use a simple character range ^D.*A[1-3]$

– steeldriver
Jan 26 at 2:09





For this particular case, you could use a simple character range ^D.*A[1-3]$

– steeldriver
Jan 26 at 2:09










3 Answers
3






active

oldest

votes


















3














You just needed to escape the or bars - you were almost there:



grep "^D.*(A1|A2|A3)$"


Note you can also use egrep instead of all the escapes:



egrep "^D.*(A1|A2|A3)$"





share|improve this answer































    5














    You need to escape the pipes (|).



    $ grep "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
    
DA1
    
DA2
    
DA3


    Or use option -E for extended regex, then you don't need to escape anything.



    $ grep -E "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
    
DA1
    
DA2
    
DA3





    share|improve this answer
























    • We can use also -P instead of -E and this is really useful in some cases, see: Grep -E, Sed -E - low performance, but why?

      – pa4080
      Jan 26 at 14:36





















    0














    Here is sed implementation, that uses the combination of the option -n and the command p:





    sed -rn '/^D.*(A1|A2|A3)$/p' in-file
    





    sed -n '/^D.*(A1|A2|A3)$/p' in-file
    





    sed -n '/^D.*A[1-3]$/p' in-file



    • option -r, --regexp-extended: use extended regular expressions in the script.


    • option -n, --quiet, --silent: suppress automatic printing of pattern space.


    • command p: print the current pattern space.







    share|improve this answer

























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3














      You just needed to escape the or bars - you were almost there:



      grep "^D.*(A1|A2|A3)$"


      Note you can also use egrep instead of all the escapes:



      egrep "^D.*(A1|A2|A3)$"





      share|improve this answer




























        3














        You just needed to escape the or bars - you were almost there:



        grep "^D.*(A1|A2|A3)$"


        Note you can also use egrep instead of all the escapes:



        egrep "^D.*(A1|A2|A3)$"





        share|improve this answer


























          3












          3








          3







          You just needed to escape the or bars - you were almost there:



          grep "^D.*(A1|A2|A3)$"


          Note you can also use egrep instead of all the escapes:



          egrep "^D.*(A1|A2|A3)$"





          share|improve this answer













          You just needed to escape the or bars - you were almost there:



          grep "^D.*(A1|A2|A3)$"


          Note you can also use egrep instead of all the escapes:



          egrep "^D.*(A1|A2|A3)$"






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jan 25 at 23:36









          Eric MintzEric Mintz

          662312




          662312

























              5














              You need to escape the pipes (|).



              $ grep "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
              
DA1
              
DA2
              
DA3


              Or use option -E for extended regex, then you don't need to escape anything.



              $ grep -E "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
              
DA1
              
DA2
              
DA3





              share|improve this answer
























              • We can use also -P instead of -E and this is really useful in some cases, see: Grep -E, Sed -E - low performance, but why?

                – pa4080
                Jan 26 at 14:36


















              5














              You need to escape the pipes (|).



              $ grep "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
              
DA1
              
DA2
              
DA3


              Or use option -E for extended regex, then you don't need to escape anything.



              $ grep -E "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
              
DA1
              
DA2
              
DA3





              share|improve this answer
























              • We can use also -P instead of -E and this is really useful in some cases, see: Grep -E, Sed -E - low performance, but why?

                – pa4080
                Jan 26 at 14:36
















              5












              5








              5







              You need to escape the pipes (|).



              $ grep "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
              
DA1
              
DA2
              
DA3


              Or use option -E for extended regex, then you don't need to escape anything.



              $ grep -E "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
              
DA1
              
DA2
              
DA3





              share|improve this answer













              You need to escape the pipes (|).



              $ grep "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
              
DA1
              
DA2
              
DA3


              Or use option -E for extended regex, then you don't need to escape anything.



              $ grep -E "^D.*(A1|A2|A3)$" <(printf 'D%sn' A1 A2 A3)
              
DA1
              
DA2
              
DA3






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Jan 25 at 23:33









              wjandreawjandrea

              9,13942363




              9,13942363













              • We can use also -P instead of -E and this is really useful in some cases, see: Grep -E, Sed -E - low performance, but why?

                – pa4080
                Jan 26 at 14:36





















              • We can use also -P instead of -E and this is really useful in some cases, see: Grep -E, Sed -E - low performance, but why?

                – pa4080
                Jan 26 at 14:36



















              We can use also -P instead of -E and this is really useful in some cases, see: Grep -E, Sed -E - low performance, but why?

              – pa4080
              Jan 26 at 14:36







              We can use also -P instead of -E and this is really useful in some cases, see: Grep -E, Sed -E - low performance, but why?

              – pa4080
              Jan 26 at 14:36













              0














              Here is sed implementation, that uses the combination of the option -n and the command p:





              sed -rn '/^D.*(A1|A2|A3)$/p' in-file
              





              sed -n '/^D.*(A1|A2|A3)$/p' in-file
              





              sed -n '/^D.*A[1-3]$/p' in-file



              • option -r, --regexp-extended: use extended regular expressions in the script.


              • option -n, --quiet, --silent: suppress automatic printing of pattern space.


              • command p: print the current pattern space.







              share|improve this answer






























                0














                Here is sed implementation, that uses the combination of the option -n and the command p:





                sed -rn '/^D.*(A1|A2|A3)$/p' in-file
                





                sed -n '/^D.*(A1|A2|A3)$/p' in-file
                





                sed -n '/^D.*A[1-3]$/p' in-file



                • option -r, --regexp-extended: use extended regular expressions in the script.


                • option -n, --quiet, --silent: suppress automatic printing of pattern space.


                • command p: print the current pattern space.







                share|improve this answer




























                  0












                  0








                  0







                  Here is sed implementation, that uses the combination of the option -n and the command p:





                  sed -rn '/^D.*(A1|A2|A3)$/p' in-file
                  





                  sed -n '/^D.*(A1|A2|A3)$/p' in-file
                  





                  sed -n '/^D.*A[1-3]$/p' in-file



                  • option -r, --regexp-extended: use extended regular expressions in the script.


                  • option -n, --quiet, --silent: suppress automatic printing of pattern space.


                  • command p: print the current pattern space.







                  share|improve this answer















                  Here is sed implementation, that uses the combination of the option -n and the command p:





                  sed -rn '/^D.*(A1|A2|A3)$/p' in-file
                  





                  sed -n '/^D.*(A1|A2|A3)$/p' in-file
                  





                  sed -n '/^D.*A[1-3]$/p' in-file



                  • option -r, --regexp-extended: use extended regular expressions in the script.


                  • option -n, --quiet, --silent: suppress automatic printing of pattern space.


                  • command p: print the current pattern space.








                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Jan 26 at 14:26

























                  answered Jan 26 at 13:37









                  pa4080pa4080

                  14.2k52668




                  14.2k52668






























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