Calculate the date from 1125 days ago on non-GNU systems?












6















On the Unix Bash commandline, I want to calculate the date from 1125 days ago using the base operating system (e.g. No Perl or Python).



On systems running GNU Date, I can do something like this:



ubuntu $ date --date="1125 days ago"
Wed Nov 7 15:12:33 PST 2007


FreeBSD or MacOSX systems don't ship with GNU Date, and don't support values like "X days ago".



freebsd81 $ date --date="+1125 days ago"
date: illegal option -- -


I can calculate a date from a few days ago on a Mac or FreeBSD system, but this is limited to a few days:



# Today is really Dec 6, 2010. 4 days ago it was:
macosx $ TZ=GMT+96 date +%Y%m%d
20101202

# But that doesn't work if I want to see the date 8 days ago:
macosx $ TZ=GMT+192 date +%Y%m%d
20101206


Can I calculate old dates on non-GNU systems without delving into tools like Perl or Python? Or must I use a more powerful scripting language?










share|improve this question





























    6















    On the Unix Bash commandline, I want to calculate the date from 1125 days ago using the base operating system (e.g. No Perl or Python).



    On systems running GNU Date, I can do something like this:



    ubuntu $ date --date="1125 days ago"
    Wed Nov 7 15:12:33 PST 2007


    FreeBSD or MacOSX systems don't ship with GNU Date, and don't support values like "X days ago".



    freebsd81 $ date --date="+1125 days ago"
    date: illegal option -- -


    I can calculate a date from a few days ago on a Mac or FreeBSD system, but this is limited to a few days:



    # Today is really Dec 6, 2010. 4 days ago it was:
    macosx $ TZ=GMT+96 date +%Y%m%d
    20101202

    # But that doesn't work if I want to see the date 8 days ago:
    macosx $ TZ=GMT+192 date +%Y%m%d
    20101206


    Can I calculate old dates on non-GNU systems without delving into tools like Perl or Python? Or must I use a more powerful scripting language?










    share|improve this question



























      6












      6








      6








      On the Unix Bash commandline, I want to calculate the date from 1125 days ago using the base operating system (e.g. No Perl or Python).



      On systems running GNU Date, I can do something like this:



      ubuntu $ date --date="1125 days ago"
      Wed Nov 7 15:12:33 PST 2007


      FreeBSD or MacOSX systems don't ship with GNU Date, and don't support values like "X days ago".



      freebsd81 $ date --date="+1125 days ago"
      date: illegal option -- -


      I can calculate a date from a few days ago on a Mac or FreeBSD system, but this is limited to a few days:



      # Today is really Dec 6, 2010. 4 days ago it was:
      macosx $ TZ=GMT+96 date +%Y%m%d
      20101202

      # But that doesn't work if I want to see the date 8 days ago:
      macosx $ TZ=GMT+192 date +%Y%m%d
      20101206


      Can I calculate old dates on non-GNU systems without delving into tools like Perl or Python? Or must I use a more powerful scripting language?










      share|improve this question
















      On the Unix Bash commandline, I want to calculate the date from 1125 days ago using the base operating system (e.g. No Perl or Python).



      On systems running GNU Date, I can do something like this:



      ubuntu $ date --date="1125 days ago"
      Wed Nov 7 15:12:33 PST 2007


      FreeBSD or MacOSX systems don't ship with GNU Date, and don't support values like "X days ago".



      freebsd81 $ date --date="+1125 days ago"
      date: illegal option -- -


      I can calculate a date from a few days ago on a Mac or FreeBSD system, but this is limited to a few days:



      # Today is really Dec 6, 2010. 4 days ago it was:
      macosx $ TZ=GMT+96 date +%Y%m%d
      20101202

      # But that doesn't work if I want to see the date 8 days ago:
      macosx $ TZ=GMT+192 date +%Y%m%d
      20101206


      Can I calculate old dates on non-GNU systems without delving into tools like Perl or Python? Or must I use a more powerful scripting language?







      freebsd date osx non-gnu






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Dec 6 '10 at 23:39







      Stefan Lasiewski

















      asked Dec 6 '10 at 23:24









      Stefan LasiewskiStefan Lasiewski

      8,787196178




      8,787196178






















          3 Answers
          3






          active

          oldest

          votes


















          7














          Well, you can do something sneaky like:




          $ echo "`date +%s` - (1125 * 24 * 60 *60)" |bc
          1194478815
          $ date -r 1194478689
          Wed, 07 Nov 2007 18:38:09 -0500


          Tested on OpenBSD (definitely non gnu based date), and seems to work.



