Sort three numbers using only if-statements












10












$begingroup$


Beginner here, trying to make a small program that sorts three numbers from smallest to largest only by using ifs. Any thoughts on how to improve this?



#include <iostream>

using namespace std;
int main ()
{
int num1, num2, num3;
int smallest, middle, biggest;
cin >> num1 >> num2 >> num3;

cout << endl;

if ((num1 < num2) && (num1 < num3))
{
smallest = num1;
if (num2 > num3)
{
biggest = num2;
middle = num3;
}
}
if ((num1 < num2) && (num3 << num1))
{
smallest = num1;
if (num2 < num3)
{
middle = num2;
biggest = num3;
}
}
if ((num1 > num2) && (num3 > num1))
{
middle = num1;
if (num2 < num3)
{
smallest = num2;
biggest = num3;
}
}
if ((num1 < num2) && (num3 < num1))
{
middle = num1;
if (num2 > num3)
{
biggest = num2;
smallest = num3;
}
}
if ((num1 > num2) && (num1 > num3))
{
biggest = num1;
if (num3 > num2)
{
middle = num3;
smallest = num2;
}
}

if ((num1 > num2) && (num1 > num3))
{
biggest = num1;
if (num2 > num3)
{
middle = num2;
smallest = num3;
}
}

cout << smallest << ", " << middle << ", " << biggest << endl;


return 0;
}









share|improve this question











$endgroup$








  • 5




    $begingroup$
    Why the requirement of only using if? You might discover new things by trying other tools too :)
    $endgroup$
    – Morwenn
    May 27 '15 at 9:54






  • 2




    $begingroup$
    I still haven't reached that part of the book :)
    $endgroup$
    – liquid3
    May 27 '15 at 9:58
















10












$begingroup$


Beginner here, trying to make a small program that sorts three numbers from smallest to largest only by using ifs. Any thoughts on how to improve this?



#include <iostream>

using namespace std;
int main ()
{
int num1, num2, num3;
int smallest, middle, biggest;
cin >> num1 >> num2 >> num3;

cout << endl;

if ((num1 < num2) && (num1 < num3))
{
smallest = num1;
if (num2 > num3)
{
biggest = num2;
middle = num3;
}
}
if ((num1 < num2) && (num3 << num1))
{
smallest = num1;
if (num2 < num3)
{
middle = num2;
biggest = num3;
}
}
if ((num1 > num2) && (num3 > num1))
{
middle = num1;
if (num2 < num3)
{
smallest = num2;
biggest = num3;
}
}
if ((num1 < num2) && (num3 < num1))
{
middle = num1;
if (num2 > num3)
{
biggest = num2;
smallest = num3;
}
}
if ((num1 > num2) && (num1 > num3))
{
biggest = num1;
if (num3 > num2)
{
middle = num3;
smallest = num2;
}
}

if ((num1 > num2) && (num1 > num3))
{
biggest = num1;
if (num2 > num3)
{
middle = num2;
smallest = num3;
}
}

cout << smallest << ", " << middle << ", " << biggest << endl;


return 0;
}









share|improve this question











$endgroup$








  • 5




    $begingroup$
    Why the requirement of only using if? You might discover new things by trying other tools too :)
    $endgroup$
    – Morwenn
    May 27 '15 at 9:54






  • 2




    $begingroup$
    I still haven't reached that part of the book :)
    $endgroup$
    – liquid3
    May 27 '15 at 9:58














10












10








10


1



$begingroup$


Beginner here, trying to make a small program that sorts three numbers from smallest to largest only by using ifs. Any thoughts on how to improve this?



#include <iostream>

using namespace std;
int main ()
{
int num1, num2, num3;
int smallest, middle, biggest;
cin >> num1 >> num2 >> num3;

cout << endl;

if ((num1 < num2) && (num1 < num3))
{
smallest = num1;
if (num2 > num3)
{
biggest = num2;
middle = num3;
}
}
if ((num1 < num2) && (num3 << num1))
{
smallest = num1;
if (num2 < num3)
{
middle = num2;
biggest = num3;
}
}
if ((num1 > num2) && (num3 > num1))
{
middle = num1;
if (num2 < num3)
{
smallest = num2;
biggest = num3;
}
}
if ((num1 < num2) && (num3 < num1))
{
middle = num1;
if (num2 > num3)
{
biggest = num2;
smallest = num3;
}
}
if ((num1 > num2) && (num1 > num3))
{
biggest = num1;
if (num3 > num2)
{
middle = num3;
smallest = num2;
}
}

if ((num1 > num2) && (num1 > num3))
{
biggest = num1;
if (num2 > num3)
{
middle = num2;
smallest = num3;
}
}

cout << smallest << ", " << middle << ", " << biggest << endl;


return 0;
}









share|improve this question











$endgroup$




Beginner here, trying to make a small program that sorts three numbers from smallest to largest only by using ifs. Any thoughts on how to improve this?



#include <iostream>

using namespace std;
int main ()
{
int num1, num2, num3;
int smallest, middle, biggest;
cin >> num1 >> num2 >> num3;

cout << endl;

if ((num1 < num2) && (num1 < num3))
{
smallest = num1;
if (num2 > num3)
{
biggest = num2;
middle = num3;
}
}
if ((num1 < num2) && (num3 << num1))
{
smallest = num1;
if (num2 < num3)
{
middle = num2;
biggest = num3;
}
}
if ((num1 > num2) && (num3 > num1))
{
middle = num1;
if (num2 < num3)
{
smallest = num2;
biggest = num3;
}
}
if ((num1 < num2) && (num3 < num1))
{
middle = num1;
if (num2 > num3)
{
biggest = num2;
smallest = num3;
}
}
if ((num1 > num2) && (num1 > num3))
{
biggest = num1;
if (num3 > num2)
{
middle = num3;
smallest = num2;
}
}

if ((num1 > num2) && (num1 > num3))
{
biggest = num1;
if (num2 > num3)
{
middle = num2;
smallest = num3;
}
}

cout << smallest << ", " << middle << ", " << biggest << endl;


return 0;
}






c++ beginner algorithm sorting






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited May 27 '15 at 17:04









200_success

129k15153415




129k15153415










asked May 27 '15 at 9:46









liquid3liquid3

53115




53115








  • 5




    $begingroup$
    Why the requirement of only using if? You might discover new things by trying other tools too :)
    $endgroup$
    – Morwenn
    May 27 '15 at 9:54






  • 2




    $begingroup$
    I still haven't reached that part of the book :)
    $endgroup$
    – liquid3
    May 27 '15 at 9:58














  • 5




    $begingroup$
    Why the requirement of only using if? You might discover new things by trying other tools too :)
    $endgroup$
    – Morwenn
    May 27 '15 at 9:54






  • 2




    $begingroup$
    I still haven't reached that part of the book :)
    $endgroup$
    – liquid3
    May 27 '15 at 9:58








5




5




$begingroup$
Why the requirement of only using if? You might discover new things by trying other tools too :)
$endgroup$
– Morwenn
May 27 '15 at 9:54




$begingroup$
Why the requirement of only using if? You might discover new things by trying other tools too :)
$endgroup$
– Morwenn
May 27 '15 at 9:54




2




2




$begingroup$
I still haven't reached that part of the book :)
$endgroup$
– liquid3
May 27 '15 at 9:58




$begingroup$
I still haven't reached that part of the book :)
$endgroup$
– liquid3
May 27 '15 at 9:58










5 Answers
5






active

oldest

votes


















12












$begingroup$

I will try to take several things into account but to keep things simple. A few remarks:





  • First, it seems that you have a typo here:



    if ((num1 < num2) && (num3 << num1))


    I think that you meant num3 < num1 instead of num3 << num1 in your second condition.




  • As @Josay says, you better write small functions. I would add that you better separate the input/output operations (that you can keep in main) and the sorting function. In my opinion, this would be a good enough signature for the sorting function:



    void sort3(int& a, int& b, int& c);


    You would give three variables to it and it would sort them in-place so that you end up with $ a le b le c $.




