Selecting elements from lists based on string pattern
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
$endgroup$
add a comment |
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
$endgroup$
add a comment |
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
$endgroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
list-manipulation string-manipulation
asked 3 hours ago
Suite401Suite401
988312
988312
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
$endgroup$
add a comment |
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression
if your strings do not all begin with word characters.
$endgroup$
add a comment |
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f190698%2fselecting-elements-from-lists-based-on-string-pattern%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
$endgroup$
add a comment |
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
$endgroup$
add a comment |
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
$endgroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered 30 mins ago
kglrkglr
181k10200413
181k10200413
add a comment |
add a comment |
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression
if your strings do not all begin with word characters.
$endgroup$
add a comment |
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression
if your strings do not all begin with word characters.
$endgroup$
add a comment |
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression
if your strings do not all begin with word characters.
$endgroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression
if your strings do not all begin with word characters.
answered 2 hours ago
BillBill
5,62569
5,62569
add a comment |
add a comment |
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
$endgroup$
add a comment |
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
$endgroup$
add a comment |
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
$endgroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered 2 hours ago
Bob HanlonBob Hanlon
59.5k33596
59.5k33596
add a comment |
add a comment |
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f190698%2fselecting-elements-from-lists-based-on-string-pattern%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown