Determine whether a word appears in a sentence












2














Given an array of words representing a sentence and a word to search for, the method must determine whether the word appears in the sentence.



Specifications




  • Case insensitive.

  • The arguments are never null.

  • The sentence is in the English language.


/**
* A case-insensitive search on a sentence to find whether a given word can be found in it. It
* keeps certain punctuation in mind.
*
* @param aSentence An array of words forming a sentence. Cannot be {@code null}.
* @param aWord The word to search for. Cannot be {@code null}.
*
* @return {@code true} if the word appeared at least once in the sentence, {@code false}
* otherwise.
*/
public boolean sentenceContainsWord(final String aSentence, String aWord)
{
// The search is case-insensitive
aWord = aWord.toLowerCase();

// Loop through the words in the sentence
for (int i = 0; i < aSentence.length; i++)
{
String sentenceWord = aSentence[i];

// If the word in the sentence matches, return immediately
if (sentenceWord.toLowerCase().equals(aWord))
{
return true;
}

// The word could end with punctuation like a comma or a dot
int lastSentenceWordIndex = sentenceWord.length() - 1;
String lastCharacter = Character.toString(sentenceWord.charAt(lastSentenceWordIndex));
if (lastCharacter.matches("[.,:;]") && sentenceWord.substring(0, lastSentenceWordIndex).equals(aWord))
{
return true;
}
}

return false;
}











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  • What about punctuation inside or in front of a word? 'Like,' he said 'RobAu's comment?' ?
    – RobAu
    yesterday












  • Also, if to pass an empty-string as word, you will get an IndexOutOfBoundsException
    – RobAu
    yesterday
















2














Given an array of words representing a sentence and a word to search for, the method must determine whether the word appears in the sentence.



Specifications




  • Case insensitive.

  • The arguments are never null.

  • The sentence is in the English language.


/**
* A case-insensitive search on a sentence to find whether a given word can be found in it. It
* keeps certain punctuation in mind.
*
* @param aSentence An array of words forming a sentence. Cannot be {@code null}.
* @param aWord The word to search for. Cannot be {@code null}.
*
* @return {@code true} if the word appeared at least once in the sentence, {@code false}
* otherwise.
*/
public boolean sentenceContainsWord(final String aSentence, String aWord)
{
// The search is case-insensitive
aWord = aWord.toLowerCase();

// Loop through the words in the sentence
for (int i = 0; i < aSentence.length; i++)
{
String sentenceWord = aSentence[i];

// If the word in the sentence matches, return immediately
if (sentenceWord.toLowerCase().equals(aWord))
{
return true;
}

// The word could end with punctuation like a comma or a dot
int lastSentenceWordIndex = sentenceWord.length() - 1;
String lastCharacter = Character.toString(sentenceWord.charAt(lastSentenceWordIndex));
if (lastCharacter.matches("[.,:;]") && sentenceWord.substring(0, lastSentenceWordIndex).equals(aWord))
{
return true;
}
}

return false;
}











share|improve this question







New contributor




Skere is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • What about punctuation inside or in front of a word? 'Like,' he said 'RobAu's comment?' ?
    – RobAu
    yesterday












  • Also, if to pass an empty-string as word, you will get an IndexOutOfBoundsException
    – RobAu
    yesterday














2












2








2







Given an array of words representing a sentence and a word to search for, the method must determine whether the word appears in the sentence.



Specifications




  • Case insensitive.

  • The arguments are never null.

  • The sentence is in the English language.


/**
* A case-insensitive search on a sentence to find whether a given word can be found in it. It
* keeps certain punctuation in mind.
*
* @param aSentence An array of words forming a sentence. Cannot be {@code null}.
* @param aWord The word to search for. Cannot be {@code null}.
*
* @return {@code true} if the word appeared at least once in the sentence, {@code false}
* otherwise.
*/
public boolean sentenceContainsWord(final String aSentence, String aWord)
{
// The search is case-insensitive
aWord = aWord.toLowerCase();

// Loop through the words in the sentence
for (int i = 0; i < aSentence.length; i++)
{
String sentenceWord = aSentence[i];

// If the word in the sentence matches, return immediately
if (sentenceWord.toLowerCase().equals(aWord))
{
return true;
}

// The word could end with punctuation like a comma or a dot
int lastSentenceWordIndex = sentenceWord.length() - 1;
String lastCharacter = Character.toString(sentenceWord.charAt(lastSentenceWordIndex));
if (lastCharacter.matches("[.,:;]") && sentenceWord.substring(0, lastSentenceWordIndex).equals(aWord))
{
return true;
}
}

return false;
}











share|improve this question







New contributor




Skere is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Given an array of words representing a sentence and a word to search for, the method must determine whether the word appears in the sentence.



Specifications




  • Case insensitive.

  • The arguments are never null.

  • The sentence is in the English language.


/**
* A case-insensitive search on a sentence to find whether a given word can be found in it. It
* keeps certain punctuation in mind.
*
* @param aSentence An array of words forming a sentence. Cannot be {@code null}.
* @param aWord The word to search for. Cannot be {@code null}.
*
* @return {@code true} if the word appeared at least once in the sentence, {@code false}
* otherwise.
*/
public boolean sentenceContainsWord(final String aSentence, String aWord)
{
// The search is case-insensitive
aWord = aWord.toLowerCase();

// Loop through the words in the sentence
for (int i = 0; i < aSentence.length; i++)
{
String sentenceWord = aSentence[i];

// If the word in the sentence matches, return immediately
if (sentenceWord.toLowerCase().equals(aWord))
{
return true;
}

// The word could end with punctuation like a comma or a dot
int lastSentenceWordIndex = sentenceWord.length() - 1;
String lastCharacter = Character.toString(sentenceWord.charAt(lastSentenceWordIndex));
if (lastCharacter.matches("[.,:;]") && sentenceWord.substring(0, lastSentenceWordIndex).equals(aWord))
{
return true;
}
}

return false;
}








java






share|improve this question







New contributor




Skere is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Skere is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




Skere is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









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New contributor




Skere is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Skere is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Skere is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • What about punctuation inside or in front of a word? 'Like,' he said 'RobAu's comment?' ?
    – RobAu
    yesterday












  • Also, if to pass an empty-string as word, you will get an IndexOutOfBoundsException
    – RobAu
    yesterday


















  • What about punctuation inside or in front of a word? 'Like,' he said 'RobAu's comment?' ?
    – RobAu
    yesterday












  • Also, if to pass an empty-string as word, you will get an IndexOutOfBoundsException
    – RobAu
    yesterday
















What about punctuation inside or in front of a word? 'Like,' he said 'RobAu's comment?' ?
– RobAu
yesterday






What about punctuation inside or in front of a word? 'Like,' he said 'RobAu's comment?' ?
– RobAu
yesterday














Also, if to pass an empty-string as word, you will get an IndexOutOfBoundsException
– RobAu
yesterday




Also, if to pass an empty-string as word, you will get an IndexOutOfBoundsException
– RobAu
yesterday










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