          Breaking it down in steps:




          • get the current unixtime (seconds since beginning of unix epoch):



          $ date +%s
          1291679934



          • get the number of seconds in 1125 days



          $ echo "1125 * 24 * 60 *60" | bc
          97200000



          • subtract one from the other (1291679934 - 97200000) = 1194478815



          • use the new unixtime (1194478815) to print a pretty date




            $ date -r 1194478689
            Wed, 07 Nov 2007 18:38:09 -0500



          • As an alternative, on solaris you can do this to print the date*:



            /bin/echo "0t1194478815>Yn<Y=Y" |adb



          * referenced from http://www.sun.com/bigadmin/shellme/



          Also, an alternative on Solaris for getting the current timestamp from the date command** is:


          /usr/bin/truss /usr/bin/date 2>&1 |  nawk -F= '/^time()/ {gsub(/ /,"",$2);print $2}'


          ** referenced from http://www.commandlinefu.com/commands/view/7647/unix-timestamp-solaris






          share|improve this answer


























          • Note that %s and date -r are BSDisms (from the very early days, so they're on all BSD platforms). Don't expect to see them on System V platforms (e.g. Solaris has neither).

            – Gilles
            Dec 7 '10 at 0:09











          • Ah, Solaris, how I love thee... (;

            – gabe.
            Dec 7 '10 at 0:14











          • @Gilles: Are you sure? Solaris has a multitude of bin directories, such as /usr/ucb/bin, that contain versions from other variations of unix. SunOS 4.X was BSD-based after all.

            – camh
            Dec 7 '10 at 1:24











          • This fails when any of the intervening days have more or less than 60*60*24 seconds, such as leap seconds and calendar changes.

            – Sparr
            Dec 7 '10 at 7:01






          • 1





            @Sparr: Good point. A safe approach is to subtract the current time of day from the current absolute date, and add 12*60*60. This returns a time-of-day between 10:59 and 13:01. Adding 24-hour periods to this and obtaining the corresponding date is safe.

            – Gilles
            Dec 7 '10 at 19:06



















          2














          Previous answer was far too complicated. FreeBSD/macOS have the -v flag for date, from the MAN page (abbreviated description):




          Adjust (i.e., take the current date and display the result of the adjustment; not actually set the date) the second, minute, hour, month day, week day, month or year according to val. If val is preceded with a plus or minus sign, the date is adjusted forwards or backwards according to the remaining string, otherwise the relevant part of the date is set. The date can be adjusted as many times as required using these flags. Flags are processed in the order given.




          So for your purpose, date -v1125d will simply do what you need



          $ date; date -v-1125d
          Thu 19 Oct 2017 11:35:25 EDT
          Sat 20 Sep 2014 11:35:25 EDT





          share|improve this answer































            0














            I was having a similar issue i found the dateutils pkg for OpenBSD 6.4. It was a simple pkg_add dateutils for me.



            #!/bin/ksh
            # Using dateutils dadd (get current date) -1month -f (format to strftime)
            # Set Year in YYYY formant y is YY format
            lastMonth=$(dadd date -1mo -f "%Y.%m")
            echo $lastMonth
            mkdir /home/$usr/History/$lastMonth


            My out put here is



            #2018.11


            UPDATE 1



            I am running this command on 2018.12.10



            HostNameHere# dadd date -1125d -f "%Y.%m"


            Result



             2015.11


            It supports any time additions or subtractions that i can tell. Here is the commands help print out. #dadd -h (this is not the entirety of the print out. There is more info on options.



                Usage: dadd [OPTION]... [DATE/TIME] [DURATION]
            Add DURATION to DATE/TIME and print the result.
            If DATE/TIME is omitted but DURATION is given, read a list of DATE/TIMEs from
            stdin. If DURATION is omitted but DATE/TIME is given, read a list of DURATIONs from
            stdin.

