How to write linux find command with for loop on Jupyter












0















I am able to have a list of file names in a list named 'a' using the linux terminal command on Jupiter as follows;



a=!find . -type f ! -name '*.*' -print


To have the files names without extensions, the corresponding command works on linux terminal;



find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +


But how can I run this command on Jupyter assigning it to a name 'a' like above. The below code didn`t work.



a=!find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +


I have tried changing the indentation of lines as well, i get syntax error, or nothing. From my search on the command line of for loop on Jupiter the '!' should be perhaps in a different location. How can I make it work?










share|improve this question























  • Define "didn't work". How is it not working as expected or intended? Why are you not using Python's internal file traversal rather than escaping out to a shell? Are you aware that there is no such thing as an "file extension" in a POSIX environment?

    – DopeGhoti
    Jan 23 at 22:30













  • thanks. I meant if i preserve to indentation i get invalid syntax for 'pathname do', if i remove the indentations, nothing happens but when i print 'a' i get ''sh: 1: sh: Syntax error: end of file unexpected (expecting "done")''. I am not familiar with Python's internal file traversal or the POSIX environment yet.

    – kutlus
    Jan 23 at 22:51











  • You may need to escape the newlines by ending each line of the multi-line quoted content with a backslash, or just deal with it being one ugly line and get rid of the newlines altogether.

    – DopeGhoti
    Jan 23 at 22:53
















0















I am able to have a list of file names in a list named 'a' using the linux terminal command on Jupiter as follows;



a=!find . -type f ! -name '*.*' -print


To have the files names without extensions, the corresponding command works on linux terminal;



find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +


But how can I run this command on Jupyter assigning it to a name 'a' like above. The below code didn`t work.



a=!find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +


I have tried changing the indentation of lines as well, i get syntax error, or nothing. From my search on the command line of for loop on Jupiter the '!' should be perhaps in a different location. How can I make it work?










share|improve this question























  • Define "didn't work". How is it not working as expected or intended? Why are you not using Python's internal file traversal rather than escaping out to a shell? Are you aware that there is no such thing as an "file extension" in a POSIX environment?

    – DopeGhoti
    Jan 23 at 22:30













  • thanks. I meant if i preserve to indentation i get invalid syntax for 'pathname do', if i remove the indentations, nothing happens but when i print 'a' i get ''sh: 1: sh: Syntax error: end of file unexpected (expecting "done")''. I am not familiar with Python's internal file traversal or the POSIX environment yet.

    – kutlus
    Jan 23 at 22:51











  • You may need to escape the newlines by ending each line of the multi-line quoted content with a backslash, or just deal with it being one ugly line and get rid of the newlines altogether.

    – DopeGhoti
    Jan 23 at 22:53














0












0








0








I am able to have a list of file names in a list named 'a' using the linux terminal command on Jupiter as follows;



a=!find . -type f ! -name '*.*' -print


To have the files names without extensions, the corresponding command works on linux terminal;



find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +


But how can I run this command on Jupyter assigning it to a name 'a' like above. The below code didn`t work.



a=!find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +


I have tried changing the indentation of lines as well, i get syntax error, or nothing. From my search on the command line of for loop on Jupiter the '!' should be perhaps in a different location. How can I make it work?










share|improve this question














I am able to have a list of file names in a list named 'a' using the linux terminal command on Jupiter as follows;



a=!find . -type f ! -name '*.*' -print


To have the files names without extensions, the corresponding command works on linux terminal;



find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +


But how can I run this command on Jupyter assigning it to a name 'a' like above. The below code didn`t work.



a=!find . -type f -exec sh -c '
for pathname do
pathname=$( basename "$pathname" )
printf "%sn" "${pathname%.*}"
done' sh {} +


I have tried changing the indentation of lines as well, i get syntax error, or nothing. From my search on the command line of for loop on Jupiter the '!' should be perhaps in a different location. How can I make it work?







linux






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asked Jan 23 at 22:10









kutluskutlus

596




596













  • Define "didn't work". How is it not working as expected or intended? Why are you not using Python's internal file traversal rather than escaping out to a shell? Are you aware that there is no such thing as an "file extension" in a POSIX environment?

    – DopeGhoti
    Jan 23 at 22:30













  • thanks. I meant if i preserve to indentation i get invalid syntax for 'pathname do', if i remove the indentations, nothing happens but when i print 'a' i get ''sh: 1: sh: Syntax error: end of file unexpected (expecting "done")''. I am not familiar with Python's internal file traversal or the POSIX environment yet.

    – kutlus
    Jan 23 at 22:51











  • You may need to escape the newlines by ending each line of the multi-line quoted content with a backslash, or just deal with it being one ugly line and get rid of the newlines altogether.

    – DopeGhoti
    Jan 23 at 22:53



















  • Define "didn't work". How is it not working as expected or intended? Why are you not using Python's internal file traversal rather than escaping out to a shell? Are you aware that there is no such thing as an "file extension" in a POSIX environment?

    – DopeGhoti
    Jan 23 at 22:30













  • thanks. I meant if i preserve to indentation i get invalid syntax for 'pathname do', if i remove the indentations, nothing happens but when i print 'a' i get ''sh: 1: sh: Syntax error: end of file unexpected (expecting "done")''. I am not familiar with Python's internal file traversal or the POSIX environment yet.

    – kutlus
    Jan 23 at 22:51











  • You may need to escape the newlines by ending each line of the multi-line quoted content with a backslash, or just deal with it being one ugly line and get rid of the newlines altogether.

    – DopeGhoti
    Jan 23 at 22:53

















Define "didn't work". How is it not working as expected or intended? Why are you not using Python's internal file traversal rather than escaping out to a shell? Are you aware that there is no such thing as an "file extension" in a POSIX environment?

– DopeGhoti
Jan 23 at 22:30







Define "didn't work". How is it not working as expected or intended? Why are you not using Python's internal file traversal rather than escaping out to a shell? Are you aware that there is no such thing as an "file extension" in a POSIX environment?

– DopeGhoti
Jan 23 at 22:30















thanks. I meant if i preserve to indentation i get invalid syntax for 'pathname do', if i remove the indentations, nothing happens but when i print 'a' i get ''sh: 1: sh: Syntax error: end of file unexpected (expecting "done")''. I am not familiar with Python's internal file traversal or the POSIX environment yet.

– kutlus
Jan 23 at 22:51





thanks. I meant if i preserve to indentation i get invalid syntax for 'pathname do', if i remove the indentations, nothing happens but when i print 'a' i get ''sh: 1: sh: Syntax error: end of file unexpected (expecting "done")''. I am not familiar with Python's internal file traversal or the POSIX environment yet.

– kutlus
Jan 23 at 22:51













You may need to escape the newlines by ending each line of the multi-line quoted content with a backslash, or just deal with it being one ugly line and get rid of the newlines altogether.

– DopeGhoti
Jan 23 at 22:53





You may need to escape the newlines by ending each line of the multi-line quoted content with a backslash, or just deal with it being one ugly line and get rid of the newlines altogether.

– DopeGhoti
Jan 23 at 22:53










1 Answer
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oldest

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0














I solved this problem in a different way if anyone has a similar issue. I used the command line
a=!find . -type f ! -name '*.*' -print



this created a list of filenames with extensions. I removed the extensions from each element.



files = [os.path.splitext(fname)[0] for fname in a]





share|improve this answer























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    1 Answer
    1






    active

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    active

    oldest

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    active

    oldest

    votes









    0














    I solved this problem in a different way if anyone has a similar issue. I used the command line
    a=!find . -type f ! -name '*.*' -print



    this created a list of filenames with extensions. I removed the extensions from each element.



    files = [os.path.splitext(fname)[0] for fname in a]





    share|improve this answer




























      0














      I solved this problem in a different way if anyone has a similar issue. I used the command line
      a=!find . -type f ! -name '*.*' -print



      this created a list of filenames with extensions. I removed the extensions from each element.



      files = [os.path.splitext(fname)[0] for fname in a]





      share|improve this answer


























        0












        0








        0







        I solved this problem in a different way if anyone has a similar issue. I used the command line
        a=!find . -type f ! -name '*.*' -print



        this created a list of filenames with extensions. I removed the extensions from each element.



        files = [os.path.splitext(fname)[0] for fname in a]





        share|improve this answer













        I solved this problem in a different way if anyone has a similar issue. I used the command line
        a=!find . -type f ! -name '*.*' -print



        this created a list of filenames with extensions. I removed the extensions from each element.



        files = [os.path.splitext(fname)[0] for fname in a]






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 24 at 0:45









        kutluskutlus

        596




        596






























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