Shopping List Creation
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For my coding class I have to build a shopping list by having the user enter the number of items they need and then each item (one at a time). I then have to output the final shopping list in a multi-line dialogue box (one item per line). I have the first two parts done where users enter the number of items and what items they would like, but can't figure out how to output all the items. Any help would be great, thanks!
Also, I am using jgrasp and we don't use println to output messages.
//user enter numItems
//count = 0
//while count is less than numItems
//user inputs items
//count + 1
//Output all items
public class ShoppingList
{
public static void main (String args)
{
String items;
int numItems, count;
numItems = Input.readInt("Enter number of items: ");
count = 0;
while (count < numItems)
{
items = Input.readString("Enter item: ");
count = count + 1;
}//end while
Output.showMessage(items.toString());
} //end main
} //end ShoppingList
java
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For my coding class I have to build a shopping list by having the user enter the number of items they need and then each item (one at a time). I then have to output the final shopping list in a multi-line dialogue box (one item per line). I have the first two parts done where users enter the number of items and what items they would like, but can't figure out how to output all the items. Any help would be great, thanks!
Also, I am using jgrasp and we don't use println to output messages.
//user enter numItems
//count = 0
//while count is less than numItems
//user inputs items
//count + 1
//Output all items
public class ShoppingList
{
public static void main (String args)
{
String items;
int numItems, count;
numItems = Input.readInt("Enter number of items: ");
count = 0;
while (count < numItems)
{
items = Input.readString("Enter item: ");
count = count + 1;
}//end while
Output.showMessage(items.toString());
} //end main
} //end ShoppingList
java
New contributor
$endgroup$
add a comment |
$begingroup$
For my coding class I have to build a shopping list by having the user enter the number of items they need and then each item (one at a time). I then have to output the final shopping list in a multi-line dialogue box (one item per line). I have the first two parts done where users enter the number of items and what items they would like, but can't figure out how to output all the items. Any help would be great, thanks!
Also, I am using jgrasp and we don't use println to output messages.
//user enter numItems
//count = 0
//while count is less than numItems
//user inputs items
//count + 1
//Output all items
public class ShoppingList
{
public static void main (String args)
{
String items;
int numItems, count;
numItems = Input.readInt("Enter number of items: ");
count = 0;
while (count < numItems)
{
items = Input.readString("Enter item: ");
count = count + 1;
}//end while
Output.showMessage(items.toString());
} //end main
} //end ShoppingList
java
New contributor
$endgroup$
For my coding class I have to build a shopping list by having the user enter the number of items they need and then each item (one at a time). I then have to output the final shopping list in a multi-line dialogue box (one item per line). I have the first two parts done where users enter the number of items and what items they would like, but can't figure out how to output all the items. Any help would be great, thanks!
Also, I am using jgrasp and we don't use println to output messages.
//user enter numItems
//count = 0
//while count is less than numItems
//user inputs items
//count + 1
//Output all items
public class ShoppingList
{
public static void main (String args)
{
String items;
int numItems, count;
numItems = Input.readInt("Enter number of items: ");
count = 0;
while (count < numItems)
{
items = Input.readString("Enter item: ");
count = count + 1;
}//end while
Output.showMessage(items.toString());
} //end main
} //end ShoppingList
java
java
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asked 13 mins ago
Liam EricksonLiam Erickson
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Liam Erickson is a new contributor. Be nice, and check out our Code of Conduct.
Liam Erickson is a new contributor. Be nice, and check out our Code of Conduct.
Liam Erickson is a new contributor. Be nice, and check out our Code of Conduct.
Liam Erickson is a new contributor. Be nice, and check out our Code of Conduct.
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