            Durations are specified as nY, nMO, nW, or nD for years, months, weeks, or days
            respectively, or nH, nM, nS for hours, minutes, and seconds, where N is a
            (possibly negative) number. The unit symbols can be written lower-case as well
            (y, mo, w, d, h, m, s) and the unit symbol `d' can be omitted.

            Note that duration addition is not commutative!
            2000-03-30 +1mo +1d -> 2000-05-01
            2000-03-30 +1d +1mo -> 2000-04-30


            Here are the commands.



            Here are the formatting options.






            share|improve this answer


























            • (1) It's nice that this program supports -1mo. Can you demonstrate that it allows the user to calculate the date from 1125 days ago, as the question asks? (2) The question says "using the base operating system (e.g. No Perl or Python)." That would seem to preclude adding a new package.

              – G-Man
              Dec 7 '18 at 20:41






            • 1





              @G-Man Thank you for the comment. I am new to contributing on StackExchange. Thank you for the help. See UPDATE 1

              – babyPenguin
              Dec 10 '18 at 14:48













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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            7














            Well, you can do something sneaky like:




            $ echo "`date +%s` - (1125 * 24 * 60 *60)" |bc
            1194478815
            $ date -r 1194478689
            Wed, 07 Nov 2007 18:38:09 -0500


            Tested on OpenBSD (definitely non gnu based date), and seems to work.



            Breaking it down in steps:




            • get the current unixtime (seconds since beginning of unix epoch):



            $ date +%s
            1291679934



            • get the number of seconds in 1125 days



            $ echo "1125 * 24 * 60 *60" | bc
            97200000



            • subtract one from the other (1291679934 - 97200000) = 1194478815



            • use the new unixtime (1194478815) to print a pretty date




              $ date -r 1194478689
              Wed, 07 Nov 2007 18:38:09 -0500



            • As an alternative, on solaris you can do this to print the date*:



              /bin/echo "0t1194478815>Yn<Y=Y" |adb



            * referenced from http://www.sun.com/bigadmin/shellme/



            Also, an alternative on Solaris for getting the current timestamp from the date command** is:


            /usr/bin/truss /usr/bin/date 2>&1 |  nawk -F= '/^time()/ {gsub(/ /,"",$2);print $2}'


            ** referenced from http://www.commandlinefu.com/commands/view/7647/unix-timestamp-solaris






            share|improve this answer


























            • Note that %s and date -r are BSDisms (from the very early days, so they're on all BSD platforms). Don't expect to see them on System V platforms (e.g. Solaris has neither).

              – Gilles
              Dec 7 '10 at 0:09











            • Ah, Solaris, how I love thee... (;

              – gabe.
              Dec 7 '10 at 0:14











            • @Gilles: Are you sure? Solaris has a multitude of bin directories, such as /usr/ucb/bin, that contain versions from other variations of unix. SunOS 4.X was BSD-based after all.

              – camh
              Dec 7 '10 at 1:24











            • This fails when any of the intervening days have more or less than 60*60*24 seconds, such as leap seconds and calendar changes.

              – Sparr
              Dec 7 '10 at 7:01






            • 1





              @Sparr: Good point. A safe approach is to subtract the current time of day from the current absolute date, and add 12*60*60. This returns a time-of-day between 10:59 and 13:01. Adding 24-hour periods to this and obtaining the corresponding date is safe.

              – Gilles
              Dec 7 '10 at 19:06
















            7














            Well, you can do something sneaky like:




            $ echo "`date +%s` - (1125 * 24 * 60 *60)" |bc
            1194478815
            $ date -r 1194478689
            Wed, 07 Nov 2007 18:38:09 -0500


            Tested on OpenBSD (definitely non gnu based date), and seems to work.



            Breaking it down in steps:




            • get the current unixtime (seconds since beginning of unix epoch):



            $ date +%s
            1291679934



            • get the number of seconds in 1125 days



            $ echo "1125 * 24 * 60 *60" | bc
            97200000



            • subtract one from the other (1291679934 - 97200000) = 1194478815



            • use the new unixtime (1194478815) to print a pretty date




              $ date -r 1194478689
              Wed, 07 Nov 2007 18:38:09 -0500



            • As an alternative, on solaris you can do this to print the date*:



              /bin/echo "0t1194478815>Yn<Y=Y" |adb



            * referenced from http://www.sun.com/bigadmin/shellme/



            Also, an alternative on Solaris for getting the current timestamp from the date command** is:


            /usr/bin/truss /usr/bin/date 2>&1 |  nawk -F= '/^time()/ {gsub(/ /,"",$2);print $2}'


            ** referenced from http://www.commandlinefu.com/commands/view/7647/unix-timestamp-solaris






            share|improve this answer


























            • Note that %s and date -r are BSDisms (from the very early days, so they're on all BSD platforms). Don't expect to see them on System V platforms (e.g. Solaris has neither).

              – Gilles
              Dec 7 '10 at 0:09











            • Ah, Solaris, how I love thee... (;

              – gabe.
              Dec 7 '10 at 0:14











            • @Gilles: Are you sure? Solaris has a multitude of bin directories, such as /usr/ucb/bin, that contain versions from other variations of unix. SunOS 4.X was BSD-based after all.

              – camh
              Dec 7 '10 at 1:24











            • This fails when any of the intervening days have more or less than 60*60*24 seconds, such as leap seconds and calendar changes.

              – Sparr
              Dec 7 '10 at 7:01






            • 1





              @Sparr: Good point. A safe approach is to subtract the current time of day from the current absolute date, and add 12*60*60. This returns a time-of-day between 10:59 and 13:01. Adding 24-hour periods to this and obtaining the corresponding date is safe.

              – Gilles
              Dec 7 '10 at 19:06














            7












            7








            7







            Well, you can do something sneaky like:




            $ echo "`date +%s` - (1125 * 24 * 60 *60)" |bc
            1194478815
            $ date -r 1194478689
            Wed, 07 Nov 2007 18:38:09 -0500


            Tested on OpenBSD (definitely non gnu based date), and seems to work.



            Breaking it down in steps:




            • get the current unixtime (seconds since beginning of unix epoch):



            $ date +%s
            1291679934



            • get the number of seconds in 1125 days



            $ echo "1125 * 24 * 60 *60" | bc
            97200000



            • subtract one from the other (1291679934 - 97200000) = 1194478815



            • use the new unixtime (1194478815) to print a pretty date




              $ date -r 1194478689
              Wed, 07 Nov 2007 18:38:09 -0500



            • As an alternative, on solaris you can do this to print the date*:



              /bin/echo "0t1194478815>Yn<Y=Y" |adb



            * referenced from http://www.sun.com/bigadmin/shellme/



            Also, an alternative on Solaris for getting the current timestamp from the date command** is:


            /usr/bin/truss /usr/bin/date 2>&1 |  nawk -F= '/^time()/ {gsub(/ /,"",$2);print $2}'


            ** referenced from http://www.commandlinefu.com/commands/view/7647/unix-timestamp-solaris






            share|improve this answer















            Well, you can do something sneaky like:




            $ echo "`date +%s` - (1125 * 24 * 60 *60)" |bc
            1194478815
            $ date -r 1194478689
            Wed, 07 Nov 2007 18:38:09 -0500


            Tested on OpenBSD (definitely non gnu based date), and seems to work.



            Breaking it down in steps:




            • get the current unixtime (seconds since beginning of unix epoch):



            $ date +%s
            1291679934



            • get the number of seconds in 1125 days



            $ echo "1125 * 24 * 60 *60" | bc
            97200000



            • subtract one from the other (1291679934 - 97200000) = 1194478815



            • use the new unixtime (1194478815) to print a pretty date




              $ date -r 1194478689
              Wed, 07 Nov 2007 18:38:09 -0500



            • As an alternative, on solaris you can do this to print the date*:



              /bin/echo "0t1194478815>Yn<Y=Y" |adb



            * referenced from http://www.sun.com/bigadmin/shellme/



            Also, an alternative on Solaris for getting the current timestamp from the date command** is:


            /usr/bin/truss /usr/bin/date 2>&1 |  nawk -F= '/^time()/ {gsub(/ /,"",$2);print $2}'


            ** referenced from http://www.commandlinefu.com/commands/view/7647/unix-timestamp-solaris







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Feb 10 '11 at 22:09

























            answered Dec 6 '10 at 23:46









            gabe.gabe.

            6,51593654




            6,51593654













            • Note that %s and date -r are BSDisms (from the very early days, so they're on all BSD platforms). Don't expect to see them on System V platforms (e.g. Solaris has neither).

              – Gilles
              Dec 7 '10 at 0:09











            • Ah, Solaris, how I love thee... (;

              – gabe.
              Dec 7 '10 at 0:14











            • @Gilles: Are you sure? Solaris has a multitude of bin directories, such as /usr/ucb/bin, that contain versions from other variations of unix. SunOS 4.X was BSD-based after all.

              – camh
              Dec 7 '10 at 1:24











            • This fails when any of the intervening days have more or less than 60*60*24 seconds, such as leap seconds and calendar changes.

              – Sparr
              Dec 7 '10 at 7:01






            • 1





              @Sparr: Good point. A safe approach is to subtract the current time of day from the current absolute date, and add 12*60*60. This returns a time-of-day between 10:59 and 13:01. Adding 24-hour periods to this and obtaining the corresponding date is safe.

              – Gilles
              Dec 7 '10 at 19:06



















            • Note that %s and date -r are BSDisms (from the very early days, so they're on all BSD platforms). Don't expect to see them on System V platforms (e.g. Solaris has neither).

              – Gilles
              Dec 7 '10 at 0:09











            • Ah, Solaris, how I love thee... (;

              – gabe.
              Dec 7 '10 at 0:14











            • @Gilles: Are you sure? Solaris has a multitude of bin directories, such as /usr/ucb/bin, that contain versions from other variations of unix. SunOS 4.X was BSD-based after all.

              – camh
              Dec 7 '10 at 1:24











            • This fails when any of the intervening days have more or less than 60*60*24 seconds, such as leap seconds and calendar changes.

              – Sparr
              Dec 7 '10 at 7:01






            • 1





              @Sparr: Good point. A safe approach is to subtract the current time of day from the current absolute date, and add 12*60*60. This returns a time-of-day between 10:59 and 13:01. Adding 24-hour periods to this and obtaining the corresponding date is safe.

              – Gilles
              Dec 7 '10 at 19:06

















            Note that %s and date -r are BSDisms (from the very early days, so they're on all BSD platforms). Don't expect to see them on System V platforms (e.g. Solaris has neither).

            – Gilles
            Dec 7 '10 at 0:09





            Note that %s and date -r are BSDisms (from the very early days, so they're on all BSD platforms). Don't expect to see them on System V platforms (e.g. Solaris has neither).

            – Gilles
            Dec 7 '10 at 0:09













            Ah, Solaris, how I love thee... (;

            – gabe.
            Dec 7 '10 at 0:14





            Ah, Solaris, how I love thee... (;

            – gabe.
            Dec 7 '10 at 0:14













            @Gilles: Are you sure? Solaris has a multitude of bin directories, such as /usr/ucb/bin, that contain versions from other variations of unix. SunOS 4.X was BSD-based after all.

            – camh
            Dec 7 '10 at 1:24





            @Gilles: Are you sure? Solaris has a multitude of bin directories, such as /usr/ucb/bin, that contain versions from other variations of unix. SunOS 4.X was BSD-based after all.

            – camh
            Dec 7 '10 at 1:24













            This fails when any of the intervening days have more or less than 60*60*24 seconds, such as leap seconds and calendar changes.

            – Sparr
            Dec 7 '10 at 7:01





            This fails when any of the intervening days have more or less than 60*60*24 seconds, such as leap seconds and calendar changes.

            – Sparr
            Dec 7 '10 at 7:01




            1




            1





            @Sparr: Good point. A safe approach is to subtract the current time of day from the current absolute date, and add 12*60*60. This returns a time-of-day between 10:59 and 13:01. Adding 24-hour periods to this and obtaining the corresponding date is safe.

            – Gilles
            Dec 7 '10 at 19:06





            @Sparr: Good point. A safe approach is to subtract the current time of day from the current absolute date, and add 12*60*60. This returns a time-of-day between 10:59 and 13:01. Adding 24-hour periods to this and obtaining the corresponding date is safe.

            – Gilles
            Dec 7 '10 at 19:06













            2














            Previous answer was far too complicated. FreeBSD/macOS have the -v flag for date, from the MAN page (abbreviated description):




            Adjust (i.e., take the current date and display the result of the adjustment; not actually set the date) the second, minute, hour, month day, week day, month or year according to val. If val is preceded with a plus or minus sign, the date is adjusted forwards or backwards according to the remaining string, otherwise the relevant part of the date is set. The date can be adjusted as many times as required using these flags. Flags are processed in the order given.




            So for your purpose, date -v1125d will simply do what you need



            $ date; date -v-1125d
            Thu 19 Oct 2017 11:35:25 EDT
            Sat 20 Sep 2014 11:35:25 EDT





            share|improve this answer




























              2














              Previous answer was far too complicated. FreeBSD/macOS have the -v flag for date, from the MAN page (abbreviated description):




              Adjust (i.e., take the current date and display the result of the adjustment; not actually set the date) the second, minute, hour, month day, week day, month or year according to val. If val is preceded with a plus or minus sign, the date is adjusted forwards or backwards according to the remaining string, otherwise the relevant part of the date is set. The date can be adjusted as many times as required using these flags. Flags are processed in the order given.




              So for your purpose, date -v1125d will simply do what you need



              $ date; date -v-1125d
              Thu 19 Oct 2017 11:35:25 EDT
              Sat 20 Sep 2014 11:35:25 EDT





              share|improve this answer


























                2












                2








                2







                Previous answer was far too complicated. FreeBSD/macOS have the -v flag for date, from the MAN page (abbreviated description):




                Adjust (i.e., take the current date and display the result of the adjustment; not actually set the date) the second, minute, hour, month day, week day, month or year according to val. If val is preceded with a plus or minus sign, the date is adjusted forwards or backwards according to the remaining string, otherwise the relevant part of the date is set. The date can be adjusted as many times as required using these flags. Flags are processed in the order given.




                So for your purpose, date -v1125d will simply do what you need



                $ date; date -v-1125d
                Thu 19 Oct 2017 11:35:25 EDT
                Sat 20 Sep 2014 11:35:25 EDT





                share|improve this answer













                Previous answer was far too complicated. FreeBSD/macOS have the -v flag for date, from the MAN page (abbreviated description):




                Adjust (i.e., take the current date and display the result of the adjustment; not actually set the date) the second, minute, hour, month day, week day, month or year according to val. If val is preceded with a plus or minus sign, the date is adjusted forwards or backwards according to the remaining string, otherwise the relevant part of the date is set. The date can be adjusted as many times as required using these flags. Flags are processed in the order given.




                So for your purpose, date -v1125d will simply do what you need



                $ date; date -v-1125d
                Thu 19 Oct 2017 11:35:25 EDT
                Sat 20 Sep 2014 11:35:25 EDT






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Oct 19 '17 at 15:34









                brentbrent

                1354




                1354























                    0














                    I was having a similar issue i found the dateutils pkg for OpenBSD 6.4. It was a simple pkg_add dateutils for me.



                    #!/bin/ksh
                    # Using dateutils dadd (get current date) -1month -f (format to strftime)
                    # Set Year in YYYY formant y is YY format
                    lastMonth=$(dadd date -1mo -f "%Y.%m")
                    echo $lastMonth
                    mkdir /home/$usr/History/$lastMonth


                    My out put here is



                    #2018.11


                    UPDATE 1



                    I am running this command on 2018.12.10



                    HostNameHere# dadd date -1125d -f "%Y.%m"


                    Result



                     2015.11


                    It supports any time additions or subtractions that i can tell. Here is the commands help print out. #dadd -h (this is not the entirety of the print out. There is more info on options.



                        Usage: dadd [OPTION]... [DATE/TIME] [DURATION]
                    Add DURATION to DATE/TIME and print the result.
                    If DATE/TIME is omitted but DURATION is given, read a list of DATE/TIMEs from
                    stdin. If DURATION is omitted but DATE/TIME is given, read a list of DURATIONs from
                    stdin.

                    Durations are specified as nY, nMO, nW, or nD for years, months, weeks, or days
                    respectively, or nH, nM, nS for hours, minutes, and seconds, where N is a
                    (possibly negative) number. The unit symbols can be written lower-case as well
                    (y, mo, w, d, h, m, s) and the unit symbol `d' can be omitted.

                    Note that duration addition is not commutative!
                    2000-03-30 +1mo +1d -> 2000-05-01
                    2000-03-30 +1d +1mo -> 2000-04-30


                    Here are the commands.