  • Now, let's choose an algorithm. For three values, the easiest is to implement a bubble sort which shouldn't be really slower than other algorithms (when you want to sort more values, it becomes horribly slower though).



    void sort3(int& a, int& b, int& c)
    {
    if (a > b)
    {
    std::swap(a, b);
    }
    if (b > c)
    {
    std::swap(b, c);
    }
    if (a > b)
    {
    std::swap(a, b);
    }
    }


    Most sorting algorithms heavily rely on swapping values. The one I just implemented sorts your values with only three comparisons and at most three swaps and is, in my opinion, far simpler to understand than what you had.



    Note that there are more efficient algorithms but I deliberately chose to present one that is not that bad while easy to understand.



  • This is not a problem in your case, but we can't stress out enough that using namespace std; is often considered bad practice. It is the case when used in a header file, especially in a library header file since it will pollute the global namespace of every file including it. That's not a problem for you since you're probably doing everything in a .cpp file but it's better to keep that in mind.


  • You don't need to return 0; at the end of main. If the compiler reaches the end of the main function without having encountered a return statement, it automagically adds a return 0; for you. Note that it only works with main though. Dropping this line is an interesting way to document that your program cannot return error codes and that it will only ever return 0.







share|improve this answer











$endgroup$













  • $begingroup$
    Thanks for your answers, i'm afraid i can't give thumbs up because i need more rep
    $endgroup$
    – liquid3
    May 27 '15 at 10:50










  • $begingroup$
    why did you test if a > b twice?
    $endgroup$
    – Ritchie Shatter
    May 27 '15 at 12:33






  • 1




    $begingroup$
    @RitchieShatter If the values are $3, 2, 1$ the first two swaps will make the values $2, 1, 3$ so you need to swap a and b again.
    $endgroup$
    – Morwenn
    May 27 '15 at 12:37






  • 2




    $begingroup$
    @RitchieShatter - don't know if this helps, but if you've studied how bubble sort works, think of this code as a bubble sort with the loops unrolled; the smallest values bubble down from the top.
    $endgroup$
    – Pete Becker
    May 27 '15 at 20:41






  • 1




    $begingroup$
    "You don't need to return 0; at the end of main"—technically correct, of course, but is it really advisable not to? Nothing good will come of not returning zero…a careless port to C (not C++), for example, will cause the exit status to be undefined.
    $endgroup$
    – wchargin
    May 27 '15 at 22:40



















5












$begingroup$

A few pieces of advice:




  • write small functions you can test


  • write tests



I did it for you and discovered problems quickly :



#include <iostream>

using namespace std;

void sort(int num1, int num2, int num3, int* smallest, int* middle, int* biggest)
{
if ((num1 < num2) && (num1 < num3))
{
*smallest = num1;
if (num2 > num3)
{
*biggest = num2;
*middle = num3;
}
}
if ((num1 < num2) && (num3 << num1))
{
*smallest = num1;
if (num2 < num3)
{
*middle = num2;
*biggest = num3;
}
}
if ((num1 > num2) && (num3 > num1))
{
*middle = num1;
if (num2 < num3)
{
*smallest = num2;
*biggest = num3;
}
}
if ((num1 < num2) && (num3 < num1))
{
*middle = num1;
if (num2 > num3)
{
*biggest = num2;
*smallest = num3;
}
}
if ((num1 > num2) && (num1 > num3))
{
*biggest = num1;
if (num3 > num2)
{
*middle = num3;
*smallest = num2;
}
}

if ((num1 > num2) && (num1 > num3))
{
*biggest = num1;
if (num2 > num3)
{
*middle = num2;
*smallest = num3;
}
}


}

//==========================================================================
int main ()
{
int num1, num2, num3;
int smallest, middle, biggest;

//cin >> num1 >> num2 >> num3;
//sort(num1, num2, num3, &smallest, &middle, &biggest);
//cout << endl;
//cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 1; num2 = 2; num3 = 3;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 4; num2 = 4; num3 = 4;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 5; num2 = 5; num3 = 6;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 7; num2 = 8; num3 = 7;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 9; num2 = 10; num3 = 10;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 11; num2 = 13; num3 = 12;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 15; num2 = 14; num3 = 16;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 19; num2 = 18; num3 = 17;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 21; num2 = 22; num3 = 20;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

num1 = 25; num2 = 23; num3 = 24;
sort(num1, num2, num3, &smallest, &middle, &biggest);
cout << smallest << ", " << middle << ", " << biggest << endl;

return 0;
}


gives :



1, 2, 3
1, 2, 3
1, 2, 3
7, 2, 3
9, 2, 3
11, 12, 13
14, 15, 16
17, 18, 19
20, 21, 22
23, 24, 25





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$endgroup$













  • $begingroup$
    Thanks for the answer, the problem is when i type 2 same numbers
    $endgroup$
    – liquid3
    May 27 '15 at 10:13



















3












$begingroup$

Your code compiles, but your program is not exactly small. I like what you are trying to do. When I learn something new, I like to write a program to help showcase it. The problem is you need to bring the correct tools for the job.
Analogously You probably could hammer a nail with a screwdriver, but I wouldn't recommend it.



There are multiple ways you could get this code under 10 lines.
use of "else" and "else if" may help. however you will make your life considerably easier using logical operators. For example



#define max(x,y) ( x > y ? x : y )


you can make a simple preprocessor command that will give you the maximum value.



The logic for that command would read as if x is greater than y the answer is x, otherwise it's y.



The swap command mentioned above would work well to.
I highly recommend before limiting yourself to one statement you read a little about c++ operators. Try here.



http://www.cplusplus.com/doc/tutorial/operators/






share|improve this answer









$endgroup$













  • $begingroup$
    You can get into some rather dangerous waters with that max macro if you do things such as max(foo + 1, bar). Code golf is great for people who understand the full set of tricks for the language, but code that is understandable to the coder(or next person) is often something to strive for. Clever code needs you to be more clever to debug it - and if the code is at your edge of cleverness this can cause problems.
    $endgroup$
    – user22048
    May 27 '15 at 14:06






  • 2




    $begingroup$
    Why define a max macro when there is already the safer std::max in the standard library? :(
    $endgroup$
    – Morwenn
    May 27 '15 at 14:07










  • $begingroup$
    Interesting. I wasn't aware of std::max. nor std::swap. I guess I need to look through the std libraries at some point. MichaelT, your point is well taken. However, I still feel that a strong understanding of operators should be an early fundamental for learning c/c++
    $endgroup$
    – mreff555
    May 27 '15 at 17:12



















2












$begingroup$

Assuming you define min and max (or use std::min, std::max), you can do this:



int low, mid, high;
// Find the minimum of number 1 and the minimum of number 2 and number 3.
low = std::min(num1, std::min(num2, num3));
// Find the maximum of the minimum of number 1 and number 2 and the minimum of number 2 and number 3.
mid = std::max(std::min(num1, num2), std::min(num2, num3));
// Find the maximum of number 1 and the maximum of number 2 and number 3.
high = std::max(num1, std:max(num2, num3));


Which basically moves all of your if-else logic into standard library calls.



