Reach to the last index starting at index 0
$begingroup$
The task:
Given an integer list where each number represents the number of hops
you can make, determine whether you can reach to the last index
starting at index 0.
For example,
[2, 0, 1, 0]
returnstrue
while[1, 1, 0, 1]
returns
false
.
My solutions:
// functional:
const reachLastIndexOf = (arr, start) => {
const next = start + arr[start];
if (start === next || next >= arr.length) return false;
if (next === arr.length -1) return true;
return reachLastIndexOf(arr, next);
}
// imperative:
const reachLastIndexOf2 = arr => {
let start = 0;
while(start < arr.length) { // I'm tempted to write `while(true)` here
const next = start + arr[start];
if (start === next || next >= arr.length) return false;
if (next === arr.length - 1) return true;
start = next;
}
}
javascript functional-programming
$endgroup$
add a comment |
$begingroup$
The task:
Given an integer list where each number represents the number of hops
you can make, determine whether you can reach to the last index
starting at index 0.
For example,
[2, 0, 1, 0]
returnstrue
while[1, 1, 0, 1]
returns
false
.
My solutions:
// functional:
const reachLastIndexOf = (arr, start) => {
const next = start + arr[start];
if (start === next || next >= arr.length) return false;
if (next === arr.length -1) return true;
return reachLastIndexOf(arr, next);
}
// imperative:
const reachLastIndexOf2 = arr => {
let start = 0;
while(start < arr.length) { // I'm tempted to write `while(true)` here
const next = start + arr[start];
if (start === next || next >= arr.length) return false;
if (next === arr.length - 1) return true;
start = next;
}
}
javascript functional-programming
$endgroup$
add a comment |
$begingroup$
The task:
Given an integer list where each number represents the number of hops
you can make, determine whether you can reach to the last index
starting at index 0.
For example,
[2, 0, 1, 0]
returnstrue
while[1, 1, 0, 1]
returns
false
.
My solutions:
// functional:
const reachLastIndexOf = (arr, start) => {
const next = start + arr[start];
if (start === next || next >= arr.length) return false;
if (next === arr.length -1) return true;
return reachLastIndexOf(arr, next);
}
// imperative:
const reachLastIndexOf2 = arr => {
let start = 0;
while(start < arr.length) { // I'm tempted to write `while(true)` here
const next = start + arr[start];
if (start === next || next >= arr.length) return false;
if (next === arr.length - 1) return true;
start = next;
}
}
javascript functional-programming
$endgroup$
The task:
Given an integer list where each number represents the number of hops
you can make, determine whether you can reach to the last index
starting at index 0.
For example,
[2, 0, 1, 0]
returnstrue
while[1, 1, 0, 1]
returns
false
.
My solutions:
// functional:
const reachLastIndexOf = (arr, start) => {
const next = start + arr[start];
if (start === next || next >= arr.length) return false;
if (next === arr.length -1) return true;
return reachLastIndexOf(arr, next);
}
// imperative:
const reachLastIndexOf2 = arr => {
let start = 0;
while(start < arr.length) { // I'm tempted to write `while(true)` here
const next = start + arr[start];
if (start === next || next >= arr.length) return false;
if (next === arr.length - 1) return true;
start = next;
}
}
javascript functional-programming
javascript functional-programming
asked 8 mins ago
thadeuszlaythadeuszlay
457213
457213
add a comment |
add a comment |
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