                    Here are the formatting options.






                    share|improve this answer


























                    • (1) It's nice that this program supports -1mo. Can you demonstrate that it allows the user to calculate the date from 1125 days ago, as the question asks? (2) The question says "using the base operating system (e.g. No Perl or Python)." That would seem to preclude adding a new package.

                      – G-Man
                      Dec 7 '18 at 20:41






                    • 1





                      @G-Man Thank you for the comment. I am new to contributing on StackExchange. Thank you for the help. See UPDATE 1

                      – babyPenguin
                      Dec 10 '18 at 14:48


















                    0














                    I was having a similar issue i found the dateutils pkg for OpenBSD 6.4. It was a simple pkg_add dateutils for me.



                    #!/bin/ksh
                    # Using dateutils dadd (get current date) -1month -f (format to strftime)
                    # Set Year in YYYY formant y is YY format
                    lastMonth=$(dadd date -1mo -f "%Y.%m")
                    echo $lastMonth
                    mkdir /home/$usr/History/$lastMonth


                    My out put here is



                    #2018.11


                    UPDATE 1



                    I am running this command on 2018.12.10



                    HostNameHere# dadd date -1125d -f "%Y.%m"


                    Result



                     2015.11


                    It supports any time additions or subtractions that i can tell. Here is the commands help print out. #dadd -h (this is not the entirety of the print out. There is more info on options.



                        Usage: dadd [OPTION]... [DATE/TIME] [DURATION]
                    Add DURATION to DATE/TIME and print the result.
                    If DATE/TIME is omitted but DURATION is given, read a list of DATE/TIMEs from
                    stdin. If DURATION is omitted but DATE/TIME is given, read a list of DURATIONs from
                    stdin.

                    Durations are specified as nY, nMO, nW, or nD for years, months, weeks, or days
                    respectively, or nH, nM, nS for hours, minutes, and seconds, where N is a
                    (possibly negative) number. The unit symbols can be written lower-case as well
                    (y, mo, w, d, h, m, s) and the unit symbol `d' can be omitted.

                    Note that duration addition is not commutative!
                    2000-03-30 +1mo +1d -> 2000-05-01
                    2000-03-30 +1d +1mo -> 2000-04-30


                    Here are the commands.



                    Here are the formatting options.






                    share|improve this answer


























                    • (1) It's nice that this program supports -1mo. Can you demonstrate that it allows the user to calculate the date from 1125 days ago, as the question asks? (2) The question says "using the base operating system (e.g. No Perl or Python)." That would seem to preclude adding a new package.

                      – G-Man
                      Dec 7 '18 at 20:41






                    • 1





                      @G-Man Thank you for the comment. I am new to contributing on StackExchange. Thank you for the help. See UPDATE 1

                      – babyPenguin
                      Dec 10 '18 at 14:48
















                    0












                    0








                    0







                    I was having a similar issue i found the dateutils pkg for OpenBSD 6.4. It was a simple pkg_add dateutils for me.



                    #!/bin/ksh
                    # Using dateutils dadd (get current date) -1month -f (format to strftime)
                    # Set Year in YYYY formant y is YY format
                    lastMonth=$(dadd date -1mo -f "%Y.%m")
                    echo $lastMonth
                    mkdir /home/$usr/History/$lastMonth


                    My out put here is



                    #2018.11


                    UPDATE 1



                    I am running this command on 2018.12.10



                    HostNameHere# dadd date -1125d -f "%Y.%m"


                    Result



                     2015.11


                    It supports any time additions or subtractions that i can tell. Here is the commands help print out. #dadd -h (this is not the entirety of the print out. There is more info on options.



                        Usage: dadd [OPTION]... [DATE/TIME] [DURATION]
                    Add DURATION to DATE/TIME and print the result.
                    If DATE/TIME is omitted but DURATION is given, read a list of DATE/TIMEs from
                    stdin. If DURATION is omitted but DATE/TIME is given, read a list of DURATIONs from
                    stdin.

                    Durations are specified as nY, nMO, nW, or nD for years, months, weeks, or days
                    respectively, or nH, nM, nS for hours, minutes, and seconds, where N is a
                    (possibly negative) number. The unit symbols can be written lower-case as well
                    (y, mo, w, d, h, m, s) and the unit symbol `d' can be omitted.