By the way, a popular method for switching numbers in place without a temporary integer goes as follows:



x = x ^ y;
y = y ^ x;
x = x ^ y;


Which replaces the need for a temp variable. Try it out and see.



if(a > b) {
a = a ^ b;
b = b ^ a;
a = a ^ b;
}
if(b > c) {
b = b ^ c;
c = c ^ b;
b = b ^ c;
}
if(a > b) {
a = a ^ b;
b = b ^ a;
a = a ^ b;
}


Of course, you could instead use std::swap. However, given all the alternatives, if performance was a non-issue (e.g. absolute clock cycle count was unimportant), I'd impress simply using std::min and std::max.






share|improve this answer









$endgroup$





















    -1












    $begingroup$

    #include <iostream>

    int min (int g, int a, int b){
    if (g < a && g < b){
    return g;
    }
    else if (a < g && a < b){
    return a;
    }
    else if (b < a && b < g){
    return b;
    }
    }
    int max (int g, int a, int b){
    if (g > a && g >> b){
    return g;
    }
    else if(a > g && a > b)
    {
    return a;
    }
    else if (b > g && b > a)
    {
    return b;
    }
    }
    int sort(int *g, int *a, int *b){
    int small = min(*g ,*a, *b);
    int big = max(*g, *a, *b);
    int mid ;
    if ((big != *g) && (small < *g)){
    mid= *g;
    }
    if ((big != *a) && (small < *a)){
    mid= *a;
    }
    if ((big != *b) && (small < *b)){
    mid= *b;
    }
    std::cout << "*output :"<< std::endl;
    std::cout << " small: " << small<< std::endl;
    std::cout << " mid: " << mid<< std::endl;;
    std::cout << " big: " << big<< std::endl;;

    }

    int main(){

    int first,secnd,thered;

    do {
    std::cout << "*what numbers to sort?";
    std::cout << std::endl;
    std::cin >> first >>secnd >> thered ;
    std::cout << std::endl;
    if (first != 0) {
    sort(&first, &secnd, &thered);

    }

    }while(first != 0);

    }





    share|improve this answer








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    $endgroup$













    • $begingroup$
      You have presented an alternative solution, but haven't reviewed the code. Please explain your reasoning (how your solution works and why it is better than the original) so that the author and other readers can learn from your thought process.
      $endgroup$
      – Jamal
      22 mins ago










    protected by Jamal 22 mins ago



    Thank you for your interest in this question.
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    5 Answers
    5






    active

    oldest

    votes








    5 Answers
    5






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    12












    $begingroup$

    I will try to take several things into account but to keep things simple. A few remarks:





    • First, it seems that you have a typo here:



      if ((num1 < num2) && (num3 << num1))


      I think that you meant num3 < num1 instead of num3 << num1 in your second condition.




    • As @Josay says, you better write small functions. I would add that you better separate the input/output operations (that you can keep in main) and the sorting function. In my opinion, this would be a good enough signature for the sorting function:



      void sort3(int& a, int& b, int& c);


      You would give three variables to it and it would sort them in-place so that you end up with $ a le b le c $.




    • Now, let's choose an algorithm. For three values, the easiest is to implement a bubble sort which shouldn't be really slower than other algorithms (when you want to sort more values, it becomes horribly slower though).



      void sort3(int& a, int& b, int& c)
      {
      if (a > b)
      {
      std::swap(a, b);
      }
      if (b > c)
      {
      std::swap(b, c);
      }
      if (a > b)
      {
      std::swap(a, b);
      }
      }


      Most sorting algorithms heavily rely on swapping values. The one I just implemented sorts your values with only three comparisons and at most three swaps and is, in my opinion, far simpler to understand than what you had.



      Note that there are more efficient algorithms but I deliberately chose to present one that is not that bad while easy to understand.



    • This is not a problem in your case, but we can't stress out enough that using namespace std; is often considered bad practice. It is the case when used in a header file, especially in a library header file since it will pollute the global namespace of every file including it. That's not a problem for you since you're probably doing everything in a .cpp file but it's better to keep that in mind.


    • You don't need to return 0; at the end of main. If the compiler reaches the end of the main function without having encountered a return statement, it automagically adds a return 0; for you. Note that it only works with main though. Dropping this line is an interesting way to document that your program cannot return error codes and that it will only ever return 0.







    share|improve this answer











    $endgroup$













    • $begingroup$
      Thanks for your answers, i'm afraid i can't give thumbs up because i need more rep
      $endgroup$
      – liquid3
      May 27 '15 at 10:50










    • $begingroup$
      why did you test if a > b twice?
      $endgroup$
      – Ritchie Shatter
      May 27 '15 at 12:33






    • 1




      $begingroup$
      @RitchieShatter If the values are $3, 2, 1$ the first two swaps will make the values $2, 1, 3$ so you need to swap a and b again.
      $endgroup$
      – Morwenn
      May 27 '15 at 12:37






    • 2




      $begingroup$
      @RitchieShatter - don't know if this helps, but if you've studied how bubble sort works, think of this code as a bubble sort with the loops unrolled; the smallest values bubble down from the top.
      $endgroup$
      – Pete Becker
      May 27 '15 at 20:41






    • 1




      $begingroup$
      "You don't need to return 0; at the end of main"—technically correct, of course, but is it really advisable not to? Nothing good will come of not returning zero…a careless port to C (not C++), for example, will cause the exit status to be undefined.
      $endgroup$
      – wchargin
      May 27 '15 at 22:40
















    12












    $begingroup$

    I will try to take several things into account but to keep things simple. A few remarks:





    • First, it seems that you have a typo here:



      if ((num1 < num2) && (num3 << num1))


      I think that you meant num3 < num1 instead of num3 << num1 in your second condition.




    • As @Josay says, you better write small functions. I would add that you better separate the input/output operations (that you can keep in main) and the sorting function. In my opinion, this would be a good enough signature for the sorting function:



      void sort3(int& a, int& b, int& c);


      You would give three variables to it and it would sort them in-place so that you end up with $ a le b le c $.




    • Now, let's choose an algorithm. For three values, the easiest is to implement a bubble sort which shouldn't be really slower than other algorithms (when you want to sort more values, it becomes horribly slower though).



      void sort3(int& a, int& b, int& c)
      {
      if (a > b)
      {
      std::swap(a, b);
      }
      if (b > c)
      {
      std::swap(b, c);
      }
      if (a > b)
      {
      std::swap(a, b);
      }
      }


      Most sorting algorithms heavily rely on swapping values. The one I just implemented sorts your values with only three comparisons and at most three swaps and is, in my opinion, far simpler to understand than what you had.



      Note that there are more efficient algorithms but I deliberately chose to present one that is not that bad while easy to understand.



    • This is not a problem in your case, but we can't stress out enough that using namespace std; is often considered bad practice. It is the case when used in a header file, especially in a library header file since it will pollute the global namespace of every file including it. That's not a problem for you since you're probably doing everything in a .cpp file but it's better to keep that in mind.


    • You don't need to return 0; at the end of main. If the compiler reaches the end of the main function without having encountered a return statement, it automagically adds a return 0; for you. Note that it only works with main though. Dropping this line is an interesting way to document that your program cannot return error codes and that it will only ever return 0.







    share|improve this answer











    $endgroup$













    • $begingroup$
      Thanks for your answers, i'm afraid i can't give thumbs up because i need more rep
      $endgroup$
      – liquid3
      May 27 '15 at 10:50










    • $begingroup$
      why did you test if a > b twice?
      $endgroup$
      – Ritchie Shatter
      May 27 '15 at 12:33






    • 1




      $begingroup$
      @RitchieShatter If the values are $3, 2, 1$ the first two swaps will make the values $2, 1, 3$ so you need to swap a and b again.
      $endgroup$
      – Morwenn
      May 27 '15 at 12:37






    • 2




      $begingroup$
      @RitchieShatter - don't know if this helps, but if you've studied how bubble sort works, think of this code as a bubble sort with the loops unrolled; the smallest values bubble down from the top.
      $endgroup$
      – Pete Becker
      May 27 '15 at 20:41






    • 1




      $begingroup$
      "You don't need to return 0; at the end of main"—technically correct, of course, but is it really advisable not to? Nothing good will come of not returning zero…a careless port to C (not C++), for example, will cause the exit status to be undefined.
      $endgroup$
      – wchargin
      May 27 '15 at 22:40














    12












    12








    12





    $begingroup$

    I will try to take several things into account but to keep things simple. A few remarks:





    • First, it seems that you have a typo here:



      if ((num1 < num2) && (num3 << num1))


      I think that you meant num3 < num1 instead of num3 << num1 in your second condition.