                    Note that duration addition is not commutative!
                    2000-03-30 +1mo +1d -> 2000-05-01
                    2000-03-30 +1d +1mo -> 2000-04-30


                    Here are the commands.



                    Here are the formatting options.






                    share|improve this answer















                    I was having a similar issue i found the dateutils pkg for OpenBSD 6.4. It was a simple pkg_add dateutils for me.



                    #!/bin/ksh
                    # Using dateutils dadd (get current date) -1month -f (format to strftime)
                    # Set Year in YYYY formant y is YY format
                    lastMonth=$(dadd date -1mo -f "%Y.%m")
                    echo $lastMonth
                    mkdir /home/$usr/History/$lastMonth


                    My out put here is



                    #2018.11


                    UPDATE 1



                    I am running this command on 2018.12.10



                    HostNameHere# dadd date -1125d -f "%Y.%m"


                    Result



                     2015.11


                    It supports any time additions or subtractions that i can tell. Here is the commands help print out. #dadd -h (this is not the entirety of the print out. There is more info on options.



                        Usage: dadd [OPTION]... [DATE/TIME] [DURATION]
                    Add DURATION to DATE/TIME and print the result.
                    If DATE/TIME is omitted but DURATION is given, read a list of DATE/TIMEs from
                    stdin. If DURATION is omitted but DATE/TIME is given, read a list of DURATIONs from
                    stdin.

                    Durations are specified as nY, nMO, nW, or nD for years, months, weeks, or days
                    respectively, or nH, nM, nS for hours, minutes, and seconds, where N is a
                    (possibly negative) number. The unit symbols can be written lower-case as well
                    (y, mo, w, d, h, m, s) and the unit symbol `d' can be omitted.

                    Note that duration addition is not commutative!
                    2000-03-30 +1mo +1d -> 2000-05-01
                    2000-03-30 +1d +1mo -> 2000-04-30


                    Here are the commands.



                    Here are the formatting options.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Jan 23 at 21:22









                    Rui F Ribeiro

                    39.8k1479133




                    39.8k1479133










                    answered Dec 7 '18 at 20:16









                    babyPenguinbabyPenguin

                    84




                    84













                    • (1) It's nice that this program supports -1mo. Can you demonstrate that it allows the user to calculate the date from 1125 days ago, as the question asks? (2) The question says "using the base operating system (e.g. No Perl or Python)." That would seem to preclude adding a new package.

                      – G-Man
                      Dec 7 '18 at 20:41






                    • 1





                      @G-Man Thank you for the comment. I am new to contributing on StackExchange. Thank you for the help. See UPDATE 1

                      – babyPenguin
                      Dec 10 '18 at 14:48





















                    • (1) It's nice that this program supports -1mo. Can you demonstrate that it allows the user to calculate the date from 1125 days ago, as the question asks? (2) The question says "using the base operating system (e.g. No Perl or Python)." That would seem to preclude adding a new package.

                      – G-Man
                      Dec 7 '18 at 20:41






                    • 1





                      @G-Man Thank you for the comment. I am new to contributing on StackExchange. Thank you for the help. See UPDATE 1

                      – babyPenguin
                      Dec 10 '18 at 14:48



















                    (1) It's nice that this program supports -1mo. Can you demonstrate that it allows the user to calculate the date from 1125 days ago, as the question asks? (2) The question says "using the base operating system (e.g. No Perl or Python)." That would seem to preclude adding a new package.

                    – G-Man
                    Dec 7 '18 at 20:41





                    (1) It's nice that this program supports -1mo. Can you demonstrate that it allows the user to calculate the date from 1125 days ago, as the question asks? (2) The question says "using the base operating system (e.g. No Perl or Python)." That would seem to preclude adding a new package.

                    – G-Man
                    Dec 7 '18 at 20:41




                    1




                    1





                    @G-Man Thank you for the comment. I am new to contributing on StackExchange. Thank you for the help. See UPDATE 1

                    – babyPenguin
                    Dec 10 '18 at 14:48







                    @G-Man Thank you for the comment. I am new to contributing on StackExchange. Thank you for the help. See UPDATE 1

                    – babyPenguin
                    Dec 10 '18 at 14:48




















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