    • As @Josay says, you better write small functions. I would add that you better separate the input/output operations (that you can keep in main) and the sorting function. In my opinion, this would be a good enough signature for the sorting function:



      void sort3(int& a, int& b, int& c);


      You would give three variables to it and it would sort them in-place so that you end up with $ a le b le c $.




    • Now, let's choose an algorithm. For three values, the easiest is to implement a bubble sort which shouldn't be really slower than other algorithms (when you want to sort more values, it becomes horribly slower though).



      void sort3(int& a, int& b, int& c)
      {
      if (a > b)
      {
      std::swap(a, b);
      }
      if (b > c)
      {
      std::swap(b, c);
      }
      if (a > b)
      {
      std::swap(a, b);
      }
      }


      Most sorting algorithms heavily rely on swapping values. The one I just implemented sorts your values with only three comparisons and at most three swaps and is, in my opinion, far simpler to understand than what you had.



      Note that there are more efficient algorithms but I deliberately chose to present one that is not that bad while easy to understand.



    • This is not a problem in your case, but we can't stress out enough that using namespace std; is often considered bad practice. It is the case when used in a header file, especially in a library header file since it will pollute the global namespace of every file including it. That's not a problem for you since you're probably doing everything in a .cpp file but it's better to keep that in mind.


    • You don't need to return 0; at the end of main. If the compiler reaches the end of the main function without having encountered a return statement, it automagically adds a return 0; for you. Note that it only works with main though. Dropping this line is an interesting way to document that your program cannot return error codes and that it will only ever return 0.







    share|improve this answer











    $endgroup$



    I will try to take several things into account but to keep things simple. A few remarks:





    • First, it seems that you have a typo here:



      if ((num1 < num2) && (num3 << num1))


      I think that you meant num3 < num1 instead of num3 << num1 in your second condition.




    • As @Josay says, you better write small functions. I would add that you better separate the input/output operations (that you can keep in main) and the sorting function. In my opinion, this would be a good enough signature for the sorting function:



      void sort3(int& a, int& b, int& c);


      You would give three variables to it and it would sort them in-place so that you end up with $ a le b le c $.




    • Now, let's choose an algorithm. For three values, the easiest is to implement a bubble sort which shouldn't be really slower than other algorithms (when you want to sort more values, it becomes horribly slower though).



      void sort3(int& a, int& b, int& c)
      {
      if (a > b)
      {
      std::swap(a, b);
      }
      if (b > c)
      {
      std::swap(b, c);
      }
      if (a > b)
      {
      std::swap(a, b);
      }
      }


      Most sorting algorithms heavily rely on swapping values. The one I just implemented sorts your values with only three comparisons and at most three swaps and is, in my opinion, far simpler to understand than what you had.



      Note that there are more efficient algorithms but I deliberately chose to present one that is not that bad while easy to understand.



    • This is not a problem in your case, but we can't stress out enough that using namespace std; is often considered bad practice. It is the case when used in a header file, especially in a library header file since it will pollute the global namespace of every file including it. That's not a problem for you since you're probably doing everything in a .cpp file but it's better to keep that in mind.


    • You don't need to return 0; at the end of main. If the compiler reaches the end of the main function without having encountered a return statement, it automagically adds a return 0; for you. Note that it only works with main though. Dropping this line is an interesting way to document that your program cannot return error codes and that it will only ever return 0.








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited May 23 '17 at 12:40









    Community

    1




    1










    answered May 27 '15 at 10:19









    MorwennMorwenn

    15k248113




    15k248113












    • $begingroup$
      Thanks for your answers, i'm afraid i can't give thumbs up because i need more rep
      $endgroup$
      – liquid3
      May 27 '15 at 10:50










    • $begingroup$
      why did you test if a > b twice?
      $endgroup$
      – Ritchie Shatter
      May 27 '15 at 12:33






    • 1




      $begingroup$
      @RitchieShatter If the values are $3, 2, 1$ the first two swaps will make the values $2, 1, 3$ so you need to swap a and b again.
      $endgroup$
      – Morwenn
      May 27 '15 at 12:37






    • 2




      $begingroup$
      @RitchieShatter - don't know if this helps, but if you've studied how bubble sort works, think of this code as a bubble sort with the loops unrolled; the smallest values bubble down from the top.
      $endgroup$
      – Pete Becker
      May 27 '15 at 20:41






    • 1




      $begingroup$
      "You don't need to return 0; at the end of main"—technically correct, of course, but is it really advisable not to? Nothing good will come of not returning zero…a careless port to C (not C++), for example, will cause the exit status to be undefined.
      $endgroup$
      – wchargin
      May 27 '15 at 22:40


















    • $begingroup$
      Thanks for your answers, i'm afraid i can't give thumbs up because i need more rep
      $endgroup$
      – liquid3
      May 27 '15 at 10:50










    • $begingroup$
      why did you test if a > b twice?
      $endgroup$
      – Ritchie Shatter
      May 27 '15 at 12:33






    • 1




      $begingroup$
      @RitchieShatter If the values are $3, 2, 1$ the first two swaps will make the values $2, 1, 3$ so you need to swap a and b again.
      $endgroup$
      – Morwenn
      May 27 '15 at 12:37






    • 2




      $begingroup$
      @RitchieShatter - don't know if this helps, but if you've studied how bubble sort works, think of this code as a bubble sort with the loops unrolled; the smallest values bubble down from the top.
      $endgroup$
      – Pete Becker
      May 27 '15 at 20:41






    • 1




      $begingroup$
      "You don't need to return 0; at the end of main"—technically correct, of course, but is it really advisable not to? Nothing good will come of not returning zero…a careless port to C (not C++), for example, will cause the exit status to be undefined.
      $endgroup$
      – wchargin
      May 27 '15 at 22:40
















    $begingroup$
    Thanks for your answers, i'm afraid i can't give thumbs up because i need more rep
    $endgroup$
    – liquid3
    May 27 '15 at 10:50




    $begingroup$
    Thanks for your answers, i'm afraid i can't give thumbs up because i need more rep
    $endgroup$
    – liquid3
    May 27 '15 at 10:50












    $begingroup$
    why did you test if a > b twice?
    $endgroup$
    – Ritchie Shatter
    May 27 '15 at 12:33




    $begingroup$
    why did you test if a > b twice?
    $endgroup$
    – Ritchie Shatter
    May 27 '15 at 12:33




    1




    1




    $begingroup$
    @RitchieShatter If the values are $3, 2, 1$ the first two swaps will make the values $2, 1, 3$ so you need to swap a and b again.
    $endgroup$
    – Morwenn
    May 27 '15 at 12:37




    $begingroup$
    @RitchieShatter If the values are $3, 2, 1$ the first two swaps will make the values $2, 1, 3$ so you need to swap a and b again.
    $endgroup$
    – Morwenn
    May 27 '15 at 12:37




    2




    2




    $begingroup$
    @RitchieShatter - don't know if this helps, but if you've studied how bubble sort works, think of this code as a bubble sort with the loops unrolled; the smallest values bubble down from the top.
    $endgroup$
    – Pete Becker
    May 27 '15 at 20:41




    $begingroup$
    @RitchieShatter - don't know if this helps, but if you've studied how bubble sort works, think of this code as a bubble sort with the loops unrolled; the smallest values bubble down from the top.
    $endgroup$
    – Pete Becker
    May 27 '15 at 20:41




    1




    1




    $begingroup$
    "You don't need to return 0; at the end of main"—technically correct, of course, but is it really advisable not to? Nothing good will come of not returning zero…a careless port to C (not C++), for example, will cause the exit status to be undefined.
    $endgroup$
    – wchargin
    May 27 '15 at 22:40




    $begingroup$
    "You don't need to return 0; at the end of main"—technically correct, of course, but is it really advisable not to? Nothing good will come of not returning zero…a careless port to C (not C++), for example, will cause the exit status to be undefined.
    $endgroup$
    – wchargin
    May 27 '15 at 22:40













    5












    $begingroup$

    A few pieces of advice:




    • write small functions you can test


    • write tests



    I did it for you and discovered problems quickly :



    #include <iostream>

    using namespace std;

    void sort(int num1, int num2, int num3, int* smallest, int* middle, int* biggest)
    {
    if ((num1 < num2) && (num1 < num3))
    {
    *smallest = num1;
    if (num2 > num3)
    {
    *biggest = num2;
    *middle = num3;
    }
    }
    if ((num1 < num2) && (num3 << num1))
    {
    *smallest = num1;
    if (num2 < num3)
    {
    *middle = num2;
    *biggest = num3;
    }
    }
    if ((num1 > num2) && (num3 > num1))
    {
    *middle = num1;
    if (num2 < num3)
    {
    *smallest = num2;
    *biggest = num3;
    }
    }
    if ((num1 < num2) && (num3 < num1))
    {
    *middle = num1;
    if (num2 > num3)
    {
    *biggest = num2;
    *smallest = num3;
    }
    }
    if ((num1 > num2) && (num1 > num3))
    {
    *biggest = num1;
    if (num3 > num2)
    {
    *middle = num3;
    *smallest = num2;
    }
    }

    if ((num1 > num2) && (num1 > num3))
    {
    *biggest = num1;
    if (num2 > num3)
    {
    *middle = num2;
    *smallest = num3;
    }
    }


    }

    //==========================================================================
    int main ()
    {
    int num1, num2, num3;
    int smallest, middle, biggest;

    //cin >> num1 >> num2 >> num3;
    //sort(num1, num2, num3, &smallest, &middle, &biggest);
    //cout << endl;
    //cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 1; num2 = 2; num3 = 3;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 4; num2 = 4; num3 = 4;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 5; num2 = 5; num3 = 6;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 7; num2 = 8; num3 = 7;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 9; num2 = 10; num3 = 10;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 11; num2 = 13; num3 = 12;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 15; num2 = 14; num3 = 16;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 19; num2 = 18; num3 = 17;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 21; num2 = 22; num3 = 20;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 25; num2 = 23; num3 = 24;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    return 0;
    }


    gives :



    1, 2, 3
    1, 2, 3
    1, 2, 3
    7, 2, 3
    9, 2, 3
    11, 12, 13
    14, 15, 16
    17, 18, 19
    20, 21, 22
    23, 24, 25





    share|improve this answer











    $endgroup$













    • $begingroup$
      Thanks for the answer, the problem is when i type 2 same numbers
      $endgroup$
      – liquid3
      May 27 '15 at 10:13
















    5












    $begingroup$

    A few pieces of advice:




    • write small functions you can test


    • write tests



    I did it for you and discovered problems quickly :



    #include <iostream>

    using namespace std;

    void sort(int num1, int num2, int num3, int* smallest, int* middle, int* biggest)
    {
    if ((num1 < num2) && (num1 < num3))
    {
    *smallest = num1;
    if (num2 > num3)
    {
    *biggest = num2;
    *middle = num3;
    }
    }
    if ((num1 < num2) && (num3 << num1))
    {
    *smallest = num1;
    if (num2 < num3)
    {
    *middle = num2;
    *biggest = num3;
    }
    }
    if ((num1 > num2) && (num3 > num1))
    {
    *middle = num1;
    if (num2 < num3)
    {
    *smallest = num2;
    *biggest = num3;
    }
    }
    if ((num1 < num2) && (num3 < num1))
    {
    *middle = num1;
    if (num2 > num3)
    {
    *biggest = num2;
    *smallest = num3;
    }
    }
    if ((num1 > num2) && (num1 > num3))
    {
    *biggest = num1;
    if (num3 > num2)
    {
    *middle = num3;
    *smallest = num2;
    }
    }

    if ((num1 > num2) && (num1 > num3))
    {
    *biggest = num1;
    if (num2 > num3)
    {
    *middle = num2;
    *smallest = num3;
    }
    }


    }

    //==========================================================================
    int main ()
    {
    int num1, num2, num3;
    int smallest, middle, biggest;

    //cin >> num1 >> num2 >> num3;
    //sort(num1, num2, num3, &smallest, &middle, &biggest);
    //cout << endl;
    //cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 1; num2 = 2; num3 = 3;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 4; num2 = 4; num3 = 4;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 5; num2 = 5; num3 = 6;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 7; num2 = 8; num3 = 7;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 9; num2 = 10; num3 = 10;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 11; num2 = 13; num3 = 12;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 15; num2 = 14; num3 = 16;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 19; num2 = 18; num3 = 17;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 21; num2 = 22; num3 = 20;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 25; num2 = 23; num3 = 24;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    return 0;
    }


    gives :



    1, 2, 3
    1, 2, 3
    1, 2, 3
    7, 2, 3
    9, 2, 3
    11, 12, 13
    14, 15, 16
    17, 18, 19
    20, 21, 22
    23, 24, 25





    share|improve this answer











    $endgroup$













    • $begingroup$
      Thanks for the answer, the problem is when i type 2 same numbers
      $endgroup$
      – liquid3
      May 27 '15 at 10:13














    5












    5








    5





    $begingroup$

    A few pieces of advice:




    • write small functions you can test


    • write tests



    I did it for you and discovered problems quickly :



    #include <iostream>

    using namespace std;

    void sort(int num1, int num2, int num3, int* smallest, int* middle, int* biggest)
    {
    if ((num1 < num2) && (num1 < num3))
    {
    *smallest = num1;
    if (num2 > num3)
    {
    *biggest = num2;
    *middle = num3;
    }
    }
    if ((num1 < num2) && (num3 << num1))
    {
    *smallest = num1;
    if (num2 < num3)
    {
    *middle = num2;
    *biggest = num3;
    }
    }
    if ((num1 > num2) && (num3 > num1))
    {
    *middle = num1;
    if (num2 < num3)
    {
    *smallest = num2;
    *biggest = num3;
    }
    }
    if ((num1 < num2) && (num3 < num1))
    {
    *middle = num1;
    if (num2 > num3)
    {
    *biggest = num2;
    *smallest = num3;
    }
    }
    if ((num1 > num2) && (num1 > num3))
    {
    *biggest = num1;
    if (num3 > num2)
    {
    *middle = num3;
    *smallest = num2;
    }
    }

    if ((num1 > num2) && (num1 > num3))
    {
    *biggest = num1;
    if (num2 > num3)
    {
    *middle = num2;
    *smallest = num3;
    }
    }


    }

    //==========================================================================
    int main ()
    {
    int num1, num2, num3;
    int smallest, middle, biggest;

    //cin >> num1 >> num2 >> num3;
    //sort(num1, num2, num3, &smallest, &middle, &biggest);
    //cout << endl;
    //cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 1; num2 = 2; num3 = 3;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 4; num2 = 4; num3 = 4;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 5; num2 = 5; num3 = 6;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 7; num2 = 8; num3 = 7;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 9; num2 = 10; num3 = 10;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 11; num2 = 13; num3 = 12;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 15; num2 = 14; num3 = 16;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 19; num2 = 18; num3 = 17;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 21; num2 = 22; num3 = 20;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 25; num2 = 23; num3 = 24;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    return 0;
    }


    gives :



    1, 2, 3
    1, 2, 3
    1, 2, 3
    7, 2, 3
    9, 2, 3
    11, 12, 13
    14, 15, 16
    17, 18, 19
    20, 21, 22
    23, 24, 25





    share|improve this answer











    $endgroup$



    A few pieces of advice:




    • write small functions you can test


    • write tests



    I did it for you and discovered problems quickly :



    #include <iostream>

    using namespace std;

    void sort(int num1, int num2, int num3, int* smallest, int* middle, int* biggest)
    {
    if ((num1 < num2) && (num1 < num3))
    {
    *smallest = num1;
    if (num2 > num3)
    {
    *biggest = num2;
    *middle = num3;
    }
    }
    if ((num1 < num2) && (num3 << num1))
    {
    *smallest = num1;
    if (num2 < num3)
    {
    *middle = num2;
    *biggest = num3;
    }
    }
    if ((num1 > num2) && (num3 > num1))
    {
    *middle = num1;
    if (num2 < num3)
    {
    *smallest = num2;
    *biggest = num3;
    }
    }
    if ((num1 < num2) && (num3 < num1))
    {
    *middle = num1;
    if (num2 > num3)
    {
    *biggest = num2;
    *smallest = num3;
    }
    }
    if ((num1 > num2) && (num1 > num3))
    {
    *biggest = num1;
    if (num3 > num2)
    {
    *middle = num3;
    *smallest = num2;
    }
    }

    if ((num1 > num2) && (num1 > num3))
    {
    *biggest = num1;
    if (num2 > num3)
    {
    *middle = num2;
    *smallest = num3;
    }
    }


    }

    //==========================================================================
    int main ()
    {
    int num1, num2, num3;
    int smallest, middle, biggest;

    //cin >> num1 >> num2 >> num3;
    //sort(num1, num2, num3, &smallest, &middle, &biggest);
    //cout << endl;
    //cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 1; num2 = 2; num3 = 3;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 4; num2 = 4; num3 = 4;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 5; num2 = 5; num3 = 6;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 7; num2 = 8; num3 = 7;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 9; num2 = 10; num3 = 10;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 11; num2 = 13; num3 = 12;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 15; num2 = 14; num3 = 16;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 19; num2 = 18; num3 = 17;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 21; num2 = 22; num3 = 20;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    num1 = 25; num2 = 23; num3 = 24;
    sort(num1, num2, num3, &smallest, &middle, &biggest);
    cout << smallest << ", " << middle << ", " << biggest << endl;

    return 0;
    }


    gives :



    1, 2, 3
    1, 2, 3
    1, 2, 3
    7, 2, 3
    9, 2, 3
    11, 12, 13
    14, 15, 16
    17, 18, 19
    20, 21, 22
    23, 24, 25






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 1 '16 at 8:52

























    answered May 27 '15 at 10:01









    JosayJosay

    25.7k14087




    25.7k14087












    • $begingroup$
      Thanks for the answer, the problem is when i type 2 same numbers
      $endgroup$
      – liquid3
      May 27 '15 at 10:13


















    • $begingroup$
      Thanks for the answer, the problem is when i type 2 same numbers
      $endgroup$
      – liquid3
      May 27 '15 at 10:13
















    $begingroup$
    Thanks for the answer, the problem is when i type 2 same numbers
    $endgroup$
    – liquid3
    May 27 '15 at 10:13




    $begingroup$
    Thanks for the answer, the problem is when i type 2 same numbers
    $endgroup$
    – liquid3
    May 27 '15 at 10:13











    3












    $begingroup$

    Your code compiles, but your program is not exactly small. I like what you are trying to do. When I learn something new, I like to write a program to help showcase it. The problem is you need to bring the correct tools for the job.
    Analogously You probably could hammer a nail with a screwdriver, but I wouldn't recommend it.



    There are multiple ways you could get this code under 10 lines.
    use of "else" and "else if" may help. however you will make your life considerably easier using logical operators. For example



    #define max(x,y) ( x > y ? x : y )


    you can make a simple preprocessor command that will give you the maximum value.



    The logic for that command would read as if x is greater than y the answer is x, otherwise it's y.



    The swap command mentioned above would work well to.
    I highly recommend before limiting yourself to one statement you read a little about c++ operators. Try here.



    http://www.cplusplus.com/doc/tutorial/operators/






    share|improve this answer









    $endgroup$













    • $begingroup$
      You can get into some rather dangerous waters with that max macro if you do things such as max(foo + 1, bar). Code golf is great for people who understand the full set of tricks for the language, but code that is understandable to the coder(or next person) is often something to strive for. Clever code needs you to be more clever to debug it - and if the code is at your edge of cleverness this can cause problems.
      $endgroup$
      – user22048
      May 27 '15 at 14:06






    • 2




      $begingroup$
      Why define a max macro when there is already the safer std::max in the standard library? :(
      $endgroup$
      – Morwenn
      May 27 '15 at 14:07










    • $begingroup$
      Interesting. I wasn't aware of std::max. nor std::swap. I guess I need to look through the std libraries at some point. MichaelT, your point is well taken. However, I still feel that a strong understanding of operators should be an early fundamental for learning c/c++
      $endgroup$
      – mreff555
      May 27 '15 at 17:12
















    3












    $begingroup$

    Your code compiles, but your program is not exactly small. I like what you are trying to do. When I learn something new, I like to write a program to help showcase it. The problem is you need to bring the correct tools for the job.
    Analogously You probably could hammer a nail with a screwdriver, but I wouldn't recommend it.



    There are multiple ways you could get this code under 10 lines.
    use of "else" and "else if" may help. however you will make your life considerably easier using logical operators. For example



    #define max(x,y) ( x > y ? x : y )


    you can make a simple preprocessor command that will give you the maximum value.



    The logic for that command would read as if x is greater than y the answer is x, otherwise it's y.



    The swap command mentioned above would work well to.
    I highly recommend before limiting yourself to one statement you read a little about c++ operators. Try here.



    http://www.cplusplus.com/doc/tutorial/operators/






    share|improve this answer









    $endgroup$













    • $begingroup$
      You can get into some rather dangerous waters with that max macro if you do things such as max(foo + 1, bar). Code golf is great for people who understand the full set of tricks for the language, but code that is understandable to the coder(or next person) is often something to strive for. Clever code needs you to be more clever to debug it - and if the code is at your edge of cleverness this can cause problems.
      $endgroup$
      – user22048
      May 27 '15 at 14:06






    • 2




      $begingroup$
      Why define a max macro when there is already the safer std::max in the standard library? :(
      $endgroup$
      – Morwenn
      May 27 '15 at 14:07










    • $begingroup$
      Interesting. I wasn't aware of std::max. nor std::swap. I guess I need to look through the std libraries at some point. MichaelT, your point is well taken. However, I still feel that a strong understanding of operators should be an early fundamental for learning c/c++
      $endgroup$
      – mreff555
      May 27 '15 at 17:12














    3












    3








    3





    $begingroup$

    Your code compiles, but your program is not exactly small. I like what you are trying to do. When I learn something new, I like to write a program to help showcase it. The problem is you need to bring the correct tools for the job.
    Analogously You probably could hammer a nail with a screwdriver, but I wouldn't recommend it.



    There are multiple ways you could get this code under 10 lines.
    use of "else" and "else if" may help. however you will make your life considerably easier using logical operators. For example



    #define max(x,y) ( x > y ? x : y )


    you can make a simple preprocessor command that will give you the maximum value.



    The logic for that command would read as if x is greater than y the answer is x, otherwise it's y.



    The swap command mentioned above would work well to.
    I highly recommend before limiting yourself to one statement you read a little about c++ operators. Try here.



    http://www.cplusplus.com/doc/tutorial/operators/






    share|improve this answer









    $endgroup$



    Your code compiles, but your program is not exactly small. I like what you are trying to do. When I learn something new, I like to write a program to help showcase it. The problem is you need to bring the correct tools for the job.
    Analogously You probably could hammer a nail with a screwdriver, but I wouldn't recommend it.



    There are multiple ways you could get this code under 10 lines.
    use of "else" and "else if" may help. however you will make your life considerably easier using logical operators. For example



    #define max(x,y) ( x > y ? x : y )


    you can make a simple preprocessor command that will give you the maximum value.



    The logic for that command would read as if x is greater than y the answer is x, otherwise it's y.



    The swap command mentioned above would work well to.
    I highly recommend before limiting yourself to one statement you read a little about c++ operators. Try here.



    http://www.cplusplus.com/doc/tutorial/operators/







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered May 27 '15 at 13:59









    mreff555mreff555

    1662




    1662












    • $begingroup$
      You can get into some rather dangerous waters with that max macro if you do things such as max(foo + 1, bar). Code golf is great for people who understand the full set of tricks for the language, but code that is understandable to the coder(or next person) is often something to strive for. Clever code needs you to be more clever to debug it - and if the code is at your edge of cleverness this can cause problems.
      $endgroup$
      – user22048
      May 27 '15 at 14:06






    • 2




      $begingroup$
      Why define a max macro when there is already the safer std::max in the standard library? :(
      $endgroup$
      – Morwenn
      May 27 '15 at 14:07










    • $begingroup$
      Interesting. I wasn't aware of std::max. nor std::swap. I guess I need to look through the std libraries at some point. MichaelT, your point is well taken. However, I still feel that a strong understanding of operators should be an early fundamental for learning c/c++
      $endgroup$
      – mreff555
      May 27 '15 at 17:12


















    • $begingroup$
      You can get into some rather dangerous waters with that max macro if you do things such as max(foo + 1, bar). Code golf is great for people who understand the full set of tricks for the language, but code that is understandable to the coder(or next person) is often something to strive for. Clever code needs you to be more clever to debug it - and if the code is at your edge of cleverness this can cause problems.
      $endgroup$
      – user22048
      May 27 '15 at 14:06






    • 2




      $begingroup$
      Why define a max macro when there is already the safer std::max in the standard library? :(
      $endgroup$
      – Morwenn
      May 27 '15 at 14:07










    • $begingroup$
      Interesting. I wasn't aware of std::max. nor std::swap. I guess I need to look through the std libraries at some point. MichaelT, your point is well taken. However, I still feel that a strong understanding of operators should be an early fundamental for learning c/c++
      $endgroup$
      – mreff555
      May 27 '15 at 17:12
















    $begingroup$
    You can get into some rather dangerous waters with that max macro if you do things such as max(foo + 1, bar). Code golf is great for people who understand the full set of tricks for the language, but code that is understandable to the coder(or next person) is often something to strive for. Clever code needs you to be more clever to debug it - and if the code is at your edge of cleverness this can cause problems.
    $endgroup$
    – user22048
    May 27 '15 at 14:06




    $begingroup$
    You can get into some rather dangerous waters with that max macro if you do things such as max(foo + 1, bar). Code golf is great for people who understand the full set of tricks for the language, but code that is understandable to the coder(or next person) is often something to strive for. Clever code needs you to be more clever to debug it - and if the code is at your edge of cleverness this can cause problems.
    $endgroup$
    – user22048
    May 27 '15 at 14:06




    2




    2




    $begingroup$
    Why define a max macro when there is already the safer std::max in the standard library? :(
    $endgroup$
    – Morwenn
    May 27 '15 at 14:07




    $begingroup$
    Why define a max macro when there is already the safer std::max in the standard library? :(
    $endgroup$
    – Morwenn
    May 27 '15 at 14:07












    $begingroup$
    Interesting. I wasn't aware of std::max. nor std::swap. I guess I need to look through the std libraries at some point. MichaelT, your point is well taken. However, I still feel that a strong understanding of operators should be an early fundamental for learning c/c++
    $endgroup$
    – mreff555
    May 27 '15 at 17:12




    $begingroup$
    Interesting. I wasn't aware of std::max. nor std::swap. I guess I need to look through the std libraries at some point. MichaelT, your point is well taken. However, I still feel that a strong understanding of operators should be an early fundamental for learning c/c++
    $endgroup$
    – mreff555
    May 27 '15 at 17:12











    2












    $begingroup$

    Assuming you define min and max (or use std::min, std::max), you can do this:



    int low, mid, high;
    // Find the minimum of number 1 and the minimum of number 2 and number 3.
    low = std::min(num1, std::min(num2, num3));
    // Find the maximum of the minimum of number 1 and number 2 and the minimum of number 2 and number 3.
    mid = std::max(std::min(num1, num2), std::min(num2, num3));
    // Find the maximum of number 1 and the maximum of number 2 and number 3.
    high = std::max(num1, std:max(num2, num3));


    Which basically moves all of your if-else logic into standard library calls.



    By the way, a popular method for switching numbers in place without a temporary integer goes as follows:



    x = x ^ y;
    y = y ^ x;
    x = x ^ y;


    Which replaces the need for a temp variable. Try it out and see.



    if(a > b) {
    a = a ^ b;
    b = b ^ a;
    a = a ^ b;
    }
    if(b > c) {
    b = b ^ c;
    c = c ^ b;
    b = b ^ c;
    }
    if(a > b) {
    a = a ^ b;
    b = b ^ a;
    a = a ^ b;
    }


    Of course, you could instead use std::swap. However, given all the alternatives, if performance was a non-issue (e.g. absolute clock cycle count was unimportant), I'd impress simply using std::min and std::max.






    share|improve this answer









    $endgroup$


















      2












      $begingroup$

      Assuming you define min and max (or use std::min, std::max), you can do this:



      int low, mid, high;
      // Find the minimum of number 1 and the minimum of number 2 and number 3.
      low = std::min(num1, std::min(num2, num3));
      // Find the maximum of the minimum of number 1 and number 2 and the minimum of number 2 and number 3.
      mid = std::max(std::min(num1, num2), std::min(num2, num3));
      // Find the maximum of number 1 and the maximum of number 2 and number 3.
      high = std::max(num1, std:max(num2, num3));


      Which basically moves all of your if-else logic into standard library calls.



      By the way, a popular method for switching numbers in place without a temporary integer goes as follows:



      x = x ^ y;
      y = y ^ x;
      x = x ^ y;


      Which replaces the need for a temp variable. Try it out and see.



      if(a > b) {
      a = a ^ b;
      b = b ^ a;
      a = a ^ b;
      }
      if(b > c) {
      b = b ^ c;
      c = c ^ b;
      b = b ^ c;
      }
      if(a > b) {
      a = a ^ b;
      b = b ^ a;
      a = a ^ b;
      }


      Of course, you could instead use std::swap. However, given all the alternatives, if performance was a non-issue (e.g. absolute clock cycle count was unimportant), I'd impress simply using std::min and std::max.






      share|improve this answer









      $endgroup$
















        2












        2








        2





        $begingroup$

        Assuming you define min and max (or use std::min, std::max), you can do this:



        int low, mid, high;
        // Find the minimum of number 1 and the minimum of number 2 and number 3.
        low = std::min(num1, std::min(num2, num3));
        // Find the maximum of the minimum of number 1 and number 2 and the minimum of number 2 and number 3.
        mid = std::max(std::min(num1, num2), std::min(num2, num3));
        // Find the maximum of number 1 and the maximum of number 2 and number 3.
        high = std::max(num1, std:max(num2, num3));


        Which basically moves all of your if-else logic into standard library calls.



        By the way, a popular method for switching numbers in place without a temporary integer goes as follows:



        x = x ^ y;
        y = y ^ x;
        x = x ^ y;


        Which replaces the need for a temp variable. Try it out and see.



        if(a > b) {
        a = a ^ b;
        b = b ^ a;
        a = a ^ b;
        }
        if(b > c) {
        b = b ^ c;
        c = c ^ b;
        b = b ^ c;
        }
        if(a > b) {
        a = a ^ b;
        b = b ^ a;
        a = a ^ b;
        }


        Of course, you could instead use std::swap. However, given all the alternatives, if performance was a non-issue (e.g. absolute clock cycle count was unimportant), I'd impress simply using std::min and std::max.






        share|improve this answer









        $endgroup$



        Assuming you define min and max (or use std::min, std::max), you can do this:



        int low, mid, high;
        // Find the minimum of number 1 and the minimum of number 2 and number 3.
        low = std::min(num1, std::min(num2, num3));
        // Find the maximum of the minimum of number 1 and number 2 and the minimum of number 2 and number 3.
        mid = std::max(std::min(num1, num2), std::min(num2, num3));
        // Find the maximum of number 1 and the maximum of number 2 and number 3.
        high = std::max(num1, std:max(num2, num3));


        Which basically moves all of your if-else logic into standard library calls.



        By the way, a popular method for switching numbers in place without a temporary integer goes as follows:



        x = x ^ y;
        y = y ^ x;
        x = x ^ y;


        Which replaces the need for a temp variable. Try it out and see.



        if(a > b) {
        a = a ^ b;
        b = b ^ a;
        a = a ^ b;
        }
        if(b > c) {
        b = b ^ c;
        c = c ^ b;
        b = b ^ c;
        }
        if(a > b) {
        a = a ^ b;
        b = b ^ a;
        a = a ^ b;
        }


        Of course, you could instead use std::swap. However, given all the alternatives, if performance was a non-issue (e.g. absolute clock cycle count was unimportant), I'd impress simply using std::min and std::max.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered May 27 '15 at 21:27









        phyrfoxphyrfox

        54248




        54248























            -1












            $begingroup$

            #include <iostream>

            int min (int g, int a, int b){
            if (g < a && g < b){
            return g;
            }
            else if (a < g && a < b){
            return a;
            }
            else if (b < a && b < g){
            return b;
            }
            }
            int max (int g, int a, int b){
            if (g > a && g >> b){
            return g;
            }
            else if(a > g && a > b)
            {
            return a;
            }
            else if (b > g && b > a)
            {
            return b;
            }
            }
            int sort(int *g, int *a, int *b){
            int small = min(*g ,*a, *b);
            int big = max(*g, *a, *b);
            int mid ;
            if ((big != *g) && (small < *g)){
            mid= *g;
            }
            if ((big != *a) && (small < *a)){
            mid= *a;
            }
            if ((big != *b) && (small < *b)){
            mid= *b;
            }
            std::cout << "*output :"<< std::endl;
            std::cout << " small: " << small<< std::endl;
            std::cout << " mid: " << mid<< std::endl;;
            std::cout << " big: " << big<< std::endl;;

            }

            int main(){

            int first,secnd,thered;

            do {
            std::cout << "*what numbers to sort?";
            std::cout << std::endl;
            std::cin >> first >>secnd >> thered ;
            std::cout << std::endl;
            if (first != 0) {
            sort(&first, &secnd, &thered);

            }

            }while(first != 0);

            }





            share|improve this answer








            New contributor




            Subice45 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$













            • $begingroup$
              You have presented an alternative solution, but haven't reviewed the code. Please explain your reasoning (how your solution works and why it is better than the original) so that the author and other readers can learn from your thought process.
              $endgroup$
              – Jamal
              22 mins ago
















            -1












            $begingroup$

            #include <iostream>

            int min (int g, int a, int b){
            if (g < a && g < b){
            return g;
            }
            else if (a < g && a < b){
            return a;
            }
            else if (b < a && b < g){
            return b;
            }
            }
            int max (int g, int a, int b){
            if (g > a && g >> b){
            return g;
            }
            else if(a > g && a > b)
            {
            return a;
            }
            else if (b > g && b > a)
            {
            return b;
            }
            }
            int sort(int *g, int *a, int *b){
            int small = min(*g ,*a, *b);
            int big = max(*g, *a, *b);
            int mid ;
            if ((big != *g) && (small < *g)){
            mid= *g;
            }
            if ((big != *a) && (small < *a)){
            mid= *a;
            }
            if ((big != *b) && (small < *b)){
            mid= *b;
            }
            std::cout << "*output :"<< std::endl;
            std::cout << " small: " << small<< std::endl;
            std::cout << " mid: " << mid<< std::endl;;
            std::cout << " big: " << big<< std::endl;;

            }

            int main(){

            int first,secnd,thered;

            do {
            std::cout << "*what numbers to sort?";
            std::cout << std::endl;
            std::cin >> first >>secnd >> thered ;
            std::cout << std::endl;
            if (first != 0) {
            sort(&first, &secnd, &thered);

            }

            }while(first != 0);

            }





            share|improve this answer








            New contributor




            Subice45 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$













            • $begingroup$
              You have presented an alternative solution, but haven't reviewed the code. Please explain your reasoning (how your solution works and why it is better than the original) so that the author and other readers can learn from your thought process.
              $endgroup$
              – Jamal
              22 mins ago














            -1












            -1








            -1





            $begingroup$

            #include <iostream>

            int min (int g, int a, int b){
            if (g < a && g < b){
            return g;
            }
            else if (a < g && a < b){
            return a;
            }
            else if (b < a && b < g){
            return b;
            }
            }
            int max (int g, int a, int b){
            if (g > a && g >> b){
            return g;
            }
            else if(a > g && a > b)
            {
            return a;
            }
            else if (b > g && b > a)
            {
            return b;
            }
            }
            int sort(int *g, int *a, int *b){
            int small = min(*g ,*a, *b);
            int big = max(*g, *a, *b);
            int mid ;
            if ((big != *g) && (small < *g)){
            mid= *g;
            }
            if ((big != *a) && (small < *a)){
            mid= *a;
            }
            if ((big != *b) && (small < *b)){
            mid= *b;
            }
            std::cout << "*output :"<< std::endl;
            std::cout << " small: " << small<< std::endl;
            std::cout << " mid: " << mid<< std::endl;;
            std::cout << " big: " << big<< std::endl;;

            }

            int main(){

            int first,secnd,thered;

            do {
            std::cout << "*what numbers to sort?";
            std::cout << std::endl;
            std::cin >> first >>secnd >> thered ;
            std::cout << std::endl;
            if (first != 0) {
            sort(&first, &secnd, &thered);

            }

            }while(first != 0);

            }





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            $endgroup$



            #include <iostream>

            int min (int g, int a, int b){
            if (g < a && g < b){
            return g;
            }
            else if (a < g && a < b){
            return a;
            }
            else if (b < a && b < g){
            return b;
            }
            }
            int max (int g, int a, int b){
            if (g > a && g >> b){
            return g;
            }
            else if(a > g && a > b)
            {
            return a;
            }
            else if (b > g && b > a)
            {
            return b;
            }
            }
            int sort(int *g, int *a, int *b){
            int small = min(*g ,*a, *b);
            int big = max(*g, *a, *b);
            int mid ;
            if ((big != *g) && (small < *g)){
            mid= *g;
            }
            if ((big != *a) && (small < *a)){
            mid= *a;
            }
            if ((big != *b) && (small < *b)){
            mid= *b;
            }
            std::cout << "*output :"<< std::endl;
            std::cout << " small: " << small<< std::endl;
            std::cout << " mid: " << mid<< std::endl;;
            std::cout << " big: " << big<< std::endl;;

            }

            int main(){

            int first,secnd,thered;

            do {
            std::cout << "*what numbers to sort?";
            std::cout << std::endl;
            std::cin >> first >>secnd >> thered ;
            std::cout << std::endl;
            if (first != 0) {
            sort(&first, &secnd, &thered);

            }

            }while(first != 0);

            }






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            answered 25 mins ago









            Subice45Subice45

            1




            1




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            New contributor





            Subice45 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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            • $begingroup$
              You have presented an alternative solution, but haven't reviewed the code. Please explain your reasoning (how your solution works and why it is better than the original) so that the author and other readers can learn from your thought process.
              $endgroup$
              – Jamal
              22 mins ago


















            • $begingroup$
              You have presented an alternative solution, but haven't reviewed the code. Please explain your reasoning (how your solution works and why it is better than the original) so that the author and other readers can learn from your thought process.
              $endgroup$
              – Jamal
              22 mins ago
















            $begingroup$
            You have presented an alternative solution, but haven't reviewed the code. Please explain your reasoning (how your solution works and why it is better than the original) so that the author and other readers can learn from your thought process.
            $endgroup$
            – Jamal
            22 mins ago




            $begingroup$
            You have presented an alternative solution, but haven't reviewed the code. Please explain your reasoning (how your solution works and why it is better than the original) so that the author and other readers can learn from your thought process.
            $endgroup$
            – Jamal
            22 mins ago





            protected by Jamal 22 mins ago



            Thank you for your interest in this question.
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